Qu 4.
How many protons, neutrons, and electrons are present in an atom of gold, Au,
with a mass number of 197?
197 protons, 276 neutrons, 79 electrons
79 protons, 118 neutrons, 79 electrons
Du Do
79 protons, 197 neutrons, 118 electrons
&
118 protons, 72 neutrons, 118 electrons

Answer:

1) clouds 2) quick 3) near 4) levels 5)nucleus 6) two 7) eight 8) eighteen 9) pairs 10) properties

Explanation:

hope i helped!

Answer:

1. clouds

2. quick

3. near

4. levels

5. nucleus

6. two

7. eight

8. eighteen

9. pairs

10. properties

Answer:

c

Explanation:

bacteria can be a single cell and archaebacteria live in the human body

Answer:

c

Explanation:

Answer:

metal and non metal-electrovalent

Answer:

w = d x f

Explanation:

hope it helps u

Answer:

[tex]\boxed {\boxed {\sf A. \ About \ 5.14 *10^{24} \ molecules \ H_2O}}[/tex]

Explanation:

To convert from moles to units, we must use Avogadro's Number: 6.022 * 10²³

This tells us the number of units (molecules of water in this problem) in 1 mole of a substance (water). We can use it as a ratio or fraction.

[tex]\frac{6.022 *10^{23} \ molecules \ H_2O}{1 \ mol \ H_2 O}[/tex]

Now, we can multiply this fraction by the moles of water (8.54) given.

[tex]8.54 \ mol \ H_2O*\frac{6.022 *10^{23}\ molecules \ H_2O}{1 \ mol \ H_2 O}[/tex]

When we multiply, the moles of water will cancel out.

[tex]8.54 *\frac{6.022 \ molecules \ H_2O}{1 \ }[/tex]

Since the fraction has a 1 as a denominator, we can remove it. The problem will be a simple multiplication problem.

[tex]8.54*6.022 \ molecules \ H_2O[/tex]

[tex]5.142788*10^{24} \ molecules \ H_2O[/tex]

The original measurement of 8.54 has 3 significant figures (8, 5, and 4). Therefore, we must round our answer to 3 sig figs, which is the hundredth place in this case.

The 2 in the thousandth place tells us to leave the 4 in the hundredth place.

[tex]5.14 *10^{24} \ molecules \ H_2 O[/tex]

There are about 5.14*10²⁴ molecules of water in 8.54 moles.

Answer:

5.14 x 10^24 molecules of H2O.

Explanation:

just took the test

Answer:

Poor Science

Explanation:

I took the quiz also just think that doesn't seem like a good, higher level scientist, or popular one, SO THERE YOU GUYS GO!!!

Answer:

poor science

Explanation:

500 mL of He at 98 kPa expands to 750 mL. Find P2.

P₂ = 65.3 kPa

Given

V₁=500 ml

P₁=98 kPa

V₂=750 ml

Required

P₂

Solution

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

[tex]\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}[/tex]

Input the value :

[tex]\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_1=\dfrac{98.500}{750}\\\\P_2=65.3~kPa[/tex]

Answer:

Pasteurization involves heating liquids at high temperatures for short amounts of time, it can make it better if you wanted hot cocoa but bad for milk

Explanation:

Answer:

Pasteurization kills harmful microbes in milk without affecting the taste or nutritional value

Explanation:

Answer:

Mass = 0.35 g

Explanation:

Given data:

Mass of sodium = 8.0 g

Mass of hydrogen produced = ?

Solution:

Chemical equation:

2Na + 2H₂O     →    2NaOH + H₂

Number of moles of sodium:

Number of moles = mass/molar mass

Number of moles = 8.0 g/ 23 g/mol

Number of moles = 0.35 mol

now we will compare the moles of sodium and hydrogen

             Na           :           H₂

             2             :            1

           0.35          :      1/2×0.35 = 0.175 mol

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 0.175 mol × 2 g/mol

Mass = 0.35 g

Answer:

3. P and N

Explanation:

Since they are in the same family group on the periodic table (the elements in vertical lines), they are the most similar. Hope this helps!

Answer:

3. P and N

Explanation:

Both elements are in the same group, sharing the most similar properties.

