Answer:
pt 1: [tex]m=1.66698*10^{21} kg[/tex]
Pt 2: [tex]KE=1212.23531 J[/tex]
Explanation:
Information Given: (p = density)
l = 5200km d = 35km p = 2700kg/[tex]m^{2}[/tex]
Part 1: Mass
Find volume [tex]V=(l)^2(d)[/tex][tex]V=(4.2*10^6)^2(35*10^3)[/tex][tex]V=61.74*10^{16}[/tex]Find Mass[tex]m=Vp[/tex][tex]m=(61.74*10^{16})(2700)[/tex][tex]m=1.66698*10^{21}[/tex]Part 2: Kinetic Energy
[tex]v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}[/tex][tex]v=1.20497*10^{-9}[/tex][tex]KE=\frac{1}{2}mv^2[/tex]
[tex]KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2[/tex]
[tex]KE=1212.23531 J[/tex]
Part 3: Jogger Speed
set up, because I don't have the mass :(
Information given:
[tex]KE_{jogger}[/tex]
[tex]KE=\frac{1}{2}mv^2[/tex][tex]v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }[/tex]Input the valuesHope it helps :)
Need help fast it’s on forces!
i think the answer is h if am wrong am sorry
Explanation:
which of the following is a lever
Answer: the last one
Explanation: it pushes the lid off in a upward motion
Answer:
the last one
Explanation:
Can you mark me as BRAINLLIEST, PLEASE!!!!!!!!!!!!
(○’ω’○) (ToT) ↖(^ω^)↗ -_-z ◑﹏◐ 囧 ^O^ B-)
turns into _____ energy (when plants convert into food)
Answer:
its called photosynthesis
Explanation:
when plants turn food into energy. Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy and stored in the form of starch which can be used later.
Answer:
The answer would be photosynthesis
Explanation:
In this case plants convert light energy (1) into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy. :)
A 1.2 kg block of wood hangs motionless from strings. A 50 g bullet, traveling horizontally, strikes the block and becomes embedded inside the block. Immediately after the bullet becomes embedded in the block, the block is observed to have a speed of 8.0 m/s. What was the speed of the bullet before it hit the block?
A. 200 m/s.
B. 12 m/s.
C 98 m/s.
D 9,604 m/s.
E 57 m/s.
Answer:
A. 200m/s
Explanation:
Using the law of conservation of momentum expressed as;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the respective velocities
v is the common velocity
Given
m1 = 1.2kg
u1 = 0m/s (block is a stationary object)
m2 = 50g= 0.05kg
u2 = ?
v = 8.0m/s
Substitute the values into the formula and get u2 (speed of the bullet before hitting the block)
1.2(0)+0.05u2 = (1.2 + 0.05)(8)
0.05u2 = 1.25(8)
0.05u2 = 10
u2 = 10/0.05
u2 = 200m/s
Hence the speed of the bullet before it hit the block is 200m/s
in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s
Answer:25 N
Explanation:
in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s is 25N
what is speed ?Speed is the ratio of distance with respect to the time in which the distance was covered. Speed is a scalar quantity as it does not have magnitude only have direction
The formula of speed can be represented as s=d/t, Where, s is the speed in m.s-1, d is the distance traveled in m, t is the time taken in s
Uniform speed is defined when the object covers equal distance at equal time intervals, variable speed is defined as when the object covers a different distance at equal intervals of times.
Average speed is defined as the total distance travelled by an object to the total time taken by the object.
Instantaneous speed is defined as when the object is move with variable speed, then the speed at any instant of time is known as instantaneous speed.
For more details regarding speed, visit
brainly.com/question/13263542
#SPJ5
A block with mass m = 0.200 kg is placed against a compressed spring at the bottom of a ramp that is at an angle of 53.0∘ above the horizontal. The spring has 8.00 J of elastic potential energy stored in it. The spring is released, and the block moves up the incline. After the block has traveled a distance of 3.00 m, its speed is 4.00 m/s. Part A What is the magnitude of the friction force that the ramp exerts on the block while the block is moving? Express your answer with the appropriate units.
