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The nth term of the pattern is (n²-1)

To find the nth term identify the patterns in a given sequence and use algebraic expressions to generalize the pattern and find the nth term.

By observing the given series we say that each number is one less than perfect Like 8 is one less than 9, 15 is one less than 16, etc. Use this condition to solve the problem.

Here we have

0, 3, 8, 15...    

To find the nth terms identify the patterns in a given sequence

Here each term can be written as follows

1st term => 0 = (1)² - 1 = 0

2nd term => 3 = (2)² - 1 = 3

3rd term => 8 = (3)² - 1 = 8

4th term => 15 = (4)² - 1 = 15

Similarly

nth term = (n)² - 1 = (n²-1)

Therefore,

The nth term of the pattern is (n²-1)

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The transition matrix from b to b' is  P = [2 1, 4 3]

To find the transition matrix from b to b', we need to find the matrix P such that P[b] = b'.

First, we need to express the elements of b' in terms of the basis b. To do this, we solve the equation x[1](1,0) + x[2](0,1) = (2,4) for x[1] and x[2]. This gives us x[1] = 2 and x[2] = 4. Similarly, we solve the equation y[1](1,0) + y[2](0,1) = (1,3) for y[1] and y[2]. This gives us y[1] = 1 and y[2] = 3.

Now, we can construct the matrix P using the coefficients we just found. The columns of P are the coordinate vectors of the elements of b' expressed in terms of the basis b.

P = [x[1] y[1], x[2] y[2]]
 = [2 1, 4 3]

Therefore, the transition matrix from b to b' is  P = [2 1, 4 3]

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Answer:

height = 10 m

lengths of bases = 5 m and 10 m

[tex] \frac{1}{2} (10)(5 + 10) = 5(15) = 75[/tex]

So the area of this trapezoid is 75 square meters.

Check the picture below.

[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ a=5\\ b=10\\ h=10 \end{cases}\implies A=\cfrac{10(5+10)}{2}\implies A=75~m^2[/tex]

The expression e^(-3)(1+3+3^2/2!+3^3/3!+3^4/4!) equals the cumulative probability of 4 arrivals during an interval for which the average number of arrivals equals 3.

Here's a step-by-step explanation:

1. Recognize that the given expression represents the cumulative probability for a Poisson distribution.
2. Identify the average number of arrivals (λ) as 3, which is the exponent in the e^(-3) term.
3. Recognize that the terms inside the parentheses correspond to the Poisson probability mass function (PMF) for k=0, 1, 2, 3, and 4 arrivals.
4. Since the expression sums up the probabilities for k=0 to k=4, it represents the cumulative probability of 4 arrivals.
5. In summary, the expression represents the cumulative probability of 4 arrivals during an interval where the average number of arrivals is 3.

Given Set S is S spans P_2.

The set S = {1, x², 4 + x²} spans P_2 if every polynomial in P_2 can be expressed as a linear combination of 1, x², and 4 + x².

Let's consider a general polynomial in P_2, which has the form ax^2 + bx + c, where a, b, and c are constants. We need to determine if there exist constants k1, k2, and k3 such that:

ax² + bx + c = k1(1) + k2(x²) + k3(4 + x²)

Simplifying the right-hand side gives:

ax² + bx + c = (k2 + k3)x² + 4k3

For this equation to hold for all values of x, we must have a = k2 + k3, b = 0, and c = 4k3. Therefore, every polynomial in P_2 can be expressed as a linear combination of the elements in S if and only if we can find constants k1, k2, and k3 that satisfy these equations.

Solving the equations, we get:

k1 = 4k3 - a

k2 = a - k3

k3 is free

Since k3 is a free variable, we can choose it to be any value we like. This means that we can always find constants k1, k2, and k3 that satisfy the equations, and so S spans P_2.

Therefore, the answer is S spans P_2.

