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Answer:

Equation for SHM can be written

V = w A cos w t        where w is the angular frequency and the velocity is a                                         maximum at t = 0

V1 = w1  A cos w1 t

V2 = w2 A cos w2 t

V2 / V1 = w2 / w1     since cos X t = 1 if t = zero

V2 / V1 = 2 pi f2 / (2 pi f1) = f2 / f1 = T1 / T2

If the velocity is twice as large the period will be 1/2 long

Answer:

op

Explanation:

At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

Explanation:

The power P dissipated by a heater is defined as

[tex]P = VI[/tex]

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

[tex]I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}[/tex]

b) The resistance R of the heater is

[tex]P = VI = (IR)I = I^2R[/tex]

where [tex]V= IR[/tex] is our familiar Ohm's Law.

[tex]\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}[/tex]

[tex]R = 110.8\:Ω[/tex]

The current running through the heater when it is operating is 1.08 A.

The resistance of the heater is 110.8 ohm.

So, from the above equation we can calculate,

              current I = P/V

                      ∴   I = 130 / 120

                      ∴   I = 1.08 A

So, from the equation we can calculate,

                   Resistance R = P/I^2

                                  ∴  R = 130/(1.08)^2

                                  ∴  R = 110.8 ohm

Thus, the current running through the heater when it is operating is 1.08 A.

The resistance of the heater is 110.8 ohm.

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Answer:

D. Scientist back up their statements with facts.

Explanation:

The majority of the laws, theorems and thesis are base on with experiments. The follow different strategies for confirm the hypothesis with facts, one of the most famous models is the scientific method. That is a way of proof something in a trustworthy.

In the image is the resume about this method (graphical organizer).

Answer: An ice hockey player picks up a trophy as he slides past it.

Two pool balls colliding precisely inelastically and rebounding off one another is an example. So, the correct option is A.

Inelastic collisions are those in which the total kinetic energy is lower after the impact than it was before. The stick is travelling quickly in the direction of the ball before to the contact. The stick comes to a stop following the accident. It transfers some of its kinetic energy to the cue ball, which rolls forward.

The type of collision mentioned in the given example is known as an inelastic collision is one in which the system's momentum is preserved but its kinetic energy is not. In a ballistic pendulum, an example of an inelastic collision. Dropped ball of clay is another illustration of an inelastic collision.

Thus, the correct option is A.

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Your question is incomplete, most probably the complete question is:

Which of the following statements describes a perfectly inelastic collision?

A. Two billiard balls bounce off of each other,

B. A car crashes into a tree and rebounds in the other direction,

C. A wad of chewing gum is thrown and sticks to a moving truck,

D. Two ice skaters hit each other and fall over in opposite directions,

Answer:

(i) 0.6s (ii) 8.42m

Explanation:

U² = 6.02² + 7²

U = 9.23

angle of projection

tanø = 6.02/7

ø = 40.7

Time of fligt

t = Usinø/g

t = 9.23 sin 40.7/10

t = 0.6

H range = U²sin2ø/g

H = 9.23²sin 81.4/10

H = 8.42m

The time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.

Velocity ​​is defined as the directional motion of an object which is indicated by the rate of change of position as observed from a particular frame of reference. It is measured by a particular standard of time. It is a vector quantity as it has both magnitude and direction.

It can be expressed as:

v= d/t

Where. v is the velocity in m/s

d is the displacement measured in meter 'm'

t is the time measured in seconds 's'

For above given information,

v = 6.02 +7.0j, so the initial velocity will be u

u² = 6.02² + 7²

u = 9.23m/s

Angle of projection, tanø = 6.02/7

ø = 40.7

Time taken=  t = u sinø/g

t = 9.23 sin 40.7/10

t = 0.6s

Horizontal range  = u²sin2ø/g

H = 9.23²sin 81.4/10

H = 8.42m

Thus, the time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.

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The equilibrium conditions allow to find the results for the balance forces are:

When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.

            ∑ F = 0

            ∑ τ = 0

Where F are the forces and τ the torques.

The torque  is the product of the force and the perpendicular distance to the point of support,

The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.

We write the translational equilibrium condition.

           F₁ - W₁ - W₂ + F₂ = 0

We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.

         F₂ 2 - W₁ 1 - W₂ 1.5 = 0[tex]\frac{W_1 \ 1 + W_2 \ 1.5}{2}[/tex]

Let's calculate F₂

         F₂ = [tex]\frac{W_1 \ 1 + W_2 \ 1.5 }{2}[/tex]  

         F₂ = (m g + M g 1.5)/ 2

         F₂ = [tex]\frac{(12 + 68 \ 1.5 ) \ 9.8}{2}[/tex]  

         F₂ = 558.6 N

We substitute in the translational equilibrium equation.

