Solve: 6x - 13 = 4(x + 10) + 2x

A uniform solid disk with a mass of 2.91 kg and a radius of 0.200 m is rotating about a fixed axis perpendicular to its face with an angular frequency of 5.94 rad/s.

The angular frequency of an object rotating about a fixed axis represents the rate at which it completes one full revolution in radians per second. In this case, the disk has an angular frequency of 5.94 rad/s.

The moment of inertia of a uniform solid disk rotating about its axis can be calculated using the formula:

I = (1/2) * m * [tex]r^2[/tex]

where I is the moment of inertia, m is the mass of the disk, and r is the radius of the disk. Substituting the given values, we have:

I = (1/2) * 2.91 kg * [tex](0.200 m)^2[/tex]= 0.0582 kg·[tex]m^2[/tex]

The moment of inertia is a measure of an object's resistance to changes in rotational motion. In this case, the disk's moment of inertia is 0.0582 kg·[tex]m^2[/tex].

The angular frequency, moment of inertia, and mass of the disk are related by the equation:

I * ω = L

where ω is the angular frequency and L is the angular momentum. Rearranging the equation, we can solve for the angular momentum:

L = I * ω = 0.0582 kg·[tex]m^2[/tex] * 5.94 rad/s = 0.3456 kg·[tex]m^2[/tex]/s

Therefore, the angular momentum of the rotating disk is 0.3456 kg·[tex]m^2[/tex]/s.

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Answer:

(-1,2) i think

Step-by-step explanation:

Answer:

B. A = 1/2(7)h

Step-by-step explanation:

Formula for area of triangle = 1/2 x base x height

H is the height of the triangle.

7cm is identified as the base of the triangle.

1/2(7)h is also the same thing as 1/2 x 7 x h basically.

Answer:

B

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

Here b = 7 and h = h , then

A = [tex]\frac{1}{2}[/tex] (7) h → B

Answer:

7 is the answer

Step-by-step explanation:

Because 6x + 3 -8 + x = x is 6

it's simple it's really easy so the answer is 2.0 1682

Answer:

The answer your looking for is, C.

Answer:

The radius is 3.5 inches I think.

Step-by-step explanation:

Hope this helped Mark BRAINLIEST!!!

Answer:

3.5

Step-by-step explanation:

You would simply divide 7 inches by 2 because the radius is one-half the measure of the diameter.

We can conclude that the null hypothesis is rejected. There is sufficient evidence to support the claim that the mean cost in Utah hospitals is below the national mean of $1231.

H₀: μ ≥ 1231 (The mean cost in Utah hospitals is greater than or equal to the national mean)

Hₐ: μ < 1231 (The mean cost in Utah hospitals is below the national mean)

Given

The test statistic for a one-sample t-test is given by

t = (x - μ) / (σ / √n)

Substituting we have

t = (1103 - 1231) / (252 / √25)

≈ -6.103

To determine the critical value, we need to find the critical t-value at the 5% significance level with degrees of freedom

(df) equal to (n - 1)

= (25 - 1)

= 24.

Using a t-distribution table or calculator, the critical value is approximately -1.711.

Since the calculated test statistic (-6.103) is smaller than the critical value (-1.711) and falls into the critical region, we reject the null hypothesis.

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Step-by-step explanation:

[tex] \frac{ - 48 + 6}{ - 7} + ( - 3)( - 4)( - 2) \\ = \frac{ - 42}{ - 7} + 12( - 2) \\ = 6 + ( - 24) \\ = 6 - 24 \\ = - 18[/tex]

*see attachment for the diagram given

Answer:

Volume of the toy = 68 in.³

Step-by-step explanation:

The equation to find the volume of the toy = volume of the wooden rectangular prism - volume of the triangular prism removed form the center

Volume of the toy = (L*W*H) - (½*bhl)

Where,

L = 8 inches

W = 3 inches

H = 3 inches

b = 1 inch

h = 1 inch

l = 8 inches

Plug in the values into the equation

Volume of the toy = (8*3*3) - (½*1*1*8)

Volume = 72 - 4

Volume of the toy = 68 in.³

Answer:

3n + 2

Step-by-step explanation:

−n+(−4)−(−4n)+6

-n - 4 + 4n + 6

3n + 2

The parametric equations for the line of intersection of the planes 4x - 3y + z = 1 and 3x + y - 4z = 4 are:

x = (208 + 70t) / 52

y = (13 + 19t) / 13

z = t

To find the parametric equations for the line of intersection of the planes 4x - 3y + z = 1 and 3x + y - 4z = 4, we can solve these two equations simultaneously.