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Which class has the lowest median grade? Class 1

Which class has the highest median grade? Class 2

Which class has the lowest interquartile range? Class 1

When the correct time is 8 p.m. the following evening, the faulty watch, which gains 10 seconds an hour will show 8:04 p.m.

The time is determined using the mathematical operations of division and multiplication.

The time that the faulty watch gains per hour = 10 seconds

The total number of hours from 8 p.m. one evening to the next = 24 hours

The total number of seconds that the faulty watch must have gained during the 24 hours = 240 seconds (24 x 10)

60 seconds = 1 minute

240 seconds = 4 minutes (240 ÷ 60)

Thus, while the correct time is showing 8 p.m., the faulty watch will be showing 8:04 p.m.

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Answer:

Step-by-step explanation:

Using the least squares regression method, we obtain the equation of the regression line: y = 22.4x + 26.2. The y-intercept is the value of y when x = 0, which is 26.2. Therefore, the answer is d) 26.2.

The correct answer is d) can be used to predict a value of y if the corresponding x value is given. A least squares regression line is a statistical method used to find the equation of a line that best fits the data points. It can be used to predict the value of the dependent variable (y) for a given value of the independent variable (x).

The regression function is ŷ = 900 + 6x, where x is the advertising in $100s and ŷ is the sales in $1,000s. To find the point estimate for sales when advertising is $10,000, we substitute x = 100 in the regression function: ŷ = 900 + 6(100) = 1,500. Therefore, the answer is a) $1,500.

The least squares estimate of the y-intercept is 42.6.

An intercept is a point on the y-axis, through which the slope of the line passes. It is the y-coordinate of a point where a straight line or a curve intersects the y-axis. This is represented when we write the equation for a line, y = mx+c, where m is slope and c is the y-intercept.

Given that,

x    y

2   50

5   70

4   75

3   80

6   94

Calculate the means of x and y values:

x_mean = (2 + 5 + 4 + 3 + 6) / 5 = 20 / 5 = 4

y_mean = (50 + 70 + 75 + 80 + 94) / 5 = 369 / 5 = 73.8

Calculate the differences from the means for x and y:

x_diff = [2-4, 5-4, 4-4, 3-4, 6-4] = [-2, 1, 0, -1, 2]

y_diff = [50-73.8, 70-73.8, 75-73.8, 80-73.8, 94-73.8] = [-23.8, -3.8, 1.2, 6.2, 20.2]

Calculate the product of the x and y differences and the square of x differences:

xy_diff = [-2×(-23.8), 1×(-3.8), 0×1.2, -1×6.2, 2×20.2] = [47.6, -3.8, 0, -6.2, 40.4]

x_squared_diff = [-2², 1², 0², -1², 2²] = [4, 1, 0, 1, 4]

4. Sum up the product of the x and y differences and the square of x differences:

sum_xy_diff = 47.6 - 3.8 + 0 - 6.2 + 40.4 = 78

sum_x_squared_diff = 4 + 1 + 0 + 1 + 4 = 10

Calculate the slope (m):

m = 78 / 10 = 7.8

Use the slope (m) to find the least squares estimate of y-intercept (b) using the equation

b = 73.8 - 7.8 × 4 = 73.8 - 31.2

= 42.6

Therefore, the least squares estimate of the y-intercept is 42.6.

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1. The sequence (n+4)/n converges to 1 as n approaches infinity.
2. The sequence (n+8)/(n^2) converges to 0 as n approaches infinity.
3. The sequence tan((n(pi))/(4n+3)) oscillates and does not converge.
4. The sequence ln(3n/(n+1)) converges to ln(3) as n approaches infinity.
5. The sequence n^2/(sqrt(8n^4+1)) converges to 1/(sqrt(8)) = 1/4 as n approaches infinity.
6. The sequence (1+(1/n))^(5n) converges to e^5 as n approaches infinity.

