PLS HELP!!!!!
Convert the following measurements. Show all work, including units that cancel.
8.5x10^24 molecules NO2 -> mol

The wettability of silica particles can be gradually reduced and made more hydrophobic by altering the silanol surface anchoring groups.

Surface silanol groups are created during the condensation polymerization of silicic acid, which results in the substance known as silica gel. The majority of the silanol groups on the surface are free silanol groups. There are numerous ways to modify these silanol groups.

Siloxane is a functional group and silane is an inorganic molecule with the chemical formula. The main distinction between silane and siloxane is that the former is a chemical compound, whilst the latter is an organosilicon functional group.

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At STP, the temperature is 0 degrees Celsius and the pressure is 1 atm (101.325 kPa).

Temperature is a measure of the hotness or coldness of an object or environment. It is measured by thermometers using a numerical scale. Temperature is a physical property of matter that is described as the intensity of heat. Temperature is measured in units such as Celsius, Fahrenheit, and Kelvin. The temperature of an object or environment is determined by the average kinetic energy of the particles that make up the object or environment. Temperature affects many aspects of life, from human comfort to the ability of certain species of animals to survive in a given environment. Temperature can also affect the rate of chemical reactions, the strength of certain materials, and the behavior of sound waves.

According to the ideal gas law, the volume of a gas is inversely proportional to the pressure, and directly proportional to the temperature. Therefore, the volume of the oxygen gas at STP will be:

V2 = V1 * (T2/T1) * (P1/P2)

V2 = 400 ml * (273K / 323K) * (101.325 kPa / 250 mmHg)

V2 = 284.7 ml

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Answer:

(NH4)2SO4 gives colourless and odourless gas, which is ammonia (NH3), on thermal decomposition. This is because ammonium sulfate decomposes upon heating to produce ammonia gas and water:

(NH4)2SO4 → 2NH3 + H2O + SO2

The other compounds listed in the question do not produce colourless and odourless gases on thermal decomposition.

- Pb(NO3)2 decomposes to form nitrogen dioxide gas, which has a reddish-brown color and a pungent odor.

- ZnSO4.7H2O decomposes to form water vapor and sulfur dioxide gas, which has a pungent odor and a choking sensation.

- (NH4)2Cr2O7 decomposes explosively to form nitrogen gas, water vapor and chromium oxide, which has a green color.

Therefore, the correct answer to the question is (NH4)2SO4.

Solute content in 50.0 mL of 0.488 M K4[Cu(CN)6] is 10.3 g.

The solution has a molarity of 0.0757 M.

In 439 mL of 0.0250 M CuSO4 solution, 1.75 g of solute is contained.

a. The first step is to use the formula:

number of moles = Molarity × volume (in liters)

We need to convert the given volume (in mL) to liters by dividing it by 1000:

50.0 mL = 50.0/1000 = 0.0500 L

Now we can substitute the given values and solve for the number of moles:

number of moles = 0.488 mol/L × 0.0500 L = 0.0244 mol

Finally, we can convert the number of moles to grams using the molar mass of K4[Cu(CN)6]:

mass of solute = number of moles × molar mass = 0.0244 mol × 422.88 g/mol = 10.3 g

Therefore, 50.0 mL of 0.488 M K4[Cu(CN)6] contains 10.3 g of solute.

b. We can use the formula:

Molarity = number of moles/volume (in liters)

First, we need to convert the given mass (in grams) to moles using the molar mass of (NH₄)₂SO₄:

number of moles = 4.00 g / 132.14 g/mol = 0.0303 mol

Next, we need to convert the given volume (in mL) to liters by dividing it by 1000:

400.0 mL = 400.0/1000 = 0.400 L

Now we can substitute the given values and solve for the molarity:

Molarity = 0.0303 mol / 0.400 L = 0.0757 M

Therefore, the molarity of the solution is 0.0757 M.

c. We can use the formula:

number of moles = Molarity × volume (in liters)

First, we need to convert the given mass (in grams) to moles using the molar mass of CuSO₄:

number of moles = 1.75 g / 159.61 g/mol = 0.01097 mol

Now we can substitute the given values and solve for the volume (in liters):

0.01097 mol = 0.0250 mol/L × volume (in L)

volume (in L) = 0.01097 mol / 0.0250 mol/L = 0.439 L

Finally, we can convert the volume to mL by multiplying by 1000:

volume (in mL) = 0.439 L × 1000 mL/L = 439 mL

Therefore, 1.75 g of solute in 0.0250 M CuSO₄ solution is present in 439 mL of solution.

