Please help me I only need d. ​

The opposite sides are parallel.

Their angle measures add to 360°

Answer:

A. Increasing by 4%.

Step-by-step explanation:

Answer:

A) The price of product A is increasing by 3% per year.

(B) The product A recorded a greater percentage change in price over the previous year.

Step-by-step explanation:

(A)

The function representing the price, in dollars, of product A after x years is:

FA(x)=0.69*(1.03)x

The function  FA(x)can be written as:

FA(x)=0.69*1+(0.03)x

The function FA(x) is similar to the exponential growth function, y=a(1+r)x .

Here r is the growth rate.

Thus, it can be said that the price of product A is increasing by 3% per year.

(B)

Consider the data of product B for the year 3 and 4.

The price of product B for year 3 and 4 are 10,303.01 and 10,406.04.

Compute the percent price change from year 3 to 4 as follows:

10406.04-10303.01/10303.01*100

which is 0.999%

~1%

The price of product B is increasing by 1% per year.

Thus, the product A recorded a greater percentage change in price over the previous year.

Answer:

Did this help?

Step-by-step explanation:

Answer:

multiply 75.4 by 60 =4,524

hola'

your answer is going to be 2.22 or 0.002 i think .

Answer:

0.75

Step-by-step explanation:

There are 3 favorable outcomes (pink, green, or blue).

There are 4 possible outcomes since there are 4 equal sectors.  

​

P(not purple)=3/4 =0.75

Answer:

$360

Step-by-step explanation:

Find 3% of 500 = 15

Multiply 15 by 24 = 360

Answer:

6(x - 3 ) = 6x - 18

2(3x - 3) = 6x - 6

Step-by-step explanation:

a)  the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 3, (n+1)² > n³

b) the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 4, 2⁽ⁿ⁺²⁾ > 3ⁿ.

(a) To prove the statement for every integer n such that 0 ≤ n < 3, (n+1)² > n³ using proof by exhaustion, we will evaluate the inequality for each value of n within the given range.

For n = 0:

(0+1)² > 0³

(1)² > 0

1 > 0 - This is true.

For n = 1:

(1+1)² > 1³

(2)² > 1

4 > 1 - This is true.

For n = 2:

(2+1)² > 2³

(3)² > 8

9 > 8 - This is true.

Since the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 3, (n+1)² > n³

(b) To prove the statement for every integer n such that 0 ≤ n < 4, 2⁽ⁿ⁺²⁾ > 3ⁿ using proof by exhaustion, we will evaluate the inequality for each value of n within the given range.

For n = 0:

2⁽⁰⁺²⁾ > 3⁰

2² > 1

4 > 1 - This is true.

For n = 1:

2⁽¹⁺²⁾ > 3¹

2³ > 3

8 > 3 - This is true.

For n = 2:

2⁽²⁺²⁾ > 3²

2⁴ > 9

16 > 9 - This is true.

For n = 3:

2⁽³⁺²⁾ > 3³

2⁵ > 27

32 > 27 - This is true.

Since the inequality holds true for all values of n within the given range, we can conclude that for every integer n such that 0 ≤ n < 4, 2⁽ⁿ⁺²⁾ > 3ⁿ.

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The function f(x) is discontinuous at x = 0 and x = 1.To determine the points of discontinuity, we need to look at the different intervals defined by the function.

At x = 0, the function has different definitions for the left and right sides of the point. For x < 0, f(x) = x + 3, and for x ≥ 0 and x ≤ 1, f(x) = 3x^2. Therefore, at x = 0, f(x) is discontinuous. It is continuous from the left (approaching from x < 0) and from the right (approaching from x > 0).

At x = 1, the function has different definitions for the left and right sides of the point. For x ≤ 1, f(x) = 3x^2, and for x > 1, f(x) = 3 - x. Therefore, at x = 1, f(x) is discontinuous. It is continuous from the left (approaching from x ≤ 1) and from the right (approaching from x > 1).

