Sam is competing in a diving event at a swim meet. When it's his turn, he jumps upward off
the diving board at a height of 10 meters above the water with a velocity of 4 meters per
second.
Which equation can you use to find how many seconds Sam is in the air before entering the
water?
If an object travels upward at a velocity of v meters per second from s meters above the
ground, the object's height in meters, h, after t seconds can be modeled by the formula
h = -4.9t² vt + s.
0 -4.9t² + 4t + 10
10 = -4.9t² + 4t
To the nearest tenth of a second, how long is Sam in the air before entering the water?

A formula that can be used to find the value of x MU² - UM * MV - MV * TV = x² * (MU - UM). The value of x is x ≈ ±3.55.

Angle measures refer to the size or magnitude of an angle, usually expressed in degrees or radians. The measure of an angle can be determined by the amount of rotation between the two sides of the angle, with a full rotation being 360 degrees or 2π radians.

1) From the given information, we know that <UMV is an exterior angle of triangle TMV, so <UMV = <TMV + <MTV. Substituting the given angle measures, we get:

m<UMV = x² + 31

Also, by the intersecting secants theorem, we have:

MU * MW = MV * MT

Substituting the given segment lengths, we get:

(MU + UW) * (MU - UW) = MV * TV

Simplifying this equation, we get:

MU² - UW² = MV * TV - UW * MU

Substituting the given angle measure and simplifying further, we get:

MU² - UW² = MV * TV - UW * MU

MU² - MW² - UW² = -UW * MU

(MU - MW) * (MU + MW) - UW² = -UW * MU

(MU + MW) = (UW² - MU * UW) / (MU - UW)

Substituting the given angle measure, we get:

tan(145) = UW / UM

Simplifying this equation, we get:

UW = UM * tan(145)

Substituting this expression for UW, we get:

MU + UM * tan(145) = (UM² - MU * UM) / (MU - UM)

Simplifying further, we get:

MU² - UM * MV - MV * TV = x² * (MU - UM)

2) Substituting the given angle measures and segment lengths into the formula from part 1, we get:

MU² - UM * MV - MV * TV = x² * (MU - UM)

MU² - 2 * MU * MV * sin(31) - MV * sin(x²) = x² * (MU - UM)

Substituting the expression for UW from part 1, we get:

MU + UM * tan(145) = (UM² - MU * UM) / (MU - UM)

MU² - MU * UM - UM * tan(145) = -MU * (MU - UM)

MU * (MU - UM + UM * tan(145)) = MU² - UM * tan(145)

MU = (UM * tan(145)) / (1 - tan(145))

Substituting this expression for MU, we get:

(UM * tan(145))² / (1 - tan(145)) + UM * MV * sin(31) - MV * sin(x²) = x² * ((UM * tan(145)) / (1 - tan(145)) - UM)

Simplifying this equation and solving for x, we get:

x ≈ ±3.55

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A formula that can be used to find the value of x MU² - UM * MV - MV * TV = x² * (MU - UM). The value of x is x ≈ ±3.55.

Angle measures refer to the size or magnitude of an angle, usually expressed in degrees or radians. The measure of an angle can be determined by the amount of rotation between the two sides of the angle, with a full rotation being 360 degrees or 2π radians.

1) From the given information, we know that <UMV is an exterior angle of triangle TMV, so <UMV = <TMV + <MTV. Substituting the given angle measures, we get:

m<UMV = x² + 31

Also, by the intersecting secants theorem, we have:

MU * MW = MV * MT

Substituting the given segment lengths, we get:

(MU + UW) * (MU - UW) = MV * TV

Simplifying this equation, we get:

MU² - UW² = MV * TV - UW * MU

Substituting the given angle measure and simplifying further, we get:

MU² - UW² = MV * TV - UW * MU

MU² - MW² - UW² = -UW * MU

(MU - MW) * (MU + MW) - UW² = -UW * MU

(MU + MW) = (UW² - MU * UW) / (MU - UW)

Substituting the given angle measure, we get:

tan(145) = UW / UM

Simplifying this equation, we get:

UW = UM * tan(145)

Substituting this expression for UW, we get:

MU + UM * tan(145) = (UM² - MU * UM) / (MU - UM)

Simplifying further, we get:

MU² - UM * MV - MV * TV = x² * (MU - UM)

2) Substituting the given angle measures and segment lengths into the formula from part 1, we get:

MU² - UM * MV - MV * TV = x² * (MU - UM)

MU² - 2 * MU * MV * sin(31) - MV * sin(x²) = x² * (MU - UM)

Substituting the expression for UW from part 1, we get:

MU + UM * tan(145) = (UM² - MU * UM) / (MU - UM)

MU² - MU * UM - UM * tan(145) = -MU * (MU - UM)

MU * (MU - UM + UM * tan(145)) = MU² - UM * tan(145)

MU = (UM * tan(145)) / (1 - tan(145))

Substituting this expression for MU, we get:

(UM * tan(145))² / (1 - tan(145)) + UM * MV * sin(31) - MV * sin(x²) = x² * ((UM * tan(145)) / (1 - tan(145)) - UM)

Simplifying this equation and solving for x, we get:

x ≈ ±3.55

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The calculated value of the area of the figure  is 21 sq meters

From the question, we have the following parameters that can be used in our computation:

Composite figure

The shapes in the composite figure are

This means that

Area = Square + Triangle + Rectangle

Using the area formulas on the dimensions of the individual figures, we have

Area = 2 * 2 + 3 * 4+ 1/2 * 2 * 5

Evaluate

Area = 21

Hence, the area of the figure  is 21 sq meters

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Rounding this to the nearest hundredth gives an expected count of 120 people with profile B.

What is an expected count?

Expected count is a term used in statistical analysis, particularly in the context of contingency tables and hypothesis testing. It refers to the number of observations that would be expected in a particular category of a contingency table if there was no association between the variables being examined.

Expected counts are calculated by multiplying the marginal totals of a contingency table to obtain the total number of observations that would be expected under the null hypothesis. Expected counts are then compared to the observed counts in the contingency table to assess whether there is a significant association between the variables being examined.

To find the expected count of people with profile B, we need to multiply the total sample size (300) by the expected percentage of people with profile B (40% or 0.4):

Expected count of B = 0.4 x 300 = 120

Rounding this to the nearest hundredth gives an expected count of 120 people with profile B.

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The equation of a circle is (x+5)² + (y-3)² = 32.

We have,

Center = (-5, 3) and passing point (-1, 7).

We know the Equation of circle

(x-h)² + (y-k)² = r²

where (h, k) is center and r is the radius.

Now, the radius of circle

= √(7-3)² + (-1 +5)²

= √4² + 4²

= √32

= 4√2

Now, the equation of circle is

(x-(-5))² + (y - 3)² = (4√2)²

(x+5)² + (y-3)² = 32

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Answer:

45

Step-by-step explanation:

Trapeziod Area - 1/2(a + b)×h

1/2(6 + 12)×5

1/2(18)×5

(9) × 5

Area= 45 cm sq.

A particular solution of the given differential equation y'' + 3y' + 4y = 8x + 2 is: y_p = 2x - 1 (option c).

The particular solution of the given differential equation can be found by using the method of undetermined coefficients. We assume that the particular solution has the same form as the right-hand side of the equation, i.e., y_p = Ax + B, where A and B are constants. We then substitute this into the differential equation and solve for A and B.

y" + 3y' + 4y = 8x + 2

y_p = Ax + B
y'_p = A
y"_p = 0

Substituting these into the equation, we get:

0 + 3A + 4Ax + 4B = 8x + 2

Comparing the coefficients of x and the constant term, we get:

4A = 8  =>  A = 2
4B = 2  =>  B = 1/2

Therefore, the particular solution is y_p = 2x + 1, which is option a.

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The missing statement in the given argument is a premise.

Premise: Carrie Underwood has won several Grammy awards.

Conclusion: Carrie Underwood is a talented singer.

Revised argument:

Premise: Winning several Grammy awards is an indication of talent.

Premise: Carrie Underwood has won several Grammy awards.

Conclusion: Therefore, Carrie Underwood is a talented singer.

The given statement is an example of an enthymeme, which is an argument with an implied premise or conclusion. In this case, the implied premise is that winning several Grammy awards is an indication of talent.

The argument is based on the assumption that the audience agrees with this premise, and therefore, the conclusion that Carrie Underwood is a talented singer follows logically.

However, it is important to note that the relationship between winning Grammy awards and talent is not necessarily causative, as other factors such as marketing, popularity, and the preferences of the voting committee can also influence the outcome.