         F₁ = W₁ + W₂ - F₂

         F₁ = (m + M) g - F₂

         F₁ = (12 +68) 9.8 - 558.6

         F₁ = 225.4 N

In conclusion using the equilibrium conditions we can find the forces of the balance are:

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An example of a point source water pollutant is a sewer pipe draining directly into a river.

According to the United States Environmental Protection Agency, a  point source pollution is defined as;  “any single identifiable source of pollution from which pollutants are discharged, such as a pipe, ditch, ship or factory smokestack.”

Hence, an example of a point source water pollutant is a sewer pipe draining directly into a river. The pollution is coming from an easily identifiable source which is a sewer pipe connected to a river directly.

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Answer:

0.25

Explanation:

That is the right answer.

The fraction of the initial kinetic energy is lost in the collision is 35.3%.

The given parameters:

The initial kinetic energy of the system collision is calculated as follows;

[tex]K.E_i = \frac{1}{2} mv_1_i^2 + \frac{1}{2} mv_2_i^2\\\\K.E_i = \frac{1}{2} (m)(8.3)^2 + \frac{1}{2} (m) (0)^2\\\\K.E_i = 34.445 m[/tex]

The final velocity of ball A after collision is calculated as follows;

[tex]u_1 + v_1 = u_2 + v_2\\\\8.3 + v_1 = 0 + 6.4\\\\v_1 = 6.4 - 8.3\\\\v_1 = -1.9 \ m/s[/tex]

The final kinetic energy of the system after collision is calculated as follows;

[tex]K.E_f = \frac{1}{2} m(-1.9)^2 + \frac{1}{2} m(6.4)^2\\\\K.E_f = 22.285 \ m \[/tex]

The fraction of the initial kinetic energy is lost in the collision is calculated as follows;

[tex]= \frac{K_i - K_f}{K_i} \\\\= \frac{34.445 - 22.285}{34.445} \\\\= 0.353\\\\= 35.3\%[/tex]

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The velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

The given parameters;

The resultant vertical velocity of the boat is calculated as;

[tex]v_y = 8 \ - \ 5 sin(30)\\\\v_y = 8 - 2.5\\\\v_y = 5.5 \ km/h[/tex]

The resultant horizontal velocity of the boat is calculated as;

[tex]v_x = -2 \ + 5cos(30)\\\\v_x = 2.33 \ km/h[/tex]

The resultant boat velocity is calculated as follows;

[tex]v = \sqrt{v_x^2 + v_y^2} \\\\v = \sqrt{2.33^2 + 5.5^2} \\\\v = 5.97 \ km/h[/tex]

The direction of the velocity;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{5.5}{2.33} )\\\\\theta = 67 \ ^0[/tex]

Thus, the velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

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Answer:

P1 = 1.3 (500 + 60) = 728 kg-m      total momentum to right at start

P2 = (v2 - 10) 60 + 500 v2

total momentum after running at -10 with respect to cart = 728 where v2 is the new speed of the cart

728 = 560 v2 - 600

v2 = 1328 / 560 = 2.37 m/s    new speed of cart

Check:

After:    p2 for cart = 500 * 2.37 = 1186

p1 for man = (2.37 - 10) * 60 = -458

P2 = p1 + p2 = 728       total momentum unchanged

Answer:

Our eyes are most sensitive to the wavelengths corresponding to the yellow and green colors of the spectrum. Flashy signs and some fire engines are painted in a yellowish-green color to attract our attention.

Answer:

1250[tex]\sqrt{3}[/tex]

Explanation:

Let's look at this in a simple manner, because it is.

The crane weights 250Kg. Okay.

Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)

Since F = m * a

F = 250 * 10

F = 2500

Now we know that the downward Force is 2500N.

To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be [tex]\frac{\sqrt{3}}{2}[/tex].

Therefore, the force pulling the box in the cable's direction is:

[tex]\frac{2500\sqrt{3} }{2} = 1250\sqrt{3}[/tex]

If you have any questions feel free to comment.

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Answer:

Explanation:

No,the poping of microvave is not same there time is different

Answer:

Kinetic Energy.

Explanation:

The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy.

Since the marble will loose mechanical energy, the hill should be a little less than 1.5 m (meters) high.

