Select the correct answer. Imagine a Carnot engine has a hot reservoir of 680 K and a cold reservoir of 220 K. What is the efficiency of the engine

Answers

Answer 1

According to the given statement 67.7%  is the efficiency of the engine.

What is efficiency ?

A comparison of the energy output and input in a particular system is called efficiency in physics (and frequently in chemistry). Its definition is the proportion of output energy to input energy, which is provided by the equation: To describe energy in the form of heat or power, this equation is frequently utilized.

n = 1 - (QC/QH)

n = efficiency

QC = Cold Reservoir = 220 K

QH = Hot Reservoir = 680 K

n = 1 - (220 ÷ 680)(÷10)

n = 1 - (22 - 68) (2)

n = 1 - (11 ÷ 34 )

n = (34 - 11) ÷ 34

n = 23 ÷ 34

n = 0.676 * 100

n = 67.6

Therefore, 67.6% is the efficiency of the engine.

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Related Questions

A 5-ft3 rigid tank contains 5 lbm of water at 20 psia. Determine (a) the temperature, (b) the total enthalpy, and (c) the mass of each phase of water

Answers

After that, we will calculate the temperature, total enthalpy, and masses of each water phase using the steam table.

What are temps and what is its unit?

Given the water's initial mass and pressure, we can determine whether it is superheated or saturated by utilizing a steam table. On a variety of scales, including the Fahrenheit and Celsius systems, temperature is a unit that is used to denote hotness or coolness.

Heat energy will logically go from a hotter (body with a higher temperature) to a colder (body with a lower temperature) according to temperature (one at a lower temperature).

A comparison of a substance's temperature to a set of hot and cold reference values can be used to determine its temperature. The letter "T" stands for "temperature," which is denoted by the SI unit of "°C."

The three scales that are most frequently used to measure temperature are the Celsius scale, the Fahrenheit scale, and the Kelvin scale.

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A student heats 3.55 g of copper and 4.60 g of iodine for 6.25 g of a new compound. All of the iodine reacted, but there is some copper left over unused. How much copper is left?

Answers

The mass of copper that is left unreacted at the end of the chemical reaction is 1.90 g

What mass of copper is left unreacted at the end of the reaction?

The mass of copper that is left untreated at the end of the chemical reaction is determined as follows:

Mass of copper before the reaction = 3.55 g

Mass of iodine before the reaction = 4.60 g

Mass of product = 6.25 g

According to the law of conservation of mass;

Mass of reactant = mass of product + mass of unreacted copper

Mass of reactants = 3.55 + 4.60

Mass of reactants = 8.15 g

The difference in the mass of the product obtained and the mass of the unreacted copper

Mass of unreacted copper = 8.15 g - 6.25 g

Mass of unreacted copper = 1.90 g

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How can you tell which elements will form ions?

Answers

Answer: The position of an element on the periodic table, see resources, tells you the type of ions it will form, with the elements on the right forming anions (negative charge) and those further to the left forming cations (positive charge).

Hope this helps any

Find the y-component of this vector: 22.3 m 77.1° Remember, angles are measured from the +x axis.​

Answers

Answer:

-21.7m

Explanation:

To find the y-component of the vector, we need to find the vertical displacement from the point at the bottom of the vector to the x-axis (or its y-coordinate value).

To calculate this we can create a triangle with the vector as the hypotenuse, the y-axis as the second side and draw an imaginary line from the end of the vector directly horizontally across to the y-axis.

We can use the given angle to find the angle between the y-axis and the angle. Since the angle of a quadrant is 90 degrees, the angle within our triangle must be [tex]90-77.1=12.9[/tex] degrees.

From here, to find the length of the side on the y-axis we can use the trigonometric cos function.

[tex]cos \theta =\frac{adjacent side}{hypotenuse}[/tex]

Therefore [tex]cos 12.9=\frac{y-component}{22.3}[/tex] and [tex]ycomponent = 22.3cos12.9[/tex]

This gives us a value of 21.7 (3.s.f) for our y-component.

