Answer: a variety of ohmic valu example, VIN = VR1 + VR2.
Potentiometer Example No1
A resistor of 250 ohms is connected in series with a second resistor of 750 ohms so that the 250 ohm resistor is connected to a supply of 12 volts and the 750 ohm resistor is connected to ground (0v). Calculate the total series resistance, the current flowing through the series circuit and the voltage drop across the 750 ohm resistor.
potentiometer example one
Explanation:
uman ear has a logarithmic response and is therefore non-linear.
If we where to use a linear potentiometer to control the volume, it would give the impression to the ear that most of the volume adjustment was restricted to one end of the pots track. The logarithmic potentiometer however, gives the impression of a more even and balanced volume adjustment across the full rotation of the volume control.
So the operation of a logarithmic potentiometers when adjusted is to produce an output signal which closely matches the nonlinear sensitivity of the human ear making the volume level sound as though it is increasing linearly. However, some cheaper logarithmic potentiometers are more exponential in resistance changes rather than logarithmic but are still called logarithmic because their resistive response is linear on a log scale. As well as logarithmic potentiometers, there are also anti-logarithmic potentiometers in which their resistance quickly increases initially but then levels off.
The all potentiometers and rheostats are available in a choice of different resistive tracks or patterns, known as laws, being either linear, logarithmic, or anti-logarithmic. These terms are more commonly abbreviated to lin, log, and anti-log, respectively.
The best way to determine the type, or law of a particular potentiometer is to set the pots shaft to the center of its travel, that is about half way, and then measure the resistance across each half from wiper to end terminal. If each half has more or less equal resistance, then it’s a Linear Potentiometer. If the resistance appears to be split at about 90% one way and 10% the other then chances are it’s a Logarithmic Potentiometer.
Potentiometer Summary
In this tutorial about potentiometers, we have seen that a potentiometer or variable resistor basically consists of a resistive track with a connection at either end and a third terminal called the wiper with the position of the wiper dividing the resistive track. The position of the wiper on the track is adjusted mechanically by rotating a shaft or by using a screwdriver.
Variable resistors can be categorised into one of two operational modes – the variable voltage divider or the variable current rheostat. The potentiometer is a three terminal device used for voltage control, while the rheostat is a two terminal device used for current control.
We can summarise this in the following table:
Type Potentiometer Rheostat
Number of
Connections Three Terminals Two Terminals
Number of Turns Single and Multi-turn Single-turn Only
Connection Type Connected Parallel with a Voltage Source Connected in Series with the Load
Quantity Controlled Controls Voltage Controls Current
Type of Taper Law Linear and Logarithmic Linear Only
Then the potentiometer, trimmer and rheostat are electromechanical devices designed so that their resistance values can be easily changed. They can be designed as single-turn pots, presets, slider pots, or as multi-turn trimmers. Wirewound rheostats are mainly used to control an electrical current. Potentiometers and rheostats are also available as multi-gang devices and can be classified as having either a linear taper or a logarithmic taper.
Either way, potentiometers can provide highly precise sensing and measurement for linear or rotary movement as their output voltage is proportional to the wipers position. The advantages of potentiometers include low cost, simple operation, lots of shapes, sizes and designs and can be used in a vast array of different applications.
However as mechanical devices, their disadvantages include eventual wear-out of the sliding contact wiper and/or track, limited current handling capabilities (unlike Rheostats), electrical power restrictions and rotational angles that are limited to less than 270 degrees for single turn pots
Two resistors, R1 and R2, are connected
in series to a 5.00 V battery. R1 is
12.0 Ohm. A current of 0.167 A flows
through the circuit.
What is resistance of R2?
Answer:
18 ohms
Explanation:
V = I(R1 + R2)
5V = (0.167A)(12 ohms + R2)
Solving for R2
R2 = 18 ohms
The density of the atmosphere on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). What is the graphical relationship between altitude and atmospheric density on this planet? Altitude (km) Almospheric Density (km/mº)
Α.inverse plot B. quadratic plot C. velocity plot D. acceleration plot E.parabolic plot
Answer:I think it’s Velocity plot.
Explanation:
I hope i can help you, have a great day and good like with everything.
Answer: inverse plot
Explanation: lucky guess lmk if its right
Can anyone help me!!!
I need this really soon!!!!
Q. Rama's weight is 40kg . She is carrying a load of 20 kg up to a height of 20 metres. What work does she do? Also mention the type of work
No links!!!!
No spams!!!!
Answer:
3920 N.
Explanation:
that's what the answer is..
PLEASE HELP!!!!!!!!!!
An object's velocity increases, multiplied by a factor of 9. What factor would its Kinetic Energy increase by?
