PLEASE HELP ME, I AM DESPERATE

PLEASE HELP ME, I AM DESPERATE
PLEASE HELP ME, I AM DESPERATE
PLEASE HELP ME, I AM DESPERATE
PLEASE HELP ME, I AM DESPERATE
PLEASE HELP ME, I AM DESPERATE

Answers

Answer 1

Explanation:

for the first one go to the website mathaway and just put the equation in and you would press graph.


Related Questions

A bowling ball rests on the floor. The bowling ball is given a push.




Which of the following is the most likely change to happen to the bowling ball?
It will move.

It will gain mass.

It will change colors.

It will change shape.

Answers

Answer:

A. It will move.

This is agree or disagree I need help ASAP!!

Answers

all of them are agree :)
I’m pretty sure all of them are agree

PLEASE HELPPPPPPPP
Why do organic materials decompose so slowly inside of a landfill? List 3 factorsthat are required for biodegradation

Answers

Answer:

3 factors that are required for biodegradation are

a) Appropriate moisture

b) Oxygen supply  

c) Stable condition

Explanation:

For biodegradation in a landfill, following conditions are essential –  

a) Appropriate moisture

b) Oxygen supply  

c) Stable condition

Contrast to above three conditions, the waste in landfill is kept dry, devoid of oxygen supply, and stirred continuously due to which the organic matter mummify instead of decomposing.  

You are on vacation with your family up in the mountains. Your friend is on vacation near the equator by the ocean. Explain which climate will experience the most precipitation.

A.) Both climates will have the same amount of precipitation.

B.)The ocean climate will have less precipitation because it is close to sea level.

C.)The climate around the equator will have more precipitation because it is very hot.

D.)The mountain climate will have more precipitation because it increases with elevation.

Answers

Answer:

I gonna go wit number C

Explanation:

Answer: C

Explanation:

Determine from the balanced chemical reaction if
the derived mole ratio is correct or incorrect.
2FeBr3 + 3Na2S → Fe2S3 + 6NaBr
2 moles FeBra
3 moles Na2S

Answers

Answer:

Correct

Explanation:

According to the balanced chemical reaction, 2 mol FeBr3 are consumed for every 3 mol Na2S consumed.

A balanced equation obey the law of conservation of mass. The coefficients are the numbers which are added to balance the chemical equation. Here the given mole ratio is correct.

What is a balanced equation?

An equation in which the number of atoms of reactants and products on both sides of the equation are balanced is defined as the balanced chemical equation. The coefficients which are added in front of the formula of each component represents the number of the species.

A molar ratio denotes the ratio between the amounts in moles of any two compounds involved in a balanced chemical reaction. By comparing the coefficient of each component, the mole ratio can be determined.

Here for the given reaction, for every 3 moles of Na₂S consumption 2 moles of FeBr₃ is also consumed. So the molar ratio of Na₂S to FeBr₃ is 2/3. Molar ratios are used as the conversion factors between products and reactants in many chemistry problems.

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HELPPPP PLEASEE 50 POINTS
A graph labeled Solubility versus Temperature for a variety of salts has Temperature from 0 to 100 on the x axis and solubility in grams per 100 grams of water from 0 to 90 on the y axis. 5 solutes are shown. All data are approximate. Upper N a Upper C l starts at (0, 35) and rises evenly across the graph to (100, 40). Upper N a Subscript 2 Baseline Upper H Upper A s Upper O Subscript 4 Baseline starts at (0, 8), and rises steadily through (30, 38) to (80, 85). Upper B a (Upper N Upper O Subscript 3) Subscript 2 Baseline starts at (0, 5) and rises steadily across the graph to (100, 33). Upper N a Subscript 2 Baseline Upper S Upper O Subscript 4 Baseline starts at (0, 5), curves up steeply to (30, 50), and declines slowly to (100, 43). Upper C e Subscript 2 Baseline (Upper S Upper O Subscript 4) Subscript 3 Baseline times 9 Upper H Subscript 2 Baseline Upper O starts at (0, 19), falls to (20, 10), and continues to decline to (100, 0).
What is the solubility of Na2HAsO4 at 60°C?

20 g/100 mL of water
46 g/100 mL of water
65 g/100 mL of water
70 g/100 mL of water

Answers

Answer:

65 g/100 mL of water

Explanation:

Answer:

65g/100ml of water.

Explanation:

Edge 2021.

Is a 3.3% solution dilute or concentrated?



