sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?

Answers

Answer 1

Answer:

The depth of focus achievable with those lenses is small.

Explanation:

A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.

Hope this helps!


Related Questions

Suppose that a cart is moving along a road at a constant velocity. Give two examples of ways to cause the cart to decelerate, explaining how the net force is affected. (2 points)

Answers

The cart moving at a constant velocity will decelerate when a braking force is applied or the road is made to become rougher.

Deceleration is also known as negative acceleration. It occurs when velocity decreases with time. There are two ways by which the cart moving at constant velocity can be made to decelerate. These two ways are;

By applying a braking force: A braking force causes the velocity to decrease with time. When a braking force is applied the frictional force exceeds the forward force hence the net force decreases.By increasing the roughness of the road: When the roughness of the road is increased, the frictional force also increases causing the net force on the cart to decrease hence it decelerates.

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What is the ideal temperature for a lithium-ion battery?.

Answers

Answer:

16 to 25 degrees f

Explanation:

25 n object requires a 5. 0 n to start moving over a horizontal surface. What is the coefficient of static friction?.

Answers

Answer:

μ=1/5=0.2

Explanation:

using the formula

Fs=Fn*μ

Where

Fs is the static force

Fn = Normal force

μ= coefficient

so if Fn=25n

and it requires 5 n to start moving, means the max Fs is 5n

5=25μ

μ=5/25

μ=1/5=0.2

why do air waves move faster than earthquake waves?

Answers

Answer:

P-waves and S-waves are body waves that propagate through the planet. P-waves travel 60% faster than S-waves on average because the interior of the Earth does not react the same way to both of them. ... The energy is thus less easily transmitted through the medium, and S-waves are slower.

Explanation:

can you give me brainliest

Help, please. I am not sure what to do.

Answers

Answer:

option D) -3m

Explanation:

if 6m is diplaced by -3m then it would be -3+6=3m

feel free to ask if you are confused

Acceration is a change in motion over time:
True False

Answers

The answers is definitely true for a fact

Help meeeeeeeeeeeeee

Answers

837474838/$77777uujj

What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod

Answers

Answer:

C) 5ML^2

Explanation:

2 Spheres of mass M

Bug's mass 3M

Rod length 2L, radius L

Find Rotational Inertia I

I=Σmr^2

I=(3M+M+M)L^2

I=5ML^2

The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Rotational inertia of the system

The rotational inertia of the system is determined by summing all the masses together and multiply with the radius.

I(t) = Σmr²

Where;

m is the massr is the radius

I(t) = Inertia of the 2 spheres + inertia of the bug

I(t) = (M + M)L²  + (3M)L²

I(t) = 2ML² + 3ML²

I(t) = 5ML²

Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Complete question is below:

There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.

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What is the instruments used to measure light intensity, wind intensity and relative humidity ​

Answers

Answer:

we use : photometer to measure light intensity

:Anemometer to measure wind intensity

:Hygrometer to measure relative humidity

You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it decays into (Thorium-231). The half life of Uranium-235 is 700 million years. How old is this rock?

Answers

The age of the given rock is 700 million years.

The given parameters;

original mass of the rock, = 20 gmass of the rock remaining after decay, = 10 ghalf life of Uranium, [tex]t_{1/2}[/tex] = 700 years

age of the rock ----------------------------- mass remaining

0 [tex](t_0)[/tex]  -------------------------------------------  20 g

1 half life ([tex]1 \ t_{1/2}[/tex] ) ------------------------------ 10 g

Age of the rock [tex]= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years[/tex]

Thus, the age of the given rock is 700 million years.

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(50 POINTS!!) 3. Make a model that shows the forces acting on two blocks on a flat, frictionless surface:
a. A 1 N block at rest
b. A 1 N block with 2 N of force applied in one horizontal direction
Include arrows to represent the forces and labels to indicate the magnitude of each force. Use your model to compare and explain the motion of each block.

Answers

The change in position of an object is known as motion. Force is external that causes a body to change its position

For a body is to be at rest, the sum of all the forces acting on the object must be zero

For a 1N block to be at rest, the normal force acting opposite to the weight must also be 1N.

For 1 N block with 2 N of force applied in one horizontal direction, the image of the body is as shown in the attachment

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Answer:

In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.

what is radiation?....​

Answers

Answer:

the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.

is called radiation

Answer:

Radiation is energy that comes from a source and travels through space at the speed of light

Explanation:

I hope it's help u

BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?

Answers


Anyways the answer is x=2

Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.

What quantity is represented by the mass number minus the atomic number?.

Answers

Answer:

Mass = mass of nucleus

Atomic Number = number of protons (charge) of nucleus

Mass - Atomic Number = number of neutrons

There are many isotopes of the element technetium (TC).
What do the nuclei of different technetium isotopes have in common?
[

Answers

Answer:

hikknn says he is not happy birthday hun

Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high

Answers

Answer:

2 time

Explanation:

when distance double the work double

The range of a target is found to be 20km. A shell leaves a gun with a velocity of 500m/s . What must be the angle of elevation of the gun if the ground is level

Answers

The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.

