TE Irene has a collection of 32 dolls that have either blue eyes or green eyes. She has 14 more green-eyed dolls than blue-eyed dolls. How many dolls of each type does Irene have? Let x represent the number of green-eyed dolls. Let y represent the number of blue-eyed dolls.​

Answers

Answer 1

The formula

x + y = 32

Find our X value

y + 14 = x

Sub for x

(y + 14) + y = 32

Remove Parathesis

y + 14 + y = 32

Add

2y + 14 = 32

Subtract

2y = 18

Divide

y = 9

Sub for y

x + 9 = 32

Subtract

x = 23

Double Check:

9 + 14 = 23

23 + 9 = 32

I hope this helps! :)


Related Questions

What is the solution to the equation −6z+1=−4−7z , given the replacement set {−5, −3, −1} ?

−5

−3

−1

I don't know.

Answers

the solution to the system of equation from the replacement set is -5

Given the equation −6z+1=−4−7z, we are to find the value of z from the given equation:

Given

−6z+1=−4−7z

Collect the like terms;

-6z + 7z = -4 - 1

Simplify the result

z = -4 -1

z= -5

Hence the solution to the system of the equation from the replacement set is -5

Learn more on equation here: https://brainly.com/question/2972832

Answer:

-5

Step-by-step explanation:

I took the quiz in k12

Some one help me? ill give 50 points

Answers

Answer:

v=[tex]\frac{(w+v)/t}{2}[/tex]

Step-by-step explanation:

just inverse operations and you will always get your answer :)

A line has a slope of and passes through the point (4, 7). What is its equation in
slope-intercept form?

Answers

Answer:

y = (7/4)x + 0

Step-by-step explanation:

yeah-ya....... right?

The function v(t) is the velocity in m/sec of a particle moving along the x-axis. Use analytic methods to do each of the following: (a) Determine when the particle is moving to the right, to the left, and stopped. (b) Find the particle's displacement for the given time interval. If s(0) = 3, what is the particle's final position? (c) Find the total distance traveled by the particle. v(t) = 5 (sint)^2(cost); 0 ≤ t ≤ 2π

Answers

Answer:

(a) The particle is moving to the right in the interval  [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].

(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].

(c)  The total distance traveled by the particle is 9.67 (2 d.p.)

Step-by-step explanation:

(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).

Situation 1: When the particle stops.

[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].

Situation 2: When the particle moves to the right.

[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]

Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .  

*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.

Situation 3: When the particle moves to the left.

[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]

Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or  [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].

(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.

[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]

To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where

[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].

[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]

Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].

The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].

(c)

[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]

[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]

[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].

The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].

Which of the following is a rational number?

Answers

the correct answer is B

How do I simplify the ratio of

42 : 28 : 21

Answers

Answer:

6:4:3

Step-by-step explanation:

each can be divided by 7

Answer:

6 4 3

Step-by-step explanation:

#13) Mrs. Frye says that the following triangles are congruent. Is she correct? Why or why not? ​

Answers

Answer: The following triangles are congruent.

Helpppppppp me …………………..

Answers

Answer:

first let's solve for x

x + (x + 30) + 2x = 180

4x + 30 = 180

-30          -30

4x = 150

/4      /4

x = 37.5

Now solve for the angle measures:

(x + 30)    =    (37.5 + 30) = 67.5

2x       =        2(37.5) = 75

x = 37.5

Answer:

X= 37.5

Step-by-step explanation:

find the derivitive of f(x)=(x+9)/(x+1)

Answers

[tex]\dfrac{d}{dx} \left(\dfrac{x+9}{x+1}\right)\\\\\\=\dfrac{(x+1)\dfrac{d}{dx}(x+9) - (x+9) \dfrac{d}{dx}(x+1)}{(x+1)^2}\\\\\\=\dfrac{(x+1) - (x+9)}{(x+1)^2}\\\\\\=\dfrac{x+1-x-9}{(x+1)^2}\\\\\\=-\dfrac{8}{(x+1)^2}[/tex]

You buy candy bars at 85 cents each plus one newspaper for 60 cents. You can spend no more than $4. How many candy bars can you buy? answer

Answers

Answer:

4

Step-by-step explanation:

Well first you want to take 0.60 from the total amount which is $4 leaving you with $3.40

then you want to divide the remaining amount of money by the cost of a candy bar ($0.85)

So you do 3.40/0.85 which is equal to 4

14. What's the least common denominator of 3/4, 4/5, and 2/3?
A. 60
B. 20
C. 15
D. 12

Answers

im pretty sure it's 60

A bakery sold a total of 500 cupcakes in a day, and 190 of them were vanilla flavored. What percentage of cupcakes sold that day were vanilla flavored?

