True, the entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
The third law of thermodynamics states that, the entropy of a system approaches a constant value as the temperature of the system approaches absolute zero.
The entropy of any perfectly ordered, crystalline substance at absolute zero temperature is zero. That is, the entropy of a pure, perfect crystalline substance at 0 K is 0 J/K.
Thus, we can conclude that the given statement is true. The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
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Pls answer this question
Answer:
A carbon dioxide and oxygen
The valence electrons of a krypton (Kr) atom in the ground state are located in the
A. first energy level (shell).
B. second energy level (shell).
C. third energy level (shell).
D. fourth energy level (shell).
Answer:
D
Explanation:
The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.
how much sucrose can dissolve in 200g of water at 70 °C?
The maximum amount of a substance that can be dissolved in a solvent at a given temperature is referred to as its solubility.
Sucrose has a solubility of 320 g/100 g H2O at 70°C.
How is solubility usually measured?The equilibration of a suspension followed by an assessment of the solution composition, from which the solution concentration can be determined, is a widely accepted and accurate method for measuring solubility.The maximum amount of a substance that can be dissolved in a solvent at a given temperature is referred to as its solubility. This type of solution is known as saturated. To calculate the solubility in g/100g, divide the mass of the compound by the mass of the solvent and multiply by 100 g.The ability of a compound to dissolve in a liquid that functions as a solvent aids in the determination of the solubility test. The tests are critical because they determine the polarity of unknown compounds.Sucrose has a solubility of 320 g/100 g H2O at 70°C.
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If there is direct variation and y=75 when x=25, find x when y=48.
A. x=16
B. x=10
C. x=12
D. x=14
If there is direct variation and y=75 when x=25,when y=48 X = 16. Therefore, option A is correct.
What is direct variation ?link between two variables that can be described mathematically by an equation where one variable equals a constant multiplied by the other. For instance, the constant of variation is k = = 3 if y varies straight as x and y = 6 when x = 2. Consequently, y = 3x is the equation that describes this direct variation.
When x is not equal to zero, an equation of the form y = kx describes the linear function known as direct variation. When x is not equal to zero and k is a nonzero real number constant, the equation of the form xy = k describes the nonlinear function known as inverse variation.
x = ky
where k is constant
25 = k × 75
25 / 75 = k
k = 1 / 3
now when y = 48 then substitute the values
x = ky
x = 1 ÷ 3 × 48
x = 16
Thus, option A is correct.
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What is the correct form of the equilibrium constant for the reaction of hydrogen and oxygen to form water? The equation is:
2H 2( g) + O 2( g) ⇌ H 2O( g)
Kc = ([H2O]/[O2] [H2])
Kc = ([H2O]/[O2] [H2]2)
Kc = ([H2O]/[O2] [H22])
Kc = ([H2O]2/[O2] [H22])
Kc = ([H2O]/[O2] [2H2])
The value of probability density will be
The probability density function is nonnegative everywhere, and its integral over the entire space is equal to the terms "probability distribution function" and "probability function" .
What is probability density function?
In probability theory, a probability density function (PDF), or density of a continuous random variable, is a function whose value at any given sample (or point) in the sample space (the set of possible values taken by the random variable) can be interpreted as providing a relative likelihood that the value of the random variable would be equal to that sample.
Probability density is the probability per unit length, in other words, while the absolute likelihood for a continuous random variable to take on any particular value is 0 (since there is an infinite set of possible values to begin with), the value of the PDF at two different samples can be used to infer, in any particular draw of the random variable, how much more likely it is that the random variable would be close to one sample compared to the other sample.
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What volume in liters of carbon dioxide will be produced by the reaction of 18.5 liters of oxygen gas at STP?
L CO2
C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(g)
**Report your answer to the correct number of significant digits!
Answer:
0.16 L
Explanation:
Step 1: Write the balanced equation
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)
Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂
The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.
Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure
At STP, 1 mole of CO₂ occupies 22.4 L.
0.0072 mol × 22.4 L/1 mol = 0.16 L
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How is the atomic mass of an element related to a mole?
O A. The atomic mass, in grams, is the mass of 6.02 x 1023 moles.
O B. The atomic mass, in grams, is the mass of 6.02 x 1023 electrons.
O C. The atomic mass, in grams, is the mass of one mole of atoms.
