Consider the following equation.
-(3/2)^x+12 = 2x- 3
Approximate the solution to the equation above using three terations of successive approximation. Use the graph below as a starting point.
A. X=35/8
B. X=33/8
C. X=69/16
D. X=71/16
The solution of the graph is approximately
D. X=71/16What is solution of the graphThe solution of a graph depends on the type of graph and the problem being represented. In general, a solution of a graph refers to a point or set of points that satisfy the conditions or constraints of the problem.
For the problem, the solution of the graph is the point where the two graphs intersects.
Deducing from the graph this is at point x approximately 4.455 the closest value to this point in the option is x = 71/16
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How many solutions does the equation sin(4x) = 1/2 have on the interval
(0, 2π]?
The equation sin(4x) = 1/2 has two solutions on the interval (0, 2π]: x = π/24 and x = 5π/24.
The equation sin(4x) = 1/2 has two solutions on the interval (0, 2π].
The first solution occurs when 4x = π/6, or x = π/24. This corresponds to an angle of π/24 radians, or 7.5°.
The second solution occurs when 4x = 5π/6, or x = 5π/24. This corresponds to an angle of 5π/24 radians, or 112.5°.
Therefore, the equation sin(4x) = 1/2 has two solutions on the interval (0, 2π]: x = π/24 and x = 5π/24.
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The five number summary of a dataset was found to be:
0, 5, 8, 16, 20
An observation is considered an outlier if it is below:
-11.5
Correct
An observation is considered an outlier if it is above:
32.5
Correct
That's correct. An observation is considered an outlier if it is more than 1.5 times the interquartile range (IQR) above the third quartile (Q3) or below the first quartile (Q1).
How to further determine the value?The IQR is the difference between Q3 and Q1:
IQR = Q3 - Q1
In this case, the first quartile Q1 is 5 and the third quartile Q3 is 16. So the IQR is:
IQR = Q3 - Q1 = 16 - 5 = 11
An observation is considered an outlier if it is more than 1.5 times the IQR above Q3 or below Q1.
To find the upper outlier bound, we add 1.5 times the IQR to Q3:
Upper outlier bound = Q3 + 1.5(IQR) = 16 + 1.5(11) = 32.5
So any observation above 32.5 is considered an outlier.
To find the lower outlier bound, we subtract 1.5 times the IQR from Q1:
Lower outlier bound = Q1 - 1.5(IQR) = 5 - 1.5(11) = -11.5
So any observation below -11.5 is considered an outlier.
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Which of the following is equal to
OA. Speed
OB. Displacement
OC. Velocity
OD. Acceleration
distance
time
SUBI
Answer:b
Step-by-step explanation:
tammy spends $15 each time she travels the toll roads. she started the mount wit $210 in her toll road account. the amount, A( in dollars), that she has left in the account after t trips on the toll roads is given by the following function
Work sheet is pretty hard giving 20 points
Part A: The Table for the data set above and it's title are attached accordingly.
Part B:
1) The shortest marker in the data set is Marker 1, which has a length of 4.00 inches.
2) The longest marker in the data set is Marker 14, which has a length of 6.75 inches.
3) The range of the data set is 2.75 inches, calculated by subtracting the shortest marker (4.00 inches) from the longest marker (6.75 inches).
4) To find the median, we need to arrange the data set in order from smallest to largest:
4.00, 4.25, 4.75, 5.00, 5.00, 5.25, 5.50, 5.50, 5.625, 6.00, 6.25, 6.25, 6.25, 6.50, 6.75
The median is the middle value, which is 5.50 inches.
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Name:___________ Period:___
6-1 Populations & Samples
LT: I can ________________________________________________
_______________________________________________________.
Population: An ________ group of objects - _________, _________, _____________ - from which _________ can be collected.
Sample: A _____________ of the ______________.
Why use a sample?
When you ask a ____________ question about a _____________, it is often more efficient to gather data from a _____________ of the ______________.
Representative Sample: Accurately reflects the _________________ of the entire ______________.
(It has the __________ characteristics as the _________________.)
Random Sample:
→ Each ___________ of the population has an _________ chance of being ____________.
→ Tends to be a ___________________ __________of a population.