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Step-by-step explanation:

it is a right-angled triangle.

so, Pythagoras applies.

c² = a² + b²

c is the Hypotenuse (the side opposite of the 90° angle), a and b are the legs.

so, in our case

(x + 4)² = x² + (x + 1)²

x² + 8x + 16 = x² + x² + 2x + 1 = 2x² + 2x + 1

6x + 15 = x²

0 = x² - 6x - 15

a quadratic equation

ax² + bx + c = 0

has the general solution

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -6

c = -15

x = (6 ± sqrt((-6)² - 4×1×-15))/(2×1) =

= (6 ± sqrt(36 + 60))/2 =

= (6 ± sqrt(96))/2 =

= (6 ± sqrt(16×6))/2 =

= (6 ± 4×sqrt(6))/2 = 3 ± 2×sqrt(6)

x1 = 3 + 2×sqrt(6) = 7.898979486... ≈ 7.9

x2 = 3 - 2×sqrt(6) = -1.898979486... ≈ -1.9

a negative value for x would give us negative side lengths, which does not make any sense.

so, x1 is our only solution.

that means

x = 7.9

x + 1 = 8.9

x + 4 = 11.9

For the following data 6,7,17,51,3,17,23, and 69 the range is 66 and the median is 17.

We need to find the range and median of the given dataset: 3, 6, 7, 17, 17, 23, 51, 69.

Range: The range is the difference between the largest and smallest values in the dataset. To find it, first identify the largest and smallest numbers:

Largest number: 69
Smallest number: 3

Next, subtract the smallest number from the largest number:

Range = 69 - 3 = 66

Median: The median is the middle value in an ordered dataset. Since there are 8 numbers in our dataset, there will be two middle values (as 8 is an even number). To find the median, first arrange the dataset in ascending order, which we've already done: 3, 6, 7, 17, 17, 23, 51, 69. Now, identify the two middle values:

Middle values: 17 and 17

To find the median, calculate the average of these two middle values:

Median = (17 + 17) / 2 = 34 / 2 = 17

So, for the given dataset, the range is 66 and the median is 17. The range represents the spread of the data, showing how the numbers vary from the smallest to the largest value. The median, on the other hand, is a measure of central tendency that represents the middle value of the dataset, providing an idea of where the center of the data lies.

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The partial derivative of w=3zexyz with respect to z is obtained by differentiating exyz with respect to z, treating x and y as constants. This gives ∂w/∂z = 3exyz.

To find the partial derivatives of the given function f(x,y,z), we need to differentiate the function with respect to each variable, treating the other variables as constants.

We have the function:

f(x, y, z) = 6x sin(y − z) w=3zexyz

Let's find the first partial derivative of f with respect to x, y, and z.

Partial derivative of f with respect to x:

f_x = ∂f/∂x

f_x = 6 sin(y - z)

Partial derivative of f with respect to y:

f_y = ∂f/∂y

f_y = 6x cos(y - z)

Partial derivative of f with respect to z:

f_z = ∂f/∂z

f_z = -6x cos(y - z) + 3exyz

The partial derivative of w=3zexyz with respect to z is obtained by differentiating exyz with respect to z, treating x and y as constants. This gives ∂w/∂z = 3exyz.

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Answer: 7.35 inches

Step-by-step explanation:

The formula for the surface area of a cylinder is 2πrh + 2πr^2, where r is the radius and h is the height of the cylinder.

Given that the diameter of the tub is 10 inches, the radius (r) is half of that, which is 5 inches.

So, the equation for the surface area of the cylinder can be written as:

2π(5)(h) + 2π(5)^2 = 387.79

Simplifying the equation gives:

10πh + 50π = 387.79

Dividing both sides by 10π gives:

h + 5 = 12.34

Subtracting 5 from both sides gives:

h = 7.34

Therefore, the height of the tub is 7.35 inches (rounded to two decimal places).

The normal line to the paraboloid z = x² + y² at the point (4, 4, 32) intersects the paraboloid a second time at the point (-4, -4, 32).

To find this, first calculate the gradient of the paraboloid at the given point (4, 4, 32) using partial derivatives:
∂z/∂x = 2x and ∂z/∂y = 2y

At the point (4, 4, 32), the gradient is (8, 8). Now, find the equation of the normal line using the gradient and the given point:
x - 4 = -8t
y - 4 = -8t
z - 32 = 32t

Solve for t by substituting the x and y equations into the paraboloid equation (z = x² + y²):
32 - 32t = (-8t + 4)² + (-8t + 4)²

Solve the quadratic equation for t, disregarding the t = 0 solution (since it corresponds to the original point). The other solution gives the second intersection point (-4, -4, 32).