Answer:
[tex]0.566\; \rm N[/tex] (assuming that while the block is moving, the friction on the block is constant.)
Explanation:
The mechanical energy of a system is the sum of its:
elastic potential energy, gravitational potential energy, andkinetic energy.Friction does work on the block as the block moves up the ramp. The amount of energy that the block-string system has lost would be equal in size to the work that friction has done on the block. The size of the friction on the block could thus be computed.
Before this block was released, the block-spring system has no kinetic energy because there was no movement. Assume that the system has no gravitational potential energy at that moment, either. The only type of mechanical energy in this system at that moment would be elastic potential energy: [tex]8\; \rm J[/tex] according to the question.
The question states that the ramp is [tex]53.0^\circ[/tex] above horizontal. Therefore, after the block has traveled [tex]3.00\; \rm m[/tex] (along the ramp,) the height of this block would have increased by [tex]\Delta h = 3.00\; \rm \sin\left(53^\circ\right) \approx 2.39591\; \rm m[/tex]. Calculate the corresponding gain in gravitational potential energy:
[tex]\begin{aligned}& m \cdot g \cdot \Delta h\\ &\approx 0.200\; \rm kg& \\\ &\quad\times 9.81\; \rm N \cdot kg^{-1} \\ &\quad \times 2.39591\; \rm m \\ &\approx 4.70077\; \rm J\end{aligned}[/tex].
On the other hand, the question states that the speed of the block ([tex]m = 0.200\; \rm kg[/tex]) at that moment is [tex]v = 4.00\; \rm m \cdot s^{-1}[/tex]. Calculate the corresponding kinetic energy:
[tex]\begin{aligned}& \frac{1}{2}\, m \cdot v^{2} = 1.6\; \rm J \end{aligned}[/tex].
Because the block was already released, there should be no elastic potential energy in the spring.
Hence, the mechanical of the block-spring system would be approximately [tex]4.70077\; \rm J+ 1.6\; \rm J \approx 6.30077\; \rm J[/tex].
Approximate the amount of mechanical energy that is lost:
[tex]8\; \rm J - 6.30077\; \rm J \approx 1.69923\; \rm J[/tex].
In other words, when applied over [tex]3\; \rm m[/tex], the friction on this block would do approximately [tex]1.69923\; \rm J[/tex] of work. Approximate the size of that friction:
[tex]\begin{aligned}F &= \frac{W}{s} \\ &\approx \frac{1.69923\; \rm J}{3.00\; \rm m}\approx 0.566\; \rm N\end{aligned}[/tex].
A rocket falls from the apogee (0 meters per second) until it hits the ground with a speed of 10 meters per second. Gravity pulled it down with an acceleration of 9.8m/s^2. The time during which the ball is in free fall is approximately what time?
Answer:
Approximately 1.02 seconds
Explanation:
Use the final velocity (vf) formula for a uniformly accelerated movement under "g" (acceleration of gravity):
[tex]v_f=v_i+g\,*\,t[/tex]
in our case:
[tex]10=0+9.8\,*\,t\\t=10/9.8\\t\approx 1.02\,\,sec[/tex]
A drag racing vehicle travels from 0 to 100 mph in 5 seconds north. What is the acceleration?
Answer:
20 m/s^2
Explanation:
Use the formula Vf=Vi+at
Vf=100
Vi=0
a=?
t=5
Then solve for (a)
Initial velocity of a car is 36 km/hr. Find the distance after one min, if it goes with acceleration 2m/s².
[A] 4000 m.
[B] 4200 m.
[C] 4400 m.
[D] 4600 m.