How might you generate a random sample? Step 1:
Step 2:
Step 3:
Step 4:
Step 5:
Use the Pythagorean theorem to find the unknown side of the right triangle.
I need help please
Answer:
[tex]\boxed{17}[/tex]
Step-by-step explanation:
Pythagorean theorem:
[tex]c^2=a^2+b^2[/tex]
where:
[tex]c=[/tex] hypothenuse
[tex]a=[/tex] the small size of the triangle
[tex]b=[/tex] the large size of the triangle
In this problem, we have the values of a and b, so:
[tex]c^2=(8)^2+(15)^2\\c^2=64+225\\c^2=289\\\sqrt{c^2}=\sqrt{289}\\ c=17[/tex]
Therefore the value of the unknown side of the triangle is 17.
Hope it helps.
[tex]\text{-B$\mathfrak{randon}$VN}[/tex]
A STUDY OF INTERIOR DESIGNERS OPIONIONS WITH RESPECT TO THE MOST DESIRABEL PRIMARY COLOR FOR EXECUTIVE OFFICES SHOWED THE FOLLOWING
The probability that a designer does not prefer red is 0.77. The Option 2 is correct.
What is probability?Probability is a measure of how likely an event is to happen. Probability is represented as a fraction and always lies between 0 and 1.
The total number of opinions is:
= 92 + 86 + 46 + 91 + 37 + 46 + 2
= 400
The number of designers who do not prefer red is the sum of the opinions for all colors except red:
= 86 + 46 + 91 + 37 + 46 + 2
= 308
Therefore, the probability that a designer does not prefer red is:
= 308/400
= 0.77.
Full question "A study of interior designers' opinions with respect to the most desirable primary color for executive offices showed that:
Primary Color Number of Opinions
Red 92
Orange 86
Yellow 46
Green 91
Blue 37
Indigo 46
Violet 2
What is the probability that a designer does not prefer red? 1.00 0.77 0.73 0.23".
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Faber Kozlowski had 6 times as much money as Theriault Luigi. After Faber Kozlowski spent 1/3 of his money and Theriault Luigi spent 4/5 of his money, they had a total of $1155 left.
(a) How much money did Faber Kozlowski and Theriault Luigi have altogether at first?
(b) Theriault Luigi spent 3/4 of his remaining money on a hoodie. What fraction of his original amount of money did he spend on the hoodie?
Answer:
Step-by-step explanation:
Let's use variables to represent the amount of money each person had at first.
Let x be the amount of money that Theriault Luigi had.
Then, according to the problem, Faber Kozlowski had 6 times as much money as Theriault Luigi, which means Faber Kozlowski had 6x dollars.
After Faber Kozlowski spent 1/3 of his money, he had 2/3 of his money left, which is (2/3)(6x) = 4x dollars.
After Theriault Luigi spent 4/5 of his money, he had 1/5 of his money left, which is (1/5)x dollars.
Together, they had a total of $1155 left, which means:
4x + (1/5)x = 1155
Multiplying both sides by 5 to eliminate the fraction gives:
20x + x = 5775
Combining like terms gives:
21x = 5775
Dividing both sides by 21 gives:
x = 275
Therefore, Theriault Luigi had $275 at first, and Faber Kozlowski had 6 times as much, which is $1650 at first.
So, the answer to (a) is $275 + $1650 = $1925.
For (b), Theriault Luigi spent 3/4 of his remaining money on a hoodie, which means he spent (3/4)(1/5)x = 3/20 of his original amount of money on the hoodie.
Therefore, Theriault Luigi spent 3/20 of his original amount of money on the hoodie.
Answer:
(a) $1925
(b) 15%
Step-by-step explanation:
(a)
Let f = original amount of money Faber had.
Let t = original amount of money Theriault had.
"Faber Kozlowski had 6 times as much money as Theriault Luigi. "
f = 6t
"After Faber Kozlowski spent 1/3 of his money"
He has now: 2/3 f
"and Theriault Luigi spent 4/5 of his money"
He has now: 1/5 t
"they had a total of $1155 left"
2/3 f + 1/5 t = 1155
f = 6t
2/3 f + 1/5 t = 1155
2/3 (6t) + 1/5 t = 1155
4.2t = 115
t = 1155/4.2
t = 275
f = 6t = 6(275) = 1650
f + t = 275 + 1650 = 1925
Part (a) answer: $1925
(b)
Original amount: t = 275
He first spent 4/5 of the original amount, so he had 1/5 left.