Answers

Answer: 50/19

Step-by-step explanation:

I'm no math genius however I believe this is division.

500/190 gave me a fraction which is 50/19.

The awnser above me is not a percentage . The percentage of 19/50 would be 38%

How do you add fractions with a whole number? Please explain the rules of it too! To be marked as brainliest

Answers

Hello this is how you do it!<3

9/4 = 21/4 therefore, 9/4 = 21/4

24/10 try to reduce the numerator and denominator by a common denominator 24/10 divided 2/2 = 12/5

16/2 divided 2/2 = 8/1 = 8

I hoped that help!<3

Please help with this question !!

Answers

Answer:

c) i^337 is equivalent to the expression i^137

Match each shape with its area formula. ​

Answers

square: A=s^2

triangle: A=(1/2)bh

rectangle: A=lw

parallelogram: A=bh

Which of the following is the graph of y=x+3

Answers

Answer:ITS THE SECOND ONE

Step-by-step explanation:

A group of pigs and ducks has a total of 40 feet. There are twice as many ducks as pigs. How many of each animal are there?

Answers

The question relates to the total number of pairs of feet ducks and a pigs

are known to have.

There are 5 pigs and 10 ducks

Reasons:

The length of the group of ducks and pigs = 40 feet

Number of ducks = Twice the number of pigs

Each duck has 2 feet.Each pig has 4 feet.

Let x represent the number of pigs, and let y represent the number of ducks, we have;

y = 2 × x

4·x + 2·y = 40

Which gives;

4·x + 2 × (2·x) = 40

8·x = 40

x = 40 ÷ 8 = 5

The number of pigs, x = 5

y = 2 × x

Therefore;

y = 2 × 5 = 10

The number of ducks, y = 10

Learn more about solving word problems in mathematics here:

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-2(x-6)=6 help me out

Answers

Answer:

x = 9

Step-by-step explanation:

i took the quiz

[tex]\mathfrak{-2(x-6)=6} [/tex]

[tex]\mathfrak{-2x+12=6} [/tex]

[tex]\mathfrak{-2x=6-12} [/tex]

[tex]\mathfrak{-2x=-6} [/tex]

[tex]\boxed{\mathfrak{x=3} }[/tex]

sin(83)cos(7) + cos(83)sin(7)

Answers

Answer:

1

Step-by-step explanation:

correct on edge

sin(83 radians) * cos(7 radians)) + (cos(83 radians) * sin(7 radians)) =

0.893996664

Answer:

hope it helps

x-5y=16 , 4x-2y=-8 solve using elimination method

Answers

Answer:

x = -4

y = -4

Step-by-step explanation:

L1     x - 5y = 16

L2  4x - 2y = -8

4*L1 - L2

4x - 20y = 64

-4x + 2y  =    8

-----------------------

      -18y = 72

          y = 72 / -18

          y = -4

x - 5y = 16

x = 16 + 5y

x = 16 + 5(-4)

x = 16 - 20

x = -4

Veronica made 960 cookies to sell. She wants to package the cookies in boxes of 16. Her goal is to make $630 from selling her cookies.

Answers

Answer: She should charge $10.50 for each box

Step-by-step explanation:

Total cookies = 960

Each box has 16 cookies

Her goal is $630

First, you want to find out how many boxes she made

960÷ 16 = 60

She made 60 boxes

Now you want to find the price for each box

630 ÷ 60 = 10.5

She should charge $10.50 for each box

I hope this helps!!!

Ron wants to make money painting portraits of people at the local mall. The mall
charges Ron $22.00 a day for Ron to set up his materials to sell his portraits. He
charges $15.50 a portrait, but it costs him $3.25 in materials to make that portrait.
If x represents the number of portraits that Ron sells at the mall, which of the
following expressions would represent Ron's profit (how much money Ron will walk
away with at the end of the day)? (There is more than one answer)
12. 25x – 22.00
15.50x – 22.00
0-22.00 + 15.50x – 3.25x
15.50x
3. 25x – 22.00
22.00x – 3.25x
15.50

Answers

Answer:

A and C

Step-by-step explanation:

With the amount x of portraits the daily balance is:

- $22.00+ $15.50x- $3.25x

The total is:

15.50x - 3.25x - 22.00 ⇒ 12.25x - 22.00

Correct choices are A and C

With the amount x of portraits the daily balance is:

- $22.00

+ $15.50x

- $3.25x

The total is:

15.50x - 3.25x - 22.00 ⇒ 12.25x - 22.00

Correct choices are A and C

A self-storage center has many storage rooms that are 6 feet wide, 10 feet deep, and 12 feet high. What is the volume of the room?