O D. The atomic mass, in grams, is the mass of one mole of protons.
Answer:
i the answer to your question should be C
Explanation:
Hope this helps!
The atomic mass of an element related to a mole in grams, is the mass of one mole of atoms. Therefore, option C is correct.
What is an atomic mass ?An atom's mass is its atomic mass. Although the kilogramme is the SI measure of mass, the unified atomic mass unit, or dalton, is a common way to express atomic mass. An unbound carbon-12 atom in its ground state has a mass of 112 of a Da.
A mass that is one-twelfth the mass of an atom of carbon-12 is known as an atomic mass unit. Any isotope of any element's mass is represented in terms of the carbon-12 reference standard.
The size of an atom is indicated by its atomic mass. Technically speaking, an atom's mass is the total weight of its protons, neutrons, and electrons.
Thus, option C is correct.
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What is one advantage of asexual reproduction?
O A. It is advantageous in a changing environment.
B. It is the slowest way to reproduce.
O C. It results in genetically different offspring.
D. It requires only one parent.
Answer: D.
Explanation:
Asexual reproduction requires only one parent, making it more efficient and take a shorter amount of time than sexual reproduction.
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Which of these is a likely impact of stronger than normal trade winds in the Pacific Northwest of the United States?
A. Jet stream would be displaced northwards causing drought
B. Jet stream would be displaced southwards causing drought
C. Jet stream would be displaced southwards causing heavy rain and flooding
D. Jet stream would be displaced northwards causing heavy rain and flooding
I think correct answer is C.Jet stream would be displaced southwards causing heavy rain and flooding
The statement that is a likely impact of stronger than normal trade winds in the Pacific Northwest to the United States is Jet stream would be displaced southwards causing heavy rain and flooding.
Drawing and dialogue please help due tomorrow
Answer:
Gravity will always be pulling everything towards Earth's center at an acceleration of 9.81 m/sec².
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Which climate condition is typically found in the tropics due to the interaction of the atmosphere and hydrosphere?
A.Dry with low humidity
B.Dry with high humidity
C.Wet with high humidity
D.Stormy with low humidity
Answer:
A- Dry with low humidity
Explanation:
The hydrosphere includes the water which is on the surface of the earth, below the ground and in the air.
On analyzing the climatic conditions in the tropics due to the interaction of the atmosphere and hydrosphere, the presence of water droplets in tropics is less resulting in less humidity and, thus the climatic condition is dry.
Therefore the climatic condition that is typically found in tropics due to interaction of the atmosphere and hydrosphere is dry with low humidity.
Hope this helps!
Identify the unit that is used for atomic masses
Answer:
Explanation: Atomic weight is measured in atomic mass units (amu), also called daltons.
You already converted mass to moles for the reactants. Now convert mass to moles for the product, copper. 0.71 g Cu equals moles.
Answer: it wound'nt let me type the equations out so i did it on g.o.o.gl.e docs :')
Explanation:
hope this helps <3
have a great day/night/noon
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You have a block of an unknown metal. Which properties would be most helpful in determining what it is? If it could be
Which element(s) would you expect to behave similarly to Gadolinium? What properties of would you expect to be the same, what would be different?
The elements in the lanthanide series are similar to gadolinium.
The periodic table is arranged in groups and periods. Elements in the same group have similar properties. At the bottom row of the periodic table lies a group of elements that have unique properties called the lanthanides. This is where Gadolinium belongs.
The elements in the lanthanide series such as europium and terbium are similar to gadolinium. The lanthanides are similar in chemical reactivity and appearance. However, the density of the metals differ because it increases with increase in atomic number.
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Seeds Roots Cones Stem Spores Leaves 1. Mongo 2. Moss 3. Ferns 4. Pine Tree 5. Guava 6. Mango 7. Coconut 8. Katakataka 9. Potato 10. Okra 14
The method of propagation of the given organisms is shown below:
1. Mongo ---> seeds
2. Moss ---> spores
3. Ferns ---> stem
4. Pine Tree ---> cones
5. Guava ---> seeds
6. Mango ---> seeds
7. Coconut ---> seeds
8. Katakataka ---> leaves
9. Potato ---> stem
10. Okra ---> seeds
Definition of reproductionRepr0duction is the process by which living organisms produce young ones of their kind.