Answer:
by 81
Explanation:
KE = (1/2)mv^2. If v2 ---> 9v then
KE2 = (1/2)m(9v)^2 = 81[(1/2)mv^2]
= 81 KE
Answer:
by a factor of 4
Explanation:
The kinetic energy is proportional to the square of the speed so doubling the speed increases.
- Determine the speed of a 350 Hz sound wave with a wavelength of 0.971 m
adio wave transmitted to the moon through snace by
Explanation:
[tex]from \: the \: wave \: equation \\ Speed \: \: V = f \lambda \\ = 350 \times 0.971 \\ = 339 850 \: {ms}^{ - 1} [/tex]
PLEASE HEEELLLPPPPP
Two ice skaters on ice push away from each other. The friend on the left is 45 kg and the friend on the right is
40 kg. The right skater gets pushed and moves with an acceleration 2 m/s". Based on this scenario what will
happen to the left skater?
What formula should I use?
How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation:
A friend insists that electric current is the same as electrical energy. Work with a partner to develop a rebuttal
against your friend's misconception.
Answer: The electrons flowing through the wire are referred to as a quantity of electricity, and the flow of electricity is referred to as “an electric current.”
Explanation: Hope it Helps have a blessed day
An electron and a proton are held on an x axis, with the electron at x = + 1.000 m
and the proton at x = - 1.000 m . If a second electron is initially at x = + 20.00 m on the x axis and is given an initial velocity of 450 m/s towards the origin, will it reach and origin? And how close will it get to the origin if it doesn't?
Answer:
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Explanation:
For this exercise we must use conservation of energy
the electric potential energy is
U = [tex]k \frac{q_1q_2}{r_{12}}[/tex]
for the proton at x = -1 m
U₁ =[tex]- k \frac{e^2 }{r+1}[/tex]
for the electron at x = 1 m
U₂ = [tex]k \frac{e^2 }{r-1}[/tex]
starting point.
Em₀ = K + U₁ + U₂
Em₀ = [tex]\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}[/tex]
final point
Em_f = [tex]k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})[/tex]
energy is conserved
Em₀ = Em_f
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²( [tex]\frac{2}{(r_2+1)(r_2-1)}[/tex] )
we substitute the values
½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ [tex]- \frac{1}{20+1} + \frac{1}{20-1}[/tex] ) = 9 109 (1.6 10-19) ²( [tex]\frac{2}{r_2^2 -1}[/tex] )
2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( [tex]\frac{1}{r_2^2 -1}[/tex] )
2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷ [tex]\frac{1}{r_2^2 -1}[/tex]
[tex]\frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}[/tex]
r₂² -1 = (4.443 10⁸)⁻¹
r2 = [tex]\sqrt{1 + 2.25 10^{-9}}[/tex]
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Can someone please help me with history.
Answer:
Yes my name is Axelrod I can help you
In a perfectly inelastic collision between two balls:
a) No changes happen to the internal structure of the balls
b) The total kinetic energy of the balls is conserved
c) The balls have the same velocity after the collision
d) The balls temperature does not change.
Answer:
c) The balls have the same velocity after the collision
Explanation:
In a perfectly inelastic collision between two balls, there is a loss in the maximum kinetic energy of the system and the two ball stick together, and thereby have the same velocity after the collision and also the coefficient of restitution of the two balls is also zero accompanied by a loss in the kinetic energy of the system
Therefore, the correct option is that both balls will have the same (equal) velocity after the collision.
the distance between the sun and moon is 480 light second. convert the distance into meter
Answer:
1.439 × 10¹¹ m is the answer.
Explanation:
1 light-second = 2.998 × 10⁸m
480 light-seconds = 480 × 2.998 × 10⁸
= 1439.04 × 10⁸
= 1.439 × 10¹¹
∴ 1.439 × 10¹¹ m is the answer.
The distance converted into the meter will be 1.439×10¹¹ m.In one light second, there are 2.998 ×10⁸ m.
What is the distance?Distance is a numerical representation of the distance between two objects or locations.
The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
The given data in the problem is;
The distance between the sun and moon is,d= 480 light second
[tex]\rm d_m[/tex] is the distance in meter
As we know,
[tex]\rm 1\ light\ second = 2.998 \times 10^8m \\\\ 480\ light\ seconds = 480 \times 2.998 \times 10^8\ m \\\\ d_m= 1439.04 \times 10^8 \\\\ d_m = 1.439 \times 10^{11}[/tex]
Hence the distance converted into the meter will be 1.439×10¹¹ m.
