The pulley shown in the attached diagram has a diameter of 30 centimeters and a mass of 19 kilograms. The pulley is a solid disk with an axle through its center.

(a.) What is the moment of inertia of the pulley?

(b.) What is the magnitude of the net torque on the pulley about its axis

(c.) What is the direction of the net torque on the pulley?

(d.) What is the magnitude of the angular acceleration of the pulley?

(e.) What is direction of the angular acceleration?

The Pulley Shown In The Attached Diagram Has A Diameter Of 30 Centimeters And A Mass Of 19 Kilograms.

Answers

Answer 1

Answer:

Explanation:

a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²

b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m

c) CCW

d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²

e) CCW


Related Questions

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string. (a) If the breaking strength of the string is 120 N, what’s the minimum angle the string can make with the horizontal? (b) At this minimum angle, what’s the rock’s speed?

Answers

(a) The minimum angle the string can make with the horizontal is 4.4 ⁰.

(b) The rocks speed at the minimum angle is 165.7 m/s.

The given parameters;

mass of the rock, m = 940 g = 0.94 kglength of the string, L = 1.3 mTension on the string, T = 120 N

The net force on the string is calculated as follows;

[tex]Tsin(\theta) = mg\\\\Tcos(\theta) = \frac{mv^2}{r} \\\\\frac{Tsin(\theta)}{Tcos(\theta)} = \frac{mg r}{mv^2} \\\\tan(\theta) = \frac{rg}{v^2} \\\\v^2 = \frac{rg}{tan (\theta)} \\\\v = \sqrt{\frac{rg}{tan (\theta)}}[/tex]

The minimum angle the string can make with the horizontal is calculated as follows;

[tex]Tsin(\theta) = mg\\\\sin(\theta) = \frac{mg}{T} \\\\sin(\theta) = \frac{0.94 \times 9.8}{120} \\\\sin(\theta) = 0.0767\\\\\theta = sin^{-1} (0.0767)\\\\\theta = 4.4 \ ^o[/tex]

The rocks speed at the minimum angle is calculated as follows;

[tex]v = \sqrt{\frac{rg}{tan(\theta)} } \\\\v = \sqrt{\frac{1.3 \times 9.8}{tan(4.4)} } \\\\v = 165.7 \ m/s[/tex]

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A man with a mass of 60 kg rides a bike with a mass of 13 kg. What is the force needed by the man to accelerate the bike at 0.90 m/s2?​

Answers

bro it would be9999999 cuh cuh

define potential difference as used in electricity​

Answers

Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit.

Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... The energy is transferred to the electrical components in a circuit when the charge carriers pass through them. We use a voltmeter to measure potential difference (or voltage).

Thinking Mathematically: Explore the quantitative dependencies of the acceleration upon the speed and the radius of curvature. Then answer the following questions. a. For the same speed, the acceleration of the object varies _____________ (directly, inversely) with the radius of curvature. b. For the same radius of curvature, the acceleration of the object varies _____________ (directly, inversely) with the speed of the object. c. As the speed of an object is doubled, the acceleration is __________________ (one-fourth, one-half, two times, four times) the original value. d. As the speed of an object is tripled, the acceleration is __________________ (one-third, one-ninth, three times, nine times) the original value. e. As the radius of the circle is doubled, the acceleration is __________________ (one-fourth, one-half, two times, four times) the original value. f. As the radius of the circle is tripled, the acceleration is __________________ (one-third, one-ninth, three times, nine times) the original value.

Answers

The expression for the centripetal acceleration allows to find the results for the questions are:

A) The acceleration varies INVERSELY with the radius of curvature.

B) The acceleration varies DIRECTLY with the speed.

C) The acceleration becomes four times greater.

D) The acceleration becomes nine times greater.

E) The acceleration is reduced to half.

F) The acceleration is reduced to a third.

In circular motion there must be an acceleration towards the center of the circle, it is called cenripetal acceleration, in this case all the energy supplied to the system is used to change the direction of the speed even when its magnitude remains constant.

        [tex]a_c = \frac{v^2}{r}[/tex]  

Where [tex]a_c[/tex] the centripetal acceleration, v is the speed and r the radius of curvature of the circle.

Now we can answer the questions about centripetal acceleration.

A) For the same speed, the acceleration varies INVERSELY with the radius of curvature.

B) For the same radius of curvature the acceleration varies DIRECTLY with the speed.