Dilute



Concentrated

Answers

Answer:

Dilute

Explanation:

A concentrated solutions is a one which has relatively large amount of dissolved solute in the solution whereas a dilute solution is a one which has relatively lower concentration of dissolved solute.

In the given solution there is only 3.3% of solute. So, we can say that the given solution is a dilute solution. However, these terms are relative.

how many Na atomd are shown in the reactants​

Answers

Answer:

On the reactant side, there are two H atoms and two O atoms

A 20 ml of 0.27M of solution of the salt NaA has a pH of 8.70. Calculate the pKa value of the acid HA.

Answers

Answer:

pKa = 3.97

Explanation:

Let's state the equations:

NaA →  A⁻  +  Na⁺

A⁻ + H₂O  ⇄  OH⁻  +  HA    Kb

We don't have the concentration of [OH⁻] but we do know pH, so we can determine, pOH and after that, [OH⁻].

14 - pH = pOH → 14 - 8.70 = 5.30

10^-pOH = [OH⁻]  → 10⁻⁵'³⁰ = 5.01×10⁻⁶ M

Initially we can know, the moles of base, we had.

20 mL . 0.27M = 5.4 mmoles. So now, let's make the expression for Kb.

Kb = [OH⁻] . HA / [A⁻]

As the [OH⁻]  is so low, we can assume, there where no loses and the salt is well concentrated. So:

Kb = (5.01×10⁻⁶)² / 0.27 → 9.29×10⁻¹¹

Kw = Ka . Kb, then Ka = Kw/ Kb

Ka = 1×10⁻¹⁴ /9.29×10⁻¹¹ = 1.08×10⁻⁴

pKa = - log Ka → - log 1.08×10⁻⁴ = 3.97

Which one of the following compounds is insoluble in water?

a) Na2CO3

b) K2SO4

c) Fe(NO3)3

d) ZnS

Answers

Answer: ZnS

Explanation: usually salts of alkali metals are well soluble in water.

Also most nitrates are well soluble.

Sulfides of transition metals are generally insoluble in water

Zinc sulfide is a compound which is insoluble in water as it is a  sulfide salt of transition metal which are water-insoluble.

What is a compound ?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.

Learn more about compounds,here:

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A sample of neon gas is at a temperature of 60°C and has a volume of 300 cm. What is the volume of the gas if it is heated to 100°C at a constant pressure?​

Answers

Answer:

336.04 cm

Explanation:

T1 = 60+273 = 333K

T2 = 100+273 = 373K

V2 = (V1×T2)/T1

V2 = 300×373/333

V2 = 336.04 cm

A pH scale has how many sections on it?

Answers

Answer:

0-14

Explanation:

How much water would I need to add to a 175 mL of a 0.45 M KOH solution to make a 0.2 M solution?

Answers

Answer:

393.75mL

Explanation:

We know that

C1V1= C2V2

where C = centration, V= volume

C1= 0.45 M

V1= 175 mL = 0.175 L

C2 = 0.2M

⇒V2= C1V1/C2

⇒V2 = 0.175×0.45/0.2

=0.39375L

Therefore, amount of water needed= 393.75mL

A 20.0 mL of 0.27 M solution of the salt NaA has a pH of 8.70.

a) Calculate the pk, value of the acid HA.


(Correct to 3 sig. fig)

b) Calculate the pH of a solution containing 0.3 M HA and 0.1 M NaA.


(Correct to 3 sig. fig)



Thanks!!

Answers

Answer:

a) 3.969

b) 3.487

Explanation:

Given data:

m =  0.27 M

pH = 8.7

a) Calculate PKa of acid HA

pH value = 1/2 ( Pkw + Pka + log C )

    8.7 * 2 = 14 + log C + Pka

        17.4 = 14 + log ( 0.27 ) + Pka

∴Pka = 17.4 - 14.5686 = 3.9686 ≈ 3.969

b) Calculate the pH of solution

pH = pKa + log ( salt / acid )

     = 3.9686 + log ( 0.1 / 0.3 )

     = 3.487

please help me ASAP!

Answers

Answer:

let me tell u what ASAP stands for Explanation:

HELP MY FRIEND NEEDS HELP WITH THIS!!!!!!

can somebody please help? I'm asking for a friend

If 263 ml of a gas is collected at 47°c and 2.77 atm, what will the final temp be in C if the volume decreases to 195 mL and the pressure increases to 3.87 atm?​

Answers

Answer:

Oh hey sorry, they deleted my account again..