Repr0duction can either involve two parents through the joining of male and female gametes to produce a zygote i.e. seeds in plants and embryo in animals or can involve only one parent and occurs through vegetative parts such as roots, stem, or leaves.
List of organisms and their propagation partsThe table below gives organisms and their propagation parts:
1. Mongo ---> seed
2. Moss ---> spores
3. Ferns ---> stem
4. Pine Tree ---> cones
5. Guava ---> seeds
6. Mango ---> seeds
7. Coconut ---> seeds
8. Katakataka ---> leaves
9. Potato ---> stem
10. Okra ---> seeds
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Which of the following describes a heterotroph?
Heterotrophs get their energy directly from the sun.
Heterotrophs conduct photosynthesis.
Heterotrophs can create their own food.
Heterotrophs cannot create their own food.
heterotrophs cannot create their own food and rely on others for food
You have 15 grams of of MgSO4, how
many moles of MgSO4 do you have?
A 0.125 Moles of MgSO4
B 0.75 Moles of MgSO4
C 7.5 Moles of MgSO4
D 15.88 Moles of MgSO4
Answer:
C 7.5 Moles of MgSO4
Explanation:
A chemical engineer must be able to predict the changes in chemical concentration in a reaction. dC/dt = -kCn where C is chemical concentration and k is rate constant. Order of reaction is the value of n. The first order reaction that combines tert-butyl bromide and water to produce tert-butyl alcohol and hydrogen bromide is shown below; (CH3)3CBr + H2O (CH3)3COH +HBr From the experimental data, k was estimated to be k = 0.0537 (h -1 ). Determine concentration after 1 hour, if C(0) = 0.2 mol/L
Answer:
Explanation:
Consider the general chemical reaction
[tex]\mathrm{A} \ \overset{k}{\longrightarrow} \ \mathrm{product}[/tex] .
If [A] is the concentration of A (reactant) at any time t and n is the reaction order for the whole equation, the rate is then related to the concentration of reactant A with the following differential form of equation
[tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{n}[/tex] .
where k is the rate constant.
*Note that the differential term [tex]\displaystyle\frac{d[\mathrm{A}]}{dt}[/tex] has a negative sign to denote that the concentration of A is decreasing over time t.
Since the chemical reaction between tert-butyl bromide and water is given to be a first-order reaction, hence n = 1, and the resulting differential equation becomes
[tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{1} \ = \ k[\mathrm{A}][/tex]
To solve this first-order linear homogenous differential equation, the method of separation of variables can be used.
[tex]\-\hspace{1cm} \displaystyle\frac{d[\mathrm{A}]}{dt} \ = -\ k[\mathrm{A}] \\ \\ \-\hspace{0.5cm} \displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = -\ k \, dt \\ \\ \int\ {\displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = \ -\int {k} \, {dt}[/tex]
[tex]\ln{[\mathrm{A}]} \ = \ -kt \ + \ C \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt \ + \ C} \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt}e^{C} \ \ \ \ \ \ \ \ \ (e^{a \ + \ b} \ = \ e^{a}e^{b} \ \ \ \mathrm{by \ the \ law \ of \ indices})[/tex]
Since the term [tex]e^{C}[/tex] is a constant, let [tex]\alpha \ = \ e^{C}[/tex], hence [tex][\mathrm{A}] \ = \ \alpha e^{-kt}[/tex] or [tex]C \ = \ \alpha e^{-kt}[/tex] according to the question. Given that the initial concentration (t = 0) of tert-butyl bromide is 0.2 mol/L and k = 0.0537[tex]\mathrm{h^{-1}}[/tex], so
[tex]0.2 \ = \ \alpha e^{-0.0537 \ \times \ 0} \\ \\ 0.2 \ = \ \alpha \ \ \ \ \ (e^{0} \ = \ 1)[/tex]
Therefore, the rate equation is [tex]C \ = \ 0.2e^{-0.0537t}[/tex].