To learn more about the distance refer to the link;
https://brainly.com/question/26711747
Simple harmonic motion occurs when an object is displaced from its stable equilibrium position and the force or torque pushing it back toward equilibrium is ______ in displacement. Group of answer choices exponential sinusoidal quadratic linear
Answer:
force is of the LINEAR type
Explanation:
In simple harmonic movements the restoring force is of the Hooke e-force type, which has the form
F = - k (x-x₀)
where x₀ is the initial length of the spring.
Therefore we can see this force is of the LINEAR type
What is the driving force behind the movement of Earth's plates?
Convection currents in the mantle are slowly causing the plates to move.
The magnetic pull of the poles are pulling the plates apart.
The inertia of the rotation of the Earth causes the plates to move.
The aliens are playing with the Earth like a puzzle.
Convection currents in the mantle are slowly causing the plates to move.
Which would result in an increase in the magnetic field strength produced by an electromagnet? A) increasing the space between the turns in the coil B) increasing the number of turns in the coil C) decreasing the current in the coil D) decreasing the voltage in the coil
Answer:
B) increasing the number of turns in the
Explanation:
A) Increasing the space between the turns in the coil will decrease the number of coils. It will result in a decrease in the strength of the magnetic field because the strength of the magnetic field of an electromagnet is directly proportional to the number of coils.
B) Increasing the no. of turns in the coil will result in an increase in the strength of the magnetic field.
C) Strength of magnetic field is directly proportional to the magnitude of current passing through the electromagnet. Therefore, decreasing the current will decrease the strength of the magnetic field.
D) Decreasing the voltage will decrease the current and as a result, the strength of the magnetic field will also be decreased.
Hence, the correct option is:
B) increasing the number of turns in the
What type of reaction results in the formation of a salt?
True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil of wire changes.
Answer:
Yes, its true
Explanation:
hdheheishdhieijzuwhs
Answer: yes its true
Explanation:
nmo
Select the correct answer?
Answer:
The answer is d i think so yea
Explanation:
hope u hae a really good day
An ocean wave travels at 2.2m/s if the wavelength is 11 meters what’s the frequency of the wave in Hz
Answer:
0.2 Hz
Explanation:
f = v / λ.
Where f = frequency,
v = velocity/speed,
λ = wavelength.
f = v / λ →
f = 2.2m/s / 11 m
f = 2.2 / 11 [1 / s]
f = 1 / 5 [Hz]
f = 0.2 Hz
Which statement can be made about waves A and B? Wave A has a lower amplitude than Wave B. Wave A has a higher amplitude than Wave B. Wave A has a lower frequency than Wave B. Wave A has a higher frequency than Wave B.
Answer:
Wave A has a higher amplitude than Wave B.
Explanation:
please check the attached image for the waves
Answer:
b
Explanation:
got it right on edge
PLS HELP ME!!!
The engine cars that pull high-speed trains usually taper to a point in front, as shown in the illustration. How does this shape change the forces acting on the moving engine car?
Convertir 0.3 Hm en cm.
Answer:
3000 cm
Explanation:
List and discuss 5 importances
of land-
While traveling along a highway a driver slows from 31 m/s to 15 m/s in 8 seconds. What is the automobile’s acceleration? (Remember that a negative value indicates a slowing down or deceleration.)
Answer:
The automobile's acceleration in that time interval is -2 m/s^2
Explanation:
The acceleration is defined as the rate of change of the velocity.
The average acceleration in a given lapse of time is calculated as:
A = (final velocity - initial velocity)/time.
In this case, we have:
initial velocity = 31 m/s
final velocity = 15 m/s
time = 8 seconds.
Then the average acceleration is:
A = (15m/s - 31m/s)/8s = -2 m/s^2
How has modern safety equipment found in automobiles helped to counteract Newton’s First Law of Motion?
Answer:
Well. the law says "an object in motion stays in motion" So seatbelts could be one. they stop us humans from continuing to move when the car stops.
pls help with science!!!!!
Answer:
Your answer is C~
Explanation:
A negative charge of - 0.0005 C exerts an attractive force of 7.0 N on a second charge that is 10 m away. What is the magnitude of the second charge?
Answer:
the magnitude of the second charge is 0.000156 C.
Explanation:
Given;
mangitude of the first charge, q₁ = 0.0005 C
attractive force between the two charges, F = 7.0 N
distance between the two charges, r = 10 m
let the magnitude of the second charge = q₂
The magnitude of the second charge is calculated by applying Coulomb's law;
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
Where;
K is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]q_2 = \frac{Fr^2}{kq_1} \\\\q_2 = \frac{7 \times \ 10^2}{(9\times 10^9)(0.0005)} \\\\q_2 = 0.000156 \ C[/tex]
Therefore, the magnitude of the second charge is 0.000156 C.
What type of specialized cell in the eye is used for detecting low levels of light?
Answer:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
Answer:
Rods
Explanation:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
Can someone help me with this please