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Answer:

B

Step-by-step explanation:

Answer:

She will make a total commission of $1130+$325=$1445

Then 5% of $1445= $1445×5%=$72,75

Answer:

19

Step-by-step explanation:

ngl its kinda easy 5(2)+3(3) = 10+9 = 19

Answer:19

Step-by-step explanation:5x2=10+3x3=9 so 10+9=19

Answer:

The first choice is the correct one.

Step-by-step explanation:

The first choice is the correct one.  It starts with the base salary and then is multiplied by (1 + 0.02)^t, which is the correct formula for compounding once per year.

Step-by-step explanation:

In math the area of the parallelogram equal the base times the high

Where.....

A stand for (Area)

b stand for (Base)

h stand for (High)

Like shown in the photo above

I hope that is useful for you :)

Answer:

2/5x7

Step-by-step explanation:

The exact value of A in the general solution is 87/2 and B is 0

From the question, we have the following parameters that can be used in our computation:

y = Ax² + Bx + C

The differential equation is given as

y' = 87x

When y = Ax² + Bx + C is differentiated, we have

y' = 2Ax + B

So, we have

87x = 2Ax + B

By comparing both sides of the equation, we have

2Ax = 87x

B = 0

So, we have

2A = 87

B = 0

Divide both sides of 2A = 87 by 2

A = 87/2

B = 0

Hence, the value of A in the general solution is 87/2 and B is 0

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Answer:

-84

Step-by-step explanation:

Since m=-4, we can plug -4 into the expression and use PEMDAS

7(m - 8)

7((-4)-8)

7(-12)

-84

Answer:

y = -2x + 3

Step-by-step explanation:

If you do rise/run, you recognize that the slope of the line is -6/3, which = -2. You can also see that the y-intercept of the line is at 3.

The equation of a line is represented by y=mx+b, with m being the slope and b being the y-intercept value.

Just plug in -2 as m and 3 as b in y=mx + b, and you will get your answer.

Answer:

The correct answer would be D, it is a logarithmic function.

Step-by-step explanation:

a. the Laplace transform of a(t) is (28/s^2) + (3/s) + (4/s). b. the Laplace transform of b(t) is 5/s - 10/(s + 2) - 10/(s^3 + 2s^2).

a. To find the Laplace transform of a(t) = 28t + 3 + 4u(t), where u(t) is the unit step function, we can apply the linearity property and the transform of elementary functions.

Applying the linearity property, we can split the transform into three parts:

L{28t} + L{3} + L{4u(t)}

Using the transform of t (L{t} = 1/s^2), we get:

28/s^2 + 3/s + 4/s

Simplifying, we can combine the terms:

(28/s^2) + (3/s) + (4/s)

Therefore, the Laplace transform of a(t) is:

(28/s^2) + (3/s) + (4/s).

b. To find the Laplace transform of b(t) = 5 - 5e^(-2t)(1 + 2t), we can again apply the linearity property and the transform of elementary functions.

Applying the linearity property, we can split the transform into two parts:

L{5} - L{5e^(-2t)(1 + 2t)}

The transform of 5 is simply 5/s.

For the second part, we need to use the transform of e^(-at) and t.

The transform of e^(-at) is 1/(s + a), and the transform of t is 1/s^2.

Using these formulas, we get:

-5/(s + 2)(1 + 2/s^2)

Simplifying and combining terms, we have:

5/s - 10/(s + 2) - 10/(s^3 + 2s^2)

Therefore, the Laplace transform of b(t) is:

5/s - 10/(s + 2) - 10/(s^3 + 2s^2).

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Step-by-step explanation:

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Answer:

x = -1 /2= -0.5 y = 15 /10= 1.5

The given null and alternative hypotheses, Hoi 3.1 and Ha 3.1, indicate that the hypothesis test is a two-tailed test.

In hypothesis testing, the null hypothesis (Hoi) represents the claim or assumption that is being tested, while the alternative hypothesis (Ha) represents the opposing claim or the hypothesis that the researcher is trying to support. The directionality of the test is determined by the alternative hypothesis.