The concentration of tert-butyl alcohol after 1 hour is
[tex]C \ = \ 0.2e^{-0.0537 \ \times \ 1} \\ \\ C \ = \ 0.2e^{-0.0537} \\ \\ C \ = \ 0.190 \ \mathrm{mol/L} \ \ \ (3 \ \ \mathrm{s.f.})[/tex]
Pls help plz answer this question
Answer:
A) Carbon dioxide and Oxygen
Explanation:
Percentage of gases in the Planet's atmosphere:
Carbon dioxide = 4 % Nitrogen = 72 % Oxygen = 24 %Percentage of gases in the Earth's atmosphere:
Carbon dioxide = 0.036 % (traces)Nitrogen = 78 % Oxygen = 21 %___________________
On observing the percentage composition of the atmospheres of the two Planets, we get:
The newly discovered planet has more percentage of Oxygen than The Earth. Percentage of Carbon dioxide is more in the planet than in the EarthNitrogen is less in the planet than in the Earth.___________________
Answer:
What's asked is the name of the gases that are in higher amounts in the atmosphere of the newly discover planet
Therefore,
A) Carbon dioxide and OxygenPls help!
Describe ionic and covalent bonding.
Give an example of each
Answer:
Example of ionic bonds— Sodium chloride and calcium oxide. Example of covalent bond— Water, carbon
Explanation:
ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.
A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.
For a reversible reaction, what would a large equilibrium constant indicate? Question 9 options: A) At equilibrium, the concentration of the reactants will be much higher than the concentration of the products. B) At equilibrium, the concentration of the products will be about the same as the concentration of the reactants. C) At equilibrium, the concentration of the products will be much higher than the concentration of the reactants. D) At equilibrium, there will be no reactants left because they will all have been turned into products.
true or false a change in state of matter would be considered a physical change
Answer:
true
Explanation:
Because the changes in state of matter would be considered
At what stage of development are fish the most vulnerable?
Answer:
child stage.
Explanation:
they are more vubnlerabke at that stage
Which population will increase?
Answer: World 5,306,425,000 6,895,889,000 7,503,828,180
1 China 1,139,060,000 1,341,335,000 1,384,688,986
2 India 873,785,000 1,224,614,000 1,296,834,042
3 United States 253,339,000 310,384,000 329,256,465
Explanation:
What is the theoretical amount of sodium citrate (Na3C6H5O7) produced if you react 85.0g of citric acid (H3C6H5O7) in excess amount sodium hydroxide? If you actually produced 97.3 g of sodium citrate what is the percent yield?
Answer:
i did not find the amswer sorry
4) If an object is traveling at a speed of 400 m/s, how long (in hours) will it take to reach 950.5 km?
A) 3.96 x 10-2
B) 1.43 x 105
C) 6.34
D) 39.6
E) 7.01 x 10-6
Answer:
Answer: 0.66 hours
Explanation:
[tex]{ \rm{time = \frac{distance}{speed} }} \\ \\ { \rm{time = \frac{(950.5 \times 1000) \: m}{400 \: m {s}^{ - 1} } }} \\ \\ { \rm{time = {2376.25 \: s}}}[/tex]
• Remember 1 second accounts for 1/3600 hours
[tex]{ \rm{time = \frac{2376.25}{3600} }} \\ \\ { \rm{time = 0.66 \: hours}}[/tex]
The time taken by object traveling at a speed of 400 m/s to reach 950.5 km distance is 0.66 hr or 39.6 min.
What is average velocity ?
Average velocity is given by the total distance covered by the object in total given time. SI unit of velocity is m/s.
Here in this question it is given that the object is travelling with speed v of 400 m/s and it is to find the time t to reach 950.5 km distance d.
it is known that 1 km = 1000 m
that is 950.5 km = 950500 m
Now, using the relation of speed-distance to find time t to reach 950.5 km distance :
[tex]\begin{aligned}v&=\frac{d}{t}\\t&=\frac{d}{v}\\&=\frac{950500}{400}\\&=2376.25 \text{ s}\end{aligned}[/tex]
Now converting 2376.25 sec into hrs by dividing it by 3600 we get :
2376.25/3600 = 0.66 hr or 39.6 min.
Therefore, the time taken by object to reach 950.5 km distance is 0.66 hr or 39.6 min.
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explain why soaps are soluble in water but fatty acids are not?
Answer:
Because of the two different parts of the molecule, a soap molecule is soluble in water and at the same time can dissolve fats. The fats are attracted to the non-polar tail part of the soap while the polar head makes the whole complex.
Explanation:
hope it helps
15. Explain the advantage of using spectral analysis in the identification of an elemental
species over that of using FLAME TESTS?
Answer:
to identify the element by using flame tests