The space station is 4.41 x 10^5 kg and orbits the earth 6.78 x 10^6 m from the center of earth. The mass of earth is 5.97 x 10^24 kg. What is the gravitational force between these two objects?

Answer:

Kinetic energy

Explanation:

Answer:

[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]

Explanation:

Since,

So,

1.6 kWh = 1.6 units

If,

1.6 units = 9p × 1.6

1.6 units = 14.4p

[tex]\rule[225]{225}{2}[/tex]

You are working for a manufacturing company, which is mathematically given as

a)

Generally, the equation for the force of equilibrium is mathematically given as

F=2fcos\theta

Therefore

[tex]K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3[/tex]

[tex]m=3\sqrt{2}[/tex]

b)

By force equilibrium

[tex]K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}[/tex]

Therefore

[tex]n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\[/tex]

[tex]m=\frac{15\sqrt{5}}{16}[/tex]

c)

[tex]K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}[/tex]

x^2+a^2=(14/3)^{2/3}x^2

x=a/1.338

x=0.747a

d)

By force equilibrium

[tex]K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}[/tex]

[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]

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Answer:

resolution

Explanation:

  That is the definition of resolution

Answer:

metal, non, metal, metal, non, non, metal, non

Explanation:

knowledge

Answer:

Hello there seems to be no Images in this question but Kinetic energy is a push or a pull force which has to do with motion if you just need to know what t is. Next time be sure to add the pictures for it.

Explanation:

Thank you!

Hello the other person (#Sonichj123), was indeed correct there appears to be no picture in your question. Although there is no picture in your question, If you have another question I will be gladly to help you!

Explanation:

Thank you so much! (≥ФωФ≤)

Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.

Answer:

0.24 A

Explanation:

Voltage is given by the equation :

V = I × R

Voltage = Current × Resistance

Rearrange to make Current/I the subject :

18 = I × 75

I = 18÷75

I = 0.24 A

Hope this helped and brainliest please

Answer:

When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.

Answer:

The best reason for the increased risk of cardiovascular diseases in women after menopause is the significant decrease in the levels of Estrogen in the body.

Detailed answer:

Answer:

ma+mgsinh0​+f=F∴(25)(0.75)+(25)(10)sinh0​+μk​N=F∴18.75+(250)(0.6h)+μk​(mgcosh0​=F⟹18.75+150+μk​((25)(10)(0.76))=500∴168.75+μk​(190)=500⟹μk​(190)=331.25⟹μk​=1.74

Explanation:

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

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Time for which the wagon is pushed before it speed reaches 10m/s from rest.

The momentum is the product of mass of an object and its velocity.

Let the impact force is applied for time t. The impulse is equal to the change in momentum.

F.t = m(Vf -Vi)

where Vf =10 m/s, Vi =0 m/s, m =20kg and F =200N, then time for the force applied will be

200 x t = 20 x (10)

t =1s

Thus, the time for which the wagon is pushed before it speed reaches 10m/s from rest is 1s.

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Fluid Dynamics is an area of ​​research that started a long time ago, along with Calculus. It combines techniques of Mathematical Analysis and of Dynamical Systems, such as Bifurcation Theory, among others.

Surface Tension is a phenomenon that occurs in all liquids, it is characterized by the formation of a kind of elastic membrane at its ends.

Contact angles in powders can be measured using the sessile drop measurement in the compressed powder or using the force tensiometer with the Washburn method.

In fluid dynamics, the variables of surface tension, viscosity and contact angle are treated. When dealing with viscosity we have  fluid can be viscous or a real fluid. In general, fluids are viscous.

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Hi there!

To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.

For this, we can use the work-energy theorem to solve.

Recall the following equations:
[tex]W = \Delta KE[/tex]

[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]

We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.

The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]

For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]

**λ = Linear charge density (C/m)

To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]

Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]

[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]

Now, we can begin solving for 'a'.

Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]

Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]

It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.

From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is  6.4 * 10^7 .

According to Hooke's law, the force is directly proportional to the extension of the wire.

Given that;

F = Ke

F = 240N

e = 0.8 mm or 0.0008m

K = F/e

K = 240N/0.0008m

K = 3.0 * 10^5 N/m

Now;

Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3

= 6.4 * 10^7

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T he role of oxygen in air supply is to keep all the ling beings live and healthy.

Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.

Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.

Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.

Thus, the air supply needs oxygen on the majority.

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Based on the calculations, it would take 7.5 seconds before the final velocity of this object would be equal to three times its initial velocity.

Given the following data:

Mathematically, acceleration can be calculated by using the first equation of motion:

v = u + at

Where:  

Making t the subject of formula, we have:

t = (v - u)/a

Substituting the given parameters into the formula, we have:

t = (45 - 15)/4

t = 30/4

t = 7.5 seconds.

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An object of volume 2.0×10^4cm³ is underwater, the buoyant force of the water on the object  

Fb= 1.962 *10^7N

Generally, the equation for buoyant force   is mathematically given as

Fb = g * p * V

Therefore

Fb=9.81* 2.0*10^4 *1000

Fb= 1.962 *10^7N

In conclusion,  the buoyant force

Fb= 1.962 *10^7N

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The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

The speed of the car passing you is determined by applying relative velocity principle as shown below;

Vr = Va - Vb

Vr = 26 m/s - 32 m/s

Vr = -6 m/s

Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

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Hi there!

We can use the following relationship between the Potential Difference and the Electric field:

[tex]V = E d[/tex]

V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)

We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]

Plug in the given values.

[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]

Friction can only occur between solids, liquids and gas.

Friction can be defined as the force that a moving object encounters when sliding over a surface.

The various phases of matter include solid, liquid and gases and friction occurs in all the three phases of matter.

Therefore, Friction can only occur between solids, liquids and gas.

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Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse . No matter the size of the triangle, the values of sin(θ) and cos(θ) are the same for a given θ, as illustrated below.

The reason why the moon does not fall back to the earth is that  the Moon's rotation about its own axis creates centripetal force

that balances Earth's pull.

The gravitational force is the force that keeps the solar system together. All the members of the celestial bodies are held in place by gravity.

Thus, the reason that keeps the moon from falling back to the earth is because the Moon's rotation about its own axis creates centripetal force that balances Earth's pull.

Hence,  their tangential velocity is sufficient to ensure that the flight path misses the object being orbited. The centripetal force is enough to bend the otherwise straight path into an ellipse.

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Answer:

  D. The Moon has a large tangential velocity that causes it to "miss" Earth as it falls toward it.

Explanation:

You want to know what keeps the Moon from falling directly to Earth.

The Moon does not fall directly to Earth because the direction of motion is more or less perpendicular to the direction of Earth from the Moon. That is, the large tangential velocity causes it to "miss" Earth.

Additional comment

One object will orbit another if their mutual gravitational attraction provides enough acceleration (change in speed and/or direction) to bend the path into a circular or elliptical one. If the acceleration is too little, the path may be bent, but no orbit will be established. If the acceleration is too great, the path may be bent to a curve that ultimately causes the objects to collide.

In general, the multi-body dynamics present in the solar system mean that the orbits of various objects are chaotic. In the short term, they are fairly predictable, but short-term behavior may not be predictive of long-term behavior.

Answer:

8.16m/s south

Explanation:

North is the negative direction.

60kg*(-5m/s)+79.5kg*v=(79.5kg+60kg)*(2.5m/s)

-300kgm/s+79.5kg*v=348.75kgm/s

79.5kg*v=648.75kgm/s

v=8.16m/s

Answer:

D. Poison

Explanation:

Answer:

One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.

Hence, self-representation and leadership skills are the correct answer.

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