Explanation:

A certain concentration of water in the air is needed for the reactions that cause wood to decay. Furniture can rot away very quickly in the jungle Furniture high in the mountains usually does not rot easily. This data table shows the rates of decay for a wooden chair to rot away. What can you conclude about the rates of these reactions? Object Location Decay time Average concentration of water in the air Wooden chair Very low 300 to 500 years Rocky mountaintop Wooden chair Jungle High 5 to 20 years O A. Reactions occur at the same rate, no matter what the concentration of water in the air. O B. Reactions occur more quickly in air with a high concentration of water. O C. Reactions occur more slowly in air with a high concentration of water D. There is not enough information to conclude anything about the reaction rates​

Answers

Reactions are faster when air contains a higher concentration of water.

High temperature and high relative humidity are very important factors that drive a reaction in which biomass decays. At high temperature and high relative humidity, decomposition occurs faster.

Hence, from the data presented, we can see that, reactions occur more quickly in air with a high concentration of water.

Learn more about decay: https://brainly.com/question/14437985

What body system changes the food we eat into energy?

Answers

Answer:

We need food to fuel our bodies for energy, growth and repair. The digestive system converts the foods we eat into their simplest forms, like glucose (sugars), amino acids (that make up protein) or fatty acids (that make up fats).Explanation:

hopes its right

HELP!! 30 POINTS!!!! What does the energy graph look like for this reaction??
C3H8+5O2 -> 3CO2+4H2O

I have the data, I just need to know how to make the graph, please!!

total enthalpy of reactants= -103.85
total enthalpy of products= =-2147.81
=-2043.96 kJ/mol exothermic reaction

Answers

=2043.96 kJ/mol exothermic reaction

Answer:

Bottle Nose Dolphin ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

Which of the following is an example of a tissue A chloroplast
B stomach
C human
D bone​

Answers

Answer:

In plants, chloroplasts occur in all green tissues, though they are concentrated particularly in the parenchyma cells of the leaf mesophyl. An example of a chloroplast is a cell in algae that consumes carbon dioxide and releases oxygen while creating sugar. A plastid that contains chlorophyll and is found in the cells of green plants and algae.

Explanation:

please mark brainlest

Answer: I would say C or D.

Explanation: Maybe because there are four main tissue types in the body: epithelial, connective, muscle, and nervous. Each is designed for specific functions.

In chloroplast it is the structure within the cells of plants and green algae.

In stomach tissue has a thin simple columnar epithelial layer for secretion and absorption.

In bone tissue it is tissue that gives strength and structure to bones. Bone is made up of compact tissue (the hard, outer layer) and cancellous tissue (the spongy, inner layer that contains red marrow). Bone tissue is maintained by bone-forming cells called osteoblasts and cells that break down bone called osteoclasts.

Give the following acid/base reaction:

HI(aq) + NH3(aq) ↔ NH4+(aq) + I-(aq)

Determine which substance is the acid, base, conjugate acid, and conjugate base.

Column A Column B:
1. Acid 1: I-
2. Base 2: HI
3. Conjugate base 3: NH3
4. Conjugate acid 4: NH4+

Answers

Answer:

6=100  

Explanation:

what is the pH when h+=0.045 M?

Answers

Answer:

pH≈1.35

Explanation:

-log(0.045)≈1.35

Which is a correct set of values of m for one of the subshells of n = 2?
–1, 0, 1
–1, –2, 0, 1, 2
–1, –2, –3, 0, 1, 2, 3
–1, –2, –3, –4, 0, 1, 2, 3, 4

Answers

Answer:

-1, 0, +1

Explanation:

n = 2 n = 0,1,2,3,.................n

l= n-1 = 2-1 =1. l= 1,2,3,4....................n-1

m = l is 1 so now write the value of magnetic moment as -1,0,+1

for eg . if the value of l comes to 2 then u will write the value of m as -2,-1,0,+1,+2 .

i hope it will help u .....

Given : 4.50 molte

How many moles of ammonia would you get if 4.50 moles of hydrogen gas
reacted

Answers

you would get 35.................

The equilibrium constant, Kc, for the reaction below is 0.10 at 25oC. Find the equilibrium concentration of chlorine gas, Cl2(g), if the equilibrium concentrations of ICl(g) and I2(g) are known to be 0.50 M and 0.40 M respectively.