A roller coaster is used to demonstrate the conversion of mechanical energy. In a roller coaster, potential energy is converted to a kinetic energy hence it conveniently serves as a device for demonstrating energy conversions.

As the students make their design, they must bear in mind that the hill should be a little less than 1.5 m (meters) high, because the marble will lose mechanical energy as it moves, preventing it from reaching its release

height.

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Answer:

Explanation:

What are we to use as gravity in this imaginary world? I will ASSUME 9.81 m/s² and assume no air resistance.

horizontal velocity component

vx = 55.0/2.50 = 22 m/s

vertical initial velocity component

(12.0 - 10.0) = 0 + vy₀(2.50) + ½(-9.81)2.50²

vy₀ = 13.0625 m/s

θ = arctan(vy₀/vx) = arctan(13.0625/22) = 30.6997225... = 30.7°

Answer:

Attitude, motivation and determination

Explanation:

Let me know if I'm right.

The factors leading to the success through the challenging physical activities are Attitude, motivation and determination.

Although the information regarding the live session is not mentioned, but as a general point of view, the major factors that need to considered while undergoing through the challenging physical activities are as follows:

Thus, we can conclude that the factors leading to the success through the challenging physical activities are Attitude, motivation and determination.

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Answer:

c

Explanation:

Answer:

F net ∞ [tex]\frac{1}{\sqrt{t} }[/tex]

Explanation:

In pic

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Answer:

 |F| = 35 kN

Explanation:

a = F/m

100 km/hr(1000 m/km / 3600 s/hr) = 27.8 m/s

v² = u² + 2as

   a = (v² - u²) / 2s

F/m = (v² - u²) / 2s

   F = m(v² - u²) / 2s

   F = 5000(0² - 27.8²) / 2(55)

   F = - 35,072.9517...

The correct statement is, the system performed 800 J of work on its surroundings.

The given parameters:

Apply first law of thermodynamics;

ΔU = Q + W

where;

In adiabatic process no heat is gained or lost by the system.

Q = 0

ΔU = W  (work is positive when it is done on the system by its surrounding)

If work is done by the system to the surrounding, the new equation becomes;

ΔU = - W

W = - ΔU

W  = -800 J

This implies that the system performed 800 J of work on its surroundings.

"Your question is not complete, it seems to be missing the following information";

In a thermodynamic process, the internal energy of a system in a container with adiabatic walls decreases by 800 J. Which statement is correct?

a. The system lost 800 J by heat transfer to its surroundings.

b. The system gained 800 J by heat transfer from its surroundings.

c. The system performed 800 J of work on its surroundings.

d. The surroundings performed 800 J of work on the system.

e. The 800 J of work done by the system was equal to the 800 J of heat transferred to the system from its surroundings.

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Answer:

Our atmosphere has five different layers. They are:

1. Troposphere: This is the most important layer of the atmosphere with an average height of 13 km from the earth. It is in this layer that we find the air that we breathe. Almost all the weather phenomena such as rainfall, fog and hailstorm occur here.

2. Stratosphere: This layer extends up to a height of 50 km. It presents the most ideal condition for flying airplanes. It contains a layer of ozone gas which protects us from the harmful effect of the sun rays.

3. Mesosphere: This layer extends up to a height of 80 km. Meteorites bum up in this layer on entering from the space.

4. Thermosphere: In this layer, the temperature rises very rapidly with increasing height. The ionosphere is a part of this layer. It extends between 80-400 km. This layer helps in radio transmission. Radio waves transmitted from the earth the reflected back to the earth by this layer.

5. Exosphere: It is the uppermost layer where there is very thin air. Light gases such as helium and hydrogen float into space from here.

Answer:

No - It is connected in parallel instead of series

Explanation:

The answer is No, the reason behind the answer that the ammeter is connected in parallel which is wrong it must be connected in series.

An ammeter is a device for detecting electric current in amperes, either directly (DC) or alternating (AC). Due to the fact that a shunt running parallel to the meter carries the majority of the electricity at high current values, the digital multimeter can measure a wide range of current values. A circle with the capital A in it serves as the icon for an ammeter for circuit diagrams.

The moving coil of the electrodynamics ammeter rotates in the field created by the fixed coil. It measures alternating and direct current with 0.1 to 0.25 percentage points (by converting Ac power To DC power using a rectifier).

The ammeter is connected in series and, on the other hand, the voltmeter is connected in parallel.

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Answer:

C. crests

don't trust me though

Answer:

The less dense areas created as a sound wave propagates are called rarefactions.

Explanation:

Hoped this helped.

Answer:

option B is the correct answer

Explanation:

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