need help with this problem

Answer:

1-3-4-2-5

Step-by-step explanation:

[tex]tan\frac{\theta}{2}[/tex] <== Given

[tex]\frac{sin\frac{\theta}{2}}{cos\frac{\theta}{2}}[/tex] <== Step 1

[tex]\frac{\frac{\sqrt{1-cos\theta}}{2}}{\frac{\sqrt{1+cos\theta}}{2}}[/tex] <== Step 3

[tex]\frac{\sqrt{1-cos\theta}}{\sqrt{1+cos\theta}}[/tex] <== Step 2 (as a result of Step 4)

[tex]\pm\sqrt{\frac{1-cos\theta}{1+cos\theta} }[/tex] <== Step 5

Answer:

50

Step-by-step explanation:

Answer:

£0.76

Step-by-step explanation:

1kilogram = 1000grams

1000g of grapes costs £2

380g costs = (380 × 2)/ 1000

760/1000 = £0.76

Answer:

82041000

Step-by-step explanation:

50,000,000 + 32,000,000 + 41,000

Answer:

a. about 8.3%

b. 2.172 m

Step-by-step explanation:

a. 1.81 * x = 1.96

x = 1.083

Percent increase is approximately 8.3%

b. 1.81 * 1.2 = x

x = 2.172 m

Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:

The semi-major axis length is √47196900 = 6870 km. That distance from the center of the Earth means the satellite is ...

  6780 -6370 = 500 . . . km

from the surface of the Earth.

The satellite is a maximum of 500 km from the Earth.

(It is a minimum of 250 km from Earth.)

__

The equation has a zero at t=6. When the car's velocity is zero, it is at a complete stop.

The car comes to a complete stop when time is 6 seconds.

(The car is still being accelerated, so it doesn't stay stopped.)

__

I prefer a graphing calculator for a quick solution. You can also solve this equation algebraically.

  0 = 0.5t^2 -10.5t +45 . . . . t when v(t) = 0

  t^2 -21t +90 = 0 . . . . . . . multiply by 2

  (t -6)(t -15) = 0 . . . . . . . . factor

  t = 6 or t = 15 . . . . . . . only t=6 is in the domain of the function

Answer:

B = 2.

Step-by-step explanation:

First work out 8/2. Okay so how many 2's go into 8? 4.

We now have B + 4 = 6.

Now that we've simplified it a bit we can do a reverse equation and turn it into subtraction.

Take the answer (6) and 4 and put them into a subtraction equation,

6 - 4. And simple subtraction should be easy so 6 - 4 = 2.

So B equals 2. Let's check it! 2 + 4 = 6. I think that sounds right so that will be the answer. B=2.

Hope that helps. x

Answer:

  60 nickels

Step-by-step explanation:

When a ratio between coins is given, I like to consider the problem in terms of groups of coins. Here, each group would consist of 1 nickel and 0.20 quarters. The value of that group is

  5¢ +0.20×25¢ = 10¢

Then the number of groups is ...

  (total value)/(value of 1 group) = number of groups

  600¢/10¢ = 60

Since each group has 1 nickel, there are 60 nickels.

__

Check

60 nickels + 12 quarters = $3.00 +3.00 = $6.00

_____

Additional comment

If you want to see this with equations and variables, you can do this.

Let n and q represent the numbers of nickels and quarters, respectively. The given relations are ...

  0.05n +0.25q = 6.00

  q = 0.20n

Substituting for q in the first equation gives ...

  0.05n +(0.25)(0.20n) = 6.00

Simplifying gives ...

  0.10n = 6.00

  n = 6.00/0.10 = 60

Answer:

y=-5

Step-by-step explanation:

-10/2=2y/2

-5=y

y=-5

Answer:

y = - 5

Step-by-step explanation:

You have yo divided the numbers

Cancel terms that are in both the numerator and denominator

Move the variable to the left

Answer:

3, 5, ,7 or 9, 5, 1

Step-by-step explanation:

Let the three terms in AP be a - d, a & a + d

where a = First term and d = Common difference.

Condition 1: sum of three terms in AP is 15.

a - d + a + a + d = 15

3a = 15

a = 15/3

a = 5

Condition 2: When first two terms are each decreased by 1 and the last is increased by 1 then new terms so obtained will be as follows:

a - d - 1, a - 1, a + d + 1

These terms are in G.P.