2 ICl(g) → Cl2(g) + I2(g)

Answers

Answer:

The equilibrium concentration of chlorine gas, Cl₂(g), is 0.0625 M

Explanation:

Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed, so that no changes are observed as time passes, despite the fact that the substances present continue to react with each other.

The mathematical expression that represents Chemical Equilibrium is known as the Law of Mass Action and is stated as: The ratio of the product of high concentrations to the stoichiometric coefficients in the reaction of products and reactants remains constant at equilibrium. For any reaction:

aA + bB ⇄ cC + dD

the equilibrium constant Kc is calculated as:

[tex]Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b}}[/tex]

In this case, you have:

2 ICl(g) → Cl₂(g) + I₂(g)

So, the equilibrium constant Kc is:

[tex]Kc=\frac{[Cl_{2} ]*[I_{2} ]}{[ICl]^{2} }[/tex]

Being:

Kc= 0.10[Cl₂]= ?[ICl]= 0.50 M[I₂]= 0.40 M

Replacing:

[tex]0.1=\frac{[Cl_{2} ]*0.40 M}{(0.50 M)^{2} }[/tex]

Solving:

[tex]0.1=\frac{[Cl_{2} ]*0.40 M}{0.25 M^{2} }[/tex]

0.1= 1.6 [tex]\frac{1}{M}[/tex]* [Cl₂]

[Cl₂]= 0.1 ÷ 1.6 [tex]\frac{1}{M}[/tex]

[Cl₂]= 0.0625 M

The equilibrium concentration of chlorine gas, Cl₂(g), is 0.0625 M

The equilibrium concentration of chlorine gas, if the equilibrium concentrations of ICl(g) and I₂(g) are known to be 0.50 M and 0.40 M respectively is 0.0625M.

How we calculate the equilibrium constant?

Equilibrium constant for any reaction will be define as the ratio of the concentration of products to the concentration of reactants with raise to their respective coefficients.

Given chemical reaction is:

2ICl(g) → Cl₂(g) + I₂(g)

Equilibrium constant for this reaction will be calculated as:

Kc = [Cl₂][I₂] / [ICl]², where

Kc = equilibrium constant = 0.10

[I₂] = concentration of iodine gas = 0.40 M

[ICl]² = concentration of ICl = 0.50 M = (0.50M)² = 0.25M²

[Cl₂] = concentration of chlorine gas = to find?

On putting all these values on the above equation and calculate for the value of [Cl₂] as follow:
[Cl₂] = Kc × [ICl]² / [I₂]

[Cl₂] = (0.10)(0.25) / (0.40)

[Cl₂] = 0.0625M

Hence, equilibrium concentration of chlorine gas is 0.0625M.

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Which statement correctly describes electrochemical cells?

A. Electrochemical cells involve only oxidation reactions.

B. Electrochemical cells involve only reduction reactions.

C. Electrochemical cells involve oxidation-reduction reactions.

D. Electrochemical cells do not involve oxidation-reduction reactions.​

Answers

Answer: C. Electrochemical cells involve oxidation-reduction reactions.

Explanation: Oxidation occurs at the anode, and reduction occurs at the cathode.

Can someone help me please?!!!!!

Answers

Answer: C, B, D (not sure about this one sorry) and C

Explanation:

What does the symbol NaCl(aq) mean?

Answers

Answer:

The (aq) means that the NaCl is dissolved in water.

Explanation:

Answer:

A water-based solution of sodium chloride

Explanation:

ck12

help pls this is physical science (9th grade )

Answers

Answer:

mamamkalalllaamakkaoakmaa

Which of the following compounds, sodium bicarbonate or water, should be used to extinguish a grease fire?

Answers

Answer:Douse the fire with baking soda: The chemical compound sodium bicarbonate, commonly called baking soda, is effective for extinguishing this type of fire. It takes a lot of baking soda to smother a grease fire, so pour it on while the flames are still small for the greatest effect

Explanation:

The grease fire has been put down by the addition of sodium bicarbonate as the extinguisher.

Grease fire has been defined as the fire that has been started with the over heating of the cooking oil at home. The fire has been started with the burning of the flammable liquids.

Extinguishing Grease fire

The fire in the cooking oil has been controlled with the addition of the sheet over the fire and turning off the flame.

The addition of water to grease fire results in the splashing of water over the fire and the spreading, resulting in the hazardous effects.

The sodium bicarbonate or baking soda has been used to put down grease fire.

Learn more about grease fire, here:

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