275/5 = 55
He spent 3/4 of $55 on the hoodie.
3/4 × $55 = $41.25
$41.25/$275 × 100% = 15%
Part (b) answer: 15%
brainest if correct look at picture
Answer:
i'm pretty sure its c, but if not then sorry
Step-by-step explanation:
Answer:
The equation of the line in the point-slope form is y+3=2/3(x−5)
Step-by-step explanation:
B
The last 48 boat rentals at a boat rental company were 26 sunfish, 6 kayaks, and 16 rowboats. Use this information to complete parts (a) through (c).
a) Determine the empirical probability that the next boat rental is a sunfish.
b) Determine the empirical probability that the next boat rental is a kayak.
c) Determine the empirical probability that the next boat rental is a rowboat.
The answer is , (a) Empirical probability of sunfish rental = 0.5417 or 54.17% , (b) Empirical probability of kayak rental = 0.125 or 12.5% , (c) Empirical probability of rowboat rental = 0.3333 or 33.33% .
What is Empirical probability?Empirical probability is an estimate of the probability of an event based on the frequency of its occurrence in a sample of data. It is calculated by dividing the number of times the event occurred by the total number of observations in the sample. Empirical probability is often used when there is no theoretical probability available, or when the theoretical probability is difficult to calculate or unknown. It is a useful tool in fields such as statistics, finance, and machine learning.
a) The empirical probability that the next boat rental is a sunfish is the number of sunfish rentals divided by the total number of rentals:
Empirical probability of sunfish rental = number of sunfish rentals / total number of rentals
Empirical probability of sunfish rental = 26 / 48
Empirical probability of sunfish rental = 0.5417 or 54.17%
b) The empirical probability that the next boat rental is a kayak is the number of kayak rentals divided by the total number of rentals:
Empirical probability of kayak rental = number of kayak rentals / total number of rentals
Empirical probability of kayak rental = 6 / 48
Empirical probability of kayak rental = 0.125 or 12.5%
c) The empirical probability that the next boat rental is a rowboat is the number of rowboat rentals divided by the total number of rentals:
Empirical probability of rowboat rental = number of rowboat rentals / total number of rentals
Empirical probability of rowboat rental = 16 / 48
Empirical probability of rowboat rental = 0.3333 or 33.33%
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Find the missing angle measure. Show work.
17.
7
20
24
Solve the remaining parts of the triangle.
19.
B
38
12.5 C
7
13
17.
18.
19, AC=
AB-
mzB
Need help with all these please. Asap urgent help need this done before Monday
To find the missing angle measure, we need to use the fact that the sum of angles in a triangle is 180 degrees. Let's denote the missing angle as x. We know that one angle is 38 degrees and another angle is 12.5 degrees.Therefore, the missing angle measure is 129.5 degrees.
By subtracting these two angles from 180 degrees, we get:
180 - 38 - 12.5 = 129.5
Without additional information, it is not possible to determine the remaining parts of the triangle. We would need the lengths of at least one side or the measures of other angles to solve for the missing parts.
The given information states that AC is equal to AB minus mzB. Without knowing the values of AB and mzB, we cannot determine the exact length of AC. We would need additional information to solve for the length of AC.Therefore, the missing angle measure is 129.5 degrees.
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The graph of a quadratic function F has zeros of -8 and four and a maximum at -2, 18 what is the value of “a” in the function equation?
Answer:
Since the given quadratic function has zeros of -8 and 4, we know that the factors of the quadratic equation are (x + 8) and (x - 4).
The maximum of the function occurs at the midpoint between the zeros, which is (-8 + 4)/2 = -2. So, the x-coordinate of the vertex is -2.
We also know that the y-coordinate of the vertex is 18. So, the vertex of the quadratic function is (-2, 18).
Using the vertex form of the quadratic function, we can write:
F(x) = a(x + 2)^2 + 18
Since the function has zeros of -8 and 4, we can write:
F(x) = a(x + 8)(x - 4)
a(x + 2)^2 + 18 = a(x + 8)(x - 4)
ax^2 + 6ax - 128a - 576 = ax^2 + 16ax - 32a
10ax - 96a - 576 = 0
10a(x - 6) = 0
a = 0 or x = 6.
