Answer:
6X(5 + 4)
6x(9)
54x
Answer:
the answer is 54x hope it will help full to you
Does anyone know the answer to this?
Kendra can see the top of her apartment building reflected in a small fish pond in a park across the street. She is standing 2 m from the pond, and the distance from the pond to the apartment building is 40 m. If Kendra's eyes are 150 cm above the ground, how tall is the apartment building?
Answer:
Step-by-step explanation:
According to problem description, we have two triangles
The first one: the fish pond and feet and eyes of Kendra
The second one the fish pond and the side wall of the apartment
These two triangles have angle α as common angle and its tan
tan α = 1.5/ 2 = x/ 40 then note : 150 cm = 1.5 m
1.5/ 2 = x/ 40
x = 40 * 1.5 / 2
x = 30 m
Need help ASAP ITS DUE Soon???!!!
Answer:
V=942.5
Step-by-step explanation:
V=(π)(r)^2(h)
V= (π)(10/2)^2(12)
V=942.5
In a right triangle, Sin (4x + 10) º = Cos (6x) º. What is the value of x?
Answer:
x = 8
Step-by-step explanation:
According to trigonometry identity
sin x = Cos (90-x)
Hence if we have;
Sin (4x + 10) º = Cos (6x)
Sin (4x + 10) º = Sin(90- 6x)
4x + 10 = 90 - 6x
4x+6x = 90 - 10
10x = 80
x = 80/10
x = 8
Hence the value of x is 8
There is a geometrical relation that arc of circle is equal to the central angle.
And there is another relation that arc of a circle is equal to (radius *arc)
Aren't these two relation conflicting?
Find the difference. Express the answer in scientific notation.
(5.29x 10^11)-(3.86 x 10^11)
O 1.43 x 10^11
O 9.15 x 10^11
O 1.43 x 10^22
O 9.15 x 10^22
Answer:
Option 1
Step-by-step explanation:
Take
[tex]10 {}^{11} [/tex]
common out.
[tex](5.29 - 3.86) \times 10 {}^{11 } \\ 1.43 \times 10 {}^{11} [/tex]
Answer: a
Step-by-step explanation: edge 2023
Which equation represents the general form a circle with a center at (–2, –3) and a diameter of 8 units?
x2 + y2 + 4x + 6y – 51 = 0
x² + y² – 4x – 6y – 51 = 0
x2 + y2 + 4x + 6y – 3 = 0
x2 + y2 – 4x – 6y – 3 = 0
The equation for the given circle is:
[tex]x^2 + y^2 + 4x + 6y - 3 = 0[/tex]
How to get the equation of the circle?
Remember that for a circle whose center is (a, b) and has a radius r, the equation is:
[tex](x - a)^2 + (y - b)^2 = r^2[/tex]
In this case, the center is (-2, -3) and the diameter is 8 units, so the radius is r = 4.
Then the equation is:
[tex](x + 2)^2 + (y + 3)^2 = 4^2[/tex]
Expanding the squares we get:
[tex](x^2 + 2*2*x + 4) + (y^2 + 2*3*y + 3^2) = 16\\\\x^2 + y^2 + 4x + 6y + 4 + 9 - 16 = 0\\\\x^2 + y^2 + 4x + 6y - 3 = 0[/tex]
So the correct option is the third one.
If you want to learn more about circles:
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Which equation represents a line that passes through (5,1) and has a slope of 1/2?
Answer:
y = 1/2x - 3/2
Step-by-step explanation:
y = 1/2x + b
1 = 1/2(5) + b
1 = 5/2 + b
-3/2 = b
Answer:
y=1/2x-3/2
Step-by-step explanation:
y-y1=m(x-x1)
y-1=1/2(x-5)
y-1=1/2x-5/2
y=1/2x-5/2+1
y=1/2x-5/2+2/2
y=1/2x-3/2
What scale factor is shown by this graph?
4
1/2
2
1
Answer:
If it's AL to A'L' then its 1/2
If it's A'L' to AL then its 2
In AFGH, the measure of ZH=90°, HF = 2.9 feet, and GH = 1.5 feet. Find the
measure of ZG to the nearest degree.
9514 1404 393
Answer:
63°
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
tan(G) = HF/HG
G = arctan(HF/HG) = arctan(2.9/1.5) ≈ 63°
The function f(x)=2.14/55x + 0.31 can be used to determine the cost, in dollars, of a gallon of gas x years since 1960.
Part A - According to the function, what was the cost, in cents, of a gallon of gas in 1960?