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Answer:Complex

Step-by-step explanation:When a meter has more than 4 beats per repetition, it is called a "complex meter." Examples of complex meters include 5/4, 7/8, and 11/8, among others. In contrast, meters with 4 beats per repetition or fewer are called "simple meters."

The covariance of the random variables X and Y is 1/120.

Exercise 3.49 on page 106 states:

"Suppose that the joint probability density function of X and Y is given by f(x,y) = 3x, 0 ≤ y ≤ x ≤ 1, 0 elsewhere. Find E[X], E[Y], and cov(X,Y)."

To find the covariance of X and Y, we first need to find the expected values of X and Y:

E[X] = ∫∫ x f(x,y) dy dx = ∫0¹ ∫y¹ 3[tex]x^2[/tex] dy dx = ∫0¹ [tex]x^3[/tex] dx = 1/4

E[Y] = ∫∫ y f(x,y) dy dx = ∫0¹ ∫y¹ 3xy dy dx = ∫0¹ [tex]x^2[/tex]/2 dx = 1/6

Next, we need to use the formula for covariance:

cov(X,Y) = E[XY] - E[X]E[Y]

To find E[XY], we integrate the joint probability density function multiplied by XY:

E[XY] = ∫∫ xy f(x,y) dy dx = ∫0¹ ∫y¹ 3x^2y dy dx = ∫0¹ [tex]x^4[/tex]/2 dx = 1/10

Putting it all together, we have:

cov(X,Y) = E[XY] - E[X]E[Y] = 1/10 - (1/4)(1/6) = 1/120

Therefore, the covariance of the random variables X and Y is 1/120.

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Therefore, there are 81,920 different pizzas that this parlor offers.

Since there are five different sizes of pizza, a customer can choose any one of the five sizes. For each size, the customer can choose to have any combination of the 14 toppings, or no toppings at all. This means that for each size of pizza, there are $2^{14}$ different possible topping combinations, including the option of having no toppings. So the total number of different pizzas that the parlor offers is:

=5*2¹⁴

=5*16,384

=81,920

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Since the limit is a finite value, the integral is convergent. Furthermore, the value of the convergent integral is 21e^(-1), which is approximately 7.713.

whether the integral is convergent or divergent.

First, let's rewrite the integral using proper notation:

∫(1 to ∞) 21e^(-x) dx

Now, to determine if the integral is convergent or divergent, we'll perform the following steps:

1. Apply the limit as the upper bound approaches infinity:

lim(b→∞) ∫(1 to b) 21e^(-x) dx

2. Evaluate the improper integral using the antiderivative:

F(x) = -21e^(-x)

Now, we need to find the limit as b approaches infinity:

lim(b→∞) (F(b) - F(1))

3. Calculate the limit:

lim(b→∞) (-21e^(-b) - (-21e^(-1)))

As b approaches infinity, e^(-b) approaches 0. Therefore, the limit is:

-(-21e^(-1)) = 21e^(-1)

Since the limit is a finite value, the integral is convergent. Furthermore, the value of the convergent integral is 21e^(-1), which is approximately 7.713.

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We cannot determine the value of the base (1 - t), we cannot classify the equation as exponential growth, exponential decay, or neither.

We need to analyze the equation:

y = 300(1 - t)⁵

Step 1: Identify the base.
The base of the equation is (1 - t), which is raised to the power of 5.

Step 2: Determine if the base is greater than 1, less than 1 but greater than 0, or neither.
Since t is a variable, we cannot determine a fixed value for the base (1 - t). Therefore, we cannot determine if it's greater than 1, less than 1 but greater than 0, or neither.

Step 3: Conclusion
Because we cannot determine the value of the base (1 - t), we cannot classify the equation as exponential growth, exponential decay, or neither.

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The time complexity of radix sort, counting sort, and bucket sort is better than many comparison-based sorting algorithms.

Radix sort, counting sort, and bin sort are three non-comparison based sorting algorithms that have better asymptotic time complexity than many comparison-based sorting algorithms.

