The 1985 Mexico City earthquake measured a magnitude 8.0 on the Richter scale. The Richter scale uses the function M (I) = log (StartFraction I Over I Subscript 0 Baseline EndFraction). Which equation relates the intensity of the 1985 earthquake, I, with the intensity of the threshold quake, Io?

A.) I = 810(Io)

B.) Io = 810(I)

C.) I = 108(Io)

D.) Io = 108(I)

Answers

Answer 1

Answer:

The correct option is C: I = 10⁸I₀.   

Step-by-step explanation:

The function of the Richter scale is:

[tex] M_{(I)} = log(\frac{I}{I_{0}}) [/tex]

Since the magnitude of the earthquake is 8.0, the relation between the intensity, I, with the intensity of the threshold quake, Io, is:

[tex] 8.0 = log(\frac{I}{I_{0}}) [/tex]

[tex] 10^{8} = \frac{I}{I_{0}} [/tex]

[tex] I = 10^{8}I_{0} [/tex]

Therefore, the correct option is C: I = 10⁸I₀.                

I hope it helps you!                    

Answer 2

The equation relates with the intensity of the 1985 earthquake, I, with the intensity of the threshold quake, [tex]I_0[/tex] is [tex]I = 10^8I_0[/tex].

Given that,

The 1985 Mexico City earthquake measured a magnitude of 8.0 on the Richter scale.

The Richter scale uses the function M (I) = log (Start Fraction I Over I Subscript 0 Baseline End Fraction).

We have to determine,

Which equation relates the intensity of the 1985 earthquake, I, with the intensity of the threshold quake, Io.

According to the question,

The function of the Richter scale is:

[tex]M_(_I_) =log[ \dfrac{I}{I_0}][/tex]

The magnitude of the earthquake is 8.0, the relation between the intensity, I, with the intensity of the threshold quake, [tex]I_0[/tex] is:

[tex]M_(_I_) =log[ \dfrac{I}{I_0}]\\\\8 =log[ \dfrac{I}{I_0}][/tex]

Taking log base 10 both sides,

[tex]10^8 = \dfrac{I}{I_0}\\\\I = 10^8I_0[/tex]

Hence, The equation relates with the intensity of the 1985 earthquake, I, with the intensity of the threshold quake, [tex]I_0[/tex] is [tex]I = 10^8I_0[/tex].

To know more about the Exponential function click the link given below.

https://brainly.com/question/15673235


Related Questions

Write z = 5 + 2i as an ordered pair in an Argand diagram.

Answers

Answer:no hablo espanol

Step-by-step explanation:

Select the correct answer.
Which expression is equivalent to 13 square root 22b - 10 square root 22b, if b>0?

A. 23 square root 22b
B. 130 square root 22b
C. 3 square root b^2
D. 3 square root 22b

Answers

Given:

The expression is

[tex]13\sqrt {22b}-10\sqrt{22b}, b>0[/tex]

To find:

The equivalent expression.

Solution:

We have,

[tex]13\sqrt {22b}-10\sqrt{22b}[/tex]

Taking out common factors.

[tex]=(13-10)\sqrt {22b}[/tex]

[tex]=(3)\sqrt {22b}[/tex]

[tex]=3\sqrt {22b}[/tex]

The expression [tex]3\sqrt {22b}[/tex] is equivalent to the given expression.

Therefore, the correct option is D.

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Answer:

7)x=11

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Step-by-step explanation:

Answer:

7= 11. 8=16. 9=12. 10=13 11=8. 12=3

Step-by-step explanation:

7= 9+2=11

8=12+4=16

9=9+3=12

10=8+5=14

11=7+1=8

12=3+0=3

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a shop is having a sale all items are reduced by 30% work out the sale price of an item normally priced at £110

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

AB = 8 and AD = 5

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Step-by-step explanation:

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Answers

Answer:

33

Step-by-step explanation:

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Answer:

Solution: y=2

The ratio x: y is 1:3
Which of the following statements are correct?
A x is 1/3 of y
B y is 3/4 of (x + y)
x is 1/4 of y
y is 3/4 of x

Answers

Answer:

Option A

Step-by-step explanation:

x : y = 1 : 3

This can be also written as

[tex] \frac{x}{y} = \frac{1}{3} [/tex]

Multiplying y on both the sides

[tex] = > \frac{x}{y} \times y = \frac{1}{3} \times y[/tex]

[tex] = > x = \frac{1}{3} \times y[/tex]

Hence , x is one-third of y

Answer:

A and B

x is [tex]\frac{1}{3}[/tex] of y

AND

y is [tex]\frac{3}{4}[/tex] of (x+y)

Step-by-step explanation:

x:y is 1:3

=>  y is bigger than x

=>  y is 3x bigger than x

=>  y = 3 lots of x

=>  [tex]y =[/tex] [tex]3x[/tex]

=>  [tex]\frac{y}{3}[/tex] [tex]= x[/tex]

=>  [tex]\frac{1}{3} y[/tex] [tex]= x[/tex]

So x is [tex]\frac{1}{3}[/tex] of y

y is [tex]\frac{3}{4}[/tex] of (x+y)

If x = 1 and y = 3 (substitute in values)

=>  3 is [tex]\frac{3}{4}[/tex] of (4)

=>  3 is [tex]\frac{3}{4}[/tex](4)

=>  3 is ([tex]\frac{3}{4}[/tex]x4)

=>  3 = 3

Therefore, y is [tex]\frac{3}{4}[/tex] of (x+y) is true

So the answers are:

x is [tex]\frac{1}{3}[/tex] of y

AND

y is [tex]\frac{3}{4}[/tex] of (x+y)

Bring 8/(a-x) to a denominator of x-a

Answers

Answer:

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Step-by-step explanation:

[tex]\frac{8}{a-x}[/tex]

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and now multiply and divide by -1

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Will Mark Brainliest

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

A recipe code lasagna calls for 3 pounds of tomatoes to serve 5 people. A caterer wants to make enough lasagna to serve 110 people. How many pounds of tomatoes does he neeed

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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9514 1404 393

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Step-by-step explanation:

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__

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Answer:

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Step-by-step explanation:

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Answer:

10/100*40

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