Need help ASAP
A gives the area of the rectangle. Find the
11.
12.
A-35 m²
5 m
b
6 ft

The fourth vertex is (2, 1), and horizontal length is 1.5 km and the vertical length is 3 km. Then the area of the Moon exploration area will be 4.5 square km.

Let L be the length and W be the width of the rectangle.

Then the area of the rectangle will be

Area of the rectangle = L×W square units

Scientists are sending a rover to the moon.

Their plan is to study a rectangular area of the moon by placing a grid over the map as shown.

On the grid, 1 unit represents 1 kilometer (km).

PART A.  Then the coordinates of the fourth vertex of the rectangle will be (2, 1).

PART B. Then the horizontal length of the rectangle will be 1.5 km and the vertical length of the rectangle will be 3 km.

PART C. Then the area of the Moon exploration area in square kilometers will be

Area = 3 x 1.5

Area = 4.5 square km

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Answer:

y=3x+1

Step-by-step explanation:

From the table when X=0,y=1 thus b=1.

When

We are going to multiply the fraction 3/4, to the power of 2.

This means that:

Therefore:

[tex]\bf{\left(\dfrac{3}{4}\right)^{2}=\dfrac{3\times3}{4\times4}=\dfrac{9}{16} }[/tex]

Therefore, the answer of the fraction (3/4)^2, is equal to 9/16.

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer: 41.51

Step-by-step explanation:

[tex]\sin 49^{\circ}=\frac{x}{55}\\x=55 \sin 49^{\circ} \approx \boxed{41.51}[/tex]

The value of this equation is x = 0

The representation of an equation of the first degree - is given by:

[tex] \boxed{ \large \sf ax + b = 0}[/tex]

This representation is also defined in a first degree function.

— To solve this expression, let's: add or subtract the real terms. Then we will do the division.

⚘ Resolution

[tex] \large \sf{-3+8x-5=-8}[/tex]

[tex] \large \sf{-8+8x=-8}[/tex]

[tex] \large \sf{8x=0}[/tex]

[tex] \large \sf{x=0 \div 8}[/tex]

[tex] \green{ \boxed{ \boxed{ \blue{ \large \sf{x=0}}}}} \\ [/tex]

Therefore, the value of this equation will be x = 0

Answer:

Answer: Original price = $150   Amount Paid = $90

Step-by-step explanation:

First we make a proportion 60/x = 40/100. When we cross multiply and divided to get x by itself we get $150 dollars. This is the original price of the dress. Now we take $150-$60 and we get $90. This is what Victoria paid for the dress after the 40% discount.

Hope this helps! :)

[tex](-4x+12)^{1/2}=x\\\sqrt{-4x+12}=x\\\\D:-4x+12\geq0\wedge x\geq0\\D:4x\leq12\wedge x\geq0\\D:x\leq3\wedge x\geq0\\D:x\in\langle0,3\rangle\\\\\sqrt{-4x+12}=x\\-4x+12=x^2\\x^2+4x-12=0\\x^2-2x+6x-12=0\\x(x-2)+6(x-2)=0\\(x+6)(x-2)=0\\x=-6 \vee x=2\\\\-6\not \in D\\\\\boxed{x=2}[/tex]

Using translation concepts, the graph that represents [tex]y = \sqrt[3]{x} + 2[/tex] is given at the end of the question.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

[tex]y = \sqrt[3]{x} + 2[/tex] is a shift up of 2 units of [tex]y = \sqrt[3]{x}[/tex], hence the graph is given at the end of this question.

