[tex]\left[\begin{array}{ccc}3&4\\8&-5\end{array}\right] \left[\begin{array}{ccc}4&6\\3&0\end{array}\right][/tex] evaluate

Answer:

0.034522 (for decimal)

Step-by-step explanation:

Answer:

independent

Step-by-step explanation:

Answer:

Disjointed

disjointed events: events that have no outcomes in common

so that's why it is disjointed

Answer:

712

Step-by-step explanation:

400+6.5%of 4800

312+400=712

Answer:

V=786,240cm³

Step-by-step explanation:

Volume=Length × base × height

v= 52cm×42cm×360cm

Answer:

61

Step-by-step explanation:

Answer:

think that this might help you

Answer:

1° and 89°

Step-by-step explanation:

They add up to 90°

Hope this helps! :)

Answer:

1200cm

Step-by-step explanation:

Given data

We know that 1meter is equivalent to 100cm

i,.e 1*100

so, if height is 1.2meters

Height in centimeters is 1.2*100

Hence height in centimeters is 1200cm

Answer:

[tex]y=2\sqrt{10}[/tex]

Step-by-step explanation:

By applying geometric mean theorem in the given right angle,

[tex]\frac{AD}{DB}=\frac{DB}{CD}[/tex]

By substituting values in the given ratio,

[tex]\frac{5}{y}= \frac{y}{8}[/tex]

[tex]y^2=8\times 5[/tex]

[tex]y^2=40[/tex]

[tex]y=2\sqrt{10}[/tex]

Exact value of y is [tex]2\sqrt{10}[/tex].

Answer:

No

Step-by-step explanation:

22 - 6x = 15

subtract 22 from both sides

-6x = -7

divide both sides by -6

x = 7/6 or 1 1/6

Answer:

The answer is below

Step-by-step explanation:

A drink is made by adding water to juice.

Instructions

Add an amount of water that is between 3 times and 5 times the amount of juice

Tanya has 130 ml of juice.

If she follows the instructions, work out the minimum and maximum amounts

of the drink she can make.

Solution:

The minimum amount of water that can be added to the juice is 3 times the amount of the juice, hence:

Minimum amount of water = 3 * 130 ml of juice = 390 ml of water

Therefore minimum amount of drink = 390 ml of water + 130 ml of juice

minimum amount of drink = 520 ml

The maximum amount of water that can be added to the juice is 5 times the amount of the juice, hence:

Maximum amount of water = 5 * 130 ml of juice = 650 ml of water

Therefore maximum amount of drink = 650 ml of water + 130 ml of juice

Maximum amount of drink = 780 ml

Answer:

subtract 5 , m=(-15)

Step-by-step explanation:

15-5

=10

n:

5-10

=(-5)

m:

(-5)-10

=(-15)

hope it help

Answer:

S(t) = 1000(0.729)^t

Step-by-step explanation:

S(t) = 1000(0.9)^(3t)

S(t) = 1000((.09)^(3))^t

S(t) = 1000(0.729)^t

Answer:

x = 19

Step-by-step explanation:

5x - 26 = x + 50

Subtract x on both sides of the equation.

4x - 26 = 50

Add 26 on both sides.

4x = 76

Now, divide by 4 on both sides.

x = 19

Answer:

x = 19

Step-by-step explanation:

5x-26=x+50

5x = 76 +x

4x = 76

x = 19

Answer:

1.009, 1.09, 1.7, 1.7082

Step-by-step explanation:

hope this helped.

Answer:

1 2/9 minutes faster

Step-by-step explanation:

Take the larger number and subtract the smaller number

8 5/9 minutes - 7 1/3 minutes

Get a common denominator

8 5/9 - 7 1/3 *3/3

8 5/9 - 7 3/9

1 2/9 minutes faster

Answer:

radius is 6 diameter is 2 don't know the other one tho

Answer:

y = 3

Step-by-step explanation:

3x - 4y = 12

3(8) - 4y = 12

24 - 4y = 12

- 4y + 24 = 12

- 4y + 24 - 24 = 12 - 24

- 4y = - 12

- 4y ÷ - 4 = - 12 ÷ - 4

y = 3

Slope: [tex]\frac{3}{4}[/tex]

y - intercept: (0, - 3)

Answer:

Options B, D, E

Step-by-step explanation:

If triangle ABC and triangle PQR are congruent,

∠A ≅ ∠P

∠B ≅ ∠Q

∠C ≅ ∠R

AB ≅ PQ

BC ≅ QR

AC ≅ PR

Therefore, Options B, D, E are the correct options.

Answer:

7 inches

Step-by-step explanation:

area of square=l^2

49=l^2

[tex]\sqrt{49[/tex]=l

7=l

therefore the sides of a triangle is 7 inches.