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Answer:

Oxygen gas

Explanation:

We have to know that the chlorine reacts with water in the presence of sunlight to liberate oxygen gas. Chlorine reacts with water in the presence of sunlight to give the product of hydrochloric acid and hypoechoic acid.

There will be 0.4589 mL of ethyl acetate left in the space after evaporation.

The conversion of a liquid substance into a gas is known as evaporation. As a result of the liquid absorbing energy from its surroundings, molecules begin to travel faster and faster until they finally become a vapour and escape into the environment. Usually, the energy is absorbed as heat, but it can also be in the form of light or electricity.

No, the ethyl acetate won't all evaporate. The amount of ethyl acetate that will stay in the space after evaporation can be determined using the ideal gas law. As per the ideal gas law, PV = nRT

P is the overall system pressure, V is the room's volume, n is the amount of ethyl acetate in moles, R is the ideal gas constant, and T is the temperature.

To solve for n, the quantity of moles of ethyl acetate, we can rearrange the equation as follows: n = PV/RT

When the values are plugged in, we get:

n = (94.9 torr)(7.25 m x 2.75 m x 2.75 m)/(8.314 J/K mol)(298 K)

[tex]n = 4.666 \times 10^{-3} mol[/tex]

The molar mass of ethyl acetate (88.11 g/mol) can then be used to compute the mass of ethyl acetate:

Mass = [tex]n \times M = (4.666 x 10^{-3} mol)(88.11 g/mol)[/tex] = 0.4125 g

Using the density of ethyl acetate (0.901 g/mL), it is possible to determine the volume of the liquid that is still present:

Volume = mass/density = (0.4125 g)/(0.901 g/mL) = 0.4589 mL

As a result, there will be 0.4589 mL of ethyl acetate left in the space after evaporation.

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The mass of the gallium chloride that was produced is given as 220 g.

Stoichiometry involves the use of chemical equations and balancing those equations to ensure that the same number and types of atoms are present on both sides of the equation. The coefficients in the balanced chemical equation represent the stoichiometric coefficients, which indicate the relative amounts of reactants and products that are involved in the reaction.

We know that;

Number of moles of HCI = 1.44 M * 2.6 L

= 3.744 moles

If 6 moles of HCI reacts produces 2 moles of GaCl3

3.744 moles of HCl producs 3.744 * 2/6

= 1.248 moles

Mass of the GaCl3 = 1.248 * 176 g/mol

= 220 g

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Answer: the increasing order of oxidation number of chlorine is NaCl < Cl2 < NaClO < Cl2O < KClO2 < ClO3 < ClO2 < NaClO3 < Cl2O7 < NaClO4.

Explanation:  NaClO4: +7

NaClO3: +5

NaClO: +1

KClO2: +3

Cl2O7: +7

ClO3: +5

Cl2O: +2

NaCl: -1

Cl2: 0

ClO2: +4

Arranged in increasing order:

NaCl < Cl2 < NaClO < Cl2O < KClO2 < ClO3 < ClO2 < NaClO3 < Cl2O7 < NaClO4

The oxidation state that isn't present in any of the below composites is-2.

To find the oxidation number of chlorine in each emulsion, we need to know the usual oxidation figures of the other rudiments in the emulsion and use the following rules

The oxidation number of an snippet in an essential form is always zero.

The sum of oxidation figures of all tittles in a neutral emulsion is zero.

The sum of oxidation figures of all tittles in a polyatomic ion is equal to the charge of the ion.

Using these rules, we can determine the oxidation figures of chlorine in each emulsion

NaClO4 Chlorine has an oxidation number of 7.

NaClO3 Chlorine has an oxidation number of 5.

NaClO Chlorine has an oxidation number of 1.

KClO2 Chlorine has an oxidation number of 3.

Cl2O7 The oxidation number of chlorine is seven.

ClO3 Chlorine has an oxidation number of 5.

Cl2O Chlorine has an oxidation number of 1.

NaCl Chlorine has an oxidation number of-1.

Cl2 Chlorine has an oxidation number of 0.

ClO2 Chlorine has an oxidation number of 4.

Arranging these composites in adding order of oxidation number of chlorine, we get

NaCl< Cl2< NaClO< KClO2< ClO2< NaClO3< ClO3< Cl2O< Cl2O7< NaClO4

thus, the oxidation state that isn't present in any of the below composites is-2.

The complete question is -

Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.

NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl, Cl2, ClO2.

Which oxidation state is not present in any of the above compounds?

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Hard water contains higher levels of minerals such as calcium and magnesium, while soft water has low levels of these minerals. While both hard and soft water can be safe for drinking, hard water is generally considered safer due to the minerals it contains.

The minerals in hard water can actually be beneficial to human health, as they are important for strong bones and teeth. In addition, the minerals in hard water can help to balance the body's electrolytes and may have other health benefits.

Soft water, on the other hand, may contain higher levels of sodium or other chemicals used in the softening process. While these levels are generally considered safe, some people with certain health conditions may need to avoid drinking water with higher sodium levels.

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The amount of energy released as heat when a 12.8 g sample of diethyl ether is burned is 469.23 kJ.

The given combustion reaction is:

CH₃CH₂OCH₂CH₃(l) + 6O₂(g) → 4CO₂(g) + 5H₂(g) ∆H = -2.72 × 10³ kJ

We are given a 12.8 g sample of diethyl ether (C₄H₁₀O), which has a molar mass of 74.12 g/mol. To find the amount of moles of diethyl ether, we can use the formula:

moles = mass/molar mass

moles of diethyl ether = 12.8 g / 74.12 g/mol = 0.1727 mol

According to the balanced chemical equation, one mole of diethyl ether produces -2.72 × 10³ kJ of heat. Therefore, we can find the amount of heat produced for 0.1727 moles of diethyl ether by using the following formula:

Heat produced = moles of diethyl ether × ∆H

Heat produced = 0.1727 mol × (-2.72 × 10³ kJ/mol) = -469.23 kJ

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The evidence indicating that over several hundreds of years or more there have been variations in the level of the solar activity is The use of ice cores have helped track the activity of the Sun containing information over the centuries. The correct option to this question is A.

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The evidence indicating that over several hundreds of years or more there have been variations in the level of the solar activity is The use of ice cores have helped track the activity of the Sun containing information over the centuries. The correct option to this question is A.

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The new concentration of solution 2 would be 3.00 M after the addition of the solid sodium carbonate.

Using the dilution equation:

C1V1 = C2V2

For Solution 2:

We can find the amount of sodium carbonate added by converting the given mass to moles:

Since each mole of solid sodium carbonate dissociates to give two moles of sodium ions and one mole of carbonate ions, we can calculate the increase in the number of moles of sodium ions:

Δn(Na+) = 2n(Na2CO3) = 2(0.149 mol) = 0.298 mol

The new total number of moles of sodium ions in the solution will be:

Finally, new concentration:

Therefore, the new concentration of Solution 2 is still 3.00 M after the addition of solid sodium carbonate.

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The graph's data show that throughout time, nuclear energy has lost some of its significance as a source of energy production in the US.

Since the turn of the century, the amount of nuclear energy utilised has continuously fallen while the use of natural gas, coal, and hydroelectric power has increased.

This might indicate that the nation has been moving away from using nuclear energy as its main source of electricity.  This information shows that the nation is switching from nuclear energy as its main source of electricity to other sources such as coal, natural gas, and hydroelectricity.  

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A plot of the solar spectrum in the upper atmosphere shows that the majority of the solar radiation in this region is absorbed by the ozone layer.

The energy required for the photolysis of O₂ to form the ozone layer is approximately 498 kJ/mol. Using the above equations, we can calculate the threshold frequency and cutoff wavelength:

f = (498 kJ/mol) / (6.626 x 10^-34 J s) = 7.51 x 10^15 Hz

λ = (3.00 x 10^8 m/s) / (7.51 x 10^15 Hz) = 40.0 nm

Therefore, any solar radiation with a wavelength shorter than 40.0 nm can cause the photolysis of O₂ to form the ozone layer. This portion of the spectrum is called the vacuum ultraviolet region.

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Answer:

When exposed to a base, red litmus paper becomes blue; yet, when exposed to an acid or neutral solution, it remains red. As a result, you may use red litmus paper to differentiate the basic solution from the other two solutions:

Dip the red litmus paper into the first distilled water test container. The water is neutral if the paper remains red.

In the second test tube, place the red litmus paper. If the paper becomes blue, the solution is straightforward. If the solution remains red, it is either neutral or acidic.

In the third test tube, place the red litmus paper. The solution is neutral if the paper remains red. If the paper becomes blue, the solution is straightforward.

This is due to the fact that a substance's chemical qualities, such as its molecular form, polarity, and functional groups, govern how it behaves and interacts with other substances.