Since the vertex is a maximum and the coefficient of the x^2 term is positive, we know that a > 0. Therefore, we can conclude that x = 6 and a = 3.
Hence, the value of "a" in the function equation is 3.
What do you know about this data before finding the range or the interquartile range?
187, 191, 202, 209, 218, 1984
The values are not in order.
The outlier will have no affect on the range.
The data has an outlier, therefore the interquartile range is much greater than it would be without the outlier.
The data has an outlier, therefore the range will be much greater than it would be without the outlier.
Answer:
D. The data has an outlier, therefore the range will be much greater than it would be without the outlier.
Step-by-step explanation:
The given data consists of six values, ranging from 187 to 1984. The numbers are not listed in order. There is an obvious outlier value, 1984, which is potentially impacting the spread and central tendencies of the data. However, without calculating the range or interquartile range, it is difficult to determine the extent of its impact.
Answer:
d got it right in edge.
Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of importance to the company is
the carrying load of the lumber. The company has tested 34 beams using the new glue, recording for each beam the pressure (in pounds per square foot) at
which the beam breaks. The data collected are presented in the following frequency distribution.
Carrying load
(in pounds per square foot)
860 to 879
880 to 899
900 to 919
920 to 939
940 to 959
Frequency
5
9
12
6
2
Based on the frequency distribution, using the midpoint of each data class, estimate the mean carrying load of the beams tested. For your intermediate
computations, use four or more decimal places, and round your answer to one decimal place.
Based on the given frequency distribution, the estimated mean carrying load of the beams tested is approximately 904.2 pounds per square foot.
Estimate the mean carrying load of the beams tested.To estimate the mean carrying load of the beams tested, we need to find the weighted average of the midpoints of each data class.
First, we need to find the midpoint of each class interval. We can do this by taking the average of the lower and upper limits of each interval:
Midpoint of 860 to 879 = (860 + 879) / 2 = 869.5
Midpoint of 880 to 899 = (880 + 899) / 2 = 889.5
Midpoint of 900 to 919 = (900 + 919) / 2 = 909.5
Midpoint of 920 to 939 = (920 + 939) / 2 = 929.5
Midpoint of 940 to 959 = (940 + 959) / 2 = 949.5
Next, we can find the weighted average of these midpoints, using the frequencies as weights. We can set up a table to organize our calculations:
Data class Midpoint Frequency Midpoint x Frequency
860-879 869.5 5 4,347.5
880-899 889.5 9 8,005.5
900-919 909.5 12 10,914
920-939 929.5 6 5,577
940-959 949.5 2 1,899
Total 34 30,743.5
To find the weighted average, we divide the sum of the products in the last column by the total frequency:
Weighted average = Sum of (Midpoint x Frequency) / Total frequency
Weighted average = 30,743.5 / 34
Weighted average ≈ 904.2
Therefore, based on the given frequency distribution, the estimated mean carrying load of the beams tested is approximately 904.2 pounds per square foot.
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What is the value of sin-1(1)?
ㅠ
0 -플
ㅇㅇ
ㅇ플
ㅇ TT
Answer:
Step-by-step explanation:arcsin(1) = pi/2
i need help with this trig question part A and B
Answer:
Part A: ∠A ≈ 27.7 °
Part B: c ≈ 8.75
Step-by-step explanation:
Part A:
Use the Law of Cosines.
Cosθ =
[ a² + b² - c² ] / [ 2ab ]
Sub in all the information where θ is A.
A = cos⁻¹ { [10² + 7² - 5²] / [2×10×7]
A ≈ 27.7 ° (1 decimal place)
Part B:
Use the Law of Cosines, but instead the unknown is the side c.
Rearrange to isolate c:
c² = a² + b² - 2ab×cosθ
c = √(5² + 6² - 2×5×6×cos(105°))
c ≈ 8.75 (2 decimal places)
One leg of a right triangle is 14 centimeters longer than the other leg. The length of the is 26 centimeters. What are the lengths of the legs?
The length of the shorter leg is 6 centimeters, and the length of the longer leg is x + 14 = 20 centimeters.
Explanation:
Let x be the length of the shorter leg of the right triangle.