C) The speed is doubled

         v = 2 v₀

         [tex]a_c = \frac{(2v_o)^2 }{r}[/tex]  

         [tex]a_c = 4 \ \frac{v_o^2 }{r}[/tex]  

The acceleration becomes four times greater than the original value

D) The speed is tripled

         v = 3 v₀

         [tex]a_c = 9 \frac{ v_o^2}{r}[/tex]  

Acceleration becomes nine times greater than the original

E) the radius of curvature is doubled

        r = 2 r₀  

        [tex]a_c = \frac{v_o^2}{2 r_o }[/tex]  

        [tex]a_c = \frac{1}{2} a_o[/tex]  

Acceleration is reduced to half the original value

F) The radius of curvature is tripled

       r = 3 r₀

       [tex]a_c = \frac{v_o^2 }{3 r_o} \\ \\a_c = \frac{1}{3} a_o[/tex]  

       

The acceleration is reduced to a third of the initial one.

In conclusion using the expression for the centripetal acceleration we can find the answers for the questions are:

A) The acceleration varies INVERSELY with the radius of curvature.

B) The acceleration varies DIRECTLY with the speed.

C) The acceleration becomes four times greater.

D) The acceleration becomes nine times greater.

E) The acceleration is reduced to half.

F) The acceleration is reduced to a third.

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A faulty fireworks rocket launches but never discharges. If the rocket launches
with an initial velocity of 33.0 ft/s at an angle of 85.0°, how far away from the
launch site does the rocket land?

Answers

Answer:

a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0∘ above the horizontal. During the flight, the rocket explodes into two pieces of equal mass (see Fig. 8.32). (a) What horizontal distance from the launch point will the center of mass of the two pieces be after both have landed on the ground? (b) If one piece lands a horizontal distance of 26.0 m from the launch point, where does the other piece land?

A particle of mass m is fired upwards from the surface of a planet of mass M
and radius R with velocity
Show that the maximum height the particle attains is R/3.

Answers

At the maximum height the particles position has been shown as [tex]\frac{R}{3}[/tex].

The given parameters;

mass of the particle, = Mradius of the particle, = Rmaximum height the particle attains = R/3

The velocity of the particle is given as;

[tex]v^2 = \frac{GM}{2R}[/tex]

The total mechanical energy of the particle is given as;

[tex]-\frac{GMm}{R} + \frac{1}{2} mv^2 = - \frac{GMm}{R} + \frac{1}{2} mv^2[/tex]

At maximum height the final velocity of the particle is zero.

[tex]-\frac{GMm}{R} + \frac{1}{2} mv^2 = - \frac{GMm}{R +h}[/tex]

[tex]-\frac{GMm}{R} + \frac{1}{2} m\times \frac{GM}{2R} = - \frac{GMm}{R +h}\\\\-\frac{GMm}{R} + \frac{GMm}{4R} = - \frac{GMm}{R +h}\\\\- \frac{3GMm}{4R} = - \frac{GMm}{R +h}\\\\- \frac{3}{4R} = - \frac{1}{R+ h} \\\\3(R+ h) = 4R\\\\3R + 3h = 4R\\\\3h = 4R - 3R\\\\3h = R\\\\h = \frac{R}{3}[/tex]

Thus, at the maximum height the particles position has been shown as [tex]\frac{R}{3}[/tex].

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Which statement correctly describes the relationship between thermal energy and particle movement?(1 point)

As thermal energy increases, there is more particle movement.
As thermal energy increases, there is more particle movement.

As thermal energy increases, there is less particle movement.
As thermal energy increases, there is less particle movement.

As thermal energy increases, particle movement does not change.
As thermal energy increases, particle movement does not change.

As thermal energy increases, it is not possible to predict particle movement.
As thermal energy increases, it is not possible to predict particle movement.

Answers

Answer:

As thermal energy increases,there is more particle movement

9. Steradian is the angel which lies in:
a) One dimension
b) Two dimensions

Answers

Answer:

B

Explanation:

B

How did ancient organisms become fossil fuels?

Answers

Answer:

One of the most widespread beliefs about fossil fuels — oil, natural gas and coal — is that these substances started out as dinosaurs. There’s even an oil company, Sinclair, that uses an Apatosaurus as its icon. That dino-source story is, however, a myth. What is true: These fuels got their start long, long ago — at a time when those “terrible lizards” still walked the Earth.

Fossil fuels store energy in the bonds between the atoms that make up their molecules. Burning the fuels breaks apart those bonds. This releases the energy that originally came from the sun. Green plants had locked up that solar energy within their leaves using photosynthesis, millions of years ago. Animals ate some of those plants, moving that energy up the food web. Others plants just died and decayed.