By illustrating the spatial arrangement of atoms and chemical bonds within the molecule, chemical structure establishes the molecular geometry of a compound. In doing so, chemists are given a crucial visual depiction of a chemical formula.

In a chemical reaction, reactants come into contact with one another, atoms in the reactants break their connections with one another, and then the atoms reorganise and form new bonds to create the products.

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1.04 x 10³ J is the work done when 50.0 g of tin dis- solves in excess acid at 1.00 atm and 25°C. Therefore, the correct option is option D.

One of the three distinct groups of thermodynamic processes that a thermodynamic system might use to interact with its environment in the context of energy transfer is work. By means of a mechanism, the system is able to spontaneously apply macroscopic forces to its surroundings that can be externally monitored.

W=p∆V.

n=m/M.

n=50g/118.71=0.421mol.

T=25+273=298°K.

W=0.421×8.314×298= 1.04 x 10³ J

Therefore, the correct option is option D.

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The enthalpy change for the given reaction is -7332 kJ, after using the Hess's law.

Enthalpy change, represented by ΔH, is the amount of heat absorbed or released by a system at constant pressure during a chemical reaction or physical process. It is a thermodynamic property that describes the difference in energy between the reactants and the products of a reaction.

First, we need to manipulate the given equations to obtain the target equation:

C₂H₆(g) → C₂H₂(g) + 2H₂(g)

2C₂H₂(g) +5O₂(g) → 4CO₂(g) + 2H₂O (1)

2H₂(g) + O₂(g) → 2H₂O (1)

Now we can use Hess's Law, which states that if a reaction can take place by two or more different routes, the total enthalpy change is the same for each route.

We can obtain the target equation by combining the given equations in the following way:

C₂H₆(g) + 7/2O₂(g) → 2CO₂(g) + 3H₂O (1) (multiply the 3rd equation by 3/2)

ΔH1 = -1560 kJ

2C₂H₂(g) +5O₂(g) → 4CO₂(g) + 2H₂O(1)

ΔH₂ = -572 kJ (reverse the 2nd equation and change the sign)

Adding the above two equations we get,

C₂H₆(g) + 7/2O₂(g) → 2CO₂(g) + 3H₂O (1)

ΔH₁ + ΔH₂ = -2132 kJ

Now we need to multiply the first equation by 2 to obtain the target equation:

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(1)

ΔH₃ = 2*(-2600 kJ) = -5200 kJ

Adding ΔH₁+ΔH₂ to ΔH₃, we get:

C₂H₆(g) → C₂H₂(g) + 2H₂(g)

ΔH = ΔH₁ + ΔH₂ + ΔH₃ = -7332 kJ

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Answer:

El termómetro expuesto directamente al sol medirá la temperatura del aire circundante y la radiación solar, pero no la temperatura del sol en sí.

The concentration of the 25 mL oxalic acid solution is 0.604 M.

Using the balanced chemical equation provided, we can see that the stoichiometric ratio of KMnO₄ to oxalic acid (H₂C₂O₄) is 2:5. Therefore, the number of moles of oxalic acid in the 23.7 mL of 0.0175 M KMnO₄ solution used in the titration can be calculated as follows:

0.0175 M KMnO₄ x 23.7 mL x 2/5 = 0.0151 moles H₂C₂O₄

Since the volume of the oxalic acid solution used in the titration is 25 mL, the concentration of the oxalic acid solution can be calculated as follows:

Concentration = Number of moles ÷ Volume

Concentration = 0.0151 moles ÷ 0.025 L

Concentration = 0.604 M

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The decay constant of the process is approximately 2.7 × 10⁻¹² per year.

The decay constant (λ) represents the probability of decay per unit of time. It is related to the half-life (t [tex]\frac{1}{2}[/tex]) of a radioactive isotope by the equation

λ = ln(2) ÷ t [tex]\frac{1}{2}[/tex].

To determine the decay constant, we need to first convert the percentage given to a decimal, which is 2.7 × 10⁻¹². We can then use the equation N = N0e^(-λt), where N0 is the initial number of atoms, N is the final number of atoms after time t, and e is the mathematical constant e ≈ 2.71828.

Assuming that N ≈ N0 and solving for λ, we get:

λ = -ln(1 - 2.7 × 10⁻¹²) ÷ t

Substituting t = 1.0 year, we get:

λ = -ln(1 - 2.7 × 10⁻¹²) ÷ 1.0 year

λ ≈ 2.7 × 10⁻¹² per year

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The concentration (in mole/liter) of the nitric acid is 0.139 M.

