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EXPLANATION = BRAINLIEST

the area of the triangle is ____ square in

Answer:

[tex]y \: \alpha \: {(x + 2)}^{3} \\ y = k {(x + 2)}^{3} \\ k \: is \: a \: constant \\ when \: x = 0 \: \: y = 32 : \\ 32 = k {(0 + 2)}^{3} \\ 32 = k(8) \\ k = 4 \\ \therefore \: y = 4 {(x + 2)}^{3} \\ when \: x \: is \: 1 : \\ y = 4 {(1 + 2)}^{3} \\ y = 4 \times 27 \\ y = 108[/tex]

Answer:

3,375mm^3

Step-by-step explanation:

To find the volume, you do the length times the width times the height. Since this is a cube, the length, width, and height are all 15 mm. Multiply 15 times 15 times 15 to get 3375. The answer is 3375 cubic inches or 3375mm^3

Answer:

∠EFG=2×∠EHG

∠EFG=2×42

∠EFG=84°

so,m∠EFG=84°

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have a nice day!!

Answer:

impossible

Step-by-step explanation:

a denominator can’t be equal to 0. So:

d ≠ 0 ; d ≠ 2

(10 + 4d - 8)/d(d-2) = 5d/ d(d-2)

4d + 2 = 5d

d = 2

But we have said that d can’t be equal to 2, so the equation is impossible.

Answer:

Ascending order

Step-by-step explanation:

Ascending numbers are numbers that begin from smallest to biggest.

1.

[tex](3 {x}^{2} - 4x - 1) + (8 {x}^{2} - x + 6) \\ \\ combining \: the \: like \: terms,\:we\:have\\ \\ = 3 {x}^{2} + 8 {x}^{2} - 4x - x - 1 + 6 \\ \\ = 11 {x}^{2} - 5x + 5[/tex]

2.

[tex](6 {x}^{2} - x - 4) + ( 2{x}^{2} + 5x - 5) \\ \\combining \: the \: like \: terms, \: we \: have \\ \\= 6 {x}^{2} + 2 {x}^{2} - x + 5x - 4 - 5 \\ \\= 8 {x}^{2} + 4x - 9[/tex]

3.

[tex](4 {x}^{2} + 2x - 5) + (6 {x}^{2} - x - 5) \\ \\ combining \: th e\:l ike \: terms, \: we \: have \\ \\= 4 {x}^{2} + 6 {x}^{2} + 2x - x - 5 - 5 \\ \\= 10 {x}^{2} +x - 10[/tex]

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Answer:

-1 ≤ y ≤ 0

Step-by-step explanation:

here, we simply want to know the range of values for sin x over the given interval

The range of values for sin x are simply the values in which y will take over the given interval of x

let’s start with the value sine (-pi)

We have this as;

0

And the value of sin (0) = 0

Recall, between -pi and 0, we have (-pi/2)

so sin (-pi/2) = -1

Thus, we have the correct range of values as;

-1 ≤ y ≤ 0

Answer:

1260

Step-by-step explanation:

5÷100=0.05

0.05×25200=1260

Answer:

[tex](x-1)^2 + (y-1)^2 = 10[/tex]

Step-by-step explanation:

From the graph ,

Centre of the circle is (1, 1)

To find radius we find a point through which the circle passes and find the distance between the Centre and the point.