Any of these organisms, when they die, can be turned into fossil fuels, notes Azra Tutuncu. She’s a geoscientist and petroleum engineer at the Colorado School of Mines in Golden. But it takes the right conditions, including an oxygen-free (anoxic) environment. And time. A whole lot of time.

The coal we burn today got its start some 300 million years ago. Back then, dinosaurs roamed the Earth. But they didn’t get incorporated into coal. Instead, plants in bogs and swamps died. As this greenery sunk to the bottom of those wet areas, it partially decayed and turned into peat. Those wetlands dried out. Other materials then settled down and covered the peat. With heat, pressure and time, that peat transformed into coal. To extract coal, people now have to dig deeply into the earth.

Ancient living organisms are buried quickly and altered by intense heat and pressure to form fossil fuels. Fossil fuels include solid coal, liquid petroleum, and liquid natural gas.

Source; Goo_gle

if this was helpful then please mark me the brainliest

if i was not helpful then i am very sorry

if two masses 5.2kg and 4.8kg are attached to ends of inextensible string passed over a friction less pulley then acceleration of system

Answers

Answer:

If two masses 5.2 kg and 4.8 kg are attached to the ends of inextensible strings passed over a frictionless pulley then the acceleration of system is 0.4 ms-2.

Explanation:

What is the initial velocity (in m/s) of a car if it takes 10 seconds to travel a kilometer
while accelerating at 2 m/s??

Answers

B bd eneemkelelele elelel wlelle

can anyone heelp me pls

Answers

Answer:

Capsule : solid

Suspension : liquid

lotion : semisolid

Explanation:

What is the main tenet of mechanical philosophy

Answers

Answer:362

Explanation:

i just want the points

Answer:

Some ancient philosophies held that the universe is reducible to completely mechanical principles—that is, the motion and collision of matter. This view was closely linked with materialism and reductionism, especially that of the atomists and to a large extent, stoic physics.

Explanation:

Hope this helps.

From what material did the moon form?How are eras and periods of the geologic time scale named?

Answers

Answer:

this

Explanation:

because of this its this ok

Answer: They are named for the places where geologists first described rocks or fossils from that time.

Explanation: ingenuity

The function of which system is to transport food, oxygen and enzymes, etc. to all cells and to remove carbon dioxide and wastes from cells?

Answers

Answer:

the cardiovascular system

The box is pushed to the left with 30 N of force, but does not move. What is the Friction Force?​

Answers

However here coefficient of friction is not given so unable to calculate.

You can calculate it by below formula.

The formula given by

[tex]\\ \sf\longmapsto F_f=\mu N[/tex]

Or

[tex]\\ \sf\longmapsto F_f=\mu mg[/tex]

u is coefficient of friction

N is normal reaction.

Here..

box doesn't move means the force if limiting friction is greater than applied force.

What is the kinetic energy of a 36N toy car which is moving at 5 m/s?

Answers

Answer : I think the answer is 45 J
Explanation: in the picture

somebody please help me with this

Answers

Answer:

C.

Explanation:

That is the main part of a cell, apart of the nervous system and controls all the other functions of the cell.

I hope this helped

Brainliest if it did? No pressure!

Have a great day! :D

Pls help and thank u need asap!

Answers

Answer:

ill help if u help me?its 4am

A flea can jump with an initial velocity of 2.2 m/s at an angle of 21° with respect to the
horizontal.

Answers

Answer:

Explanation:

If no one can see it because the lights were out. Did the flea really jump?

What do you want here?

Max height (2.2sin21)²/ 2(9.8) = 3.2 cm

Time of flight 2(2.2sin21)/ (9.8) = 0.16 s

distance of flight (2.2cos21)(0.16) = 33 cm

How much time does it take for a school bus traveling at 15 m/s north to get a distance of 600 meters north?

Possible answers:
40 seconds
9,000 seconds
615 seconds
0.025 seconds

Answers

Answer:

40s

Explanation:

A block slides down an incline plane that makes a 30 degree angle with the
horizontal. If the coefficient of kinetic friction is 0.3. Calculate the acceleration of the block.

Answers

Hi there!

We know that:

Force due to gravity = Mgsinθ

Force due to friction = μMgcosθ

Let the positive direction be directed in the direction of the block's acceleration, which is downward.

Thus:

ΣF = Mgsinθ - μMgcosθ

Solving for acceleration requires diving all terms by the mass, so:

a = gsinθ - μgcosθ

Substitute in given values. (g = 9.8 m/s²)

a = 9.8sin(30) - 0.3(9.8)cos(30) = 2.354 m/s²

A Wheatstone Bridge type circuit is shown (10marks) R1=20ohms, R2=10ohms, R3=8ohms, R4=5ohms, and R5=2ohms and also has 10V battery. Determine A. the p.d. between terminals B and D, and (5 marks) B. The value to which R4 must be adjusted in order to reduce the current through R3 to zero (balance the bridge). (5marks)​

Answers

Answer:

Dunno

Explanation:

Dunno

How do you explain this arrangement of fossils? What might have happened?