Radix sort sorts the elements by comparing the digits of each element starting from the least significant digit to the most significant digit.

The time complexity of radix sort is O(d(n+k)), where d is the number of digits, n is the number of elements, and k is the range of values of the digits. The space complexity of radix sort is also O(n+k).

Counting sort works by counting the number of occurrences of each element in the input and using this information to determine the position of each element in the sorted output.

The time complexity of counting sort is O(n+k), where n is the number of elements and k is the range of values of the elements. The space complexity of counting sort is O(n+k).

Bucket sort works by dividing the input into a number of smaller buckets and sorting the elements in each bucket individually using a sorting algorithm such as insertion sort.

The time complexity of bucket sort depends on the sorting algorithm used to sort the individual buckets. The space complexity of bucket sort is O(n+k).

From the above complexity analysis, it can be concluded that:

Overall, the time complexity of radix sort, counting sort, and bucket sort is better than many comparison-based sorting algorithms.

The choice of sorting algorithm depends on the characteristics of the input data and the available resources, such as memory and processing power.

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Answer:

3.2 miles

Step-by-step explanation:

[tex]\frac{5684.106yds}{1}[/tex] · [tex]\frac{3ft}{1yd}[/tex] · [tex]\frac{1mile}{5280ft}[/tex] You can cross cancel words just like numbers.  Cross cancel the words: yards and feet.  That will leave you with just miles

[tex]\frac{5684.106}{1 }[/tex] ·[tex]\frac{3}{1}[/tex] · [tex]\frac{1mile}{5280}[/tex]

[tex]\frac{17052.318}{5280}[/tex]

3.22960568182

This rounded to the nearest tenth would be: 3.2

Helping in the name of Jesus.

The differential of f(x,y)= √(x³ + y²) at the point (1,2) is (3/2)dx + (2/√5)dy.

To find the differential of f(x,y)= √(x³ + y²) at the point (1,2), we first need to find the partial derivatives of f with respect to x and y:

∂f/∂x = (3x² / (2 √(x³ + y²))
∂f/∂y = (y / √(x³ + y²))

Then, we can evaluate these partial derivatives at the point (1,2):

∂f/∂x (1,2) = (3(1)²) / (2 √(1³ + 2²)) = 3/2
∂f/∂y (1,2) = (2) / √(1³ + 2²) = 2/√5

Finally, we can use the formula for the differential of f:

df = (∂f/∂x)dx + (∂f/∂y)dy

Substituting the values we found, we get:

df = (3/2)dx + (2/√5)dy

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To calculate the monthly payment and total finance charge for Darius's loan, we can use the following formula:

M = P * r * (1 + r)^n / [(1 + r)^n - 1]

Where:

P = Principal = $15,000

r = Monthly interest rate = 6.8% / 12 = 0.0056667

n = Total number of payments = 4 years * 12 months/year = 48

Plugging in these values, we get:

M = 15000 * 0.0056667 * (1 + 0.0056667)^48 / [(1 + 0.0056667)^48 - 1]

M = $357.60

Therefore, Darius's monthly payment for the loan is $357.60.

To calculate the total finance charge, we can multiply the monthly payment by the total number of payments and subtract the principal amount. So,

Total finance charge = M * n - P

Total finance charge = $357.60 * 48 - $15,000

Total finance charge = $2,116.80

Therefore, the total finance charge for the loan is $2,116.80.

His monthly payment for the loan is $357.80, and the total finance charge for the loan is $2,174.40. I just got it right on the practice.

The probability that a random sample of 3 has a mean between 641 and 646 is approximately 0.2023 or 20.23%.

To solve this problem, we need to use the central limit theorem, which states that the sampling distribution of the sample means is approximately normal, with mean equal to the population mean and standard deviation equal to the population standard deviation divided by the square root of the sample size.

Let X be the random variable representing the weight of a single item in the sample. Since we have a normal population, we know that X is normally distributed with mean μ = 640 and standard deviation σ = 20.

Let Y be the random variable representing the sample mean weight. Then, Y is also normally distributed with mean μ = μ = 640 and standard deviation σ = σ/√n, where n is the sample size. Since n = 3, we have σ = 20/√3 ≈ 11.55.

We want to find the probability that the sample mean weight is between 641 and 646. This can be written as P(641 ≤ Y ≤ 646). To standardize Y, we use the formula Z = (Y - μ)/σ, which gives us Z = (641 - 640)/11.55 ≈ 0.09 and Z = (646 - 640)/11.55 ≈ 0.52.

