SOMEONE HELP! If I don't get this done i will fail, I have been trying for hours.

p.s. both questions have no answer choices.

1. If a baseball has a mass of 0.075kg and is traveling with an acceleration of 25 m/s2. What is the force that the baseball will hit the bat?

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2. Given the force diagram of the basketball, what can you tell about the basketball motion? (Diagram below)



Thanks in advance!!

Answer:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

Explanation:

X and Y components:

Y = 6.36 m/s

X = 10.18 m/s

Position after 0.5 seconds:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

The x and y positions of the ball 0.50s after it is kicked are 5.09 meter and  1.95 meter respectively.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Initial speed of the soccer ball at an angle 32° above the horizontal is: u = 12m/s.

Time interval: t = 0.50 second.

Now, x component of initial velocity = u cosθ = 12 × cos 32° m/s = 10.17 m/s.

y component of initial velocity = u sinθ = 12 × sin32° =6.36 m/s.

Hence,

after 0.50 s, x-position of the ball =  u cosθ t

= 10.17 × 0.50 meter

= 5.09 meter.

after 0.50 s, y-position of the ball =  u sinθ t -gt²/2

= 6.36 × 0.50 - (9.8×0.50²/2) meter

= 1.95 meter.

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Answer:

well for C the horse is at rest at 10 to 15

D is 0 to 10

E is 15 to 25

Explanation:

If you search up examples it will help with this worksheet.

If I am work then I appologize

Hi there!

[tex]\large\boxed{KE =1.245 J}}[/tex]

The equation of angular kinetic energy is:

[tex]KE = \frac{1}{2}Iw^2[/tex]

Where:

I = moment of inertia (kgm²/s)

ω = angular speed (rad/sec)

A rod rotated about one of its endpoints has a standard moment of inertia of 1/3mR², so:

[tex]KE = \frac{1}{2}(\frac{1}{3}mL^2w^2)[/tex]

[tex]KE = \frac{1}{6}mL^2w^2[/tex]

Plug in the given values:

[tex]KE = \frac{1}{6}(0.63)(0.82^2)(4.2^2) = 1.245 J[/tex]

knives, axe ,blades and nails are examples of potential energy

or sharp objects

Answer:

5.6

Explanation:

Not so sure

The water in the bucket containing the aluminium block is warmer than the bucket containing the copper block.

The specific heat is the amount of heat needed or required to elevate the temperature of 1 gram of a substance by 1° C.

At standard conditions;

We know that:

Therefore, since the specific heat of aluminium is higher than that of copper, the water bucket containing aluminium block will be warmer than the bucket containing the copper block.  

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Answer:

Explanation:

The change in force = 9.81(1.95 - 0.300) = 16.2 N

The change in length is 0.750 - 0.200 = 0.550 m

K = ΔF/Δx = 16.2/0.550 = 29.4 N/m

Answer:

The two main factors that affect kinetic energy are mass and speed.

Explanation:

Kinetic energy is the energy that is caused by the motion. The kinetic energy of an object is the energy or force that the object has due to its motion. Your moving vehicle has kinetic energy; as you increase your vehicle's speed, your vehicle's kinetic energy increases.

Have a great day! :D

Answer:

d because u now

Explanation:

sana makatulong

Answer:

C) high efficiency light bulbs, because they produce more heat

Light bulbs produce useful energy in the form of light and waste energy in the form of heat, the kind of light bulb would you use to incubate eggs are low-efficiency light bulbs, because they produce more heat, therefore the correct answer is option B.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

The type of light bulb you would use to incubate eggs is a low-efficiency light bulb since they produce more heat; consequently, option B is the right response. Light bulbs produce useful energy in the form of light and waste energy in the form of heat.

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Answer:

Explanation:

4126h2.

Answer:

Explanation:

Assuming x direction is horizontal any y direction is vertical

As the moment of inertia of the pulley is I = (½)mR²

The pulley mass will appear as ½ its actual mass in the system.

