Suppose there are two scale drawings of the same house. One uses the scale of 1 cm to 2 m, and the other uses the scale 1 cm to 4 m. Which drawing is larger?

Answer:

y-3 = 2/9 (x-8)

Step-by-step explanation:

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Since 3 feet is a yard, one foot is 1/3.

So that is the answer.

Answer:

1/3

1 mile to yards as a fraction would probably be 1/3. I'm not so sure...

Answer:

The answer is:  

[tex]\frac{6r-5q}{r^2-q^2}[/tex]

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

[tex]r^2-q^2=(r+q)\,(r-q)[/tex]

the second denominator consists of only one of these factors: [tex](r+q)[/tex], then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: [tex](r-q)[/tex]

Then we get two expressions that can be easily added as shown below:

[tex]\frac{r}{(r+q)\,(r-q)} +\frac{5\,(r-q)}{(r+q)\,(r-q)} =\frac{r+5(r-q)}{(r+q)(r-q)} =\frac{r+5r-5q}{(r+q)\,(r-q)} =\frac{6r-5q}{r^2-q^2}[/tex]

Answer:

A)

[tex]f'(x) = \left\{ \begin{array}{lIl} \frac{1}{2} & \quad x >2 \\ 0& \quad x =2\\1&\quad x<2 \end{array} \right.[/tex]

B) Continuous but not differentiable.

Step-by-step explanation:

So we have the piecewise function:

[tex]f(x) = \left\{ \begin{array}{lIl} \frac{1}{2}x+5 & \quad x >2 \\ 6& \quad x =2\\x +4&\quad x<2 \end{array} \right.[/tex]

A)

To write the differentiated piecewise function, let's differentiate each equation separately. Thus:

1)

[tex]\frac{d}{dx}[\frac{1}{2}x+5}][/tex]

Expand:

[tex]\frac{d}{dx}[\frac{1}{2}x]+\frac{d}{dx}[5][/tex]

The derivative of a linear equation is just the slope. The derivative of a constant is 0. Thus:

[tex]\frac{d}{dx}[\frac{1}{2}x+5}]=\frac{1}{2}[/tex]

2)

[tex]\frac{d}{dx}[6][/tex]

Again, the derivative of a constant is 0. Thus:

[tex]\frac{d}{dx}[6]=0[/tex]

3)

We have:

[tex]\frac{d}{dx}[x+4][/tex]

Expand:

[tex]\frac{d}{dx}[x]+\frac{d}{dx}[4][/tex]

Simplify:

[tex]=1[/tex]

Now, let's substitute our original equations for the differentiated equations. The inequalities will stay the same. Therefore:

[tex]f'(x) = \left\{ \begin{array}{lIl} \frac{1}{2} & \quad x >2 \\ 0& \quad x =2\\1&\quad x<2 \end{array} \right.[/tex]

B)

For a function to be differentiable at a point, the function must be a) continuous at that point, and b) the left and right hand derivatives must be equivalent.

Let's first determine if the function is continuous at the point. Remember that a function is continuous at a point if and only if:

[tex]\lim_{x \to n^-} f(n)= \lim_{x \to n^+}f(n)=f(n)[/tex]

Let's find the left hand limit of f(x) at it approaches 2.

[tex]\lim_{x \to 2^-}f(x)[/tex]

Since it's coming from the left, let's use the third equation:

[tex]\lim_{x \to 2^-}f(x)\\=\lim_{x \to 2^-}(x+4)[/tex]

Direct substitution:

[tex]=(2+4)=6[/tex]

So:

[tex]\lim_{x \to 2^-}f(x)=6[/tex]

Now, let's find the right-hand limit:

[tex]\lim_{x \to 2^+}f(x)[/tex]

Since we're coming from the right, let's use the first equation:

[tex]\lim_{x \to 2^+}(\frac{1}{2}x+5)[/tex]

Direct substitution:

[tex](\frac{1}{2}(2)+5)[/tex]

Multiply and add:

[tex]=6[/tex]

So, both the left and right hand limits are equivalent. Now, find the limit at x=2.  

From the piecewise function, we can see that the value of f(2) is 6.

Therefore, the function is continuous at x=2.

Now, let's determine differentiability at x=2.

For a function to be differentiable at a point, both the right hand and left hand derivatives must be equivalent.

So, let's find the derivative of the function as x approahces 2 from the left and from the right.

From the differentiated piecewise function, we can see that as x approaches 2 from the left, the derivative is 1.

As x approaches 2 from the right, the derivative is 1/2.

Therefore, the right and left hand derivatives are not the same.

Thus, the function is continuous but not differentiable.