Step 1: Set up a system of equations:

4x - 3y + z = 1

3x + y - 4z = 4

Step 2: Solve the system of equations to find the values of x, y, and z. One way to solve the system is by using the method of elimination:

Multiply the first equation by 3 and the second equation by 4 to eliminate the y term:

12x - 9y + 3z = 3

12x + 4y - 16z = 16

Subtract the first equation from the second equation:

12x + 4y - 16z - (12x - 9y + 3z) = 16 - 3

12x + 4y - 16z - 12x + 9y - 3z = 13y - 19z = 13

Step 3: Express y and z in terms of a parameter, let's call it t:

13y - 19z = 13

y = (13 + 19z) / 13

We can take z as the parameter t:

z = t

Substituting the value of z in terms of t into the equation for y:

y = (13 + 19t) / 13

Step 4: Express x in terms of t:

From the first equation of the original system:

4x - 3y + z = 1

4x - 3((13 + 19t) / 13) + t = 1

4x - (39 + 57t) / 13 + t = 1

4x - (39 + 57t + 13t) / 13 = 1

4x - (39 + 70t) / 13 = 1

4x = (39 + 70t) / 13 + 1

x = ((39 + 70t) / 13 + 13) / 4

x = (39 + 70t + 169) / 52

x = (208 + 70t) / 52

Therefore, the parametric equations for the line of intersection of the planes 4x - 3y + z = 1 and 3x + y - 4z = 4 are:

x = (208 + 70t) / 52

y = (13 + 19t) / 13

z = t

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a. Matrix A is invertible when |A| = -m ≠ 0 then statement true.

b. The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.

c. The system AX = B has an infinite number of solutions when m = n = 0 then statement true.

d. Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.

e. The system AX = 0 has a unique solution when m ≠ 0 then statement true.

f. At least one eigenvalue of the matrix A is zero when m = 0 then statement true.

g. Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.

Given that,

The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that

[A|B] = [tex]\left[\begin{array}{ccc}2&1&0 \ | \ 2\\0&-1&3 \ | \ 1 \\0&0&m \ | \ n\end{array}\right][/tex]

Where m and n are real numbers.

We know that,

a. We have to prove matrix A is invertible.

For A to be invertible.

|A| ≠ 0

|A| is the determinant of the matrix A.

|A| = 2(-m) -1(0) + 0(0) = -m

Here, m is the real number.

So, |A| = -m ≠ 0

Therefore, Matrix A is invertible when |A| = -m ≠ 0 then statement true.

b. We have to prove the system AX = B has no solution.

When Rank[A|B] > Rank[A]

m = 0 and n ≠ 0 has a real number

Therefore, The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.

c. We have to prove the system AX = B has an infinite number of solutions.

When m = n = 0, and Rank[A] < 3

Therefore, The system AX = B has an infinite number of solutions when m = n = 0 then statement true.

d. We have to prove columns of the augmented matrix (AB) are linearly independent.

When m ≠ 0 and m∈R and n= 0

Therefore, Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.

e. We have to prove the system AX = 0 has a unique solution.

When [tex]\left[\begin{array}{ccc}2&1&0 \\0&-1&3 \\0&0&m \end{array}\right]\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}0\\0\\0\end{array}\right][/tex]

The equation are 2x + y = 0, -y + 3z = 0 and mz = 0

m ≠ 0 should be any real number except zero.

Therefore, The system AX = 0 has a unique solution when m ≠ 0 then statement true.

f. We have to prove at least one eigenvalue of the matrix A is zero.

When λ = 2, 1, m

m = 0 then eigen value is zero

Therefore, At least one eigenvalue of the matrix A is zero when m = 0 then statement true.

g. We have to prove columns of the matrix A form a basis in R³.

When m ≠ 0

Therefore, Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.

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In a normal distribution, approximately 68% of scores fall between the z-scores of -1.00 and +1.00.

In a standard normal distribution, which has a mean of 0 and a standard deviation of 1, the Empirical Rule (also known as the 68-95-99.7 Rule) applies. According to this rule, approximately 68% of the data falls within one standard deviation from the mean.

Since the z-scores represent the number of standard deviations a particular value is away from the mean, a z-score of -1.00 represents one standard deviation below the mean, and a z-score of +1.00 represents one standard deviation above the mean. Therefore, using the Empirical Rule, we can conclude that approximately 68% of scores fall between these two z-scores (-1.00 and +1.00).

This percentage represents the central portion of the distribution that is within one standard deviation from the mean, providing a useful measure of the spread and concentration of data in a normal distribution.

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The principal part at the isolated singular point -1 is not provided, so we cannot determine its nature or residue. And b) The principal part at the isolated singular point 1 is (x - 1)^2022 exp(-1). It is a pole of order 2022, and its residue is 0.

a) The principal part at the isolated singular point -1 is not provided, so we cannot determine its nature (removable singular point, essential singular point, or pole) or calculate its residue without additional information.

b) The given function is (x - 1)^2022 exp(-1). At the isolated singular point x = 1, the principal part of the function is (x - 1)^2022 exp(-1). Here, (x - 1)^2022 represents the pole part of the function, and exp(-1) represents the non-pole part.

Since the term (x - 1)^2022 dominates near x = 1, we can conclude that x = 1 is a pole. The order of the pole is determined by the exponent of (x - 1), which is 2022 in this case.

To calculate the residue, we need more information about the function, specifically the coefficients of the Laurent series expansion near the singular point. Without that information, we cannot determine the residue at x = 1.

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Group A parallelogram, Group B Quadrilateral.

Answer: Parallelogram and Quadrilateral.

The  two ways of classifying shapes are: Parallelogram and Quadrilateral.

There are different ways to classify an item.

Quadrilaterals can be known by;

It is a polygon with four sides.

Since rectangle is known to be a parallelogram that has four right angles.

A trapezoid is regarded as a quadrilateral with only one pair of parallel sides.

And Parallelograms are known to be shapes that has four sides with only two pairs of sides that are known to be parallel.

So we conclude that Group A parallelogram, and Group B Quadrilateral.

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Therefore, the variance of the time it takes for someone to finish a bowl of ramen is 4.6875.

Given, The moment generating function of the time it takes for someone to finish a bowl of ramen is

M(t)= 1/ (1−0.05t​)1​,t<0.05 We have to find the variance of the time it takes for someone to finish a bowl of ramen.

The variance of the random variable can be calculated by the formula Variance = M''(0) - [M'(0)]^2 where M(t) is the moment generating function of the random variable M'(t) is the first derivative of M(t)M''(t) is the second derivative of M(t)

We need to find M''(t) and M'(t)M(t) = 1/(1 - 0.05t)M'(t) = [0.05/(1 - 0.05t)^2]M''(t) = [0.1/(1 - 0.05t)^3] Now, at t = 0, M(0) = 1, M'(0) = 1.25, M''(0) = 6.25 Variance = M''(0) - [M'(0)]^2 Variance = 6.25 - (1.25)^2 Variance = 6.25 - 1.5625 Variance = 4.6875

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Given: The time it takes for someone to finish a bowl of ramen can be modeled by a random variable with the following moment generating function: M(t)= 1/ (1−0.05t​)1​,t<0.05. The variance of the time it takes for someone to finish a bowl of ramen is 400.

The moment generating function of a random variable is defined as [tex]$M(t) = \mathbb{E}(e^{tX})$[/tex] for all t in an open interval around 0 which X is a random variable.

We are given that the moment generating function of the random variable T is given by:

[tex]$$M(t)= \frac{1}{1-0.05t} ,\ t < 0.05$$[/tex]

The [tex]$n^{th}$[/tex] derivative of M(t) at 0 is given by:

[tex]$$\frac{d^n}{dt^n} M(t) \biggr|_{t=0} = \mathbb{E}(X^n)$$[/tex]

We differentiate $[tex]M(t)$[/tex] with respect to $t$ to get [tex]$$M'(t) = \frac{0.05}{(1 - 0.05t)^2}$$[/tex].

Differentiating [tex]$M'(t)$[/tex] with respect to [tex]$t$[/tex] we get [tex]$$M''(t) = \frac{2(0.05)^2}{(1-0.05t)^3}$$[/tex].

Differentiating [tex]$M''(t)$[/tex] with respect to [tex]$t$[/tex] we get [tex]$$M'''(t) = \frac{6(0.05)^3}{(1-0.05t)^4}$$[/tex].

Substituting t = 0, we get [tex]$$M'(0) = \frac{1}{0.05} = 20$$[/tex]

[tex]$$M''(0) = \frac{2}{(0.05)^3} = 800$$[/tex]

[tex]$$M'''(0) = \frac{6}{(0.05)^4} = 4800$$[/tex]

Using the following formula to calculate the variance of X: [tex]$$Var(X) = \mathbb{E}(X^2) - [\mathbb{E}(X)]^2$$[/tex], where [tex]$$\mathbb{E}(X^2) = M''(0) = 800$$[/tex].

[tex]$$[\mathbb{E}(X)]^2 = [M'(0)]^2 = 400$$[/tex]

Hence, we get:$$Var(X) = 800 - 400 = \boxed{400}$$.

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Answer:

x= 24

Step-by-step explanation:

5x=20*6

x=120/5

x=24

Hope this helps! Plz mark as brainliest! :)

Step-by-step explanation:

1st expression

= px^4 + px

= px ( x³ + 1 )

= px ( x + 1) (x² - x + 1)

2nd expression

= qx³ - qx

= qx ( x² - 1 )

= qx ( x + 1) ( x - 1)

HCF = x ( x + 1)

Hope it will help :)❤

Answer:

x = 18

Step-by-step explanation:

The "Angle Bisector" Theorem says that an angle bisector of a triangle will divide the opposite side into two segments that are proportional to the other two sides of the triangle.

So, 20/8 = (4x + 3)/30

8(4x + 3) = 20(30)

32x + 24 = 600

32x = 576

x = 18

We have: u''(x) = ƒ(x)cot(x) - 2u'(x)cot(x).Thus, we can find a particular solution of this differential equation by using variation of parameters.

Let G(x) = ƒ(s)sin(x - s) ds.

Then, by the product rule, we have: G' = ƒ(s)cos(x - s) ds - ƒ(s)sin(x - s) ds, and G'' = -ƒ(s)sin(x - s) ds - ƒ(s)cos(x - s) ds. Hence, we have:G'' + G = ƒ(s)sin(x - s) ds - ƒ(s)cos(x - s) ds + ƒ(s)sin(x - s) ds = ƒ(s)sin(x - s) ds = G.

So, G is indeed a solution of y'' + y = ƒ(x).Next, we will use variation of parameters to find a second solution of the same differential equation.

Let us suppose that we have another solution of the form y = u(x) sin(x).

Then, y' = u(x)cos(x) + u'(x)sin(x), and y'' = - u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x).

Substituting these into the differential equation, we get:- u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x) + u(x)sin(x) = ƒ(x)2u'(x)cos(x) + u''(x)sin(x) = ƒ(x)

Dividing by sin(x), we get:2u'(x)cot(x) + u''(x) = ƒ(x)cot(x).

Now, let us assume that the second solution is of the form y = u(x)sin(x), where u is a function to be determined.

Then, we have: y' = u(x)cos(x) + u'(x)sin(x) and y'' = - u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x).

Substituting these into the differential equation, we get: - u(x)sin(x) + 2u'(x)cos(x) + u''(x)sin(x) + u(x)sin(x) = ƒ(x)2u'(x)cos(x) + u''(x)sin(x) = ƒ(x)

Dividing by sin(x), we get:2u'(x)cot(x) + u''(x) = ƒ(x)cot(x).

Hence, we have: u''(x) = ƒ(x)cot(x) - 2u'(x)cot(x).Thus, we can find a particular solution of this differential equation by using variation of parameters.

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i have now attached the picture but it can be wrong!

The probability that the patient has breast cancer given a positive result is 62.2%.

The probability of testing positive given the patient has breast cancer is:

P(P|C) = 0.869

The specificity of the test is 88.9% or 0.889, meaning that the test will correctly identify 88.9% of patients who do not have breast cancer as not having the disease.

So, the probability of testing negative given the patient does not have breast cancer is:

P(N|N) = 0.889

Now, using Bayes' theorem:

P(C|P) = P(P|C) * P(C) / P(P)

where,P(P) = P(P|C) * P(C) + P(P|N) * P(N)

Here, P(P|N) is the probability of testing positive given that the patient does not have breast cancer. This is equal to 1 - specificity = 1 - 0.889 = 0.111.

So, P(P) = P(P|C) * P(C) + P(P|N) * P(N) = 0.869 * 0.13 + 0.111 * (1 - 0.13) = 0.1823

So,P(C|P) = 0.869 * 0.13 / 0.1823 = 0.622 or 62.2%

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Answer:

c I think but I am not sure but I hope you have a good day

Answer:

A or D

Step-by-step explanation:

Step-by-step explanation:

3 Area of lateral = 3 ( bh ) = 12.2 XIO +7.04X12.2 +7.04x 12.2 = 122+85.888+85.888 = 293.776

293.776 approximate to 288