The shell experiments a parabolic motion, which is a combination of horizontal uniform motion and vertical uniform accelerated motion. If initial height of the shell is the same that its final height, then the range of the shell ([tex]d[/tex]), in meters, is described by the following expression:

[tex]d = \frac{v^{2}}{g}\cdot \sin 2\theta[/tex] (1)

Where:

[tex]v[/tex] - Initial speed of the shell, in meters per second[tex]g[/tex] - Gravitational acceleration, in meters per square second[tex]\theta[/tex] - Angle of elevation, in sexagesimal degrees

If we know that [tex]v = 500\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]d = 20000\,m[/tex], then the angle of elevation is:

[tex]\sin 2\theta = \frac{d\cdot g}{v^{2}}[/tex]

[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{d\cdot g}{v^{2}}[/tex]

[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{(20000\,m)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{\left(500\,\frac{m}{s} \right)^{2}}[/tex]

[tex]\theta \approx 25.840^{\circ}[/tex]

The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.

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What is the magnitude of the total displacement of the school bus.

Answers

Answer:

400 or 500

Explanation:

When waves are closer together, the distance between them is _________, therefore the waves have __________ wavelength.

Answers

Answer:

less' shorter

Explanation:

be cuase science

Answer:

The answer is D.

Explanation:

When waves are closer together, the distance between them is less, therefore the waves have longer wavelength.

The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant

Answers

The variable is temperature

what is the meaning of life?

Answers

Answer:

the condition that distinguishes animals and plants from inorganic matter, including the capacity for growth, reproduction, functional activity, and continual change preceding death.

Explanation:

hope this helps

If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)​

Answers

Answer:

[tex]\huge\boxed{\sf t = 40\ seconds}[/tex]

Explanation:

Given data:

Acceleration = a = 0.5 m/s²

Initial Velocity = Vi = 0 m/s

Distance = S = 400 m

Required:

Time = t = ?

Formulas used:

2 formulas

Third Equation of motion (2as = Vf²-Vi²)First Equation of motion (Vf = Vi + at)

Solution:

Using third equation of motion firstly

2as = Vf²-Vi²

2(0.5)(400) = Vf² - 0²

400 = Vf²

Taking sqrt

Vf = 20 m/s

Now, Using First equation of motion:

Vf = Vi + at

20 = 0 + 0.5t

0.5 t = 20

Divide both sides by 0.5

t = 40 seconds

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

Se lanza un balón verticalmente hacia arriba con una velocidad de 72 km/h. ¿Qué altura recorrió dicho cuerpo después de 0.05 minutos? (g = 10m/s2)

Answers

Usando la información contenida en la pregunta, la distancia que recorre la bola hacia arriba es de 15 m.

Velocidad inicial = 20 m / s

Tiempo= 3 s

Aceleración por gravedad =  10 ms-2

Velocidad final = 0 m / s

Usando la ecuación;

h = u t - 1 / 2 g t 2

h = (20 × 3) - 1/2 × 10 × (3) ^ 2

h = 60 - 45

h = 15 m

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How can you cause a cart moving to the right at a constant speed to move to the left at a constant speed.

Answers

Answer:

The answer is below hoped it helped

Explanation:

Forces, when unbalanced, cause objects to accelerate. And the direction of the acceleration is the same as the direction of the extra force. Just because an object is moving to the right does not mean there is more right force than left force. Whether the right or the left force is bigger depends on whether the object is speeding up or slowing down. There must be more right force than left force if an object is moving to the right and speeding up. There must be more left force than right force if an object is moving to the right and slowing down.

Does the dependenceof the orbital energy on nmake sense in terms of the total number of nodes in each type of orbital?.

Answers

Answer:The 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

As we move away from the nucleus, the values of the principal quantum number (n) continues to increase.

As the principal quantum number (n) increases, the orbital becomes farther away from the nucleus.

The higher energy orbital are always larger than the orbitals closer to the nucleus.

Hence, the 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

Explanation:

What is the force on a 2kg object that is moving right at 6 m/s2?
0 3.0N
Ο ΟΝ
.33N
12.0N

Answers

Answer:

12N

Explanation:

By Newton second law force is the product of the mass of the object times it's acceleration. That makes it [tex]2\cdot 6 kg \cdot m/s^2 = 12 N[/tex]

What is the mass, in kilograms, of a large dog that weighs 441 newtons?​

Answers

Answer:

441 Newtons equals 44.97 kilograms.

Josh tests an unknown liquid substance using litmus paper. When he compared the used litmus paper to a pH scale, the color matches with a 3.5 of the scale. What kind of substance did Josh test?

Answers

Answer:

acid

Explanation:

because ph below 7 is acid

What unit of pressure in ideal gas law.

Answers

essure is measured in pascals ( Pa ) — sometimes expressed as newtons per square metre ( N⋅m-2 ). These mean exactly the same thing. Be careful if you are given pressures in kilopascals ( kPa ). For example, 150 kPa = 150 000 Pa

a uniform metre rule of mass 100g balances at the 40cm mark when a mass X is placed at the 10cm mark what is the value of x.pls help I don't know how to solve it​

Answers

Answer:

The fulcrum of the metre stick is at the 40 cm mark

100 g * 10 cm = 1000 g-cm clockwise torque

x * 30 cm = 1000 gm-cm = counterclockwise torque for balance

X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm  at 10 cm to balance

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