The hypotenuse of a 30°-60°-90° triangle is 6.
A. Find the lengths of the two legs of the triangle.
B. Find the perimeter.

the last option i believe. sorry if it's wrong

Answer:

It’s B and E

Step-by-step explanation:

Three dollars plus $0.50 times the number of miles is equal to nine dollars and fifty cents.

The sum of three dollars and the product of 50 cents times the number of miles is nine dollars and fifty cents.

Answer:

ill be figuring this out rn, (theres a caculator thingy online if nobody helps u)

Step-by-step explanation:

44.4 is the Percent and as a fraction its

111/250 (thats what i got)

6.66 as a dec. and as a fraction its 333/50

sorry if these are wrong bur its what i got.

Answer:

the blue block 'side' is 10

the pink block ' bottom' is 9

the cream 'side' block is 13 (length)

the green back triangle next to the blue side is also 10

and the other side of the green back triangle is 8

Answer:

3/10

Step-by-step explanation:

Answer: 226

Step-by-step explanation:

arc ZW is 180 (it is a semi Circle) and arc WX is 46 (the angle opposite the arc)

so arc ZWX is 180+46=226

Answer:

k = 4/25 or 0.16

Step-by-step explanation:

Given the following data;

y = 4/5

x = 5

To find the variation constant, k;

y is directly proportional to x

Mathematically, y = kx

Substituting into the formula, we have;

4/5 = k5

Cross-multiplying, we have;

4 = 25k

k = 4/25

Answer:

The Pythagorean theorem states that a2 + b2 = c2 in a right triangle where c is the longest side. You can use this equation to figure out the length of one side if you have the lengths of the other two.

Answer:

angle 3x = 78°

angle opposite (4x + 30) = 226°

Step-by-step explanation:

It has 6 sides, so:

total interior angles sum = (180° x 6) - 360° = 720°

720° = 90° + 3x + 90° + 118° + (360° - (4x + 30°)) + 118°

combine like terms:

720° = 3x + 416° + (360° - 4x - 30°)

720° = -x + 746°

x = 26°

Step-by-step explanation:

The given equation is :

2x = 10

We need to find the value of x.

This equation has one solution as it is a linear equation having one variable i.e. x.

Dividing both sides by 2,

x = 5

So, the value of x is equal to 5.

Put x = 5. So,

2(5) = 10

10 = 10

Hence, this is the required solution.

The general rule for the given Sequence is a_n = 1 – 2n, where n = 1, 2, 3, ... This equation allows us to calculate any term in the sequence by substituting the corresponding value of n.

The given sequence –1, –3, –5, –7, –9,... follows a specific pattern or rule. To determine the general rule for n = 1, 2, 3,..., we can observe the sequence and identify the relationship between the terms.

Looking at the sequence, we notice that each term is decreasing by 2. Starting with –1, we subtract 2 to get the next term –3. Then, we subtract 2 again to get –5, and so on. Therefore, the rule for generating the terms in this sequence is to start with –1 and subtract 2 from each subsequent term.

We can express this rule algebraically as follows:

a_n = a_1 + (n – 1) * d

Where:

a_n represents the nth term of the sequence,

a_1 represents the first term of the sequence,

n represents the position of the term in the sequence,

d represents the common difference between the terms.

In this case, a_1 = –1 and d = –2 (since each term is decreasing by 2). Plugging these values into the equation, we get:

a_n = –1 + (n – 1) * (–2)

Simplifying further, we have:

a_n = –1 – 2n + 2

a_n = 1 – 2n

Therefore, the general rule for the given sequence is a_n = 1 – 2n, where n = 1, 2, 3, ... This equation allows us to calculate any term in the sequence by substituting the corresponding value of n.

For more questions on Sequence .

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Note the full question may be :

From the following sequence: – 1, – 3, – 5, – 7, – 9,…, What is the general rule for n=1, 2, 3,…?

Answer:

Step-by-step explanation:

Greatest common factor of 6x and 9y is 3.

6x + 9y = 3(2x + 3y)

:::::

Greatest common factor of 3c and 11c is c.

3c + 11c = (3+11)c

Answer:

n = 10

Step-by-step explanation:

From the question,

nC6 = nC4

n!/6!(n-6)! = n!/4!(n-4)!

Simplifying n! out of the equation

⇒ 1/6!(n-6)!  = 1/4!(n-4)!

Crossmultiplying

4!(n-4)! = 6!(n-6)!

4!(n-4)! = 6×5×4!(n-6)!

(n-4)! = 30(n-6)!