Answer:

[tex]\huge\boxed{x=1,\ y=2\to(1,\ 2)}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}3x+4y=11\\x-2y=-3&\text{multiply both sides by (-3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}3x+4y=11\\-3x+6y=9\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\ \ \ \ 10y=20\qquad\text{divide both sides by 10}\\.\qquad\qquad\boxed{y=2}\\\\\text{subtitute it to the second equation:}\\x-2(2)=-3\\x-4=-3\qquad\text{add 4 to both sides}\\\boxed{x=1}[/tex]

Answer:

w = 4

Step-by-step explanation:

13w-8w =20

Combine like terms

5w = 20

Divide each side by 5

5w/5 = 20/5

w = 4

Answer:

w=4

Step-by-step explanation:

13w-8w=20

5w=20

w=4

Answer:-0.5

Step-by-step explanation:

Answer:

-14

Step-by-step explanation:

[tex] \boxed{gradient = \frac{y1 - y2}{x1 - x2} } [/tex]

Using the above formula, slope

[tex] = \frac{8 - ( - 6)}{ - 4 - ( -3 )} \\ = \frac{8 + 6}{ - 4 + 3} \\ = \frac{14}{ - 1} \\ = - 14[/tex]

Answer:

√ 96

log

( 7 )

6 ! /3 !

Step-by-step explanation:

Bring all the X to the left side and all the numbers to the right side. ( remember to flip the signs )

3x - 4 - 5x = 6 + 4x + 2

3x - 5x - 4x = 6 + 2 + 4

-6x = 12

6x = -12

x = -2

Turn the percentage into a decimal.

8.25% / 100 = 0.0825

Multiply.

39.89 * 0.0825 ≈ $3.29

Subtract.

39.89 + 3.29 = $43.18

Best of Luck!

Answer:

Step-by-step explanation:

Please brailiest

Answer:

15 23

Step-by-step explanation:

Answer:

Step-by-step explanation:

11x - 6 + 15x - 8 = 90

26x - 14 = 90

26x = 104

x = 4

11(4) - 6 = 44 - 6 = 38

13y - 14 + 38= 180

13y + 24 = 180

13y = 156

y = 12

13(12) - 14 = 156 - 14=142

Answer:

see below

Step-by-step explanation:

sqrt(2)+ sqrt(98)

sqrt(2) + sqrt( 2*49)

sqrt(2) + 7sqrt(2)

8 sqrt(2)

Answer:

[tex]\sqrt{2}[/tex]+ [tex]\sqrt{98}[/tex]

 [tex]\sqrt{2}[/tex]+   [tex]\sqrt{2}[/tex] *49

[tex]\sqrt{2}[/tex] + 7[tex]\sqrt{2}[/tex]

8 [tex]\sqrt{2}[/tex]

Answer:

x = 95°

Step-by-step explanation:

The sum of the interior angles of any polygon is

sum = 180° (n - 2)

Here n = 5, thus

sum = 180° × 3 = 540°

Sum the given angles in the polygon and equate to 540

104° + 117° + 100° + 124° + x = 540°, that is

445° + x = 540° ( subtract 445° from both sides )

x = 95°

Answer:

5.58×10²⁴ atoms.

Step-by-step explanation:

From the question given above, the following data were obtained:

1 mole of silver = 107.9 g

Number of atoms in 1 mole of silver = 6.02×10²³ atoms.

Number of atoms in a kilogram of silver =.?

Next, we shall convert 1 kg of silver to grams (g). This can be obtained as follow:

1 kg = 1000g

Therefore, 1 kg of silver is equivalent to 1000g.

Finally, we shall determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:

107.9 g of silver contains 6.02×10²³ atoms.

Therefore, 1000 g of silver will contain = (1000 × 6.02×10²³) / 107.9 = 5.58×10²⁴ atoms.

Thus, a kilogram of silver contains 5.58×10²⁴ atoms.

Answer:

2Pm+Pn+2qm-qn-2rm+rn

Step-by-step explanation:

Answer:

3x =24

x = 24 -3

x = 21 (ans)

Answer:

X=8

Step-by-step explanation:

3x=24

divide each side by 3 to isolate x

x=8

Answer:

0.009804

Step-by-step explanation:

We are given;

probability of testing positive given that you have the disease is 0.99

Also, probability of not testing positive and not having the disease is 0.99

We are also told that it is a rare disease and so strikes only 1 in 1000 people = 0.0001

Let's denote positive test by T+, negative test by T¯, having the disease by D+, not having the disease by D¯.

So, we can now denote all the values in probability we have written earlier.

Thus:

P(T+ | D+) = 0.99

P(T¯ | D¯) = 0.99

P(D+) = 0.0001

Thus, P(D¯) = 1 - P(D+) = 1 - 0.0001 = 0.9999

Now, let's find probability of testing positive;

P(T+) = (P(T+ | D+) × P(D+)) + (P(T+ | D¯) × P(D¯))

Now, (P(T+ | D¯) is not given but by inspection, we can infer from the values given that it is 0.01

Thus;

P(T+) = (0.99 × 0.0001) + (0.01 × 0.9999)

P(T+) = 0.010098

Chances that one has the disease would be gotten from Baye's theorem;

P(D+ | T+) = (P(T+ | D+) × P(D+))/P(T+) = (0.99 × 0.0001)/0.010098 = 0.009804

This question is about how transformations can affect graphs.

First, we'll want to get rid of that -4 on the function of F.