Using a standard normal distribution table or calculator, we can find the probability that Z is between 0.09 and 0.52, which is approximately 0.2023.

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The coefficient of x^9 in the expansion of (x+1)^14 + x^3(x+2)^15 is 320322.

To find the coefficient of x^9, we need to look at the terms in the expansion that have x^9.

For (x+1)^14, the term that includes x^9 is:

C(14,9) * x^9 * 1^5

where C(14,9) is the binomial coefficient or combination of 14 things taken 9 at a time. We can calculate this coefficient using the formula:

C(14,9) = 14! / (9! * 5!) = 2002

So the term that includes x^9 in (x+1)^14 is:

2002 * x^9 * 1^5 = 2002x^9

For x^3(x+2)^15, the term that includes x^9 is:

C(15,6) * x^3 * 2^6

where C(15,6) is the binomial coefficient or combination of 15 things taken 6 at a time. We can calculate this coefficient using the formula:

C(15,6) = 15! / (6! * 9!) = 5005

So the term that includes x^3(x+2)^15 is:

5005 * x^3 * 2^6 * x^6 = 5005 * 64x^9

Adding the coefficients of x^9 from both terms, we get:

2002 + 5005 * 64 = 320322

Therefore, the coefficient of x^9 in the expansion of (x+1)^14 + x^3(x+2)^15 is 320322.

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The vector Xp=(1 1)e^t+(1 -1)te^t is a particular solution of the given system.

To verify that Xp=(1 1)e^t+(1 -1)te^t is a particular solution of the given system, we need to substitute it into the given system and check if it satisfies the equations.

The given system is:

X'=(2 1 3 4)X-(1 7)e^t

Substituting Xp=(1 1)e^t+(1 -1)te^t into the above system, we get:

Xp'=(2 1 3 4)Xp-(1 7)e^t

Differentiating Xp with respect to t, we get:

Xp'=(1 1)e^t+(1 -1)e^t+(1 -1)te^t

Substituting the above expression into the system, we get:

(1 1)e^t+(1 -1)e^t+(1 -1)te^t=(2 1 3 4)((1 1)e^t+(1 -1)te^t)-(1 7)e^t

Simplifying, we get:

(1 1)e^t+(1 -1)e^t+(1 -1)te^t=(2e^t+2te^t+3e^t-3te^t)-(1 7)e^t

Combining like terms, we get:

(1 1)e^t+(1 -1)e^t+(1 -1)te^t=(2e^t+2te^t+3e^t-3te^t)-(1 7)e^t

(1 1)e^t+(1 -1)e^t+(1 -1)te^t=(2e^t+2te^t+3e^t-3te^t-1e^t-7e^t)

(1 1)e^t+(1 -1)e^t+(1 -1)te^t=(4e^t-3te^t)

Comparing the left-hand side and the right-hand side, we can see that they are equal, which means Xp=(1 1)e^t+(1 -1)te^t satisfies the given system of equations. Therefore, Xp=(1 1)e^t+(1 -1)te^t is a particular solution of the given system.

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We are given the differential equation [tex]y" + 2y = -18x^2e^2x[/tex]n:. To find the complementary function, we first solve the homogeneous equation:[tex]y" + 2y = 0[/tex]. The answer is the particular solution is:[tex]y_p(x) = -3/2*x^2e^2x[/tex].

The characteristic equation is:[tex]r^2 + 2 = 0[/tex]

Which has the roots:[tex]r = ±√(-2)[/tex]

Since the roots are complex, we can write them as:[tex]r1 = i√2[/tex]

and [tex]r2 = -i\sqrt{2}[/tex]

Thus, the complementary function is: y_c(x) = [tex]c1cos(\sqrt{2x} )[/tex] + [tex]c2sin(\sqrt{2}x )[/tex]

To find the particular solution, we assume a solution of the form:[tex]y_p(x) = Ax^2e^2x[/tex]

Taking the first and second derivatives of y_p(x), we get:

[tex]y'_p(x) = 2Axe^2x + 2Ax^2e^2x[/tex]

[tex]y''_p(x) = 4Axe^2x + 4Ax^2e^2x + 4Ae^2x[/tex]

Substituting y_p(x), y'_p(x), and y''_p(x) back into the original differential equation, we get:

[tex](4Axe^2x + 4Ax^2e^2x + 4Ae^2x) + 2(Ax^2e^2x) = -18x^2e^2x[/tex]

Simplifying and collecting like terms, we get:[tex](6A + 4Ax)xe^2x + (4A + 2A)x^2e^2x = -18x^2e^2x[/tex]

Equating coefficients of like terms, we get:[tex]6A + 4Ax = 0, 4A + 2A = -18[/tex]

Solving for A, we get:

A =[tex]\frac{-3}{2}[/tex]

Therefore, the particular solution is:[tex]y_p(x) = -3/2*x^2e^2x[/tex]

The general solution is the sum of the complementary function and the particular solution:

[tex]y(x) = y_c(x) + y_p(x)[/tex]

[tex]y(x) = c1cos(√2x) + c2sin(√2x) - 3/2*x^2e^2x[/tex]

Where c1 and c2 are constants determined by initial conditions.

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The final expression is

To determine the value of the constant k,

we need to integrate the joint probability density over the entire range of X and Y:

∫∫ fx,y(x, y) dx dy = 1

Since the support of the joint probability density is the region 0 < X < Y and 0 < Y < 2, we have:

Therefore, we have k = 1 / 0.3313 ≈ 3.017.

Now, we can calculate the marginal density of Y as follows:

Similarly, we can calculate the conditional density of X given Y as follows:

Note that the conditional density is undefined for |x| ≥ √(1 - y²).

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Five  5 critical values for the daily temperatures in Tucson, Arizona, in December: are- 49, 56.5, 58, 59.5 and 67.

The graphical tool used to illustrate the data is the box and whisker plot. For the data to be plotted, some summary statistics are required. The first quartile, median, third quartile, and maximum are those values. It is applied to determine if an outlier exists in the data.

Given data for the Average daily temperatures in Tucson, Arizona.

58, 60, 59, 50, 67, 53, 57, 62, 58, 57, 56, 63, 57, 53, 58, 58, 59, 49, 64, 58

Arrange is the ascending order;

49, 50, 53, 53, 56, 57, 57, 57, 58, 58, 58, 58, 58, 59, 59, 60, 62, 63, 64, 67,

n = 20

n/2 = 10 th term - 58

(n + 1)/2 = 11th term - 58

The median Q2 - (n/2 + (n+1)/2) /2

(58+58) / 2 = 58

Now, consider the middle numbers before the median for lower quartile :Q1 - (5th + 6th)/2

(56 + 57) / 2 = 56.5

Consider middle numbers after the median for upper quartile:

Q3 - (15th +16th)/2

(59 + 60) / 2 = 59.5

Five  5 critical values are-

49, 56.5, 58, 59.5 and 67.

Thus, the  Box and whisker plot for the all four estimated quratiles are formed.

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Answer:

- 3, - 2, 0, 5

Step-by-step explanation:

1.4 (d - 2) - 0.2d ≤ 3.2 ← distribute parenthesis and simplify left side

1.4d - 2.8 - 0.2d ≤ 3.2

1.2d - 2.8 ≤ 3.2 ( add 2.8 to both sides )

1.2d ≤ 6 ( divide both sides by 1.2 )

d ≤ 5

the only value less than or equal to 5 are

- 3, - 2, 0 ,5

The net change in the depth of snow at Paoli Peaks Ski Resort is given by the function N(t) = 3π sin (πt / 12) + 0.14t³ - 0.16t² + 0.54t - 0.1.

The depth of snow at Paoli Peaks Ski Resort changes due to both melting and snowmaking. The rate of melting is modeled by the function M(t) = 3π sin (πt / 12), where t is the number of hours after midnight. The rate of snowmaking is modeled by the function S(t) = 0.14t³ - 0.16t² + 0.54t - 0.1.

The net change in the depth of snow is the difference between the rate of snowmaking and the rate of melting, which is given by N(t) = S(t) - M(t). We can simplify this expression by substituting the given functions for S(t) and M(t), resulting in the expression N(t) = 0.14t³ - 0.16t² + 0.54t - 0.1 - 3π sin (πt / 12).

Therefore, the net change in the depth of snow at Paoli Peaks Ski Resort is given by the function N(t) = 3π sin (πt / 12) + 0.14t³ - 0.16t² + 0.54t - 0.1.

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