Finally, the y-component is also a vector so it also needs a direction. Therefore like its coordinate, its value will be -21.7m.

Turn your head _______ and right and glance over your shoulder to view what cannot be seen in the side-view mirrors. back down left up Submit answer

Answers

Turn your head left and right and glance over your shoulder to view what cannot be seen in the side-view mirrors.

What is mirror ?

An item that reflects an image is a mirror or looking glass. When focused through the lens of the eye or a camera, light that reflects off a mirror will reveal a picture of whatever is in front of it. Mirrors reflect light at an equal but opposite angle, which changes the direction of the image.

What is direction?

Direction can refer to a thing's course, the route one must take to get there in particular, the direction something is beginning to take shape, or the direction you are facing. Going straight instead than left is an example of direction.

Therefore, Turn your head left and right and glance over your shoulder to view what cannot be seen in the side-view mirrors.

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What is the intensity of 60 dB sound?

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The intensity of 60 dB sound is 10⁻⁶ W/m².

A common conversation between two persons seated at a distance of around one meter (3 14 feet) is as loud as 60 dB. It is equivalent to the typical noise level in a restaurant or office.

The decibel scale is a logarithmic one rather than a linear one. Accordingly, 10 dB denotes a sound that is 10 times louder than 0 dB, which represents no sound at all. Now, a sound at 20 decibels is 100 times louder than one at 0 decibels. And so on until a sound that is 100 decibels is 1 billion times louder than total silence (0 decibels).

A sound at 60 dB is therefore 100 times louder than a sound at 40 decibels and 1000 times louder than a sound at 30 decibels, while being 10 times louder than a sound at 50 decibels.

The formula for sound volume is L = log(I/I₀), or (I/I₀) = 10^L.

Given that L = 60dB = 6bel and that we know that I₀ = 10⁻¹² W/m²,

I/I₀ = 10⁶.

or I = 10⁻¹² × 10⁶ = 10⁻⁶ W/m²

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A 65.6 kg ice skater moving to the right with a velocity of 2.65 m/s throws a 0.142 kg snowball to the right with a velocity of 32.7 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball

Answers

The velocity of the ice skater after throwing the snowball is 0.08m/s.

Given data as per the question is,

Mass of ice skater= 65.6kg

Velocity 1= 2.65m/s

Mass of the Snowball= 0.142kg

Velocity 2= 25.2m/s

Conditions before snowball is thrown:

Total mass of skater + snowball = 65.6+ 0.142 = 65.742kg

Total Momentum of skater + snowball = mv = 65.6 x 2.65 = 173.84 kgm/s

Conditions after snowball is thrown:

Let's call the velocity of the skater V.

Total momentum = momentum of skater + momentum of snowball

=65.6V + (4.6434)

= 65.6V + 4.6434

173.84  = 65.6V+4.6434

173.84- 4.6434= 65.6V

169.19=65.6 V

V= 175.156/69.22

V = 2.57m/s

The total momentum after catching the snowball is mV or:

(65.6 + 0.142) x V

So:

4.6434= 65.742V

V= 5.544/69.22

V=0.08m/s

The velocity of the ice skater after throwing the snowball is 0.08m/s

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. Two spherical objects have masses of 8,000 kg and 5.0 kg. Their centers are separated by a distance
of 1.5 m. Find the gravitational attraction between them.

Answers

Two spherical objects have masses of 8000 KG and 1500 KG their centers are separated by a distance of 1.5 M, the gravitational attraction between them is 3.56 × 10⁻⁴N.

How does gravitational force work?

The gravitational force, also known as gravity, pulls objects with mass in the same direction. We frequently think about the Earth's gravitational pull. This force is firmly holding your body in place. But every mass-bearing object attracts other mass-bearing objects toward it through gravity.