Answer:monoprotic

Explanation:

Answer:

well it might be 1.)Cadmium Fluoride CdF2 150.4078

2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403

3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714

Explanation:

Answer:

During the process of polymerization, monomers

combine by sharing electrons. This process forms a polymer, which is made of repeating subunits. The resulting material is used in a variety of ways.

Answer:

monomers and polymer.

Explanation:

Explanation:

hope it helpful ✌️✌️

Answer:

“spinoff”

Explanation:

Here is just a sampling of the many “spinoff” technologies, as NASA refers to them, resulting from space research and development that we now use in everyday life.

Answer:

forms of mercury

Explanation:

Answer:

Explanation:

Mercury is an element and a metal that is found in air, water, and soil.Mercury rarely occurs uncombined in nature, but can be found as droplets in cinnabar (mercury sulfide) ores. China and Kyrgyzstan are the main producers of mercury. The metal is obtained by heating cinnabar in a current of air and condensing the vapour.

hope this helps! Have a good day or night! :)

Answer:

7

Explanation:

ATOMIC NUMBER IS NUMBER OF PROTONS

PROTONS have positive charge

Answer:

7

Explanation:

sorry i accidentally put a 2 first

Answer:

billion is larger \ part if billion

Answer:

the most common oxidation no.of manganese is +2 +3 +4 +6 +7

Answer:Answer to: A function f is defined on the interval ~[0,4], and its derivative is { e^{sinx} - 2cos3x } a. on what interval is f increasing? b....

Missing

Explanation:

Answer:

37,818.67 m3

Explanation:

The pressure a gas will exert on a container is inversely proportional to the volume of the gas. According to Boyle's law, at a constant temperature, the pressure of a gas is inversely proportional to its volume. The law can be mathematically represented thus:

   P1V1 = P2V2

In this case, P1 = 101.3 kPa, V1 = 28,000 m3, P2 = 75 kPa, V2 = ?

V2 = P1V1/P2

         =    101.3 x 28,000/75

                = 37,818.67 m3

Hence, the new volume of the air inside the cabin after pressurizing would be 37,818.67 m3.

Fractional distillation

Answer:

PubChem CID 6393

Structure  

Find Similar Structures

Chemical Safety  

Compressed Gas

Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula CF4

Molecular Weight  

88.004 g/mol

Explanation:

Answer:

ΔG =   18KJ/mol

Explanation:

Given data:

ΔS = 0.09 Kj/mol.K

ΔH = 27 KJ/mol

Temperature  = 100 K

ΔG = ?

Solution:

Formula:

ΔG = ΔH - TΔS

ΔH = enthalpy

ΔS = entropy

by putting values,

ΔG =  27 KJ/mol - 100K(0.09 Kj/mol.K)

ΔG =  27 KJ/mol - 9 KJ/mol

ΔG =   18KJ/mol

Answer:

[tex]\boxed {\boxed {\sf C. \ More \ protons \ are \ present \ in \ the \ atomic \ nucleus}}[/tex]

Explanation:

First, let's define atomic number.

    ⇒ The number of protons in an atom.

    ⇒ This number determines the identity and properties of the atom

So, atomic number relates to protons. There is an increase in atomic number, so there must be more protons in the atom. We can eliminate choices A and B, because they pertain to electrons.

We are left with choices C and D. The difference between them is the location of the protons.

Protons are part of the nucleus of the atom: the dense, central region of the atom comprised of nucleons: protons and neutrons.

Electrons, not protons, orbit the nucleus, so  D is not correct.

We are left with choice C: more protons are present in the atomic nucleus

Answer:

option 1. Two substances in a mixture differ in density and particle size. These properties can be used to separate the substances. These properties can be manipulated in order to have a better separation between the two substances.

Explanation:

Answer:

Two substances in a mixture differ in density and particle size. These properties can be used to separate both of them using the separating funnel or using filtration (filter paper).

Explanation:

Since their densities are different, one substance should float above the other in the mixture which allows for the separating funnel to let the substance sinking below (with the heavier density) to flow out first before changing the beaker to let the lighter substance flow out.

The substance with a bigger particle size would not be able to pass through the filter paper unlike the substance with the smaller particle size as the filter paper's pores is not big enough for it to pass through, separating both substances (with one on the paper and the other outside the filter paper, preferably in the beaker placed below the paper).