Please help! Precalco

Answer:

  A = 2r²

Step-by-step explanation:

A square is a rhombus with equal-length diagonals. A square inscribed in a circle has diagonals equal to the diameter of the circle: 2r.

The area of a rhombus is half the product of the lengths of its diagonals. Hence the area of our square is ...

  A = (1/2)(2r)(2r)

  A = 2r²

Answer:

2

Step-by-step explanation:

r=1/2s[tex]\sqrt{2}[/tex]

2r=s[tex]\sqrt{2}[/tex]

2r/[tex]\sqrt{2}[/tex]=s remove [tex]\sqrt{2}[/tex] denominator by multiplying with [tex]\sqrt{2}[/tex]/[tex]\sqrt{2}[/tex]

2[tex]\sqrt{2}[/tex]r/2  -- simplify , 2 cancels

s=r[tex]\sqrt{2}[/tex]

so area = (r[tex]\sqrt{2}[/tex])^2

A(r)= 2r²

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I need Help on this question

1. what is the inverse of f(x) = x+9/10x-1?
a. 10x-1/x-9
b. x-9/10x+1
c. x+9/10x-1
d .2x+9/5x+1



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