Answer:
[tex]\bf\pink{4200\:m}[/tex]Explanation:
Given :-[tex]\sf\red{ Initial \ velocity = 36km/hr = 10m/s}[/tex][tex]\sf\orange{ Acceleration = 2m/s^{2}}[/tex][tex]\sf\green{Time = 1\:min = 60\: sec}[/tex]To Find :-[tex]\sf\blue{Distance \: Travelled}[/tex]Formula used :-[tex]\sf\purple{s = ut + \dfrac{1}{2} at^{2}}[/tex]Where,
s = [tex]\bold{Distance}[/tex]t = [tex]\bold{Time }[/tex]u = [tex]\bold{ Initial \ velocity}[/tex]a = [tex]\bodl{Acceleration}[/tex]Solution :-[tex]\Rightarrow\:\:\rm{s = 10(60) + \dfrac{1}{\cancel{2}} \times \cancel{2} \times (60)^{2}}[/tex]
[tex]\Rightarrow\:\:\rm{s = 600+60\times 60}[/tex]
[tex]\Rightarrow\:\:\rm{s = 600 + 3600}[/tex]
[tex]\Rightarrow\:\:\rm{s = {\bf{\red{4200\:m}}}}[/tex]
Hence, [tex]\bf\green{(B)}[/tex] is the correct optiona 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Find the total momentum of the system.
Explanation:It is given that,
Mass of bumper car, m₁ = 202 kg
Initial speed of the bumper car, u₁ = 8.5 m/s
Mass of the other car, m₂ = 355 kg
Initial velocity of the other car is 0 as it at rest, u₂ = 0
Final velocity of the other car after collision, v₂ = 5.8 m/s
Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁
Using the conservation of linear momentum as :
p₁ = m₁v₁ = -342 kg-m/s
So, the momentum of the 202 kg car afterwards is 342 kg-m/s. Hence, this is the required solution.
Answer:
1717 kg*m/s
Explanation:
found it put it in on acellus and it was right
A ball is thrown off a cliff at a speed of 10 m/s in a horizontally direction. The ball reaches the ground 1.5 seconds. If the ball is launched a second time at the same speed from a second higher cliff, which of the following is true?
A. The ball takes a longer time and lands further away from the foot of the cliff.
B. The ball takes longer to hit the ground, but lands at the same distance from the foot of the cliff.
C. The ball takes the same time lands at the same distance from the foot of the cliff.
D. The ball falls further away from the foot of the cliff, but takes the same time.
Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30
kg box at the same acceleration, how much force will Brianna need to apply? She applies _ N of force.
Answer:
She applies 75N of force
Explanation:
F=ma
50=20(2.5)
F=30(2.5)
F=75 N
The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of -5.05 m/s2 for 4.05 s, making straight skid marks 65.0 m long, all the way to the tree. With what speed does the car then strike the tree?
Find the answer in m/s.
Answer:
656.5 m/s
Explanation:
V = ? U = 0 m/s a = 5.05 m/s2 S = 65.0 m
V = u + 2as
V = 0 + 2× 5.05 × 65
V = 656.5 m/s
Which term describes the force applied to an object multiplied by the time the force is applied
Answer:
Momentum
Explanation:
In order for an object's momentum to change,a force must be applied for a period of time
What happens to the sunlight that does not reach Earth’s surface?
What is the formula for electrical power?
A. P = IV/R
B. P = IVR
C. P = IR
D. P = IV
Correct answer is D!
Electrical power can be defined as the product of Voltage and current. Thus, P = IV. Hence, Option D is the correct answer.
What is Power?As we study Electric power, the electric current to the another form of energy.The SI unit of power is the watt or one joule per second.Electric power can be calculated as current times voltage. Electrical energy used by equals the power of the appliances and its multiplied by the amount of time and the appliance is used.Thus, the formula for electric power,
P = IV watt
Where,
P - Power (Watt)
I - Current (Ampere)
V - Voltage (volts)
Power can be also known as the mechanical power equation.Also, the power dissipated energy can also be found with the equation.Electrical power can be defined as the product of Voltage and current. Thus, P = IV. Hence, Option D is the correct answer.
Learn more about Power,
https://brainly.com/question/27442707
#SPJ2
Which statement illustrates how progress in engineering has affected the natural environment?
A. Extracting mineral resources with modern mining equipment removes fertile topsoil.
B. Mining companies use modern equipment to extract mineral resources more efficiently.
C. Modern mining equipment has improved the health and safety of workers.
D. Modern mining practices provide materials that can be used for technological advances.
Correct answer is A
Answer:
A. Extracting mineral resources with modern mining equipment removes fertile topsoil.
Explanation:
Mining is defined as the process that involves the extraction of valuable minerals from large amounts of waste rock.
Progress in engineering has affected the natural environment and mining is one of the best examples of this. The use of modern mining equipment removes fertile topsoil and highly influences the fertility of the soil. It is hard to reconstruct topsoil and modern mining equipment continuously damaging soil fertility.
Hence, the correct answer is "A. Extracting mineral resources with modern mining equipment removes fertile topsoil."
Answer:
a
Explanation:
a pex
The effect of gravity on a falling object can be modeled by a ball dropped from different heights. What is a limitation of this model?
A. Not all objects bounce, even though balls do.
B. Some balls float in water, while others sink.
C. The ball can be dropped from varying heights.
D. Friction with air also affects the fall of the object.
Correct answer is D
Answer:
D.
Explanation:
try it.. *lil uzi vert's voice*
The limitation of the model of a ball dropped from different heights is that friction with air also affects the fall of the object. Hence, option (D) is correct.
What is Galileo's Leaning Tower of Pisa experiment?According to a biography written by Galileo's student Vincenzo Viviani in 1654 and published in 1717, between 1589 and 1592, the Italian scientist Galileo Galilei, who was then a professor of mathematics at the University of Pisa, is said to have dropped two spheres with the same volume but different masses from the Leaning Tower of Pisa to show that their time of descent was independent of their mass. A few decades previously, Italian experimenters had already proven the fundamental tenet.
Galileo, it is said, discovered through this experiment that the items fell with the same acceleration, confirming his prediction and refuting Aristotle's theory of gravity in the process (which states that objects fall at speed proportional to their mass). The majority of historians believe it to have been more of a thought experiment than a physical test.
Learn more about gravity here:
https://brainly.com/question/4014727
#SPJ2
find the base area of a cylinder with diameter 1m
Answer:
AB=0.79
Explanation:
hope this helped
The diagram shows an electromagnet made with copper wire, a steel nail,
and a 1.5 V battery. Which action could cause this electromagnet to be
stronger?
A. Replace the steel nail with a plastic straw.
B. Replace the battery with a 6 V battery.
C. Reduce the number of coils of wire wrapped around the nail.
D. Reverse the direction of the battery in the circuit.
Correct answer is B!
Answer:B
Explanation: i took the test and i got it right
Answer this question: Is math really important to giving science power? (remember the 5 Ws and the H)
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction between the refrigerator and the floor is 230 N. How much work has been performed by the mover on the refrigerator?
Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :
[tex]W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m[/tex]
Hence, this is the required solution.
Does anyone knows this for physics?
A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of its maximum speed?
Answer:
The positions are 0.0194 m and - 0.0194 m.
Explanation:
Given;
amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m
speed of simple harmonic motion is given as;
[tex]v = \omega \sqrt{A^2-x^2}[/tex]
the maximum speed of the simple harmonic motion is given as;
[tex]v_{max} = \omega A[/tex]
when the speed equal one fourth of its maximum speed
[tex]v =\frac{v_{max}}{4}[/tex]
[tex]\omega\sqrt{A^2-x^2} = \frac{\omega A}{4} \\\\\sqrt{A^2-x^2}= \frac{A}{4}\\\\A^2-x^2 = \frac{A^2}{16} \\\\x^2 = A^2 - \frac{A^2}{16} \\\\x^2 = \frac{16A^2 - A^2}{16} \\\\x^2 = \frac{15A^2}{16} \\\\x= \sqrt{\frac{15A^2}{16} } \\\\x = \sqrt{\frac{15(0.02)^2}{16} }\\\\x = 0.0194 \ m \ \ or\ - 0.0194 \ m[/tex]
Thus, the positions are 0.0194 m and - 0.0194 m.
The positions where the speed equals 1/4 of its maximum speed is mathematically given as
[tex]x \pm 0.0194[/tex]
What positions does its speed equal one-fourth of its maximum speed?Question Parameters:
an amplitude of 2.00 cm.
Generally, the equation for the speed of simple harmonic motion is mathematically given as
[tex]v = w \sqrt{A^2-x^2}\\\\v=\frac{wA}{4}[/tex]
Therefore
[tex]w \sqrt{A^2-x^2}=\frac{wA}{4}\\\\x^2=A^2-A^2/16\\\\x=\sqrt{\frac{15A^2}{16}}[/tex]
[tex]x \pm 0.0194[/tex]
In conclusion, the positions are
[tex]x \pm 0.0194[/tex]
Read more about Speed
https://brainly.com/question/4931057
A certain heat engine does 30.2 kJ of work and dissipates 9.14 kJ of waste heat in a cyclical process.
A) What was the heat input to this engine?
B) What was its efficiency?
Answer:
a) [tex]H_{in}=39.34 kJ[/tex]
b) Efficiency=76.77%
Explanation:
a)
In order to solve this problem, we can use the following formula:
[tex]H_{in}=H_{out}+W[/tex]
the problem provides us with all the necessary information so we can directly use the formula:
[tex]H_{in}=9.14kJ+30.2kJ[/tex]
[tex]H_{in}=39.34 kJ[/tex]
b) In order to find the efficiency, we can use the following formula:
[tex]Efficiency=\frac{W}{H_{in}}*100\%[/tex]
so we get:
[tex]Efficiency=\frac{30.2kJ}{39.34kJ}*100\%[/tex]
Efficiency=76.77%
6. What is the mass of a boy who is standing on top of a 1.5 meter high
wall and has 735 J of gravitational potential energy?
Answer:
m = 50 [kg]
Explanation:
The potential energy can be calculated by means of the following equation.
[tex]E_{p}=m*g*h[/tex]
where:
Ep = potential energy = 735 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1.5 [m]
Now replacing:
[tex]735=m*9.81*1.5\\m = 50 [kg][/tex]
1. The property of a material to absorb liquid like water is called
A non-porous
C. buoyancy
B. density
D. porosity
HELP ME PLEASE I MARK BRAINLIESTIF YOU ANSWER THIS♡
Answer:
A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.
Explanation:
A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.
A rescue helicopter is lifting a man with 86 kg mass from a capsized boat by means of a cable and harness. What is the tension in the cable when the man is given an initial upward acceleration of 1.35 m/s2
The man is pulled upward by a net force of
∑ F = (86 kg) (1.35 m/s²) = 116.1 N
The net force is comprised of the tension T in the cable and the man's weight W, such that
∑ F = T - W = 116.1 N
T = (86 kg) (9.80 m/s²) + 116.1 N
T = 958.9 N ≈ 960 N
____ is the ability to course change in matter
Answer:
i don't know the correct answer
but this is what i found on web
Explanation:
Changes of state are physical changes in matter. They are reversible changes that do not change matter's chemical makeup or chemical properties. Processes involved in changes of state include melting, freezing, sublimation, deposition, condensation, and evaporation. Energy is always involved in changes of state.
8) a 20kg box is sliding across the ground. If the coefficient of friction is 0.5, how much friction will the box experience?
A 490 N
B 19.6 N
C 98 N
D 2 N
Answer:
STOP CHETING
Answer:
C is the answer to your question
Explanation:
Have a great day!!! :)