(n-4)(n-5)(n-6)! = 30(n-6)!

⇒ (n-4)(n-5) = 30

n²-4n-5n+20 = 30

n²-9n+20-30

n²-9n-10 = 0

Solving the quadratic equation,

n-10n+n-10 = 0

(n-10n)+(n-10) = 0

n(n-10)+1(n-10) = 0

(n+1)(n-10) = 0

Either

n+1 = 0

n = -1

or

n-10 = 0

n = 10

n canot be a negative value,

Therefore, n = 10

Answer:

nsdjdhbdeihddjjdoeuriehdisueueeuhd

Answer:

hi

Step-by-step explanation:

10+963=973

have a nice day

Answer:

10+963= 973

Step-by-step explanation:

Answer 973

i hope this help

Answer:f

Step-by-step explanation:d

Answer:

10 h 55 min

Step-by-step explanation:

13 h 10 - 2h = 11 h 10

11 h 10 - 15 min = 10 h 55 min

Brooke earned $9.00 in interest over one year on her account with $90 at a 10% annual interest rate, compounded annually.

To solve this problem, we can use the formula for compound interest:

A =[tex]P(1 + r/n)^(^n^t^)[/tex]

where A is the amount of money in the account after t years, P is the principal (the initial amount of money), r is the annual interest rate as a decimal, n is the number of times the interest is compounded per year, and t is the time period in years.

In this case, we want to find the interest earned in one year, so we can set t = 1. We know that Brooke has $90 in her account, so P = 90. The annual interest rate is 10%, or 0.1 as a decimal. The interest is compounded annually, so n = 1.

We can plug these values into the formula and solve for the amount of money in the account after one year:

A = [tex]90(1 + 0.1/1)^(^1^*^1^)[/tex]

A = 90(1.1)

A ≈ 99

The amount of money in the account after one year is approximately $99. So, Brooke earned $99 - $90 = $9 in interest. To the nearest cent, this is $9.00.

In conclusion, using the formula for compound interest, we can calculate the interest earned on an account given the initial balance, annual interest rate, number of compounding periods per year, and time period.

For such more questions on interest

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Answer:

25

Step-by-step explanation:

Find the prime factors of each term in order to find the greatest common factor (GCF),

25

Answer:

180

Step-by-step explanation:

Answer:

B. 6.2

Step-by-step explanation:

The calculation is done by hand and verified by a TI-84 calculator.

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

24 is awnser

Step-by-step explanation:

Pls mark me as brainliest

Answer:

7/10

Step-by-step explanation:

Answer:

7/10

Step-by-step explanation:

There is a total of ten numbers, and only seven of them are odd numbers (1, 3, 7, 9, 15, 19, 21)

You have a 70% chance of picking an odd number.

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{-12=6\sqrt{x+4}}[/tex]

[tex]\mathsf{6 \sqrt{x + 4}=-12}[/tex]

[tex]\textsf{DIVIDE your BOTH SIDES by 6}[/tex]

[tex]\mathsf{\dfrac{6\sqrt{x + 4}}{6}= \dfrac{-12}{6}}[/tex]

[tex]\textsf{Introduce the new temporary equation}[/tex]

[tex]\mathsf{\sqrt{x + 4}=-2}[/tex]

[tex]\textsf{SOLVE for your SQUARE ROOT }[/tex]

[tex]\mathsf{\sqrt{{x + 4}}=-2}[/tex]

[tex]\mathsf{Like: x + 4 = (-2)^2}[/tex]

[tex]\textsf{SQUARE EACH of your SIDES}[/tex]

[tex]\mathsf{x + 4 = 4}[/tex]

[tex]\textsf{SUBTRACT your BOTH SIDES by 4 }[/tex]

[tex]\mathsf{x + 4 -4= 4-4}[/tex]

[tex]\mathsf{Cancel\ out\ 7-7 \ because\ it\ gives\ you\ 0}[/tex]

[tex]\textsf{Solving for your last temporary question}[/tex]

[tex]\mathsf{x = 4-4}[/tex]

[tex]\mathsf{4-4 = \bf 0}[/tex]

[tex]\mathsf{\bf x = 0}[/tex]

[tex]\textsf{Plug your x-value (x = 0) to make sure it works for your original equation}[/tex]

[tex]\textsf{You will see that it doesn’t work for the original problem so this means that the}\\\textsf{original equation \bf does NOT have any solutions.}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \huge\bf No solutions}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

g

Step-by-step explanation:

the point at the intersection of the parabola and its line of symmetry