According to the problem, the longer leg is 14 centimeters longer than the shorter leg, so its length is x + 14.
We also know that the length of the hypotenuse of the right triangle is 26 centimeters.By the Pythagorean theorem, we have:
x^2 + (x + 14)^2 = 26^2
Simplifying the left side:
x^2 + x^2 + 28x + 196 = 676
Combining like terms:
2x^2 + 28x - 480 = 0
Dividing by 2:
x^2 + 14x - 240 = 0
Factoring:
(x + 20)(x - 6) = 0
Therefore, x = -20 or x = 6.
Since the length of a side cannot be negative, we reject x = -20 and conclude that x = 6.
So the length of the shorter leg is 6 centimeters, and the length of the longer leg is x + 14 = 20 centimeters.
Please solve As soon as possible.
Answer:
-|x|+1
Step-by-step explanation:
Solve in order 10 points
A) The speed of the object is 6.71 units per second.
B) , the equation of the line is y = -3x + 9
C) The magnitude of the resultant force is 4.36N
How can one compute the above?a) The position of the object at time t is given by:
(x, y) = (4, -3) + t (-3 , 6)
v = (dx/ dt, dy/dt) = (-3, 6)
So the velocity vector is ( -3, 6).
For speed of the object, we need to find the magnitude of the velocity vector....
|v| = √((-3)^2 + 6^2)
= √(45)
= 3 √(5)
= 6.71 units
B
The equation given as (x, y) = (4, -3) + t (-3, 6)
Written in form of y=mx + b we have:
y = -3 t + 9
Thus,
EQuation is y = -3x + 9
C)
The angle between the two forces can be calculated as 90 ° - 30° = 60°.
To find the magnitude of the resultant force using the law of cosines, we can use the formula.....
c ² = a ² + b ² - 2ab cos(C)
In this case, we have...
a = 3N
b = 5N
C = 60 degrees
c ² = 3 ² + 5 ² - 2(3)(5) cos(60)
c ² = 9 + 25 - 30(0.5)
c ² = 19
c = √(19)
c = 4.35889894354
c ≈ 4.36
So it is right to state that the magnitude of the resultant force is 4.36N
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The federal government recently granted funds for a special program designed to reduce crime in high-crime areas. A study of the results of the program in eight high-crime areas of Miami, Florida, yielded the following results.
Number of Crimes by Area: A, B, C, D, E, F, G, H
Before: 14, 7, 4, 5, 17, 12, 8, 9
After: 2, 7, 3, 6, 8, 13, 3, 5
Has there been a decrease in the number of crimes since the inauguration of the program? Use the .01 significance level.
a. What is the p-value?
The p-value method yields P (T > 2.119) = 0.0359. It may be said that, at a 1% level of significance, there has been no decline in crime since the program's inception.
Explain about the Paired T-Test:The observations for the paired t-test are drawn from a single random pair sample. There are the same number of observations in both samples. Each respondent has two observations for the experimental variable recorded.
The alternative is:
[tex]H_{0} =[/tex]: Since the program's launch, there has been no drop in the number of crimes.
The alternate theory is that:
[tex]H_{a} =[/tex] Since the start of the programme, fewer crimes have been committed.
Mathematically,
[tex]H_{0} =[/tex] μo = 0
[tex]H_{a} =[/tex] μd > 0
Given table:
Number of Crimes Before After d = (before - after) d²
A 14 2 14-2 = 12 14² = 144
B 7 7 17 - 7 = 0 0² = 0
C 4 3 4 - 3 = 1 1² = 1
D 5 6 5 - 6 = -1 -1² = 1
E 17 8 17-8 = 9 9² = 81
F 12 13 12 - 13 = -1 -1² = 1
G 8 3 8 - 3= 5 5² = 25
H 9 5 9 -5 = 4 4² = 16
Total 8 29 269
The formula for the t statistic is:
t = ∑d / √[n(∑d²) - (∑d)²] / (n - 1)
t = 29 / √[8*269 - 29²] / (8 - 1)
t = 2.119
As a result, the test statistic's value is 2.119.
8 – 1 Equals 7 degrees of freedom.The p-value method yields P (T > 2.119) = 0.0359.The p-value is inconsequential since it exceeds the specified significance level of 0.01 in this case.