In this case, the null hypothesis is stated as Hoi 3.1, and the alternative hypothesis is stated as Ha 3.1. Without knowing the specific details of the hypotheses, it can be determined that the test is two-tailed based on the notation used. The presence of two distinct hypotheses (Hoi and Ha) indicates that the test considers both directions of the distribution.

A two-tailed test is used when the alternative hypothesis does not specify a particular direction of the effect or relationship being tested. It is designed to determine whether the observed results are significantly different from the null hypothesis in either the positive or negative direction.

Therefore, the correct answer is A. Two-tailed test.

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The derivative of the function y = x(6x + 1)⁵ is: dy/dx = (6x + 1)⁵ + 30x(6x + 1)⁴

To find the derivative of the given function, we can apply the rules of differentiation. Using the product rule, we differentiate each term separately and then add them together.

For the first term x, the derivative is simply 1.

For the second term (6x + 1)⁵, we apply the chain rule. The derivative of (6x + 1)⁵ with respect to x is 5(6x + 1)⁴ multiplied by the derivative of the inner function 6x + 1, which is 6.

Multiplying these derivatives together, we get (6x + 1)⁵ * 6 = 6(6x + 1)⁵.

For the third term x(6x + 1)⁴, we again apply the product rule. The derivative of x is 1, and the derivative of (6x + 1)⁴ is 4(6x + 1)³ multiplied by the derivative of the inner function 6x + 1, which is 6.

Multiplying these derivatives together, we get x * 4(6x + 1)³ * 6 = 24x(6x + 1)³.

Finally, we add the derivatives of each term to get the derivative of the entire function: dy/dx = (6x + 1)⁵ + 30x(6x + 1)⁴.

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Complete question:

Use the rules of differentiation to find the derivative of the function y= x(6x + 1)⁵

(6x + 1)⁵ + 30x(6x + 1)⁴

(6x + 1)⁴ (36x + 1)

x-1/6

No correct answer provided.

Answer:

It's exponential

Step-by-step explanation:

Answer:

You did not take the picture correctly, try taking it again

Step-by-step explanation:

I can’t seeeee

The value of the line integral ∫c f · dr is -cos(1) i - sin(1) j + 1/6 k.

Evaluate the integral?

To evaluate the line integral ∫c f · dr, we need to substitute the given values of f(x, y, z) and r(t) into the integral expression.

[tex]f(x, y, z) = sin(x) i cos(y) j\ x(z) k[/tex]

[tex]r(t) = t^4 i - t^3 j + t k[/tex] ,  0 ≤ t ≤ 1

The line integral becomes:

[tex]\int c f * dr = \int c (sin(x) i cos(y) j x(z) k) * (dx i + dy j + dz k)[/tex]

Substituting [tex]x = t^4,\ y = -t^3, and\ z = t:[/tex]

[tex]\int c f * dr = \int c (sin(t^4) i cos(-t^3) j (t^4)(t) k) * (4t^3 dt i - 3t^2 dt j + dt k)[/tex]

Simplifying the expression:

[tex]\int c f * dr = \int c (4t^3 sin(t^4) dt i - 3t^2 cos(t^3) dt j + t^5 dt k)[/tex]

Integrating each component separately:

[tex]\int c f * dr = (\int 0^1 4t^3 sin(t^4) dt) i - (\int 0^1 3t^2 cos(t^3) dt) j + (\int 0^1 t^5 dt) k[/tex]

Evaluating each integral:

[tex]\int c f * dr = [-(cos(t^4))][/tex] evaluated from 0 to [tex]1 i - [sin(t^3)][/tex] evaluated from 0 to [tex]1 j + [t^6/6][/tex] evaluated from 0 to 1 k

Simplifying the expression:

[tex]\int c f * dr = -cos(1) i - sin(1) j + 1/6 k[/tex]

Therefore, the value of the line integral  [tex]\int c f * dr\[/tex]  is  [tex]-cos(1) i - sin(1) j + 1/6 k.[/tex]

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