The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.​

The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

The age of Sita = (x + 5) years.

And, the age of Gautam = x years.

Now,

5 years ago, the ratio of their ages was 3 : 2

[tex] \therefore [/tex] [tex] \bf \frac{3}{2} \: = \frac{x \: + \: 5}{x} [/tex]

Now by cross multiplying, we get,

3x = 2(x + 5)

3x = 2x + 10

3x - 2x = 10

Hence, the age of Sita = (x + 5) = (10 + 5) = 15 years.

And, the age of Gautam = x = 10 years.

Now,

The present age of Sita = 15 + 5 = 20 years. (Answer)

And, the present age of Gautam = 10 + 5 = 15 years. (Answer)

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EXERCISE 6.4
Challenge
Use the given rules to complete the following tables.
1
2
3
4
12
Position in sequencen
Term in sequence y = 2n + 3
the position in the
Imagine that you
work for 30 days.
Which of the
following two salar
would you rather
earn? Explain your
choice.
2.
1
2
3
4
15
10
Position in sequencen
Term in sequence y = -2n - 4
3.
2
Position in sequencen
3
18
4
10
Term in sequence y = -5n - 4
1
2
3
4
11
Position in sequencen
Term in sequence y = -2n - 14
10c on the first
20c on the seca
day; 40c on the
third day; 800
the fourth day
so on, for 30 C
R100 on the f
day; R101 on
second day;
on the third
and so on, fa
days.
.
10
5.
1
2
3
4
10
Position in sequencen
Term in sequence y = n+1
6.
2
1
20
3
4
Position in sequences
Term in sequence y = 2r2

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