Answers

Answer:

720 ft^3

Step-by-step explanation:

6 * 10 *12

v = l * w * h

6 * 10 * 12 =  720

Volume is a three-dimensional scalar quantity. The volume of the self-storage centre room is 720 ft³.

What is volume?

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume of a room or box that is the shape of a rectangular prism is calculated by multiplying the length, width, and height of the prism.

Volume = Length × Width × Height

Given that the self-storage centre room's are 6 feet wide, 10 feet deep, and 12 feet high. Therefore, the dimension of the room can be written as,

Length = 10 ft

Width = 6 ft

Height = 12 ft

Now, the volume of the room can be written as,

Volume of the room = 10ft × 6ft × 12ft

                                  = 720 ft³

Hence, the volume of the self-storage centre room is 720 ft³.

Learn more about Volume:

https://brainly.com/question/13338592

#SPJ5

Which of the following is equal to 2,952 ÷ 24?
A.
(2,400 ÷ 24) + (480 ÷ 24) + (72 ÷ 24)
B.
(2,400 + 24) ÷ (480 + 24) ÷ (72 + 24)
C.
(2,400 + 24) + (480 + 24) + (72 + 24)
D.
(2,400 ÷ 24) - (480 ÷ 24) - (72 ÷ 24)

Answers

Answer:

A

Step-by-step explanation:

After doing long division we then know that 2,952 ÷24 = 123

We 1st follow pemdas knowing this we solve the equations in parenthesis 1st

(2,400 ÷ 24) + (480 ÷ 24) + (72 ÷ 24)

2,400 ÷ 24 = 100

480 ÷ 24 = 20

72 ÷ 24 = 3

We can then rewrite the equation as

100 + 20 + 3   We then solve left to right

100 + 20 = 120

120 + 3 = 123

Henry used his GPS to measure the distances from his house to two locations to the thousandth mile. Then, he rounded both values to the nearest hundredth. Which pair of distances could be the actual distances Henry measured?

school: 3.26 miles
piano lessons: 5.84 miles

Answers

Henri Henri use his GPS to measure the distance from his house to two locations to the thousands of miles then he rounded both values to the nearest hundred which pair of distances could be the nearest actual distances please mark me as brainless I’m really helpful and I did this the answer is 4.32

Help help help help math math

Answers

Answer:

<4 = 67 degrees

Step-by-step explanation:

Find <3

30+37+x=180

subtract 37 and 30

x = 180 - 30 - 37

x = 150 - 37

x= 113

Find <4

180 - 113

67

67 degrees im not completely sure tho but this is probably the answer

a prisms base has a perimeter of 12cm and a height of 2 cm. the area of the base was 5cm. what is the surface area of the prism.

Answers

[tex]\text{Surface Area of Prism} = (2 \times \text{Base Area}) + (\text{Base perimeter} \times \text{height})\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(2 \times 5)+(12\times 2)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=10+24\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=34~~ \text{cm}^2[/tex]

How to do this problem

Answers

Answer: a. y=3      slope = 0

b. x=-4 slope does not exist

Step-by-step explanation:

Can someone help me please?

Answers

Answer:

put your equation into fractions and then see what or which 1mathces with the image

Step-by-step explanation:

Given 2 angles that measure 50 and 80 and a side that measure 4 feet how many triangles if any can be condctuted

Answers

Answer:

The number of unique triangles that can be constructed from the given values is; Only one triangle

Step-by-step explanation:

We are given the 2 angles of a triangle as;  

∠1 = 50°  

∠2 = 80°  

Now, we know that sum of angles in a triangle is 180°. This means that if the third angle is denoted as ∠3, then we have;  

∠1 + ∠2 + ∠3 = 180°  

Thus;  

∠3 = 180 - (∠1 + ∠2)  

∠3 = 180 - (50 + 80)  

∠3 = 180 - 130  

∠3 = 50°  

Thus; ∠1 = ∠3 = 50°  

A triangle with two equal angles is called an isosceles triangle. Which means that it will also have 2 of its' sides to be equal.  

Thus, in conclusion, only one unique triangle can be drawn.

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