Using the formula of gravitational attraction

F = G× M₁M₂/d²

where G = 6.67 × 10⁻¹¹ Nm²Kg⁻²

M₁ = 8000Kg

M₂ = 1500 Kg

F =  6.67 × 10⁻¹¹ × 8000 × 1500 / (1.5)²

F = 3.56 × 10⁻⁴ N

The gravitational force of attraction between them is 3.56 × 10⁻⁴ N.

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An object is dropped from the edge of a cliff and is moving at 26.5 m/s just before it hits the ground. How high is the cliff

Answers

Here initial speed u=0m/s    final speed v=26.5 m/s and acceleration due to gravity g=9.81 m/s^2

Calculation

Where:

m = mass of the object (kg)

g = acceleration due to gravity (9.8 m/s^2)

h = height of the cliff (m)

We know the velocity of the object just before it hits the ground, which is 26.5 m/s. We can use this velocity to calculate the kinetic energy of the object just before it hits the ground.

KE = (1/2)mv^2

As the object is dropped from the cliff, its initial potential energy is converted to kinetic energy. Therefore, the initial potential energy is equal to the final kinetic energy.

GPE = KE

mgh = (1/2)mv^2

We can solve for h by rearranging the equation and substituting the known values for GPE, KE, m, and g.

How can I determine the speed of a falling object before it reaches the ground?

Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt. The item is just traveling downwards when there is a negative sign.

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A unitormly dense, spherical
planet has a mass of 4×1026 kg, as well
as a radius of 53,000 km. It also
happens to also be hollow in the
following way shown. What is the
magnitude of the gravitational field of
the planet at the point P, in N/kg?
Round your answer to two decimal
places.

Answers

The magnitude of the gravitational field of the planet depends on its mass and distance from the object being affected by it.

What is Gravitational field?

Gravitational field is a region of space where a mass or object experiences a force of gravity. It is caused by the presence of a massive object, such as a planet or star, which exerts a gravitational pull on other objects within its vicinity. The strength of the gravitational field is determined by the mass of the object and its distance from other objects.

The gravitational field of the planet at Point P can be calculated by using the equation,

g = G*M/r2

where G is the gravitational constant (6.67 x 10-11 Nm2/kg2), M is the mass of the planet (4 x 1026 kg), and r is the distance from the center of the planet to Point P (53,000 km).

Plugging in the values,

g = (6.67 x 10-11 Nm2/kg2) x (4 x 1026 kg) / (53,000 km)2

g = (6.67 x 10-11 Nm2/kg2) x (4 x 1026 kg) / (2.8409 x 1012 m2)

g = (6.67 x 10-11 Nm2/kg2) x (14.1636 x 1015 kg)

g = 9.5 x 10-5 N/kg

Therefore, the magnitude of the gravitational field of the planet at Point P is 9.50 x 10-5 N/kg.

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How do the overload and progression principles work together for strength training?

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If you are exercising with a specific goal in mind, such as improved strength or cardio fitness. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity.

Your muscles will remain challenged and you'll get stronger if you change or advance your workouts.

To get the most out of any training programme, you must follow certain rules. You won't benefit much from your workouts if you don't adhere to these rules. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity. The concept of specificity is especially important if your exercise programme is designed to help you achieve a particular goal, like increased strength or improved aerobic fitness.

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A baseball bat strikes a ball resting on a tee with a force with a magnitude of 2. 0x10^4 newtons. If the bat stays in contact with the ball for a distance of 5. 0x10^-3 meter, what kinetic energy will the ball acquire from the bat?

Answers

The kinetic energy will the ball acquire from the bat is 1.0x10^1 joules or 100 joules. This calculation is based on the equation Energy = Force x Distance, which is a fundamental equation of physics.

The kinetic energy of the ball is equal to the work done by the bat on the ball. The work done by the bat on the ball is equal to the force applied by the bat multiplied by the distance the bat stays in contact with the ball. Therefore, the kinetic energy of the ball would be equal to 2.0x10^4 newtons multiplied by 5.0x10^-3 meters, which is equal to 1.0x10^1 joules or 100 joules.

