(Please Help Im blowing most of my points for this)

In earthquake-prone areas, engineers design buildings that are resistant to earthquake damage. Here’s a diagram of an earthquake-resistant building in Japan. Explain how features A, B, and C help protect the building from earthquake damage. In your explanation, describe how you could model each feature using marshmallows and toothpicks.

The daughter element is produced from the beta decay of ¹⁴⁵₅₆Ba is ¹⁴⁵₅₇La.

A beta particle is emitted from the nucleus of an atom during radioactive decay. The electron, however, occupies regions outside the nucleus of an atom.

Beta particle has no mass and minus charge on itself.

Radioactive decay equation for the Barium is shown as follow:

¹⁴⁵₅₆Ba → ¹⁴⁵₅₇La + °₋₁β

The daughter element which is produced from the from reaction is Lanthanum.

Hence, ¹⁴⁵₅₇La is the daughter element.

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Answer:

Total pressure = 10 atm

Explanation:

The excersise can help to understant the concept of mole fraction

Mole fraction is defined as:

moles of gas / Total moles = pressure of that gas / Total pressure

Both can be summed.

Sum of moles of each gas in the mixture = Total moles

Sum of pressures of each gas in the mixture = Total pressure

Those, are laws for gases.

Total moles: 3 mol of gas A + 4 moles of gas B + 5 moles of C

                 = 12 total moles

Pressure of A is 2.5 atm.

We replace data at the mole fraction relation

moles of A / total moles = Pressure of A  / Total pressure

3 moles / 12 moles = 2.5 atm / Total pressure

Total pressure = 2.5 atm / (3mol/12mol)

Total pressure = 10 atm

Answer:

Tin exists in two oxidation states, +4 and +2. Elemental tin is readily oxidized to the dipositive ion in acidic solution, but this Sn2+ ion is converted to the Sn4+ ion by many mild oxidizing agents, including elemental oxygen. Oxidation under alkaline conditions normally gives the tetrapositive (Sn4+) state.

Answer:

The heat required, to burn a hole 15 cm in diameter through the iron door is 34,370.050 kJ

Explanation:

The information given on the door are;

The thickness of the door, t = One-meter

The diameter of the hole to be burnt out, d = 15 cm = 0.15 m

The latent heat of fusion of iron, [tex]H_f[/tex] = 247 kJ/kg

The density of iron, ρ = 7.874 g/cm³ = 7874 kg/m³

The volume of the iron to be melted off, V = π·d²/4 × t

∴ V = (π × 0.15²/4) × 1 ≈ 0.01767145867

The volume of the iron to be melted off, V ≈ 0.01767145867 m³

The mass of the iron to be melted off, m = ρ × V

∴ m = 7874 kg/m³ × 0.01767145867 m³ ≈ 139.145066 kg

The mass of the iron to be melted off, m ≈ 139.15 kg

The heat required, to melt the mass of iron at the melting point temperature and burn a hole 15 cm in diameter, ΔH, is given as follows;

ΔH = [tex]H_f[/tex] × m

∴ ΔH = 139.15 kg × 247 kJ/kg = 34,370,050 J = 34,370.050 kJ

The heat required, to burn a hole 15 cm in diameter through the iron door ΔH = 34,370.050 kJ.

Answer:

Copper(II) nitrate and silver

Explanation:

2AgNO₃(aq )  +  Cu  (s) -->  Cu(NO₃)₂(aq ) +  2Ag(s)

This can be called a redox reaction because silver nitrate is reduced and copper is oxidized.  This can also be called a single replacement reaction because copper replaces silver in the substance silver nitrate.

The functional group to which the molecule belongs is the carbonyl group.

A functional group refers to an atom, group of atoms or bond which is responsible for the chemical reactivity of a particular homologous series.

From the image of the molecule that has been shown in the question, the functional group to which the molecule belongs is the carbonyl group.

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Answer:

A

Explanation:

got it right in app filler filler filler filler

Answer:

20KJ

Explanation:

We know that heat required to raise the temperature of substance is given by

thermal energy Q= mass(m) × specific heat capacity(c) × change in temperature.(ΔT)

Q = mcΔT

given data: mass m = 2kg , c = 2000j/Kg°C and ΔT = 120-20 =100°C

Therefore, Q = 2×2000×100 = 20000 J = 20KJ

Hence, 20KJ heat is required to to heat 2 kg of cooking oil with a specific heat capacity of 2000 from 20 to 120 [ Units have been assumed as per convenience)

Answer:

Using two coils of wire wrapped around an iron core produces an input voltage and output voltage.

Explanation:

Answer:

c. floodplain

Explanation:

brainliest please!

Answer:

I think the answer is floodplain.

Explanation:

I hope this helps, have a blessed day.

Answer:

Option b which is n equal to 3

Answer:

26.56g

Explanation:

The half life of an isotope decay is the time transcurred when the initial amount of the isotope decays to the half of its amount.

For the problem, when 1 half life transcur, the sample has a mass of:

425g / 2 = 212.5g

When 2 half lives transcur:

212.5g / 2 = 106.25g

3 half lives:

106.25/2 = 53.13g

And the amount that is found after 4 half lives is:

53.13/2 =

B. Lakes fill to overflowing

Answer:

bacteria spoiling food

hope this helps

have a good day :)

Explanation:

Answer:

what language do you speak?

Explanation:

electrovalent bond covers single bond.

Covalent bond covers double or more bonds.

Answer:

side to side?

Explanation:

Answer:

hola no ablo inglés porfavor

Answer: It is important to wash it becasue that way you can disinfect the cut and protect the cut from any infections.

Answer:

This will reduce the risk of infection and help stop the bleeding. It gets rid of the bacteria that may have been there. But, it is very important to disinfect it and clean it properly after the bleeding stops.

Answor

c                                              

Explanation:

Answer:

I think the answer would be 'testable'.

Answer: what do i have to do to help.. ;-; like i need instructions and why are the words coverd off black??

;-;

Explanation:

Answer:

The unit of Atomic mass is "amu"

Explanation:

Atomic mass unit

Answer: The pressure is 2.14 atm if the gas was heated to 373 K and the volume decreased to 1.90 L.

Explanation:

Given: [tex]V_{1} = 2.50 L[/tex],      [tex]P_{1} = 1.34 atm[/tex],       [tex]T_{1} = 308 K[/tex]

[tex]P_{2} = ?[/tex] ,            [tex]V_{2} = 1.90 L[/tex],          [tex]T_{1} = 373 K[/tex]

Formula used to calculate the final pressure is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1.34 atm \times 2.50 L}{308 K} = \frac{P_{2} \times 1.90 L}{373 K}\\P_{2} = \frac{1.34 atm \times 2.50 L \times 373}{308 K \times 1.90 L}\\= 2.14 atm[/tex]

Thus, we can conclude that the pressure is 2.14 atm if the gas was heated to 373 K and the volume decreased to 1.90 L.