The formula for finding the area of a square that has a side length, s, is A = s2. If a square has an area of 40 square units,
what is the length of a side?
A. 2./10
B. 10.12
C. 20

Answer:

0.045 kg of cookies

Answer: 0.045

Step-by-step explanation:

Answer:

10×2+ 5÷2

=20+2.5

=22.5

Answer:

Question 1: A

Question 2: D

Step-by-step explanation:

I hope it helps

Answer:

The equation has one solution.

A value of x that makes the equation true is 5, which when substituted into the equation and simplified makes the equation turn into 10=10

A value of x that makes the equation false is 6, which when substituted into the equation and simplified makes the equation turn into 12=10

Step-by-step explanation:

2x=10

Divide both sides by two:

2x/2=10/2

x=5. There is no other solution to the equation, because 5 is the only possible answer.

Answer:

22

Step-by-step explanation:

a+b^2

= -3+(5^2)

= -3+25

=22

Answer:

The only option which is not available for Mr. Lloyd is to use his debit card to purchase the television now. The debit card can only be Used to make purchases when the account holder has funds or money in his or her account.

Step-by-step explanation:

Answer:

Feet and yards; the 1 whole strip could represent 1 yd. and the [tex]\frac{1}{3}[/tex] strip could represent feet.

Answer:

15 C

Step-by-step explanation:

C = 5/9( F - 32)

Let F = 59

C = 5/9( 59 -32)

Parentheses first

   = 5/9( 27)

   = 15

Answer:

48/80

Step-by-step explanation:

In order to get a denominator of 80, we need to turn the current denominator, 10, into 80. We do this by multiplying it by 8. We then have to multiply the top by 8 to keep it equal.

hope this helped :)

so u r already finished? don't post it next time

Without replacement is very important

Answer:

B and D

Step-by-step explanation:

This is because for B you do 8x9x1 which is basically 8x9 which is 72. Then, for D you do 12x3x2. Do 3x2 first and you get 6. Then, do 6x12 which is also 72. So the correct answers that will give you the volume of 72 units cube is B and D. Hope this helps!

Answer:

[tex](a)\ g(x) = \frac{2}{3}(x+1)[/tex]

[tex](b)\ h(y) = \frac{1}{3}[1 + 4y][/tex]

[tex](c)[/tex] [tex]P(x>0.5) =\frac{5}{12}[/tex]

Step-by-step explanation:

Given

[tex]f(x,y) = \left \{ {{\frac{2}{3}(x+2y)\ \ 0\le x \le 1,\ 0\le y\le 1} \right.[/tex]

Solving (a): The marginal density of X

This is calculated as:

[tex]g(x) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dy[/tex]

[tex]g(x) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dy[/tex]

[tex]g(x) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dy[/tex]

Integrate

[tex]g(x) = \frac{2}{3}(xy+y^2)|\limits^{1}_{0}[/tex]

Substitute 1 and 0 for y

[tex]g(x) = \frac{2}{3}[(x*1+1^2) - (x*0 + 0^2)}[/tex]

[tex]g(x) = \frac{2}{3}[(x+1)}[/tex]

Solving (b): The marginal density of Y

This is calculated as:

[tex]h(y) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dx[/tex]

[tex]h(y) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dx[/tex]

[tex]h(y) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dx[/tex]

Integrate

[tex]h(y) = \frac{2}{3}(\frac{x^2}{2} + 2xy)|\limits^{1}_{0}[/tex]

Substitute 1 and 0 for x

[tex]h(y) = \frac{2}{3}[(\frac{1^2}{2} + 2y*1) - (\frac{0^2}{2} + 2y*0) ][/tex]

[tex]h(y) = \frac{2}{3}[(\frac{1}{2} + 2y)][/tex]

[tex]h(y) = \frac{1}{3}[1 + 4y][/tex]

Solving (c): The probability that the drive-through facility is busy less than one-half of the time.

This is represented as:

[tex]P(x>0.5)[/tex]

The solution is as follows:

[tex]P(x>0.5) = P(0\le x\le 0.5,0\le y\le 1)[/tex]

Represent as an integral

[tex]P(x>0.5) =\int\limits^1_0 \int\limits^{0.5}_0 {\frac{2}{3}(x + 2y)} \, dx dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 \int\limits^{0.5}_0 {(x + 2y)} \, dx dy[/tex]

Integrate w.r.t. x

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 (\frac{x^2}{2} + 2xy) |^{0.5}_0\, dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 [(\frac{0.5^2}{2} + 2*0.5y) -(\frac{0^2}{2} + 2*0y)], dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 (0.125 + y), dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}(0.125y + \frac{y^2}{2})|^{1}_{0}[/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125*1 + \frac{1^2}{2}) - (0.125*0 + \frac{0^2}{2})][/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125 + \frac{1}{2})][/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125 + 0.5][/tex]