1. The sequence converges. As n approaches infinity, (n+4)/n approaches 1.
2. The sequence converges. As n approaches infinity, (n+8)/(n^2) approaches 0.
3. The sequence converges. As n approaches infinity, tan((n*pi)/(4n+3)) approaches 0 since tan(n*pi) is 0 for all integer values of n.
4. The sequence converges. As n approaches infinity, ln(3n/(n+1)) approaches ln(3) as the leading terms dominate.
5. The sequence converges. As n approaches infinity, n^2/(sqrt(8n^4+1)) approaches 0 since the denominator grows faster than the numerator.
6. The sequence converges. As n approaches infinity, (1+(1/n))^(5n) approaches e^5 using the limit definition of e.

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The value of the  trigonometric expression tan(u + v) for the given values sin u=-8/17 and cosv=-3/5 as both u and v are in quadrant II is equal to 84/77.

In the trigonometric expression ,

sin u=-8/17

Both u and v are in quadrant II.

Draw a right angle triangle ,

opposite side = -8

Hypotenuse = 17

using Pythagoras theorem ,

Adjacent side

= √(Hypotenuse)² - ( opposite side)²

=√17² - (-8)²

= -15

cos u = -15 / 17

Now,

cos v=-3/5

Both u and v are in quadrant II.

Draw a right angle triangle ,

Adjacent side = -3

Hypotenuse = 5

using Pythagoras theorem ,

Opposite side

= √(Hypotenuse)² - ( Adjacent side)²

=√5² - (-3)²

= -4

sin v = -4/5

sin(u + v ) = sinu cosv + cosu sinv

Substitute the value,

⇒sin(u + v ) = (-8/17) (-3/5) + (-15/17) (-4/5)

⇒sin(u + v ) = ( 24 + 60 )/ 85

⇒sin(u + v ) =84/85

cos ( u + v) = cosu cosv−sinu sinv

⇒cos ( u + v) = (-15/17)(-3/5) - (-8/17)(-4/5)

⇒cos ( u + v) = ( 45 + 32 ) / 85

⇒cos ( u + v) = 77/85

This implies,

tan (u + v )

= sin ( u + v) / cos( u + v)

= (84/85)/(77/85)

= 84/77

Therefore, the value of the  trigonometric expression tan (u + v )  = 84/77.

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Answer:

y=4

Step-by-step explanation:

3×−4y=8(−2−4)

Multiply 3 and −4 to get −12.

−12y=8(−2−4)

Subtract 4 from −2 to get −6.

−12y=8(−6)

Multiply 8 and −6 to get −48.

−12y=−48

Divide both sides by −12.

y=

−12

−48

​

Divide −48 by −12 to get 4.

y=4

Answer:

X= - 12

Step-by-step explanation:

3x-4*3=-16-32

3x-12= - 48

3x= - 48+12

3x= - 36

X= - 36:3

X = - 12

The solutions to the recurrence relation an = 8an−1 − 16an−2 are:

a) {an = 0}

b) {an = 1}

c) {an = 2ⁿ}

d) {an = 4ⁿ}

g) {an = (-4)ⁿ}

A recurrence relation in mathematics is an equation that states that the last term in a series of integers equals some combination of the terms that came before it.

To determine if a sequence {an} is a solution of the recurrence relation an = 8an−1 − 16an−2, we need to substitute the sequence into the recurrence relation and see if it holds for all n.

a) If an = 0, then:

an = 8an−1 − 16an−2

0 = 8(0) − 16(0)

0 = 0

This holds, so {an = 0} is a solution.

b) If an = 1, then:

an = 8an−1 − 16an−2

1 = 8(1) − 16(0)

1 = 8

This does not hold, so {an = 1} is not a solution.

c) If an = 2n, then:

an = 8an−1 − 16an−2

2n = 8(2n−1) − 16(2n−2)

2n = 8(2n−1) − 16(2n−1)

2n = −8(2n−1)

2n = −2 × 2(2n−1)

This does not hold for all n, so {an = 2n} is not a solution.