Concentration refers to the amount of a substance in a defined space. Another definition is that concentration is the ratio of solute in a solution to either solvent or total solution.

There are various methods of expressing the concentration of a solution.

Concentrations are usually expressed in terms of molarity, defined as the number of moles of solute in 1 L of solution.

Solutions of known concentration can be prepared either by dissolving a known mass of solute in a solvent and diluting to a desired final volume or by diluting the appropriate volume of a more concentrated solution (a stock solution) to the desired final volume.

Given,

Volume of NaOH = 11.02 ml

Concentration of NaOH = 0.253 M

Volume of nitric acid = 20.05 ml

Number of moles stay same on neutralisation, so

Volume of NaOH × Concentration of NaOH = Volume of nitric acid × concentration of nitric acid.

11.02 × 0.253 = 20.05 × concentration

Concentration of nitric acid = 0.139 M

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Reaction of Barium metal is heated in an atmosphere of hydrogen gas is:

Reaction of Barium metal is heated in an atmosphere of hydrogen gas is:

When barium metal is heated in an atmosphere of hydrogen gas, barium hydride is formed.

A metal is a solid material that is typically hard, shiny, and malleable, with good electrical and thermal conductivity.

The chemical equation for this reaction is:

[tex]\rm Ba + H_2 \rightarrow BaH_2[/tex]

Barium hydride is a white crystalline solid that is highly reactive and has a high affinity for water. It is used in the production of other chemicals, such as barium peroxide and barium oxide.

The reaction between barium metal and hydrogen gas is an example of a redox reaction, where the barium metal is oxidized and the hydrogen gas is reduced.

Therefore, when barium metal is heated in an atmosphere of hydrogen gas, barium hydride is formed.

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When barium metal is heated in an atmosphere of hydrogen gas, barium hydride is formed.

A metal is a solid material that is typically hard, shiny, and malleable, with good electrical and thermal conductivity.

The chemical equation for this reaction is:

[tex]\rm Ba + H_2 \rightarrow BaH_2[/tex]

Barium hydride is a white crystalline solid that is highly reactive and has a high affinity for water. It is used in the production of other chemicals, such as barium peroxide and barium oxide.

The reaction between barium metal and hydrogen gas is an example of a redox reaction, where the barium metal is oxidized and the hydrogen gas is reduced.

Therefore, when barium metal is heated in an atmosphere of hydrogen gas, barium hydride is formed.

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The calorie value of the food item is approximately 360 calories.

The amount of heat absorbed by the water can be calculated using the formula Q = mcΔT, where Q is the heat absorbed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.

Substituting the values, we get:

Since the food item is the only source of heat, the calorie value of the food item is also 360 calories. However, this is only an approximation since the calorimeter may not have captured all of the heat energy produced by the food item.

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Answer:

The balanced chemical equation for the reaction is:

5CaF2 · 3Ca3(PO4)2 + 24H2SO4 → 20H3PO4 + 10HF + 15CaSO4 · 2H2O

This equation shows that when fluorapatite is reacted with sulfuric acid, it produces phosphoric acid, hydrogen fluoride, and gypsum. The balanced equation indicates that 5 moles of CaF2·3Ca3(PO4)2 react with 24 moles of H2SO4 to produce 20 moles of H3PO4, 10 moles of HF, and 15 moles of CaSO4·2H2O.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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A system that can share both matter and energy with its surroundings is called "open." The given sentence, "The container contains 8 grams of liquid water and 4 grams of water vapor," says that water molecules have left the container in the form of water vapor. This means that both matter (water vapor) and energy (in the form of heat to turn liquid water into water vapor) have been shared between the container and its surroundings. So, it's likely that the container is an open system.

A closed system, on the other hand, lets energy (in the form of heat or work) but not matter flow between itself and its surroundings. On the other hand, a separated system can't share either matter or energy with its surroundings.

The other choices in the question don't say anything about the presence of water vapor. Instead, they only talk about the presence of water in different forms (like liquid water or ice) or the amount of water (in grams). Without water vapor, there would be no reason to think that the system is open because there would be no sign that matter (water vapor) is being traded with the outside world. Since both liquid water and water mist are mentioned in answer choice E, this suggests that the container is an open system.

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Answer:

C. The container contains 8 grams of liquid water and no ice.

Explanation:

Open system allows the ice to melt and some to evaporate out of the cup.