Part B - According to the function, how much did the cost increase each year, rounded to the nearest whole cent?
Answer:
The answer is below
Step-by-step explanation:
The equation for a linear function is given as:
y = mx + b
where m is the slope of the function (that is the rate of change), b is the initial value of y when x is 0.
Given that the function where x represent the number of years since 1960 and y is the cost in dollar as:
[tex]f(x)=\frac{2.14}{55}x+0.31[/tex]
a) In the year 1960, that is x = 0, the cost of a gallon of gas is given as:
[tex]f(0)=\frac{2.14}{55}(0)+0.31\\\\f(0)=\$0.31[/tex]
b) From the function [tex]f(x)=\frac{2.14}{55}x+0.31[/tex], we can see that the rate of change is 2.14/55. Therefore, the cost increase each year by 4 cents per year.
number 14 and 15 pls
Step-by-step explanation:
b= 140 ( alternate angle)
k = 130 ( veetically opposite angles)
may it help ub
Which value of a,b, and c correctly represent the answer in simplest form?
Answer:
A
Step-by-step explanation:
first, you turn 3 1/2 into 3 2/4'ths and change 3 two fourth's into 14/4 fraction.
next, you change 2 one fourth into 9/4th's fraction
your equation would be 14/4 divided by 9/4th's = a times b/c
when you used divide, you get get flip one of the fractions being divided, and it could turn into 14/4 TIMES 4 over 9 = a times b/c.
wait this area down here could be wrong:
when you get your equation, multiply them together and you get 56 over 36 equals a times b/c.
A times B /C is equal to 56/36 which can simple out to 28/18 which AGAIN simpled out to 14/9
C IS 9 BECAUSE IT IS THE DENOMINATOR
and because of that, A would be the answer.
Evaluate expression-What is the value of the expression when x=11 and y=7
A.4
B.128
C.49
D.14
Answer:
C. 49
Step-by-step explanation:
Start by filling in your values.
[tex]7^{2} + 99 / 11 - 9[/tex]
Solve using PEMDAS.
49 + 99 / 11 - 9
49 + 9 - 9
58 - 9
49
Answer:
[tex]c .\: \: 49[/tex]
Step-by-step explanation:
[tex] {y}^{2} + 99 \div x - 9[/tex]
[tex] {7}^{2} + 99 \div 11 - 9[/tex]
[tex] 49 +99÷11-9[/tex]
[tex]49+9-9[/tex]
[tex]58-9[/tex]
[tex]49[/tex]
Hope it is helpful...The diagram shows a pattern using four identical rhombuses.
Diagram NOT
accurately drawn
25
25
25
Work out the size of the angle marked a.
You must show your working,
Answer:
There isnt a diagram
Step-by-step explanation:
please help explain it step by step
Answer:
452 m
Step-by-step explanation:
How many solutions exist for the system of equations graphed below? 3 2 54 -3 -2 -1 1 1
Answer:
Step-by-step explanation:
One solution if they intersect (which is the case), and zero if they are parallel and apart, and infinite if they are parallel and coincident, two lines piled on top of each other.
james wrote the number 8980000 in scientific notation
Answer:
here u go
Step-by-step explanation:
8.98 x 10^6
1.) Write the probability as a fraction in simplest form. P (D) *
B.
A
С
F
D
E
1/6
4/5
about 50%
6
Answer:
Hello! answer: 1/6
Step-by-step explanation:
The probability of landing on D is 1/6 because there are 6 spots on the spinner you can land on A, B, C, D, E, and F and there is only 1 section labelled "D" therefore the probability of landing on D is 1/6 hope that helps!
Can someone help me with this please I have to have it done ??
Given:
The scale factor of the actual sports utility vehicle to the toy model is 50:1.
Actual length = 7 feet
Actual width = 5 feet
To find:
The length and width of the toy model.
Solution:
a. Let l be the length of the toy model, then
[tex]\dfrac{\text{Actual length}}{\text{Length of the toy model}}=\dfrac{50}{1}[/tex]
[tex]\dfrac{7}{l}=\dfrac{50}{1}[/tex]
[tex]7=50l[/tex]
[tex]\dfrac{7}{50}=l[/tex]
[tex]0.14=l[/tex]
Therefore, the length of the toy model is 0.14 feet.
b. Let w be the width of the toy model, then
[tex]\dfrac{\text{Actual width}}{\text{Width of the toy model}}=\dfrac{50}{1}[/tex]
[tex]\dfrac{5}{w}=\dfrac{50}{1}[/tex]
[tex]5=50w[/tex]
[tex]\dfrac{5}{50}=w[/tex]
[tex]0.10=w[/tex]
Therefore, the width of the toy model is 0.10 feet.