Let that point be (4, 0)

[tex]radius = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2} = \sqrt{(1-4)^2 + (1-0)^2} = \sqrt{10}[/tex]

Equation of the circle :

[tex](x - a)^2 + (y-b)^2 = r^2 \ , \ where \ (a,b)\ is\ the\ centre\ of\ the\ circle\ and\ r\ is\ the\ radius\\\\(x-1)^2 + (y-1)^2 = 10[/tex]

Answer:

7:20

Step-by-step explanation:

divide both by 5 to simplify

Answer:

$28.00

Step-by-step explanation:

1. The markup is 40% of the $20 cost, so the markup is:

(0.40)(20) = 8

2. Then the selling price, being the cost plus markup, is:

20 + 8 = 28

3. The CD set sold for $28.00

Step-by-step explanation:

sp=(100+p)% of cp

=100+40/100*20

=140/100*20

=28

Answer:

765 ml & 1800 ml

Step-by-step explanation:

[tex]3x + 8x = 2475\\\\11x = 2475\\\\x=225\\\\3(225)=765\\8(225)=1800[/tex]

Rewrite 50% as a decimal : 0.50

Multiply the price by 0.50:

18 x 0.50 = 9

The sale price is $9

Answer:

$9

Step-by-step explanation:

price of an item=$18

discount=50%

sale price =? (be x)

sale price= original price -discount% of original price

x=$18 -50/100 * $18

x=$1800-$900/100

=$900/100

=$9

therefore sale price of an item is $9.

Answer:

n=-2,A

Step-by-step explanation:

15-3n=21

-3n=21-15

-3n=6

n=6/-3

=-2

Answer:

d and e

Step-by-step explanation:

for a

substitute 2 for x

2 + 8 > 14

2 + 8 = 10

10 > 14

10 is not greater than 14 therefore 2 is not a solution to the inequality

for b

substitute 4 for x

4 + 8 > 14

4 + 8 = 12

12 > 14

12 is not greater than 14 therefore 4 is not a solution to the inequality

for c

substitute 6 for x

6 + 8 > 14

6 + 8 = 14

14 > 14

14 is not greater than 14 therefore 6 is not a solution to the inequality

for d

substitute 8 for x

8 + 8 > 14

8 + 8 = 16

16 > 14

16 is greater than 14 therefore 8 is a solution to the inequality

for e

substitute 10 for x

10 + 8 > 14

10 + 8 = 18

18 > 14

18 is greater than 14 therefore 10 is a solution to the inequality

we can conclude that the answers are d and e

Step-by-step explanation:

everything can be found in the picture

Answer:

[tex]n + 5 = 12[/tex]

Step-by-step explanation:

"A number increased by a 5 is 12".

The value of n.

[tex]n + 5 = 12[/tex]

[tex]n = 12-5[/tex]

[tex]n = 7[/tex]

Answer:

7

Step-by-step explanation:

subtract the sum, in this case 12. by 5 to get the answer. 12-5=7

Answer:

-3.7 =z

Step-by-step explanation:

10.42= −2.6z+0.8

Subtract .8 from each side

10.42-.8= −2.6z+0.8-.8

9.62= −2.6z

Divide each side by -2.6

9.62 / -2.6 = -2.6z/-2.6

-3.7 =z

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[tex]10.42 = - 2.6 \: z + 0.8 \\ \\✒ \: 2.6 \: z = 0.8 - 10.42\\ \\ ✒ \: 2.6 \: z = - 9.62 \\\\ ✒ \: z \: = \frac{ - 9.62}{2.6} [/tex]

To remove the decimals, we multiply both numerator and denominator by 100.

[tex]✒ \: z \: = \frac{ - 962}{260} \\ \\ ✒ \: z = - 3.7[/tex]

[tex]10.42 = - 2.6 \times ( - 3.7) + 0.8 \\ \\✒ \: 10.42 = 9.62 + 0.8 \\ \\✒ \: 10.42 = 10.42 \\\\ ✒ \: L.H.S.=R. H. S[/tex]

Hence verified.

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Answer:

[tex]1 + cot^2 \theta[/tex]

Step-by-step explanation:

Given the expression;

[tex]\frac{tan^2\theta+1}{tan^2 \theta}[/tex]

Separating into partial fraction;

[tex]\frac{tan^2 \theta}{tan^2 \theta} + \frac{1}{tan^2 \theta}\\= 1 + \frac{1}{tan^2 \theta}\\\\[/tex]

Since [tex]\frac{1}{tan \theta} = cot \theta\\[/tex]

Hence the expression becomes;

[tex]1 + cot^2 \theta[/tex]

Answer:

Domain : (-∞, ∞)

Step-by-step explanation:

Domain of a function is a set of x-values of the function.