This calculation is based on the equation of  Energy which is  Force x Distance. Additionally, this equation can be rearranged to solve for any of the variables, depending on what is known and what needs to be calculated. In this case, the known variables were the force applied by the bat and the distance the bat stayed in contact with the ball, and the variable that needed to be calculated as the kinetic energy of the ball.

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In 1935, a french destroyer , La Terrible , started from rest and accelerates to attain a speed of 93 km/h. Suppose it took 2 minutes for the ship to speed up. Find the ships average acceleration.

Answers

According to the given statement The ships average acceleration is 2790 km/hr².

What is an explain acceleration?

Rate of change in both speed and direction of motion over time. A point or object going straight forward is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because of direction is always shifting

Calculation:

We know that from newton's equation,

v² + u² = 2as

S = ut + 0.5 at²

Where, v = final speed

           u = initial speed

           a = acceleration

           S = distance covered

            t = time taken

Given, u = 0

So the equations becomes:

v² = 2as

S = 0.5 at²

Using these equations we get:

v² = 2a(0.5)at²

v² = a²t²

v = at

v/t = a

Given,  v = 93 km/hr

          t = 2 min = 2/60 hr

Putting these values in above equation we get, a = 2790 km/hr²

So, the ships average acceleration is 2790 km/hr²

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two students are sitting next to each other on chairs with wheels. They push each other and separate in opposite directions. The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s. How fast and in what direction does the other student with a 59-kg mass move?

Answers

The student with a 59-kg mass moves to the right with a velocity of 1.46 m/s.

What is law of conservation of momentum?

According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced.

The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s.

Let the student with a mass of 59 kg moves to the left with a velocity of v m/s.

As no external force applied,

48 kg × 1.8 m/s + 59 kg × v = 0

v = - 1.8 × (48/59) m/s

= - 1.46 m/s.

Hence, the velocity of the second bay is 1.46 m/s in right direct.

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i need help plssssss

Answers

The three key words that have been replaced in the cross - section of a solar panel are:

R - Insulator S - Copper T - Black

This means that Option A is correct.

What are some parts in a solar panel ?

A solar panel, also known as a photovoltaic (PV) panel, is a device that converts sunlight into electricity. It is made up of several different parts that work together to generate electricity. Solar cells are made of silicon and are responsible for converting sunlight into electricity. They are usually arranged in a grid pattern on the panel.

The backsheet is the layer of material that sits on the back of the solar cells. It is responsible for protecting the back of the solar cells from moisture and other environmental factors. It is an insulator and is shown as R.

There are also the copper wires which heat the water and they are painted black as black absorbs heat better. These are labeled S and T respectively.

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A 3.70 -uF capacitor that is initially uncharged is connected in series with a 6.20 -kohms resistor and an emf source with E=130V negligible internal resistance.
A) Just after the circuit is completed, what is the voltage drop across the capacitor?
B) Just after the circuit is completed, what is the voltage drop across the resistor?
C) Just after the circuit is completed, what is the charge on the capacitor?
D) Just after the circuit is completed, what is the current through the resistor?
E) A long time after the circuit is completed (after many time constants) what is the voltage drop across the capacitor?
F) A long time after the circuit is completed (after many time constants) what is the voltage drop across the resistor?
G) A long time after the circuit is completed (after many time constants) what is the charge on the capacitor?
H) A long time after the circuit is completed (after many time constants) what is the current through the resistor?

Answers

A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V, the voltage drop across the resistor is 25.2V, the charge on the capacitor is -7.5μC, and the current through the resistor is 1.6mA.

A) Just after the circuit is completed, the voltage drop across the capacitor is 0V.

B) Just after the circuit is completed, the voltage drop across the resistor is 130V.

C) Just after the circuit is completed, the charge on the capacitor is 0C.

D) Just after the circuit is completed, the current through the resistor is 20.8mA.