This indicates that at a 1% level of significance, the null hypothesis cannot be ruled out.
As a result, it may be said that, at a 1% level of significance, there has been no crime decline in since the program's inception.
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A trail mix recipe asks for 4 cups of raisins for every 6 cups of peanuts. There is proportional relationship between the amount of raisins, r (cups), and the amount of peanuts, p (cups), in this recipe. Write the equation for the relationship that has constant of proportionality greater than 1.
Answer:
r/p = 2
Step-by-step explanation:
The proportional relationship between the amount of raisins and the amount of peanuts can be expressed as:
r/p = k
where k is the constant of proportionality.
To find an equation with a constant of proportionality greater than 1, we simply need to choose a value of k that is greater than 1. For example, if we choose k = 2, the equation becomes:
r/p = 2
To check that this equation is correct, we can use the original ratio of 4 cups of raisins for every 6 cups of peanuts:
4/6 = 2/3
This confirms that the constant of proportionality is indeed 2, and that the equation for the relationship with a constant of proportionality greater than 1 is:
r/p = 2
What is the measure of <7 in degrees
A. Cannot be determined
B. 74
C. 16
D. 32
The measurement of angle Y which is a twin angle will be equal to 116 degrees which is option A.
What is an Isosceles Triangle?
The triangle which has any two sides equal in length is called as Isosceles Triangles. Also the two angles which is opposite to the equal sides are equal and third angle is unequal. The unequal side which is present is called the base of the triangle. Measurement of the altitude can be done from base to the vertex (which is topmost) of the triangle.
Here, the value of angle X is given 32 degree.
Therefore the value of angle Z will also be 32 degree (due to the property of isosceles triangle)
By angle sum property:
X+Y+Z=180
32+Y+32=180
Therefore, Y = 116 degree
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Suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive.
What is the probability that the number will be more than 6 or odd? (Enter your probability as a fraction.)
Start by putting the possible integers your friend can select
[tex]\text{S}=\{1,2,3,4,5,6,7,8,9,10\}[/tex]
Then, call the 2 possible events as A and B, and what are the possible integers in each event:
A = Be more than 6
B = The number is odd
[tex]\text{A}=\{7,8,9,10\}[/tex]
[tex]\text{B}=\{1,3,5,7,9\}[/tex]
The probability of the union of two events can be calculated as:
[tex]\text{P}(\text{A}\cup\text{B})=\text{P(A)}+\text{P(B)}-P(\text{A}\cap\text{B})[/tex]
Then,
[tex]\text{P(A)}=\dfrac{\text{number of elements in A}}{\text{number of elements in S}}[/tex]
[tex]\text{P(A)}=\dfrac{4}{10}[/tex]
[tex]\text{P(B)}=\dfrac{\text{number of elements in B}}{\text{number of elements in S}}[/tex]
[tex]\text{P(B)}=\dfrac{5}{10}[/tex]
[tex]\text{P(A}\cap\text{B})=\dfrac{\text{number of elements in A and B}}{\text{number of elements in S}}[/tex]
[tex]\text{P(A}\cap\text{B})=\dfrac{2}{10}[/tex]
Finally,
[tex]\text{P(A}\cup\text{B})=\dfrac{4}{10}+\dfrac{5}{10}- \dfrac{2}{10}[/tex]
[tex]\text{P(A}\cup\text{B})= \dfrac{7}{10}[/tex]
Answer:
the probability that the number will be more than 6 or odd is: 7/10
Start by putting the possible integers your friend can select
[tex]\text{S}=\{1,2,3,4,5,6,7,8,9,10\}[/tex]
Then, call the 2 possible events as A and B, and what are the possible integers in each event:
A = Be more than 6
B = The number is odd
[tex]\text{A}=\{7,8,9,10\}[/tex]
[tex]\text{B}=\{1,3,5,7,9\}[/tex]
The probability of the union of two events can be calculated as:
[tex]\text{P}(\text{A}\cup\text{B})=\text{P(A)}+\text{P(B)}-P(\text{A}\cap\text{B})[/tex]
Then,
[tex]\text{P(A)}=\dfrac{\text{number of elements in A}}{\text{number of elements in S}}[/tex]
[tex]\text{P(A)}=\dfrac{4}{10}[/tex]
[tex]\text{P(B)}=\dfrac{\text{number of elements in B}}{\text{number of elements in S}}[/tex]
[tex]\text{P(B)}=\dfrac{5}{10}[/tex]
[tex]\text{P(A}\cap\text{B})=\dfrac{\text{number of elements in A and B}}{\text{number of elements in S}}[/tex]
[tex]\text{P(A}\cap\text{B})=\dfrac{2}{10}[/tex]
Finally,
[tex]\text{P(A}\cup\text{B})=\dfrac{4}{10}+\dfrac{5}{10}- \dfrac{2}{10}[/tex]
[tex]\text{P(A}\cup\text{B})= \dfrac{7}{10}[/tex]
Answer:
the probability that the number will be more than 6 or odd is: 7/10
Benjamin is doing some remodeling at his home. He currently has a triangular patio that has a base that is four times as long as its height. He wants to increase the length of the base of the patio by 2 feet and the length of the height of the patio by 9 feet. If x represents the height of the patio, which of the following functions will give the area of the new patio?