d) If an = 4n, then:

an = 8an−1 − 16an−2

4n = 8(4n−1) − 16(4n−2)

4n = 8(4n−1) − 4 × 16(4n−1)

4n = −60 × 16(4n−1)

This does not hold for all n, so {an = 4n} is not a solution.

e) If an = n4n, then:

an = 8an−1 − 16an−2

n4n = 8(n−1)4(n−1) − 16(n−2)4(n−2)

n4n = 8(n−1)4(n−1) − 4 × 16(n−1)4(n−1)

n4n = −60 × 16(n−1)4(n−1)

This does not hold for all n, so {an = n4n} is not a solution.

f) If an = 2 ⋅ 4n/(3n4n), then:

an = 8an−1 − 16an−2

2 ⋅ 4n/(3n4n) = 8 ⋅ 2 ⋅ 4n−1/(3(n−1)4n−2) − 16 ⋅ 2 ⋅ 4n−2/(3(n−2)4n−4)

2 ⋅ 4n/(3n4n) = 16 ⋅ 4n−1/(3(n−1)4n−2) − 16 ⋅ 4n−2/(3(n−2)4n−4)

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (n−1) ⋅ 4n−1/n4n−2 − (16/3) ⋅ (n−2) ⋅ 4n−2/(n−2)4n−4

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (n−1) ⋅ 4n−1/n4n−2 − (16/3) ⋅ (n−2) ⋅ 4n−2/n4n−2

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (n−1) ⋅ 4n−1/n4n−2 − (16/3) ⋅ (n−2) ⋅ 4n−2/n4n−2

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (n−1) ⋅ 4n−1/n4n−2 − (16/3) ⋅ (n−2) ⋅ 4n−2/n4n−2

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (n−1) ⋅ 4n−1/n4n−2 − (16/3) ⋅ (n−2) ⋅ 4n−2/n4n−2

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (n−1)/n − (16/3) ⋅ (n−2)/n

2 ⋅ 4n/(3n4n) = (16/3) ⋅ (1 − 1/n) − (16/3) ⋅ (1 − 2/n)

2 ⋅ 4n/(3n4n) = (16/3n) ⋅ (2 − n)

This does not hold for all n, so {an = 2 ⋅ 4n/(3n4n)} is not a solution.

g) If an = (−4)n, then:

an = 8an−1 − 16an−2

(−4)n = 8(−4)n−1 − 16(−4)n−2

(−4)n = −8 ⋅ 4n−1 + 16 ⋅ 16n−2

(−4)n = −8 ⋅ (−4)n + 16 ⋅ (−4)n

This does not hold for all n, so {an = (−4)n} is not a solution.

h) If an = n2^(4n), then:

an = 8an−1 − 16an−2

n2^(4n) = 8(n-1)2^(4(n-1)) - 16(n-2)2^(4(n-2))

n2^(4n) = 8n2^(4n-4) - 16(n-2)2^(4n-8)

n2^(4n) = 8n2^(4n-4) - 16n2^(4n-8) + 512(n-2)

n2^(4n) - 8n2^(4n-4) + 16n2^(4n-8) - 512(n-2) = 0

n2^(4n-8)(2^16n - 8(2^12)n + 16(2^8)) - 512(n-2) = 0

This does not hold for all n, so {an = n2^(4n)} is not a solution.

Therefore, the solutions to the recurrence relation an = 8an−1 − 16an−2 are:

a) {an = 0}

b) {an = 1}

c) {an = 2ⁿ}

d) {an = 4ⁿ}

g) {an = (-4)ⁿ}

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The measures of the arc angles KL and MJ are 80° and 20° respectively derived using the Angles of Intersecting Chords Theorem

The Angles of Intersecting Chords Theorem states that the angle formed by the intersection of the chords is equal to half the sum of the intercepted arcs, and conversely, that the measure of an intercepted arc is half the sum of the two angles that intercept it.