[tex]P(x>0.5) =\frac{2}{3} * 0.625[/tex]

[tex]P(x>0.5) =\frac{2 * 0.625}{3}[/tex]

[tex]P(x>0.5) =\frac{1.25}{3}[/tex]

Express as a fraction, properly

[tex]P(x>0.5) =\frac{1.25*4}{3*4}[/tex]

[tex]P(x>0.5) =\frac{5}{12}[/tex]

Answer:

219 percent

Step-by-step explanation:

97 goes into 213 two times which is a 200 percent increase which leaves 18 books. 18.5 percent of 97 is about 18 so rounded up it is a 219 percent increase

Answer:

6

Step-by-step explanation:      6 9 0

Answer:

y = 3x+4

Step-by-step explanation:

slope formula is changes of y over the changes of x

[tex] \large \boxed{m = \frac{y_2-y_1}{x_2-x_1} }[/tex]

m is slope in y = mx+b.

Substitute the coordinate points in.

[tex] \large{m = \frac{7 + 2}{1 + 2} } \\ \large{m = \frac{9}{3}} \\ \large{m = 3}[/tex]

Since we know the slope, we rewrite by substituting m = 3 in the slope-intercept form.

[tex] \large{y = mx + b} \\ \large{y = 3x + b}[/tex]

Then we either substitute one of given coordinate points to find the value of b. I will substitute (1,7) in the equation.

[tex] \large{7 = 3(1)+ b} \\ \large{7 = 3 + b} \\ \large{7 - 3 = b} \\ \large{4 = b}[/tex]

Then rewrite the equation from y = 3x+b by substituting the value of b.

[tex] \large{y = 3x + b} \\ \large{y = 3x + 4}[/tex]

Answer:

Step-by-step explanation:

use your calculator

Answer:

I believe its c

Step-by-step explanation:

Answer:

(4, -11)

Explanation:

The coordinate's signs just change (negative becomes positive and vise versa)

Answer:

(2, 5)

Step-by-step explanation:

(x,y) -> )- y,x)

Answer:

D

Step-by-step explanation:

The mean, median, and mode all are 3

Answer:

(a) AH < HC is No

(b) AH < AC is Yes

(c) △AHC ≅ △AHB is Yes

Step-by-step explanation:

Given

See attachment for triangle

Solving (a): AH < HC

Line AH divides the triangle into two equal right-angled triangles which are: ABH and ACH (both right-angled at H).

To get the lengths of AH and HC, we need to first determine the measure of angles HAC and ACH. The largest of those angles will determine the longest of AH and HC. Since the measure of the angles are unknown, then we can not say for sure that AH < HC because the possible relationship between both lines are: AH < HC, AH = HC and AH > HC

Hence: AH < HC is No

Solving (b): AH < AC

Length AC represents the hypotenuse of triangle ACH, hence it is the longest length of ACH.

This means that:

AH < AC is Yes

Solving (c): △AHC ≅ △AHB

This has been addresed in (a);

Hence:

△AHC ≅ △AHB is Yes

Answer:

200

Step-by-step explanation:

Answer: 200

Step-by-step explanation:

The two is in the hundredths place

First, write the expression. Then solve.

9 x 10^-9

9 x 0.0000000010

0.000000009

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sorry if i'm wrong, I haven't done this in a while

Answer:

7 weeks

Step-by-step explanation:

add 10 to 125 then divide by 20

Answer: he will need to save to 7 weeks

Step-by-step explanation:

125+10=135

he needs 135 to get the kit

y=20x

135=20x

6.75=x

he will need to save to 7 weeks

Answer:

y=x+31.25

Because x stand for cauclator so 31.25 per x so it would end up being x+31.25

Step-by-step explanation:

Answer:

Step-by-step explanation:

# 12

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23

12 is a median of a data

Answer:

m=8

Step-by-step explanation:

Divide each term in

7

m

=

56

7

m

=

56

by

7

7

.

7

m

7

=

56

7

7

m

7

=

56

7

Cancel the common factor of

7

7

.

Tap for more steps...

m

=

56

7

m

=

56

7

Divide

56

56

by

7

7

.

m

=

8

m

=

8

Step-by-step explanation:

7m=56

you have to have m by itself so to do that divide 7 on both sides.

7m/7=56/7

the 7 gets cancels on the left side so now you have

m=56/7

you divide

you get m=8

Answer:

D

Step-by-step explanation:

Answer:D

Step-by-step explanation: