The art club in Northwestern middle school is selling candy bars as a fundraiser. each art club member....

Answer:

The domain in interval notation is [-4,∝) or set build: {x|x[tex]\geq[/tex]

Step-by-step explanation:

I'm assuming the 9x and the 36 are in the root

[tex]\sqrt{9x+36}[/tex]

first we must solve for x

[tex]{9x+36}\geq 0[/tex]

substract 36 to both sides

[tex]{9x}\geq -36[/tex]

divide by 9 to both sides

[tex]\frac{9x}{9} }\geq \frac{-36}{9}[/tex]

simplify left side

[tex]x\geq \frac{-36}{9}[/tex]

simplfy right side

[tex]x\geq -4[/tex]

The domain in interval notation is [-4,∝) or set build: {x|x[tex]\geq[/tex]-4}

Answer:

512

Step-by-step explanation:

64 × 8 = 512

512

64 8

16 4 2

8 2 2 1

Answer:

$40

Step-by-step explanation:

Answer:

(x, y) = (-1, 1)

Step-by-step explanation:

Answer:

1270

Step-by-step explanation:

420+300+550

$420+300=720+550=1270

The simplified expression for the product [tex](4x\sqrt{5x^2} )(2x^2\sqrt{6})[/tex] is:

[tex]8\sqrt{30} x^4[/tex]

The given expression is:

[tex](4x\sqrt{5x^2} )(2x^2\sqrt{6})[/tex]

Note that :

[tex]\sqrt{5x^2} = x\sqrt{5}[/tex]

The given expression can then be re-written as:

[tex](4x^2\sqrt{5} )(2x^2\sqrt{6})[/tex]

Multiplying like terms together:

[tex]8x^4\sqrt{30}[/tex]

Finally, the resulting expression can be written as:

[tex]8\sqrt{30} x^4[/tex]

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Answer:

D 104 x Superscript 4 + 16 x Superscript 4 Baseline StartRoot 30 EndRoot

Step-by-step explanation:

Edg 2022

Answer:

610

Step-by-step explanation:

31 x 10= different flavour and topping combination

x2 = for the whipped cream different option

Answer:

The chicken which is sold for 5 boxes for 25.50 is better priced.

Step-by-step explanation:

If you buy five boxes of the chicken from the place where it is 5.50 a box, buying five will be 27.50, which costs more than the place with the 25.50 price for five boxes.

Answer:

Hi i think its option 3 maybe just wait until someone else helps but i say option 3 but gl anyways

Step-by-step explanation:

Answer:

x = notebooks

y = indexboks

3x+4y=32 ( here is spent all money so I add 32 here )

5x+5y=50

by elemination method

3x+4y=32×5

5x+5y=50×4 ( here I'm going to eliminate y )

15 x+20y= 160

20x+20y= 200

- - = -

____________

-5x = -40

x = - 40 / -5

x = 8

here - × - = + so iam taking positive 8

now substitute the value of x in any equation

3×8+4y = 32

24 + 4y = 32

4y = 32-24

y = 8 / 4

y = 2

CHECKING

SUBSTITUTE BOTH VALUES IN ANY EQUATION

5×8+5×2 = 50

40 + 10 = 50

50 = 50

I SUBSTITUTE IN 2ND EQUATION

Answer:

(8,2)

Step-by-step explanation:

Given that:

3x + 4y = 32  --------- eq1

5x + 5y = 50 --------- eq2

From taking 5 common from eq2:

x + y = 10

Or it can also be written as:

x = 10 - y ----------eq3

Now put this value of x in eq1

3(10 - y) + 4y = 32

By simplifying:

30 - 3y +4y= 32

30 +y = 32

Subtracting 30 from both sides:

y = 32 - 30

y = 2

Putting value of y in eq 3

x = 10 - 2

x = 8

Answer:

it is c

Step-by-step explanation:

me big brain

Answer: y = 3x +1

Step-by-step explanation:

Answer:

[tex]y=-\frac{12}{5}[/tex]

I think this is the correct answer

Answer: 17) 150°C 18) 17 minutes

Step-by-step explanation:

x represents time in minutes and y represents temperature in Celsius

17) y=10x+30

y=10(12)+30

y=120+30

y=150 - Therefore, the water temperature will be 150°C after 12 minutes

18) 200=10x+30

10x+30=200

10x+30-30=200-30

10x=170

x=17  - Therefore, the water temperature will reach 200°C after 17 minutes

Answer:

y = 3x = 1

Step-by-step explanation:

Answer:

y = 3x - 1

Step-by-step explanation:

Check. Plug in the given x, and see if the result is the given y:

y = 3x - 1

When: (x = 8 , y = 23)

23 = 3(8) - 1

23 = (3 * 8) - 1

23 = (24) - 1

23 = 23 (True).

When: (x = 2 , y = 5)

5 = 3(2) - 1

5 = (3 * 2) - 1

5 = 6 - 1

5 = 5 (True)

When: (x = -3 , y = -10)

-10 = 3(-3) - 1

-10 = (3 * -3) - 1

-10 = (-9) - 1

-10 = -10 (True).

When (x = 9 , y = 26)

26 = 3(9) - 1

26 = (3 * 9) - 1

26 = (27) - 1

26 = 26 (True).

When you graph, simply graph the given points (bolded) onto the graph.

Answer:

17

Step-by-step explanation:

Answer:

plot 17

Step-by-step explanation:

12-(-5) = 12+5 = 17

Answer:

  18

Step-by-step explanation:

Triangles FEG and DEG are congruent by SAS, so DG = FG.

  a+6 = 3a

  6 = 2a

  3 = a

  3a = 3·3 = 9 = FG = DG

DF = 9+9 = 18

Answer:

Step-by-step explanation:

The answer is easy it’s 24

Answer:

P = 12 pi units + 24 units.

Step-by-step explanation:

All sides of an equilateral triangle are of the same length.  Here that length is 12 units.  We take a circle of diameter 12 units and cut it in half through its center.  Finally, we join the triangle (remembering that all of the side lengths are 12 units) to the half circle of diameter 12 units.

The half circle portion of the resulting shape has circumference 2(pi)(12 units) divided by 2, or 12 pi units.  This is half the formula C = 2(pi)(r).  The two non-attached sides of the triangle have a total length of 24 units.

Thus, the perimeter of the resulting figure is P = 12 pi units + 24 units.

Answer:

5

Step-by-step explanation:

this means it'll be $55

The answer 120 MESSAGES

Answer:

57

Step-by-step explanation:

h(-5) = (-5)^2 - 5(-5) + 7

h(-5) = 25 + 25 +7

h(-5) = 57

Answer:

[tex]\bold{h(-5)=57}[/tex]

Step-by-step explanation:

Substitute [tex]-5[/tex] for everywhere there is [tex]x[/tex]

[tex]h(x) = x^2 - 5x +7\\=-5^2 - 5(-5) +7[/tex]

[tex]-5^2 - 5(-5) +7[/tex]

PEMDAS order of operations

Parenthesis

[tex]\bold{-5\times(-5)}\\=25[/tex]

[tex]-5^2+25 +7[/tex]

Exponents

[tex]\bold{-5^2}\\=-5\times-5\\=25[/tex]

[tex]25+25 +7[/tex]

Addition

[tex]25+25+7\\=50+7\\=57[/tex]

Therefore, [tex]\bold{h(-5)=57}[/tex].

Answer:

Shift "h" units to the right, "k" units up, and reflect over the x or y axis when needed.

Step-by-step explanation:

1) I want to talk about reflections first.

2) Rigid transformations

Example (check image for visual)

We transform [tex]y = x^2[/tex] to [tex]y = -(-x-3)^2+3[/tex] , you move right 3, then reflect across the x-axis, then reflect across y-axis, then move 3 up.

--------------------------------------------------------------------------------------------------------------

Note: In the image, the red line is the original function, the blue one is the transformed function. See if you can follow along with the verbal instructions I gave above.

[tex]x^3+12x^2+47x+60\\\\=x^3+3x^2 +9x^2+27x+20x+60\\\\=x^2(x+3) + 9x(x+3)+20(x+3)\\\\=(x+3)(x^2+9x+20)\\\\=(x+3)(x^2 + 4x +5x +20)\\\\=(x+3)[x(x+4)+5(x+4)]\\\\=(x+3)(x+4)(x+5)[/tex]

The type of laboratory that is not required to have coved floors is a BSL2.

Safety in laboratories is measured through the Biosafety Level scale. This scale evaluates how much protection do people working in the laboratory need to avoid any risks while working with pathogens or toxins.

This scale goes from 1 to 4 and the 4 level represents labs in which extremely dangerous pathogens are studied, and therefore labs with the highest safety protocols.

In this context, coved floors are not required for labs classified in Biosafety level 2 because in these labs pathogens have only a moderate risk, therefore some precautions such as the coved floors are not required.

Learn more about labs in: https://brainly.com/question/14428286

Answers:

[tex]h = -\frac{b}{2a}\\\\k = \frac{-b^2+4ac}{4a}\\\\[/tex]

where 'a' cannot be zero.

=========================================================

Explanation:

The vertex is (h,k)

The x coordinate of the vertex is h which is found through this formula

[tex]x = -\frac{b}{2a}[/tex]

For example, if we had the quadratic [tex]y = 3x^2-6x+5[/tex], then we'll plug in a = 3 and b = -6 to get: [tex]h = -\frac{b}{2a} = -\frac{-6}{2*3} = 1[/tex]

------------

To find the value of k, we plug that h value into the original standard form of the quadratic and simplify.

[tex]y = ax^2+bx+c\\\\k = ah^2+bh+c\\\\k = a\left(\frac{-b}{2a}\right)^2+b\left(\frac{-b}{2a}\right)+c\\\\k = a*\frac{b^2}{4a^2}+\frac{-b^2}{2a}+c\\\\k = \frac{b^2}{4a}+\frac{-b^2}{2a}+c\\\\[/tex]

[tex]k = \frac{b^2}{4a}+\frac{-b^2}{2a}*\frac{2}{2}+c*\frac{4a}{4a}\\\\k = \frac{b^2}{4a}+\frac{-2b^2}{4a}+\frac{4ac}{4a}\\\\k = \frac{b^2-2b^2+4ac}{4a}\\\\k = \frac{-b^2+4ac}{4a}\\\\[/tex]

It's interesting how we end up with the numerator of [tex]-b^2+4ac[/tex] which is similar to [tex]b^2-4ac[/tex] found under the square root in the quadratic formula. There are other ways to express that formula above. We need [tex]a \ne 0[/tex] to avoid dividing by zero. The values of b and c are allowed to be zero.

Answer:

The minimum is at (1,-8). In the equation y = (x – 1)2 – 8, h = 1 and c = 8. So, the x-coordinate of the minimum is the same as the h-value in the equation, and the y-value of the minimum is the opposite of the c-value.

Step-by-step explanation:

plato

Answer:

  100.9 yards

Step-by-step explanation:

One circuit of the track is a distance of ...

  C = 2πr = 2π(60 yd) = 120π yd.

At Alex's running rate, the distance covered in 20 minutes is ...

  (4 yd/s)(20 min)(60 s/min) = 4800 yd

The number of circuits will be ...

  (4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits

The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,

That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd

The shortest distance along the track to Alex's starting point is about 100.9 yards.

_____

Additional comment

The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.