Answer:

7

Step-by-step explanation:

So to find this you know a square has 4 equal sides. The area is 49, and area is side length multiplied by side length. So what number multiplied by itself is 49? 7 x 7=49!

Answer:

Es ydjwj rjsbt djeiweke

Answer:

[tex]B = \{8, 16, 24, 32, 40, ...... \}[/tex]

Step-by-step explanation:

Given

[tex]x \to[/tex] element of natural number

[tex]x \to[/tex] multiple of 8

Required

Express in roster form

[tex]Natural[/tex] [tex]numbers[/tex] are 1, 2, 3, 4, 5, 6, ......

[tex]Natural[/tex] [tex]numbers[/tex]  that are multiples of 8 are 8, 16, 24, 32, 40, ......

So, the set in roster form is:

[tex]B = \{8, 16, 24, 32, 40, ...... \}[/tex]

Answer:

log 18= 2.0850

1.2925+0.7925= 2.085

Answers:

[tex]\csc(\theta) = \frac{7\sqrt{33}}{33}\\\\\sin(\theta) = \frac{\sqrt{33}}{7}\\\\\cot(\theta) = \frac{4\sqrt{33}}{33}\\\\[/tex]

=============================================

Explanation:

Before we can find the trig ratios, we need to determine the length of the missing side. Apply the pythagorean theorem

[tex]a^2+b^2 = c^2\\\\4^2+b^2 = 7^2\\\\16+b^2 = 49\\\\b^2 = 49-16\\\\b^2 = 33\\\\b = \sqrt{33}[/tex]

The vertical side is [tex]\sqrt{33}[/tex] units long.

------------------------------------

The side we just found is the opposite side to angle [tex]\theta[/tex] (greek letter theta)

The hypotenuse is 7 units long. The hypotenuse is always opposite the right angle.

Divide the hypotenuse over opposite to get the cosecant.

[tex]\csc(\theta) = \frac{\text{hypotenuse}}{\text{opposite}}\\\\\csc(\theta) = \frac{7}{\sqrt{33}}\\\\\csc(\theta) = \frac{7\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\csc(\theta) = \frac{7\sqrt{33}}{\sqrt{33*33}}\\\\\csc(\theta) = \frac{7\sqrt{33}}{\sqrt{33^2}}\\\\\csc(\theta) = \frac{7\sqrt{33}}{33}\\\\[/tex]

Note: In the third step, I multiplied top and bottom by sqrt(33) to rationalize the denominator.

------------------------------------

Recall that sine is the reciprocal of cosecant, and vice versa.

So we'll use the same idea as before, but flip the original fraction.

[tex]\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(\theta) = \frac{\sqrt{33}}{7}\\\\[/tex]

The denominator is already a rational number, so there's not much else to do here.

--------------------------------------

Cotangent is the ratio of adjacent over opposite

[tex]\cot(\theta) = \frac{\text{adjacent}}{\text{opposite}}\\\\\cot(\theta) = \frac{4}{\sqrt{33}}\\\\\cot(\theta) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\cot(\theta) = \frac{4\sqrt{33}}{\sqrt{33*33}}\\\\\cot(\theta) = \frac{4\sqrt{33}}{\sqrt{33^2}}\\\\\cot(\theta) = \frac{4\sqrt{33}}{33}\\\\[/tex]

The steps are pretty much nearly identical as the section involving csc, except we're using the adjacent in place of the hypotenuse (so that means we use 4 in place of 7).

Answer:

500

Step-by-step explanation:

that is the procedure above

Answer:

C.

Step-by-step explanation:

First you solve the bracket...

(22+50)= 72

72×2=144

Answer:

the answer is D because it has to greatest factor

A (5(8+20)=40+100

B (4(40+96)=160+384

C (2(22+50)=44+100

D (4(11+25)=44+100

Answer:

x = 24

x = 20

Step-by-step explanation:

x/3 - 2 = 6

Add 2 to both sides

x/3 = 8

multiply both sides by 3

x = 24

-----------------------------

x/5 +1 = 5

Subtract 1 from both sides

x/5 = 4

multiply both sides by 5

x = 20

Answer:

1. add two both sides and then multiply by 3 each side to get to the answer of 24.

Check: 24/3 = 8 - 2 = 6

2. x/5 + 1 = 5

subtract 1 from each side and then multiply by 4 on each side to get to the result of 20.

check: 20/5 is 4 + 1 = 5

Brainlist please :)

Answer:

2/25

Step-by-step explanation:

[tex]n^3 = \frac{8}{125}[/tex]

[tex]n^3 = (\frac{2}{5})^3[/tex]

[tex]n = \sqrt[3]{n^3} = \sqrt[3]{(\frac{2}{25})^3}[/tex]

[tex]n = \sqrt[3]{(\frac{2}{25})^3}[/tex]

[tex]n = \frac{2}{25}[/tex]