The volume of a volleyball is about 288 cubic inches. what is the radius of the volleyball, to the nearest tenth of an inch? use 3.14 for π.
[tex]r = \sqrt{ \frac{3v}{4\pi} } [/tex]
​

Answer:

rational

Best of luck!

Answer:

Step-by-step explanation:

3y = 5x - 1

y = 5/3x - 1/3

perpendicular slope is -3/5

Its the Right Answer on the Test. Hopes This Helps.

Thank You

Answer:

No Solution

Step-by-step explanation:

Step 1:

17 + 28 = - 5 ( 4x - 9 )

Step 2:

45 = - 20x + 45

Step 3:

- 20x = 0

Answer:

No Solution

Hope This Helps :)

Answer:

x = -3n/4

Step-by-step explanation:

Answer:

The answer is "[tex]\bold{\frac{343 \ \pi}{24} \ \text{cubic units}}[/tex]"

Step-by-step explanation:

The volume of the mass whose cross-sectional area has been perpendicular is usually sliced by the method The cross-section, which is based to parallel to y-axis;  

[tex]V = \int_{a}^{b} A (x)dx[/tex]

The semi-circular segment of the strong and seems to be perpendicular to foundation and  

Y-axis parallel.  

Its cross-section does have a diameter of: [tex](7-x)[/tex].  

It also transverse radius is: [tex]\frac{1}{2}(7-x)[/tex].  

The semi-circular segment area is,

[tex]Formula: \\\\ A(x)=\frac{1}{2} \times \pi \times r^2[/tex]

        [tex]=\frac{1}{2} \times \pi \times (\frac{(7-x)}{2})^2\\\\=\frac{1}{2} \times \pi \times (\frac{(7-x)^2}{4})\\\\=\frac{1}{8}\pi(7-x)^2\\[/tex]

when

[tex]0 \leq \ x \ \leq 7[/tex]

Calculating the volume from the solid accordingly:

[tex]V= \int_{0}^{7}\frac{1}{8} \times\pi \times (7-x)^2 dx[/tex]

   [tex]= \frac{1}{8} \pi \int_{0}^{7}(7-x)^2 dx \\\\= \frac{1}{8} \pi [\frac{(7-3)^3}{-3}]_{0}^{7}\\\\= \frac{\pi}{24} \times [7^3-0]\\\\= \frac{\pi}{24} \times 343\\\\= \frac{343 \pi}{24} \\[/tex]

Answer:

The length is 12yd and the width is 6yd.

Step-by-step explanation:

Answer:

Rs.15

Step-by-step explanation:

3% = 3/100 × 500 = 15

Answer:

25. 8ft

26. 3m

27. 7cm

Step-by-step explanation:

Because it says each is an area of a sqare the square root will give you the side length

Answer:

104

Step-by-step explanation:

5/8x. - - - - - - - >. 3/8x

56+x---------------> 24+x

Then solve for x

g^>JiGj+\1I1.G"yGLzn5Y^>&==o܋tǶgj<c_W#vioǾ|kZΧf՗yUwɻUʽ=އ

there are (1/6)/(1/3) one-third in one sixth

Step-by-step explanation:

that means

no. of one-third is 1/2

Answer:

there are 2 one third in one sixth

Answer:

  34.5%

Step-by-step explanation:

If we assume the relationship is approximately linear with time, we can use technology to draw a line of best fit through the given data. Extrapolating to the year 2030 predicts the value to be 34.5%.

In 2030, we might expect about 34.5% of male first-year college students to claim no religious affiliation.

_____

Additional comment

When it comes to religion, many factors are in play. The assumption we have made has no justification whatever, except that it provides a method for answering the question. (It also predicts the percentage to be 0 in 1963, which we believe to be unrealistic.) An exponential fit is better (r^2 = 0.97), and it predicts about 46.0%.

Answer:

$220 is the amount of simple interest you will earn

Step-by-step explanation:

I = p * r * t

Principle = $2000

Rate = 5.5% (you need to change this to a decimal by dividing by 100) or

         0.055

Time = 2 years

I = 2000 * 0.055 * 2

I = $220

Answer:

11

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Since, A, B, C, D are collinear.

[tex] \implies A - B - C - D \\

\therefore \: AD = (AB + BC) + CD \\ \therefore \: 18 = AC + CD.. (\because AB + BC =AC) \\ \therefore \: 18 = 8 + CD \\ \therefore \: 18 - 8 = CD \\ \therefore \: 10 = CD \\ \\ \because \: BC + CD = BD \\ BC = BD - CD \\ BC = 15 - 10 \\ BC = 5 \\ [/tex]

Answer:

[tex]\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}[/tex]

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

[tex](x-a)^2+(y-b)^2+(z-c)^2=r^2[/tex]

Where ([tex]x,y,z[/tex]) are the points on sphere.

[tex](a, b, c)[/tex] is the center of the sphere and

[tex]r[/tex] is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}[/tex]

Here,

[tex]x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3[/tex]

So, Radius is:

[tex]r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}[/tex]

Therefore the equation of the sphere is:

[tex](x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}[/tex]

Answer: He has 7 at the moment, technically, if he still has the bag, he still has all 36

Step-by-step explanation:

Answer:

he has noob 7

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Change all numbers to their decimal form.

37.5 % = 37.5 / 100 = 0.375

1/3 = 0.3333

0.3 = 0.3

40% = 40/100 = 0.4

3/5 = 0.6

Order

0.3

0.33333

0.375

0.4

0.6

Answer:

x=(-9)

PQ=2

PR=3

Step-by-step explanation:

Answer:

800,000

Step-by-step explanation:

The numbers are above 5 making it round up not down

Answer:  t > 6/5

In decimal form, this would be t > 1.2

==============================================

Work Shown:

6t > t+6

6t-t > t+6-t ...... subtracting t from both sides

5t > 6

5t/5 > 6/5 .... dividing both sides by 5

t > 6/5

t > 1.2

Answer:

39. r = 13.4

40. m = 12

Step-by-step explanation:

39. Given the equation, [tex] -0.8 + r = 12.6 [/tex], to solve for r, the following are the correct steps to take to arrive at the solution:

[tex] -0.8 + r = 12.6 [/tex] (given)

Add 0.8 to both sides of the equation (addition property of equality)

[tex] -0.8 + r + 0.8 = 12.6 + 0.8 [/tex] (this is where the error occurred.)

[tex] r = 13.4 [/tex]

40. The correct steps to take in solving the equation, [tex] -\frac{m}{3} = -4 [/tex] is as follows:

[tex] -\frac{m}{3} = -4 [/tex] (given)

Multiply both sides by 3 (multiplication property of equality)

[tex] 3*-\frac{m}{3} = 3*(-4) [/tex]

[tex] -m = -12 [/tex] (this is where the error occurred. This is what we should have at this line/step)

[tex] m = 12 [/tex] (dividing both sides by -1)

Answer: 6/11

Work Shown:

22 people total, 10 men, so 22-10 = 12 women are in the class.

12/22 = (2*6)/(2*11) = 6/11 is the fraction of women in the class

Answer:

I'm pretty sure the answer they want is 12/22 or 6/11 students are women although some people are not men or women which technically makes the question impossible to solve.

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

[tex]\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right][/tex] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

[tex]\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right][/tex]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

[tex]\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right][/tex] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

[tex]\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right][/tex]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

[tex]\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right][/tex] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

[tex]\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right][/tex]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

Answer:

Step-by-step explanation: