so 13+139+123+129 so WHAT does this =

Answer:

B

d(P,Q) = sqrt((xO-xQ)^2 + (yP-yQ)^2) = sqrt(16+9) = 5

Answer:

Step-by-step explanation:

Initial class size = 30 students

Class size now is 40% larger:

First let's find larged amount

[tex]\\ \sf\longmapsto 40\%\:of\:30[/tex]

[tex]\\ \sf\longmapsto 0.4(30)[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

Class size=30+12=42students

Answer:

[tex]\huge\colorbox{blue}{A}\huge\colorbox{orange}{N}\huge\colorbox{gray}{S}\huge\colorbox{red}{W}\huge\colorbox{yellow}{E}\huge\colorbox{purple}{R}[/tex]

hitsss

Answer:

.

Step-by-step explanation:

Answer:

p = 0.07

p-hat = 0.035

p0 = 0.07

p-value = 0.003

Step-by-step explanation:

p = population parameter, in this case, the rate of infestations across all trees in the forest

p-hat = test statistic, in this case, the rate of infestations found in the sample of trees, i.e. those in Doug's backyard

p0 = the null hypothesis, in this case, the rate of infestations within the forest is correctly evaluated at 0.07 or 7%

p-value = the likelihood any difference between p and p-hat is down to chance

In this case 0.003 as the p-value means there is only 0.3% probability of our statistic value of 0.035 being down to variability and chance meaning it is 99.7% likely that there is some reason behind this difference;

We would accept the alternative hypothesis which says the current parameter value, 0.07, is in fact incorrect (either too high or too low, in this case, likely too high).

There are 100 numbers in the range 100-199. Find the smallest and largest multiple of 13 in this range. We have

104 = 8•13

195 = 15•13

so there are 15 - 8 + 1 = 8 multiples of 13 between 100 and 199.

Then the sum we want is

[tex]\displaystyle \sum_{k=100}^{199} k - \sum_{\ell=8}^{15}13\ell[/tex]

or equivalently,

(100 + 101 + 102 + … + 199) - 13 (8 + 9 + … + 15)

To compute these sums, recall the following formula:

[tex]\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]

Then

[tex]\displaystyle \sum_{k=100}^{199} k = \sum_{k=1}^{199} k - \sum_{k=1}^{99} k = \frac{199\cdot200}2 - \frac{99\cdot100}2 = 14,950[/tex]

and

[tex]\displaystyle \sum_{\ell=8}^{15} 13\ell = 13 \left(\sum_{\ell=1}^{15} \ell - \sum_{\ell=1}^7 \ell\right) = 13 \left(\frac{15\cdot16}2 - \frac{7\cdot8}2\right) = 1,196[/tex]

which means the sum we want is 14,950 - 1,196 = 13,754.

Answer:

OOO

OOO

OO

Step-by-step explanation:

Where OOO is == 1.

OO is 2/3 of OOO.

Answer:

Step-by-step explanation:

From the question, I couldn't really tell what the chart looks like, so I am guessing it looks like this:

Sidewalk 1:

x  |  y

2  |  17

0  | 5

Sidewalk 2:

x  |  y

1  |  20

3  | 26

Part a.

Now, we have to write the equation for sidewalk 1 in slope-intercept form.

Slope-intercept form is represented as this: [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept. Because this is true for all values on the line, we can plug in values of the chart for Sidewalk 1.

[tex]17=2m+b\\5=0m+b[/tex]

Subtracting the second equation from the first, we have

[tex]12=2m[/tex], and [tex]m = 6[/tex].

Now, we can just plug 6 back into the first equation to get:

[tex]17=2(6)+b[/tex]  to get [tex]17 = 12 + b[/tex], and then [tex]b = 5[/tex].

Now, we can just rewrite slope intercept form for Sidewalk 1 to have

[tex]y=6x+5[/tex].

Part b.

Point-slope form is represented as [tex]y-y_1=m(x-x_1)[/tex], where x and y are the coordinates of one point, and x1 and y1 are the coordinates of another point on the line. Because the chart represented for Sidewalk 2 includes a point, namely [tex](1, 20)[/tex] and [tex](3, 26)[/tex], we can plug this in and solve for the slope:

[tex]26-20=m(3-1)[/tex]

This is it in point-slope form. Because the second part of the question asks us to convert to slope-intercept form, we must solve for the slope, or m.

Expanding, we have [tex]26-20=3m-m[/tex]

Combining like terms, we have [tex]6 = 2m[/tex], and then [tex]3 = m[/tex]. Now, we need to plug a point and the slope back into point-slope form, not needing another point. We choose [tex](1, 20)[/tex], even though [tex](3, 26)[/tex] works just as well.

[tex]y-20=3(x-1)[/tex]

Expanding, we have [tex]y-20=3x-3[/tex]

Adding 20 to both sides, we have [tex]y=3x+17[/tex]

Part c. and d.

We see that both equations do not have the same slope, so then they are not parallel, meaning they don't have no solutions. If they have a solution, we can set them equal to each other.

[tex]3x+17=6x+5[/tex]

Subtracting 3x, we have [tex]17=3x+5[/tex]

Subtracting 5, we have [tex]12 = 3x[/tex]

Dividing by 3, we have [tex]x = 4[/tex].

Because there is no x = x, or anything like that, the solution does not have infinite solutions and therefore has one solution, meaning it is consistent independent.

Answer:

Answer ️️

Step-by-step explanation:

5.1÷104 = 4.903846154

Step-by-step explanation:

subject arts and architecture what primary

Answer:

$2 each

Step-by-step explanation:

$14.50-$4.50=$10.00

10.00/5 games =$2 each

Answer:

Uuuuh thats kind of suspicious, maybe you could post your question without  a link? But links are usually scams, so dont do that :)

[tex]6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}[/tex]

[tex]x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}[/tex]

Answer:

c

brainlest

Step-by-step explanation:

Answer:

Jill plz tell if i am right

Step-by-step explanation:

give me schoology website

Answer:

B

Step-by-step explanation:

If you go to -4, 0 the line intersects that point

Answer: y= 1/2x + 7

Step-by-step explanation:

Answer:

Do in calculator simple answer

Answer: I'll give you formula

Step-by-step explanation: circumference = 2 x π x radius

radius = diameter÷2      area = π × radius²

Answer:

35 degrees celsius

Answer:

Step-by-step explanation:

f(x) = 2x + 1

g(x) = ?

h(x) = ln(x)

hgf(x) = ½ln(2x - 3)

All h(x) does is take a natural log of a number, therefore the output

gf(x) = [tex]\sqrt{2x - 3}[/tex]

the change between f(x) and fg(x) is a subtraction of 4 then raising the result to a power of ½.

g(x) = [tex]\sqrt{x - 4}[/tex]

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

[tex]\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2[/tex]

Answer:

Measure of Angle B = 25°

Step-by-step explanation:

Something to keep in mind: Angle A and B are Vertical Angles so they will always be equal

so;

Angle A = Angle B

(4x + 5) = (-2(x - 17.5))

4x + 5 = -2x + 35   (<= Solved by distributive property)

6x + 5 = 35

6x = 30

x = 5

Now we can find the measure of Angle B, by substituting x by 5 in the B equation;

-2 (x - 17.5) = Angle B

-2 (5 - 17.5) = Angle

-2 (-12.5) = Angel B

25 = Angle B

so measure of angle B = 25

Hope this helps!

Answer:

5.62790697674

Step-by-step explanation:

there you go

Answer:

the annswer is 5

Step-by-step explanation: you just have to divide the highlighted numbers, which are 20 ÷ 5

Answer:

Solution:

3/7x = 12

3/7x ÷ 3/7 = 12 ÷ 3/7 ( divide 3/7 in both sides )

x = 12 ÷ 3/7 (divide)

x = 84/3 (simply divide 84 and 3)

x = 28

_______________________

(solution for dividing the fraction and the whole number 12 and 3/7, for those who don't know how to divide fractions and whole numbers...)

12/1 ÷ 3/7

12/1 ÷ 7/3 (reciprocal method)

12/1 × 7/3 (change operation to multiplication)

12/1 × 7/3 = 84/3 (multiply)

84/3 ⇒ 28 (simplify)

Answer:

$9.61 per shirt

Step-by-step explanation:

You take the total cost of $48.05 and divide it by the number of t-shirts which is 5.

48.05/5 = 9.61

Answer: 12% of people responded as City D

Answer:

xd

Step-by-step explanation:

3X+4y=8

this is the graph that represents the solution

Answer:

.25

Step-by-step explanation:

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation that goes through (5,4) and (10,2)

[tex](\stackrel{x_1}{5}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{5}}}\implies \cfrac{-2}{5} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{2}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{5}{2}}\qquad \stackrel{negative~reciprocal}{+\cfrac{5}{2}\implies \cfrac{5}{2}}}[/tex]