[tex] {(a - 1)}^{2} = (a - d - 1)(a + d + 1) \\ \\ {(5 - 1)}^{2} = (5 - d - 1)(5 + d + 1) \\ \\ {(4)}^{2} = (4 - d)(6 + d) \\ \\ 16 = 24 + 4d - 6d - {d}^{2} \\ \\ 0 = 8 - 2d - {d}^{2} \\ \\ {d}^{2} + 2d - 8 = 0 \\ \\ {d}^{2} + 4d - 2d - 8 = 0 \\ \\ d(d + 4) - 2(d + 4) = 0 \\ \\ (d + 4)(d - 2) = 0 \\ \\ d + 4 = 0 \: \: or \: \: d - 2 = 0 \\ \\ d = - 4 \: \: or \: \: d = 2 \\ \\ when \: d = - 4 \\ \\ a - d = 5 - ( - 4) = 9 \\ a = 5 \\ a + d = 5 - 4 = 1 \\ \\ when \: d = 2 \\ a - d = 5 - 2 = 3 \\ a = 5 \\ a + d = 5 + 2 = 7 \\ \\ thus \: three \: terms \: in \: AP \: are: \\9, \: 5, \: 1 \: \: or \: \: 3, \: 5, \: 7[/tex]

We have:

[tex]1-\frac{1}{3} >0[/tex]    ;   [tex]1- \frac{11}{17}>0[/tex]  ;    [tex]1-\frac{132}{157}>0[/tex]   ⇒ right

[tex]\frac{-1}{7}, \frac{-51}{107},\frac{-347}{949} <0[/tex]  ⇒ wrong

[tex]\frac{7}{5}, \frac{131}{47} ,\frac{945}{711} >1[/tex] ⇒ wrong

ANSWER: [tex]\frac{1}{3} ,\frac{11}{17} ,\frac{132}{157}[/tex]

ok done. Thank to me :>

Answer:

Step-by-step explanation:

formula : m=(y2-y1)/(x2-x1)

(4 - 8) / (2 - - 5)

-4 / 7

m = -4 / 7 = -0.57143

Answer:

1111 is the answer to your question.

Answer:

Step-by-step explanation: This is the answer

Answer:

It's C. for plato. It's a rectangle

Step-by-step explanation:

Answer:

its a rectangle .

Step-by-step explanation:

Answer:

Base = 10 ft. and the height = 6.

Step-by-step explanation:

Area of triangle = 1/2bh

base is 4 + h  ⇔  base = 4 + h

height = h

Using the formula for the area of triangle substitute into the formula the given facts.

A = 1/2bh

30 = 1/2(4 + h) (h)

30 = 1/2(4h + h²)     Multiply both sides by 2

60 = 4h + h²

-60 =           -60      Add -60 to both sides

0 = h²+ 4h -60        

(h + 10)(h - 6) = 0      Factor

h + 10 = 0    h - 6 =0

h = -10         h = 6

reject any negative number and use the positive answer for h.

So h = 6      and the base = 4 + 6 ; base = 10

Answer:

2

Step-by-step explanation:

29 % 3 = 9

3x9 = 27

29 - 27 = 2

[tex]\begin{cases} x=-7\implies &x+7=0\\ x=0\implies &x=0\\ x=1\implies &x-1=0\\ x=6\implies &x-6=0 \end{cases}\qquad \implies (x+7)(x)(x-1)(x-6)=\stackrel{y}{0} \\\\\\ (x+7)(x)\stackrel{using~\mathbb{FOIL}}{(x^2-7x+6)}=0\implies (x^2+7x)(x^2-7x+6)=0[/tex]

[tex]\begin{array}{llll} x^2-7x+6\\ \qquad \times ~x^2\\\cline{1-1} x^4-7x^3+6x^2 \end{array}\qquad +\qquad \begin{array}{llll} x^2-7x+6\\ \qquad \times ~7x\\\cline{1-1} 7x^3-49x^2+42x \end{array} \\\\\\ (x^4-7x^3+6x^2)+(7x^3-49x^2+42x)=0 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x^4-43x^2+42x=y~\hfill[/tex]

Answer:

0.08

Step-by-step explanation:

a 1 in the thousandths place is dropped in standard rounding to the nearest hundredth.