50 = (KL + MJ)/2

100 = KL + MJ...(1)

30 = (MJ - KL)/2 {secant secant angle}

60 = MJ - KL...(2)

adding equations (1) and (2) we have;

160 = 2KL

divide through by 2

KL = 80°

Putting 80° for KL in equation (1), we have;

MJ = 100 - 80

MJ = 20°

Therefore, measures of the arc angles KL and MJ are 80° and 20° respectively by application of the Angles of Intersecting Chords Theorem

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Regarding the number of people who speak only Spanish or only Swahili, we can't say anything for certain without additional information. It's possible that some people speak only one of those languages, while others speak both or all three.

According to the given information,

we can use the principle of inclusion-exclusion to find the maximum number of people who speak only English.

In order to do this,

Adding the number of people who speak only English to the number of people who speak English and at least one other language.

This gives us a total of 75 people who speak English.

Now subtract the number of people who speak English and either Spanish or Swahili (or both) to avoid counting them twice.

In order to do this,

we have to find the number of people who speak both English and Spanish, both English and Swahili, and all three languages.

From the information given,

we know that there are 60 people who speak Spanish, 45 people who speak Swahili, and 100 people total.

Therefore,

There must be 100 - 60 = 40 people who do not speak Spanish, and

100 - 45 = 55 people who do not speak Swahili.

We also know that 75 people speak English, and since everyone speaks at least one language, we can subtract the total number of people who speak Spanish or Swahili (or both) from 100 to find the number of people who speak only English. So we get,

⇒ 100 - (40 + 55 + 75) = 100 - 170

                                    = -70

Since we can't have a negative number of people,

we know that there must be some overlap between the groups.

So, there must be some people who speak all three languages.

To find the maximum number of people who speak only English,

we assume that everyone who speaks two languages (English and either Spanish or Swahili) also speaks the third language.

So we get,

⇒ 75 - (60 - x) - (45 - x) - x = 75 - 60 + x - 45 + x - x

                                           = -30 + x

where x is the number of people who speak all three languages.

To maximize the number of people who speak only English,

we want to minimize x.

Since everyone who speaks two languages also speaks the third language,

We know that the total number of people who speak two or three languages is,

⇒ 60 + 45 - x = 105 - x.

Since there are 100 people in total, this means that at least 5 people speak only one language.

Therefore,

The maximum number of people who speak only English is 70 - x,

where x is the number of people who speak all three languages, subject to the constraint that x is at least 5.

Hence,

We are unable to determine with certainty the number of persons who speak just Swahili or only Spanish without more details. Some people might only speak one of those languages, while others might speak two or all three.

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The process of dividing a data set into a training, a validation, and an optimal test data set is called data partitioning.

Data partitioning is the process of dividing a dataset into separate subsets that are used for different purposes, such as training a model, validating its performance, and testing it on new data.

The most common way to partition a dataset is into three subsets: a training set, a validation set, and a test set. The training set is used to train a model, the validation set is used to tune the model's hyperparameters and assess its performance during training, and the test set is used to evaluate the final performance of the model on new, unseen data.

Data partitioning helps to prevent overfitting by providing a way to evaluate a model's performance on data that it has not seen during training.

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The requried volume of the cone is 182 cubic inches.

The area of the base of the cylinder is given by:

[tex]A_{cylinder} = \pi r^2[/tex]

where r is the radius of the cylinder. We know that the area of the base is 39 square inches, so we can write:

[tex]\pi r^2 = 39[/tex]

Solving for r, we get:

r = √(39/π)

The height of the cylinder is given as 14 inches. Therefore, the volume of the cylinder is:

[tex]A_{cylinder} = \pi r^2\\ A_{cylinder}= \pi (39/ \pi )(14)\\ A_{cylinder}= 546 \ \ \ cubic inches.[/tex]

Similarly,

The volume of the cone ([tex]V=1/3 \pi r^2h[/tex]) is 182 cubic inches.