Therefore, all x-values at which the given function is defined will be the domain of the function.

From the graph attached,

Given function is defined for all x-values.

Domain : Set of all real numbers.

Or Domain : (-∞, ∞)

Answer:

24/100

Step-by-step explanation:

Answer:

x =62

Step-by-step explanation:

The two angles form a straight line so they add to 180

x+118 = 180

Subtract 118 from each side

x = 180-118

x =62

Answer:

x = 62°

Step-by-step explanation:

These both angles are located at straight line.

So, the sum of both angles is 180 °.

x + 118 ° = 180 °

Subtract 118 ° from 180 °

x = 180 ° - 118 °

x = 62 °

Answer:

48

Step-by-step explanation:

3 ⋅ 2^t

3 * 2^4

3*16

48

Answer:

10.5 miles

Step-by-step explanation:

[tex]\frac{4\frac{2}{3} }{49} :\frac{1}{y}[/tex]

4 2/3 × y = 1 × 49

[tex]4\frac{2}{3}y=49[/tex]

[tex]4\frac{2}{3}y/4\frac{2}{3} =49/4\frac{2}{3}[/tex]

[tex]y = 10\frac{1}{2}[/tex]

x = -1

Step-by-step explanation:

[tex] {4}^{5x} = {2}^{2(5x)} = {2}^{10x} [/tex]

[tex] {( \frac{1}{32}) }^{(1 - x)} = {2}^{ - 5(1 - x)} = {2}^{(5x - 5)} [/tex]

or

[tex] {2}^{10x} = {2}^{(5x - 5)} [/tex]

Since both sides have the same base, we can write

10x = 5x - 5

or

5x = -5

x = -1

Answer:

The average rate of change of the function over the interval is 5.

Step-by-step explanation:

Average rate of change of a function:

The average rate of change of a function f(x) over an interval [a,b] is given by:

[tex]A = \frac{f(b)-f(a)}{b-a}[/tex]

Interval -3 less-than-or-equal-to x less-than-or-equal-to 3

This means that [tex]a = -3, b = 3[/tex]

[tex]f(x) = x^2 + 3x + 6[/tex]

So

[tex]f(b) = f(3) = (3)^2 + 3(3) + 6 = 9 + 9 + 6 = 24[/tex]

[tex]f(a) = f(-3) = (-3)^2 + 3(-3) + 6 = 9 - 9 + 6 = 6[/tex]

Average rate of change

[tex]A = \frac{f(b)-f(a)}{b-a} = \frac{24+6}{3-(-3)} = \frac{30}{6} = 5[/tex]

The average rate of change of the function over the interval is 5.

Answer:

The x Intercepts of y=5x^2-15x is (1, 0) and (-1, 0)

Step-by-step explanation:

Answer:

(0,0) and (3,0)

Step-by-step explanation:

5x²-15x = 0

5x(x-3) = 0

5x=0;    x=0

x-3=0;   x=3

[tex]\begin{cases} h(x)=\sqrt{x}\\ g(x)=4x^2+4 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ g(\sqrt{a})=4(\sqrt{a})^2+4\implies g(\sqrt{a})=4\sqrt{a^2}+4\implies g(\sqrt{a})=\boxed{4a+4} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(~~g(\sqrt{a})~~)\implies h\left( \boxed{4a+4} \right)=\sqrt{4a+4}\implies h(~~4a+4~~)=\sqrt{4(a+1)} \\\\\\ h(~~4a+4~~)=\sqrt{2^2(a+1)}\implies h(~~4a+4~~)=2\sqrt{a+1}[/tex]