So we can reflect the function over the y-axis and then compress it by a factor of 4 to make the graph [tex]x^2[/tex].

Then we can move the graph over to the left 3 because the c value is positive, meaning that we move the graph over to the left.

Finally, we can move the function of by [tex]\frac{2}{3}[/tex] because the d value is positive, meaning that we move the graph up.

Hope this helps.

頑張って!

Greetings from Brasil....

The intersection of two sets is given by the elements that are common - present in both - to the sets.

A = {2; 5}

B = {5; 7; 9}

Element in both sets = 5.... So

Answer:

1 metric ton is = to 1000 kilograms

Answer:

I think it's 352. 02 g/mol

Step-by-step explanation:

googled it :)

Answer:

352.02 g/mol

In chemistry, the molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample, measured in moles.

Answer:

value of x is 6.

please follow me.

Your answer would be B- 6. Hope this helps you!!

La pendiente de una recta es la tangente del ángulo que forma la recta con la dirección positiva del eje de abscisas. En funciones no lineales, la razón de cambio varía a lo largo de la curva. La derivada de la función en un punto dado es la pendiente de la línea tangente en dicho punto.

F:V  7w7

Answer:

A. 15,10,20,18 -- 15,10,18,20 -- 10,15,18,20

Step-by-step explanation:

Bubble sorting can be defined as a technique or methodology whereby numbers that are not in their proper order are sorted into proper order that is from smallest to highest( increasing to decreasing order).

The method of bubble sorting involves the shuffling or swapping of adjacent numbers until the numbers are well sorted or arranged.

In the above question, we were given, a set of numbers:

15, 20, 10, 18

Step 1

20 is adjacent to 10

20 > 10

hence we swap

= 15,10,20,18

Step 2

From, 15,10, 20,18

20 is adjacent to 18

20 > 18

hence we swap

= 15,10,18,20

Step 3

From step 2, which gave us 15,10,18,20

15 us adjacent to 10

15 > 10

We swap

= 10,15,18,20

Hence,

15, 20, 10, 18 -- 15,10,20,18 -- 15,10,18,20 -- 10,15,18,20

Therefore, Option A is the correct option.

The correct intermediate steps of data 15, 20, 10, 18 set when it is being sorted with the bubble sort is; Choice A: 15,10,20,18 -- 15,10,18,20 -- 10,15,18,20.

Definition;

Bubble sort, otherwise termed the sinking sort, is a simple sorting algorithm that repeatedly steps through the list, compares adjacent elements and swaps them if they are in the wrong order.

With emphasis on the word adjacent, it is evident Choice A is the correct intermediate steps of the data set 15, 20, 10, 18 when it is being sorted with the bubble sort.

Read more:

https://brainly.com/question/15148294

Answer:

n=-1

Step-by-step explanation:

3n-5=-8(6+5n)

3n-5=-48-40n

add 40n to both sides

43n-5=-48

n=-1

Step-by-step explanation:

Answer:

2(6x+78)

Unless it's the exact number. You hadn't specified what x is.

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x.  When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

F(x) = ∫₆ˣ t⁷ dt

F(6) = ∫₆⁶ t⁷ dt

F(6) = 0

Answer:

y' = -4eˣ sin⁵(eˣ)

Step-by-step explanation:

Part 1 of the Fundamental Theorem of Calculus simply says that the definite integral of a function is equal to the antiderivative evaluated between the limits.

∫ₐᵇ f(x) dx = F(b) − F(a), where F(x) = ∫ f(x) dx.

y = ∫ₑₓ⁰ 4 sin⁵(t) dt

To integrate, use Pythagorean identity.

y = 4 ∫ₑₓ⁰ (1 − cos²(t))² sin(t) dt

Ignoring the limits for the moment, let's say u = cos(t) and du = -sin(t) dt.

y = 4 ∫ (1 − u²)² (-du)

y = -4 ∫ (1 − 2u² + u⁴) du

y = -4 (u − ⅔u³ + ⅕u⁵) + C

y = -4 (cos(t) − ⅔ cos³(t) + ⅕ cos⁵(t)) + C

Evaluate between t = eˣ and t = 0.

y = -4 (cos(0) − ⅔ cos³(0) + ⅕ cos⁵(0)) + C − [-4 (cos(eˣ) − ⅔ cos³(eˣ) + ⅕ cos⁵(eˣ)) + C]

y = -4 (1 − ⅔ + ⅕) + 4 (cos(eˣ) − ⅔ cos³(eˣ) + ⅕ cos⁵(eˣ))

Now take derivative with respect to x.

y' = 0 + 4 (-sin(eˣ) eˣ − 2 cos²(eˣ) (-sin(eˣ) eˣ) + cos⁴(eˣ) (-sin(eˣ) eˣ))

y' = -4eˣ sin(eˣ) (1 − 2 cos²(eˣ) + cos⁴(eˣ))

y' = -4eˣ sin(eˣ) (1 − cos²(eˣ))²

y' = -4eˣ sin⁵(eˣ)

This can be more easily calculated using the Second Fundamental Theorem of Calculus.