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a) For an = 3, recurrence relation: a_n = a_(n-1); b) For an = 2n, recurrence relation: a_n = a_(n-1) + 2; c) For an = 2n + 3, recurrence relation: a_n = a_(n-1) + 2; d) For an = 5n, recurrence relation: a_n = a_(n-1) + 5; e) an = n^2, recurrence relation: a_n = a_(n-1) + 2n - 1; f) an = n^2 + n, recurrence relation: a_n = a_(n-1) + 2n; g) an = n + (-1)^n, recurrence relation: a_n = a_(n-1) + 2*(-1)^n; h) an = n!, recurrence relation: a_n = n * a_(n-1).

Explanation:
To find recurrence relations for these sequences, please note that the answers may not be unique, but I will provide one possible recurrence relation for each sequence:

a) a_n = 3

a_(n-1) = 3
Recurrence relation: a_n = a_(n-1)

b) a_n = 2n

a_(n-1) = 2(n-1)

Thus,  a_n - a_(n-1) = 2
Recurrence relation: a_n = a_(n-1) + 2

c) a_n = 2n + 3

a_(n-1)= 2(n-1) + 3

Thus, a_n - a_(n-1) = 2

a_n = a_(n-1) + 2
Recurrence relation: a_n = a_(n-1) + 2

d) a_n = 5n

a_(n-1) = 5(n-1)

Thus, a_n - a_(n-1) = 5
Recurrence relation: a_n = a_(n-1) + 5

e) a_n = n^2

a_(n-1) =  (n-1)^2

Thus, a_n - a_(n-1) = 2n - 1
Recurrence relation: a_n = a_(n-1) + 2n - 1

f) a_n = n^2 + n

a_(n-1) = (n-1)^2 +(n-1)

Thus,  a_n - a_(n-1) = 2n
Recurrence relation: a_n = a_(n-1) + 2n

g) a_n = n + (-1)^n

a_(n-1) = (n-1) + (-1)^(n-1)

Thus,  a_n - a_(n-1) = 2*(-1)^n
Recurrence relation: a_n = a_(n-1) + 2*(-1)^n

h) a_n = n!

a_(n-1) = (n-1)!

Thus,  a_n/a_(n-1)= n
Recurrence relation: a_n = n * a_(n-1)

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Answer:

13/85

Step-by-step explanation:

The sin of an angle is the opposite side over the hypotenuse.

sin B = opp/ hyp

sin B = 13/85

Answer:

sin B = 0.1529

Step-by-step explanation:

To find the Sin B angle we have to use the below formula.

[tex]\sf Sin\:B = \frac{Opposite}{Hypotenuse}[/tex]

Let us solve this now.

[tex]\sf Sin\:B = \frac{Opposite}{Hypotenuse} \\\\\sf Sin\:B = \frac{13}{85} \\\\Sin \:B =0.1529[/tex]

Additionally, To Remove sin, look at the inverse of the sin value and find the exact value of B

[tex]\sf B = sin^-^10.1529\\B=8.79\\\\[/tex]

The percentage of the original ¹⁴c is still present is  28.5%.

To calculate the percentage of original ¹⁴C still present, we need to use the formula for                                             radioactive decay:
N = N₀(1/2)^(t/h)
Where:
N₀ = initial amount of ¹⁴C
N = final amount of ¹⁴C after time t
t = time elapsed
h = half-life of ¹⁴C

Substituting the given values:
N₀ = 100%
t = 1.190 × 10⁴ years
h = 5730 years

N = 100% x (1/2)^((1.190 × 10⁴)/5730)
N = 100% x (1/2)^(2.08)
N = 100% x 0.285
N = 28.5%

Therefore, after 1.190 × 10⁴ years, approximately 28.5% of the original ¹⁴C is still present in the tree trunk.