E) A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V.

F) A long time after the circuit is completed (after many time constants), the voltage drop across the resistor is 25.2V.

G) A long time after the circuit is completed (after many time constants), the charge on the capacitor is -7.5μC.

H) A long time after the circuit is completed (after many time constants), the current through the resistor is 1.6mA

Just after the circuit is completed, the voltage drop across the capacitor is 0V, the voltage drop across the resistor is 130V, the charge on the capacitor is 0C, and the current through the resistor is 20.8mA. A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V, the voltage drop across the resistor is 25.2V, the charge on the capacitor is -7.5μC, and the current through the resistor is 1.6mA.

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In the video, Dr. Hewitt lifts a bowling ball on a rope to his teeth, then lets go, the ball swings away and returns. What happens the first time Dr. Hewitt lifts the bowling ball near his teeth and lets go?
answer choices
O The ball returns to Dr. Hewitt, stopping almost exactly at the point where it was released.
O The ball leaves Dr. Hewitt and returns to him, going past the point where it was released.
O The ball leaves Dr. Hewitt and returns to him, stopping short of the point where it was released.

Answers

Option 1 is correct choice, The ball returns to Dr. Hewitt, stopping almost exactly at the point where it was released.

Potential energy becomes kinetic energy when a stationary item begins to move. When an item in motion stops moving, its kinetic energy transforms into potential energy.

Here, the energy input from the push is transforming into kinetic energy, which would be later transformed into even more potential energy than the ball had at the beginning of the motion.

The component of swinging is called kinetic energy, and it is the speed at which the ball runs back and forth. The most powerful aspect of swinging is potential energy. The ball achieves more potential energy the higher you go on the swing, so When it comes back to Dr. Hewitt, the ball stops almost exactly where it started.

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Mess Me and You will have nonsense Explain how this riddle relates to mutation in DNA

Answers

Deoxyribonucleic acid is a polymer composed of two polynucleotide chains that coil around each other to form a double helix.

What makes a nonsense mutation nonsense?

A nonsense mutation occurs in the DNA when a sequence changes itself and gives rise to a stop codon rather than a codon specifying an amino acid. The presence of the new stop codon results in the production of a shortened protein that is non-functional.

A nonsense mutation is also known as base substitution which results in a stop codon in such a position from where there was not one before, which causes the premature termination of protein synthesis and, more than likely, a complete loss of function in the finished protein.

So we can conclude that a nonsense mutation always causes a loss of amino acids.

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When using a 20 ft ladder how far from a building should the base of the ladder be?

Answers

When using a 20 ft ladder the distance from a building should be the base of the ladder by 5 ft

The base of a ladder should be positioned one-quarter of the working length of the ladder from the building. Therefore, when using a 20 ft ladder, the base should be positioned 5 ft from the building. Additionally, the ladder should be placed on a solid and level surface, and the feet of the ladder should be securely wedged to prevent slipping.

Extend the top of the ladder three feet above the work table to get access to it, or fasten the ladder at the top.

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A 74 kg student, starting from rest, slides down an 11.8 meter high water slide. What is his kinetic energy at the bottom of the slide

Answers

The kinetic energy of the student at the bottom of the slide with a velocity of 15.21 m/s is 8,557.36 J

The mass of the student = 74 kg

The distance of the slide = 11.8 m

The final velocity at the bottom of the slide can be found using

             v² = u² + 2ax

where v is the final velocity

          u is the initial velocity

          a is the acceleration due to gravity

          x is the distance

Let us substitute the known values,

            v² = 0 + 2 x 9.8 x 11.8

            v² = 231.28

                = √231.28

             v = 15.21

Therefore, the kinetic energy at the bottom of the slide is

         K.E = 1/2mv²

                = 1/2 x 74 x 231.28

                = 8,557.36 J

The kinetic energy of the student is 8,557.36 J

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A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. What minimum coefficient of static friction is required

Answers

A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.

To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.