Answers

Answer:

The question lacks a photo to fully answer correctly

If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.

If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.

Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.

Answer:

Peripatus, which lived around 570 MYA, is in the top layer of rock. The trilobites that lived later, between 498 MYA and 445 MYA, appear in the bottom layer. Based on superposition, younger layers of rock are expected to be on top. The rock layers have been overturned, placing the younger layer on the bottom.

Explanation:

actually answer plauto

How much heat must be added to 160 g of ice at 0°C to melt the ice completely? The latent heat of fusion of ice is 80 cal/g.



The amount of heat required is
cal

Answers

To melt the ice you will need 33.4 cal

HELP!!! I HAVE NO IDEA!!!!!!!!!!!!!

1. A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?

a. 0.4 kg
b. 1.6 kg
c. 2.4 kg
d. 0.8 kg


2. Which of the following would be a situation with unbalanced forces?

a. Two people pulling on the same side of a wheelbarrow
b. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d. Two people not touching a crate that is sitting stationary.


3. Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary

a. The force of gravity on the object is different if it is stationary or not.
b. The force of friction on the object is different if it is stationary or not
c. The force of the push on the object is different if it is stationary or not
d. The normal force on the object is different if it is stationary or not.

Thanks In Advance!! (I will mark brainliest) :)

Answers

Answer:

Explanation:

The engine should create the same force

1) F = ma

  F = M(½a)

therefore

ma = ½Ma

 m = ½M

 M = 2m

 M = 2(0.8)

 M = 1.6 kg

2) Unbalanced forces

 a. Two people pulling on the same side of a wheelbarrow

 c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force

3) b. The force of friction on the object is different if it is stationary or not

A ball is projected with an angle o from the top of a tower of height h with velocity vo. The ball strikes the ground after a certain time t, then show a vo sino 2gh 1 + 1 + vo-sin20 t/​

Answers

Answer:

dvnuncxtumvd7ojf433f and tv36v54f vs Craig

a person on a bike (m=90 kg) is traveling 4 m/s at the top of a 2 m hill. what is the bikers total energy?

A) 1,944 J

B) 2,484 J

C) 1,764 J

D) 720 J

Answers

Answer:

720 J

Explanation:

Kinetic Energy = 1/2 * m *(v*v)

M= 90 kg

V=4 m/s

KE=1/2 * 90 * (4*4)

KE= 45*16= 720 J

[tex]\frac{m}{s}[/tex]Answer: D) 720 J

Explanation:

Given : m=90kg

Total Energy = K. E. + P. E.  =[tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex]+mgh

Since bike is present over a surface of Earth (top of hill) hence h=0m.

Therefore,

Total Energy=  [tex]\frac{1}{2}[/tex]*90kg*[tex](4m/s)^{2}[/tex]+(90kg)*(9.81[tex]\frac{m}{s}^2[/tex])x(0)

= 720 J

Hence total energy of bike is equal to 720 J

A 500-kg golf cart is moving on level ground in a circular path of radius 10 m with a speed of 12 m/s. What is the centripetal force acting on the cart?

Answers

Answer:

7200N

Explanation:

Centripetal force is directly proportional to the product of the mass and the square of the velocity and inversely proportional to the radius given.

in a closed system of a cannon and cannonball, which changes would both results in an increase in the kinetic energy of the cannonball when fired from the cannon?

A) decrease the mass of the cannon or decrease the mass of the cannonball

B) increase the mass of the cannon or decrease the mass of the cannonball

C) decrease the mass of the cannon or increase the mass of the cannonball

D) increase the mass of the cannon or increase the mass of the cannonball

Answers

the answer is b because when it increases the mass decreases the cannon ball

Changes that would results in an increase in the kinetic energy of the cannonball in a closed system, when it is fired from the cannon is B:increase the mass of the cannon or decrease the mass of the cannonball.

A closed system can be considered one that is not been affected by external forces. With the conservation of momentum, there would be collisions as well inexplosions.

This explains that when a cannon is fired, there would be gain of forward momentum by the cannon ball, while the cannon experience backward momentum.

For the kinetic energy of the cannonball to increase, when fired from the cannon, then the mass is the cannon would be increased or the mass of the cannonball would be decreased.

Therefore, option B is correct.

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