1. Find the value of x and round to the nearest tenth
2. Find the value of y and round to the nearest tenth.
Measure of x :
[tex]\longrightarrow4 \sqrt{5} \: \: units[/tex]
Measure of y :
[tex]\longrightarrow8 \sqrt{5} \: \: units[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{hope \: \: it \: \: helps }}{\orange{....}}}}}[/tex]
Two students are reading a book. Keith reads 6 pages a day. Tameka reads 5 pages a day, but she starts sooner and has already read 15 pages.
Part A
Write a system of equations to represent the situation, using d for days and p for pages.
Part B
Graph the system of equations. (Click to draw on the graph.)
Question 3
Part C
Will Keith and Tameka ever be on the same page on the same day? Explain.
Answer: keith
Step-by-step explanation:
The system of equations to represent the number of pages read per day by Keith and Tameka, using d for days and p for pages are,
p = 6d
p = 5d + 15
Since we know that,
A system of equations is the set of equations in which the finite set of equations is present for which the common solution is sought.
Two students are reading a book. Keith reads 6 pages a day.
The equation for Keith, where d for days and p for pages can be given as,
p = 6xd
p = 6d
Tameka reads 5 pages a day, but he starts sooner and has already read 15 pages. The equation for Tameka, where d for days and p for pages, can be given as,
p = 5xd + 15
p = 5d + 15
Hence, the system of equations to represent the number of pages read per day by Keith and Tameka, using d for days and p for pages are,
p = 6d
p = 5d + 15
Learn more about the system of equations here;
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Jose is trying to calibrate his new fitness watch. The app that come with the watch asks the user to input their average stride. Jose measures this to be approximately 2.5 feet. Using 2.5 feet as his stride how many feet will Jose walk if he takes 6000 steps in a day?
Answer:
Step-by-step explanation:
Jose is trying to calibrate his new fitness watch. The app that come with the watch asks the user to input their average stride. Jose measures this to be approximately 2.5 feet. Using 2.5 feet as his stride how many feet will Jose walk if he takes 6000 steps in a day?
mr.harrington drive 164 miles. his car used 8 gallons of gas. how many miles per gallon of gas does the car average
Answer:
20.5 mpg
Step-by-step explanation:
Here we're looking to calculate the car's fuel economy, expressed in miles per gallon, or mpg:
164 miles
------------------ = 20.5 mpg
8 gallons
#4. Find the missing angle measures
Answer:
Step-by-step explanation:
x = 55
x + 55 = 110
x + 20 = 75
x + 65 = 120
Answer:
x°=130°
The sum of two opposite angles in a quadrilateral is 180
⇒x+55°+x+65°=180°
⇒2x+120°=180°
⇒2x=60°
⇒x=30°
Có x+20 °+x°=180°
⇒30°+20°+x°=180°
⇒x°=130°
(-9x + 32) - (15x + 41)
Answer:
Step-by-step explanation:
Distribute the Negative Sign:
=−9x+32+−1(15x+41)
=−9x+32+−1(15x)+(−1)(41)
=−9x+32+−15x+−41
Combine Like Terms:
=−9x+32+−15x+−41
=(−9x+−15x)+(32+−41)
=−24x+−9
Answer:
-24x - 9
Step-by-step explanation:
Combine like terms.
Part A
Find the formula for the corresponding inverse function g(x).
Part B
Select all of the points that would appear on the graph of y = g(x).
1. A
2. B
3. C
4. D
5. E
6. F
What is the length of AC?
A.72
B.96
C.136
D.132
Answer:
The answer is 136 .
HELP ASAP 50 POINTS What is the equation of a circle with a diameter with endpoints (5,2) and (3,-4)
Answer: I believe it's (x-1) 2+(y-1) 2=13
A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle of 20° east of north. Identify the ship's vector, the water current's vector, and the vector representing the ship's actual motion.
Answer:
a. 25.98i - 15j mi/h
b. 1.71i + 4.7j mi/h
c. 27.69i -10.3j mi/h
Step-by-step explanation:
a. Identify the ship's vector
Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h
Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h
b. Identify the water current's vector
Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h
Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h
c. Identify the vector representing the ship's actual motion.
The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.
V = v + v'
= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h
= (25.98i + 1.71i + 4.7j - 15j )mi/h
= 27.68i -10.3j mi/h