F = ma

5.00(9.81) = (5.00 + 2.60/2 + 12.0)a

a =  49.05 / 18.3

a = 2.6803278...

a = 2.68 m/s²

A) T = 12.0(2.68) = 32.16... = 32.2 N

B) T = 5.00(9.81 - 2.68) = 35.65 = 35.7 N

C) aₓ = 2.68 m/s²

D) Fx = 32.2 N

   Fy = 35.7 + 2.60(9.81) = 61.2 N

A)The tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.

The given data in the problem is;

m is the mass box resting on a horizontal  =12.0 kg

the uniform solid disk of mass of 2.60 kg

d is the diameter = 0.500 m.

A)The tension in the horizontal segment of the wire will be  32.2 N

The acceleration is found as;

[tex]\rm F = ma \\\\ a= \frac{49.05}{18.3} \\\\ \rm a= 2.68 \ m/sec^2[/tex]

The tension in the horizontal segment of the wire is found as;

T=ma

T= 12.0 ×2.68

T=32.2 N

Hence the tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

T=m(g-a )

T= 5.00 × (9.8-2.68)

T=35.7 N

Hence the tension in the vertical segment of the wire will be 35.7 N

C)  the x-component of the acceleration of the box. will be 2.68 m/s².

aₓ = 2.68 m/s²

D)The x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

Fx = 32.2 N

Fy = 35.7 + 2.60(9.81) = 61.2 N

Hence the x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

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Answer:

statements?

Explanation:

Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

[tex]\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s[/tex]

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

Answer:

BBbbb

Explanation:

B is the correct answer:))))

Answer:

15-45/2 = -7.5 downwards

Explanation:

cos(60) x 45 = z

z = 45/2

sin (30) x 70 = y

y = 15

15-45/ 2 = -7.5 downwards

Answer:

Avoid heavy strenuous exercise for the 24 hours prior to testing. Do not exercise at all on the day of testing to ensure you are well rested. Wear appropriate clothing for the conditions (e.g. shorts/track pants and t-shirt/singlet/sports top) and non-slip athletic footwear with laces securely fastened

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

The speed of the cart at the second point of observation is equal to 1.62 m/s.

Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body

W= F.d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:

[tex]W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2[/tex]

Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).

Given, the work done by the cart, W = 0.91 J

The mass of the cart, m = 0.80 Kg

The speed of the cart at the first point, v₁ = 0.61 m/s

[tex]0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2[/tex]

0.40 v₂² = 1.06

v₂² = 2.65

v₂ = 1.62 m/s

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Answer:

Fnet = 5 Newton

Explanation:

Fnet = 10 N - 5 N

Fnet = 5 N

Answer:

I think that the answer is 4.318 as a=f/p

Answer:

1.96 N

Explanation:

⇒This is your full answer

five times that of object l

Answer:

d

Explanation:

A dreams

.......wkkwkwkwkwkwnwnsksk

Answer:

C. short term goal

Explanation:

took a midterm quiz on canvas, Hope this helps <3

Answer:

We are given the length, the mass and the density of the cylinder. First let us calculate for the volume by dividing the mass by the density.

volume = mass /density

where mass = 2.17 kg = 2170 g, therefore:

volume = 2170 g / (2.33 g/cm^3)

volume = 931.33 cm^3

We know that the volume of a cylinder has the formula:

volume = π r^2 h

since h = 16.8 cm, therefore calculating for radius:

931.33 cm^3 = π r^2 (16.8 cm)

r^2 = 17.646 cm^2

r = 4.2 cm

Hence the diameter (d) is:

d = 2 r

d = 8.4 cm

Explanation:

The diameter of the cylindrical rod is approximately 0.382 cm.

To find the diameter of the cylindrical rod, we can use the formula for the volume of a cylinder and then solve for the diameter.

The formula for the volume of a cylinder is:

V = π[tex]r^{2}[/tex]h,

where V is the volume, r is the radius, and h is the height (or length) of the cylinder.

In this case, we know the length of the cylinder (h) is 16.8 cm. We need to find the radius (r) in order to calculate the diameter.

The mass of the cylinder can be related to its volume and density using the formula:

m = ρV,

where m is the mass, ρ is the density, and V is the volume.

Rearranging this formula, we can solve for V:

V = m / ρ.

Now we have two equations:

V = π[tex]r^{2}[/tex]h,

V = m / ρ.

Setting these two equations equal to each other, we can solve for r:

π[tex]r^{2}[/tex]h = m / ρ.

Substituting the given values:

π[tex]r^{2}[/tex] * 16.8 cm = 2.17 kg / (2.33 g/[tex]cm^3[/tex]).

Let's solve this equation for r:

[tex]r^{2}[/tex] = (2.17 kg / (2.33 g/[tex]cm^3[/tex])) / (π * 16.8 cm).

[tex]r^{2}[/tex]  ≈ 0.036775 [tex]cm^2[/tex].

Taking the square root of both sides:

r ≈ 0.191 cm.

Finally, we can find the diameter (d) by multiplying the radius by 2:

d ≈ 2 * 0.191 cm.

d ≈ 0.382 cm.

Therefore, the diameter of the cylindrical rod is approximately 0.382 cm.

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Answer:

333.5 MJ

Explanation:

ΔV = m·g·Δh

     = 8500 · 9.81 · (15000-11000)

     = 8500 · 9.81 · 4000

     = 333 540 000

     ≈ 333.5 ·10⁶J = 333.5 MJ

The change in potential energy is 333.5 MJ

Potential energy is defined as the energy possessed by an object because of its position relative to other objects, tension within itself, its electric charge, or other factors. Any object that is raised above its rest position has energy stored in it, so it is called potential energy because it has the potential to do work when released.

It can be expressed as:

P.E.= mgh

where, m is the mass of an object measured in grams 'g'

g is the acceleration due to gravity which is [tex]9.8 m/s^2[/tex]

h is the height measured in meter 'm'

Here,

the given information is

m= 8500kg

Δh= [tex]h_2 - h_1[/tex] = 15000-11000 = 4,000m

So, P.E. = 850 x 9.8 x 4000 = 333 540 000=  333.5 ·10⁶J = 333.5 MJ

Thus, the change in potential energy is 333.5 MJ

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Answer:

Main Difference Between Mechanical and Electromagnetic waves

A wave is composed of some kind of disturbance that propagates. We can classify waves into many different types based on their properties. One of the properties of the waves depends on whether they need a medium to propagate or not. The primary difference between electromagnetic and mechanical waves is also based on this property. Mechanical waves need a medium, while electromagnetic waves do not need a medium to propagate. Electromagnetic waves can travel through a vacuum. The other differences between mechanical and electromagnetic waves are given below:

Electromagnetic waves can travel through a vacuum, that is an empty space, whereas mechanical waves cannot. They need a medium to travel such as water or air. Ripples in a pond are an example of mechanical waves whereas electromagnetic waves include light and radio signals, which can travel through the vacuum of space.

Mechanical waves can be classed as elastic waves because their transmission depends on the medium's (water, air etc.) elastic properties.

Electromagnetic waves are caused because of the varying magnetic and electric fields. They are produced by the vibration of the charged particles.

Because of these differences, the speed of each type of wave varies significantly. Electromagnetic waves travel at the speed of light but mechanical waves are far slower.

                                                                            Have a wonderful day!

                                                                                                ~Lillith of brainly~

The patient eating a candy bar instead of fasting for the test should be told

that the test results will be wrong and he may receive a wrong diagnosis.

The medical practitioners told him to fast when coming for a reason and he

forgetting and eating something means the objective for the test may have

been defeated.

This is why it's best to explain to him about the consequences of his actions

which is likely getting a wrong result and diagnosis.

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Answer:

......the answer is 496.4

Answer:

The answer should be 3-At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.

Answer:

3. At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.