Answer:
[tex] a_{old} = \frac{1}{2} (x)(4x) = 2 {x}^{2} [/tex]
[tex] a_{new} = \frac{1}{2} (x + 9)(4x + 2)[/tex]
[tex] = (x + 9)(2x + 1)[/tex]
[tex] = 2 {x}^{2} + 19x + 9[/tex]
Which type of car had the largest range in monthly sales? Explain how you came up with your answer
Sample Response: I subtracted the highest and lowest numbers. The range for new cars was 31. The range for old cars was 75. The range for used cars was much bigger.
Answer:
Without access to specific data on monthly car sales, it is impossible to determine which type of car had the largest range in monthly sales. However, one possible method for finding this information would be to gather sales data for various car models across multiple months and compare the ranges of their sales figures. Alternatively, one could use industry reports or market analysis to determine which car types tend to have the largest fluctuations in sales from month to month.
Step-by-step explanation:
Without access to specific data on monthly car sales, it is impossible to determine which type of car had the largest range in monthly sales. However, one possible method for finding this information would be to gather sales data for various car models across multiple months and compare the ranges of their sales figures. Alternatively, one could use industry reports or market analysis to determine which car types tend to have the largest fluctuations in sales from month to month.
Help me pleaseee! I need help with this problem
Answer:
Step-by-step explanation:
In the given figure, the triangle ABC is a right triangle with a right angle at C. We need to find the length of the side AB.
Using the Pythagorean theorem, we know that in a right triangle with sides of length a, b, and c (where c is the hypotenuse), we have c^2 = a^2 + b^2.
In this case, we have AC = 4 and BC = 3. So, applying the Pythagorean theorem, we get:
AB^2 = AC^2 + BC^2
AB^2 = 4^2 + 3^2
AB^2 = 16 + 9
AB^2 = 25
Therefore, AB = 5.
7
MTR
12345 6 7 8 9 10 x
Tickets
mowing lawns in you
How
much do you earn when you mow 17 lawns?
(See Example 4.)
48. MODELING REAL LIFE It costs $35 a month for membership at a wholesale store. Write and
graph an equation that represents the monthly cost (in dollars) of a membership. What is the
cost of a membership for an entire year?
Find the standard form of the equation of the ellipse with the given characteristics and center at the origin.
The x y-coordinate plane is given. The curve starts at the point (0, 2.5), goes down and right, changes direction at the point (4, 0), goes down and left, changes direction at the point (0, −2.5), goes up and left, changes direction at the point (−4, 0), goes up and right, continuing until it reaches its starting point.
The standard form equation of the ellipse as described in the task content is;
x²/4² + y²/(5/2)² = 1.What is the standard form equation of the ellipse as described?It follows from the task content that the standard form equation of the ellipse is to be determined.
Recall, the equation of an ellipse takes the form;
(x - h)²/a² + (y - k)²/b² = 1
where (h, k) is the center and a represents the distance of the center to each vertex on the major axis and b represents the distance from the center to each vertex on the minor axis.
Therefore, for the given scenario where center is at the origin; the equation of the ellipse is;
x²/4² + y²/(5/2)² = 1
Read more on equation of ellipse;
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