The centrifugal force acting on the child is given by:

= Fc

= m * r * w^2

where

= m

= 50.0 kg (mass of child)

= r

= 2.70 m (radius of the merry-go-round)

= w

= 3.95 rad/s (angular velocity)

So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2

= 6629.775 N

The force of friction acting on the child is given by:

= Ff

= friction coefficient * normal force

where

friction coefficient = minimum coefficient of static friction required (unknown)

= normal force

= m * g

The normal force is equal to the weight of the child, which is

= m * g

= 50.0 kg * 9.8 m/s^2

= 490 N

So, Ff = friction coefficient * 490 N

To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:

friction coefficient = Ff / N

friction coefficient = 6629.775 N / 490 N

= 13.56

So the minimum coefficient of static friction required is 13.56.

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For the charge distribution provided, indicate the region (a to e) along the horizontal axis where a point exists at which the net electric field is zero. (figure 1) if no such region exists on the horizontal axis choose the last option (nowhere). View available hint(s)

Answers

The region (A to E) along the horizontal axis where a point exists at which the net electric field is zero is point C.

An electric field refers to the physical field surrounding electrically charged particles which exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles. It is defined as the electric force per unit charge. The field direction is taken as the direction of the force it would exert on a positive test charge. The direction of the electric field is always away from the positive charge and towards the negative charge. As seen in the diagram, both positive charges are equidistant from region C, and the strength of charges of the particle is the same in magnitude but opposite in direction, so the net electric field of both charges will be zero in region C.

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A new way of "multiplying" two vectors is introduced in this chapter. What is it called? Select one: O a. The tensor product. O b. The angular product. Oc. The scalar product. O d. The dot product. O e. The cross product.

Answers

The correct option is option e) cross product

The cross-product is a new way of "multiplying" two vectors. It results in a new vector that is perpendicular to both the original vectors and its magnitude is given by the area of the parallelogram formed by the two original vectors.

In three-dimensional space, cross-product is a binary operation on two vectors. It yields a vector perpendicular to both vectors. a b represents the vector product of two vectors, a and b. Its resulting vector is parallel to a and b. Cross goods are another name for vector products.

The cross-product has four basic applications:

calculating the angle () between two vectorsdetermining a vector normal to a planecalculating the moment of a force about a pointcalculating the moment of a force about a line.

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What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface

Answers

According to the question linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface is 30.682× [tex]10^{10}[/tex].

What does orbit mean?

Astronomically speaking, an orbit is the curved path—typically elliptical—that a planet, satellite, comet, etc. takes when it revolves around another celestial body as a result of gravitation.

By Newton's second law

GMm/[tex]r^{2}[/tex] m[tex]v^{2}[/tex] /r.

Since the radius of Earth is 6.37 × [tex]10^{6}[/tex] m,

the orbit radius is r=(6.37×[tex]10^{6}[/tex] m+204×[tex]10^{3}[/tex] m)=1.3×[tex]10^{3}[/tex] m.

The solution for v is

v= [tex]\sqrt{\frac{GM}{r} }[/tex]​ ​ = (6.67×[tex]10^{-11}[/tex]× 5.98×[tex]10^{24}[/tex]/1.3×[tex]10^{3}[/tex])^1/2

⇒ v= 30.682× [tex]10^{10}[/tex]

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Two springs have spring constants of 10.0 N/cm and 15.0 N/cm. Which spring is more difficult to stretch

Answers

The spring with the higher spring constant (15.0 N/cm) will be more difficult to stretch than the spring with the lower spring constant (10.0 N/cm).

This is because the spring constant is directly related to the amount of force required to stretch the spring. Therefore, the higher the spring constant, the more force that is required to stretch the spring.

The spring constant is a measure of how difficult it is to stretch or compress a spring. It is determined by the stiffness of the spring material, its shape and size, and how much the spring is compressed or stretched.

The higher the spring constant, the more force is required to stretch or compress the spring. The lower the spring constant, the less force is required to stretch or compress the spring.