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The height of the rider at any time t after the initial time t=0, in meters above the ground is h = 18 - 14*sin((π/3)*t)

Now, let's consider the position of the rider at some time t after the initial time t=0.

We can find the angle that the rider has traveled around the wheel by multiplying the angular velocity by the time elapsed:

θ = (π/3) * t

To find the vertical position of the rider at this angle, we can use the sine function, since the height of the rider on the Ferris wheel varies sinusoidally as the wheel rotates:

h = 18 - 14*sin(θ)

Plugging in the expression for θ, we get:

h = 18 - 14*sin((π/3)*t)

This formula gives the height of the rider at any time t after the initial time t=0, in meters above the ground.

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Answer:

A

Step-by-step explanation:

Answer:

the ans is 6.4

Step-by-step explanation:

using the distance formula

d^2= (x2-x1)^2 + (y2-y1)^2

d^2= (8-4)^2 + (8-3)^2

d^2= (4)^2 + (5)^2

d^2= 16+ 25

d^2= 41

d= sqrt of 41*

d= 6.4units

The line integral is zero: ∫C F · dr = 0

To apply Green's Theorem, we need to find the curl of the vector field F [tex]= (3 sin y, 3x cos y)[/tex].

∂F2/∂x = 3 cos y

∂F1/∂y = 3 cos y

So, curl F = (∂F2/∂x - ∂F1/∂y) = 0

Since the curl of F is zero, we can apply Green's Theorem to evaluate the line integral along the given curve C, which is the ellipse [tex]x^2 + xy + y^2 = 36[/tex], oriented in the counterclockwise direction.

∫C F · dr = ∬R (∂F2/∂x - ∂F1/∂y) dA

where R is the region enclosed by C.

Since the curl of F is zero, the line integral is equal to the double integral of the curl of F over the region R, which is zero. Therefore, the line integral is zero:

∫C F · dr = 0

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The graph of the system of inequalities is on the image at the end.

Here we need to graph the two linear inequalities:

4x + 2y ≤ 16

x + y ≥ 4

On the same coordinate axis.

To do so, we can write both of these as lines:

y  ≥ 4 - x

y ≤ (16 - 4x)/2

y ≤ 8 - 2x

Then the system is:

y  ≥ 4 - x

y ≤ 8 - 2x

Now just graph the two lines with solid lines (because of the symbols used) and shadew the region above the first line and the region below the second line.

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a)The solution to the given initial value problem is

[tex]y(t) = ((2h/27) + (4/3))e^(^3^t^) + ((2h/27) - (4/3))e^(^-^t^) - (h/3)(t-4) - (2h/9)[/tex]

b)The solution to the given initial value problem is

[tex]x(t) = (F0/(2ω^2))sin ωt - (F0/(2ω^2))cos ωt[/tex]

For the first problem, we can use the method of undetermined coefficients to find a particular solution to the non-homogeneous differential equation.

Let's assume that the solution has the form y_p = A(t-4) + B.

Taking the first and second derivatives, we have y'_p = A and y''_p = 0.

Substituting these expressions into the differential equation, we get:

[tex]0 - 2A - 3(A(t-4) + B) = h(t-4)[/tex]

To simplify, we have:

[tex]-3At + (6A - 3B) = h(t-4)[/tex]

To satisfy this equation for all t, we must have -3A = h and 6A - 3B = 0.

Solving for A and B, we get A = -h/3 and B = -2h/9.

Therefore, the particular solution is

[tex]y_p = (-h/3)(t-4) - (2h/9).[/tex]

To find the general solution to the homogeneous differential equation, we first solve the characteristic equation:

[tex]r^2 - 2r - 3 = 0[/tex]

Factoring, we get (r-3)(r+1) = 0, so r = 3 or r = -1.