Answer:

0.08

Step-by-step explanation:

In 0.081, 0 is the tenth, 8 is the hundredth, and 1 is the thousandth. So as you want to approximate to the nearest hundredth, you have to look at the number behind 8 which is 1. And, 1 is less than 5, so you don't have to round up.

Answer:

217 Seconds.

Step-by-step explanation:

The answer is 217 seconds because 60x3+37=217.

Answer:

2

Step-by-step explanation:

Because if you add 1  to 8 you get 9 then subtract 9 by 7 then and your answer is

Answer:

7.44miles

Step-by-step explanation:

1km = 0.62miles

12km will be ; 0.62 × 12

= 7.44miles

Answer:

[tex]-37\frac{3}{4}[/tex]

Step-by-step explanation:

0.75 is equivalent to three quarters, or (3/4).

3/4 would be the fraction. -37 would be the whole number.

[tex]-37.75 = \boxed{-37\frac{3}{4}}[/tex]

Hope this helps.

Answer:

- 37 3/4

Step-by-step explanation:

Answer:

[tex]x + 5 \: + \: x \: + 6 \: + x + 7 = 2x - 1 + x + 7 + x + 7 + 2x - 1[/tex]

[tex]3x + 18 = 6x + 12[/tex]

[tex]18 = 3x + 12[/tex]

[tex]6 = 3x[/tex]

[tex]x = 6 \div 3 = 2[/tex]

[tex]x = 2[/tex]

[tex](2 + \sqrt{3} ) + (4 - \sqrt{3} ) \\ = 2 + \sqrt{3} + 4 - \sqrt{3} \\ = 2 + 4 \\ = 6[/tex]

Answer:

6

Hope you could get an idea from here.

Doubt clarification - use comment section.

[tex]\huge \bf༆ Answer ༄[/tex]

Here's the solution ~

Answer: z < -8

Step-by-step explanation:

Since z is negative, divide both sides by -1, which leaves you with z > -8.

Multiplying or dividing an inequality by a negative number flips the sign, thus the answer is z < 8.

Correct me if I am incorrect.

Answer:

19

Step-by-step explanation:

in question given ,x = 2, y = 3, z = 5 in this way

(3x+3z+2w) and find the value of w . according to given values and put

Answer:

  4 +30/w . . . . for any w≠0

Step-by-step explanation:

The given constraints resolve to 2 equations in 4 unknowns. There are an infinite number of solutions.

The ratio requirement means ...

  (x -y +z)/2 = (y -z +2w)/3 = (2x +z -10)/5

Considering the first equality, we can multiply by 6 and subtract the right side.

  3(x -y +z) -2(y -z +2w) = 0   ⇒   3x -5y +5z -4w = 0

Considering the first and last expressions, we can multiply by 10 and subtract the right side.

  5(x -y +z) -2(2x +z -10) = 0   ⇒   x -5y +3z = -20

These two equations have solutions ...

  x = 10 -z +2w

  y = 6 + 0.4z +0.4w

Using these expressions in the ratio of interest, we have ...

  (3x +3z -2w) : w = (3(10 -z +2w) +3z -2w) : w = (30 -3z +6w +3z -2w) : w

  = (30 +4w) : w

Expressed as a mixed number, the ratio of interest is ...

  (30 +4w)/w = 4 +30/w . . . . an infinite number of solutions

__

For positive values of w that are divisors of 30, there are 8 possible values:

   (w, ratio) = (1, 34), (2, 19), (3, 14), (5, 10), (6, 9), (10, 7), (15, 6), (30, 5)

_____

Check

It might be interesting to substitute the expressions for x and y into our original equation(s).

  (x -y +z)/2 = ((10 -z +2w) -(6 +0.4z +0.4w) +z)/2 = (2 -0.2z +0.8w)

  (y -z +2w)/3 = ((6 +0.4z +0.4w) -z +2w)/3 = (2 -0.2z +0.8w)

  (2x +z -10)/5 = (2(10 -z +2w) +z -10)/5 = (2 -0.2z +0.8w)

All of these expressions are identical, as they should be.

3x | 3x^3+9x^2+27x |x^2+3x+9x

- 3x^3

-------

9x^2

- 9x^2

---------

27x

- 27x

--------

0

Answer:

x^2 + 3x + 9x

Hope you could get an idea from here.

Doubt clarification - use comment section.