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Dina is observing a sample of copper metal after it was removed from a flame. She noticed that the temperature decreased. What conclusions could she draw from this observation?

a-The average kinetic energy decreased.

b-The average kinetic energy remained the same.

c-The motion of the particles increased.

d-The motion of the particles stayed the same.

Answers

Answer:

A. The average kinetic energy decreased.

Explanation:

When an object gains heat, which is a form of energy, the atoms within the object would in turn gain energy in the form of kinetic energy. Similarly, as the temperature of an object decreases, in other words losing heat energy, the atoms within the object would lose kinetic energy as a result.

A 1. 5-mole sample of an ideal gas is gently cooled at constant temperature 320 K. It contracts

from initial volume 19 L to final volume V2. A total of 1. 2 kJ of heat is removed from the gas during the contraction process. What is V2? Let the ideal-gas constant R = 8. 314 J/(mol. K).

Answers

A mole sample of an ideal gas is gently cooled at constant temperature 320 K.

What happens when gas is cooled at constant temperature?Since the internal energy of an ideal gas is proportional to temperature, it does not change when the temperature is held constant. The first law, which governs changes in internal energy, changes to 0 = Q - W, resulting in Q = W. Both the temperature and the volume of the gas decrease as it cools at a constant pressure. The fundamental behaviour of fluids with respect to volume, pressure, and temperature is described by Boyle's, Charles', and Gay Lussac's Laws. When heat is applied at constant pressure, some of it is utilised to cause gas to expand while the remainder is used to raise the gas' temperature, which increases the gas' internal energy.

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20 points! I was thinking B.) Scatter plot but want to check.

A student collected data about the speed of an object over time.

Which type of graph should the student use to represent the data?

Responses

circle graph
scatterplot

histogram

bar graph

Answers

You would definitely be using a scatter plot to measure the speed of an object over time. You will never see a velocity vs time graph as anything other than that. The other options are more the type of graphs you will see in studies or statistic classes.

Why do we calculate torque?

Answers

Torque is one of the key ideas to comprehend in order to solve problems with rotational motion. Torque is the tendency of a force to produce or change rotational motion.

Why is torque calculation important?

Torque is a measure of an engine's capacity to control a load and generate a certain level of power to turn the engine on its axis. which is an important part of an automobile engine's power-generating process. Per foot (ft) of rotation about a single point, the force is expressed in pounds (lb).

Why does the torque exist?

The force that can cause an object to revolve around an axis is measured in torque. In linear kinematics, force causes an item to accelerate, and torque causes an object to produces the angular acceleration of an object. A vector quantity is a torque.

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replace the force system acting on the post by a resultant force and couple moment at point o

Answers

By replacing the force system acting on the post with a resultant force and a couple of moments at point o we get total momentum of 1478.85 ft-lb.

As per the figure we have 3 forces: At the top 300lb left side 150lnb and at the middle 200lb.

first, we have to break down the forces into x and y components.

Now calculating each force separately:

∑Fₓ=300lb+cos 30°-150×4/3+200

=259.81-120+200

∑Fₓ=339.81lb.

Now, calculate the sum of y components.

∑Fy=300 sin 30°+150×3/5

∑Fy=300 sin 30°+90

∑Fy=240lb

Now we have to x and y components by these values we can find the actual force.

|F|=√Fx²+Fy²

|F|=√(339.81)²+(240)²                     α=tan⁻¹(∑Fₓ/∑Fy)

|F|=√115470.83+57600                      α=tan⁻¹(339.81/240)

|F|=√173070                                       α=35.23°

|F|=416.02 and 35.23°

the sum of moments at O

∑Mo=-Fx₃×2+Fx₂×4-Fx₁×6

∑Mo=-200(2)+4/5 150*4-3000cos30°(6)

∑Mo=-400+480-277.65

         =1478.85ftlb

∑Mo=1478.85ftlb

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