Therefore, the general solution to the homogeneous equation is

[tex]y_h = c_1e^(^3^t^) + c_2e^(^-^t^).[/tex]

The general solution to the entire differential equation is the sum of the homogeneous and particular solutions:

[tex]y = y_h + y_p.[/tex]

Plugging in the initial conditions, we have:

[tex]y(0) = 8 = c_1 + c_2 - (2h/9)y'(0) = 0 = 3c_1 - c_2 - (h/3)[/tex]

Solving for c_1 and c_2 in terms of h, we get

c_1 = (2h/27) + (4/3) and c_2 = (2h/27) - (4/3).

Therefore, the solution to the initial value problem is:
[tex]y(t) = ((2h/27) + (4/3))e^(^3^t^) + ((2h/27) - (4/3))e^(^-^t^) - (h/3)(t-4) - (2h/9)[/tex]


For the second problem, we can use the method of undetermined coefficients again.

Let's assume that the solution has the form x_p = A sin ωt.

Taking the second derivative, we have [tex]d^2x_p/dt^2 = -Aω^2 sin ωt.[/tex]

Substituting these expressions into the differential equation, we get:

[tex]-Aω^2 sin ωt + ω^2A sin ωt = F0 sin ωt[/tex]

Simplifying, we get -2Aω^2 sin ωt = F0 sin ωt, so A = -F0/(2ω^2).

The general solution to the homogeneous differential equation is

[tex]x_h = c_1 cos ωt + c_2 sin ωt.[/tex]

Therefore, the general solution to the entire differential equation is

[tex]x = x_h + x_p.[/tex]

Plugging in the initial conditions, we have:

x(0) = 0 = c_1

x'(0) = 0 = c_2ω - (F0/(2ω))

Solving for c_2 in terms of F0 and ω, we get c_2 = F0/(2ω^2).

Therefore, the solution to the initial value problem is:

[tex]x(t) = (F0/(2ω^2))sin ωt - (F0/(2ω^2))cos ωt[/tex]

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Answer: no polygon exists in which the ratio of the number of diagonals to the sum of the measures of the angles is 1 to 18, because the number of sides n cannot be equal to 23.

Step-by-step explanation: Let n be the number of sides of the polygon. The number of diagonals in a polygon of n sides is given by the formula:

d = n(n-3)/2

The sum of the measures of the angles in a polygon of n sides is given by the formula:

180(n-2)

The ratio of the number of diagonals to the sum of the measures of the angles is:

d / [180(n-2)] = [n(n-3)/2] / [180(n-2)] = (n-3) / 360

We want to show that this ratio cannot be equal to 1/18, or:

(n-3) / 360 ≠ 1/18

Multiplying both sides by 360, we get:

n-3 ≠ 20

Adding 3 to both sides, we get:

n ≠ 23

Therefore, no polygon exists in which the ratio of the number of diagonals to the sum of the measures of the angles is 1 to 18, because the number of sides n cannot be equal to 23.

The number x that maximizes the product xy when x and y have a sum of 62 is:

x = 31.

To find the number x when the sum of two numbers x and y is 62 and the product xy is maximum, we can use the concept of optimization.

Step 1: Write down the given information:
x + y = 62 (the sum of x and y)

Step 2: Express one variable in terms of the other:
y = 62 - x

Step 3: Write the function to be maximized:
P(x) = x * y = x * (62 - x)

Step 4: Find the derivative of the function:
P'(x) = (62 - x) - x

Step 5: Set the derivative to zero and solve for x:
0 = (62 - x) - x
2x = 62
x = 31

So, the number x that maximizes the product xy when x and y have a sum of 62 is x = 31.

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Answer:

x < -4

Step-by-step explanation:

-2x - 6 > 3x + 14  Add 2x to both sides

-2x + 2x - 6 > 3x + 2x  + 14

-6 > 5x + 14  Subtract 14 from both sides

-6 - 14 > 5x + 14 - 14

-20 > 5x  Divide both sides by 5

[tex]\frac{-20}{5}[/tex] > [tex]\frac{5}{5}[/tex] x

-4 > x or x < -4

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