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Answer:

[tex]\frac{16}{3}[/tex] or [tex]5\frac{1}{3}[/tex]

Step-by-step explanation:

Given :

[tex]2\frac{1}{3} -\frac{1}{2} \div \frac{3}{4} + 3\frac{2}{3}[/tex]

=============================================================

Rewrite in improper fraction form :

[tex](\frac{6}{3} +\frac{1}{3}) -\frac{1}{2} \div \frac{3}{4} + (\frac{9}{3} +\frac{2}{3})[/tex]

[tex]\frac{7}{3} - \frac{1}{2} \div \frac{3}{4} + \frac{11}{3}[/tex]

=============================================================

Finding the common denominator :

⇒ 3 × 4

⇒ LCM = 12

============================================================

Solving with 12 as LCM :

⇒ [tex]\frac{7\times 4}{3 \times4} - \frac{1\times6}{2\times6} \div \frac{3\times3}{4\times3} + \frac{11\times4}{3\times4}[/tex]

⇒ [tex]\frac{28}{12} - \frac{6}{12} \div \frac{9}{12} + \frac{44}{12}[/tex]

⇒ [tex]\frac{28}{12} - \frac{2}{3} + \frac{44}{12}[/tex] [Division takes place first]

⇒ [tex]\frac{28}{12} - \frac{8}{12} + \frac{44}{12}[/tex]

⇒ [tex]\frac{28}{12} + \frac{36}{12}[/tex]

⇒ [tex]\frac{64}{12}[/tex]

⇒ [tex]\frac{16}{3}[/tex] or [tex]5\frac{1}{3}[/tex]

Answer:

[tex]y= -\dfrac 17 x +\dfrac{48}7[/tex]

Step-by-step explanation:

[tex]~~~~~~~x+7y = 48\\\\\implies 7y = 48-x\\\\\implies y = \dfrac 17(48-x)\\\\\implies y= -\dfrac 17 x +\dfrac{48}7\\\\\text{It now in the slope-intercept form (y = mx+c).}[/tex]

The equation of the scatter plot is (a) y = 100x + 2

The line of best fit of the scatter plot passes through the points

(x,y) = (0,2) and (1,102)

The equation is then calculated as:

[tex]y = \frac{y_2 -y_1}{x_2 -x_1}(x - x_1) + y_1[/tex]

Substitute known values in the above equation

[tex]y = \frac{102 -2}{2-1}(x - 0) + 2[/tex]

Evaluate the expression on the right-hand side

y = 100x + 2

Hence, the equation of the scatter plot is (a) y = 100x + 2

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Answer:

2

Step-by-step explanation:

Step-by-step explanation:

if there is no typo, or there are no parts missing, then

-1 <= 2-j < -5

cannot have any solution, because already for the outside limits -1 < -5 is impossible. -1 is larger than -5 !

Step-by-step explanation:

try this option (see the attachment), all the correct answers are marked with colour.

Answer:

Step-by-step explanation:

Note that in this diagram, point A represents point X, point B represents point Y, and point C represents point Z.

From the diagram, it appears as if [tex]\overline{XZ} \perp \overline{XY}[/tex]. To determine if this is the case, we can find the slopes of both segments.

[tex]m_{\overline{XZ}}=\frac{4-1}{4-1}=1\\m_{\overline{XY}}=\frac{-1-1}{3-1}=-1[/tex]

Since these slopes are negative reciprocals, we know that they are perpendicular.

This means we can use the formula [tex]A=\frac{1}{2}bh[/tex], where b is the base (XY) and h is the height (XZ).

Using the distance formula,

[tex]XY=\sqrt{(3-1)^{2}+(-1-1)^{2}}=2\sqrt{2}\\XZ=\sqrt{(4-1)^{2}+(4-1)^{2}}=3\sqrt{2}[/tex]

This means the area is [tex]\frac{1}{2}(2\sqrt{2})(3\sqrt{2})=\boxed{6}[/tex]

The exact area of the isosceles trapezoid inscribed in a circle is determined as 196 sq units.

The height of the trapezoid is calculated as follows;

From the image, the sum of h1 and h2 is the height of the trapezoid.

Each of the height will be calculated using Pythagoras theorem as follows;

h1² = r² - (b1/2)²

h1² = 10² - 6²

h1² = 64

h1 = √64

h1 = 8

h2² = r² - (b1/2)²

h2² = 10² - 8²

h2² = 36

h2 = √36

h2 = 6

Total height = 8 + 6 = 14

A = ¹/₂(b₁ + b₂)H

A = ¹/₂(12 + 16) x 14

A = 196 sq units.

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The values of x = -6 and y = 6 satisfy both the equations; therefore, (-6, 6) is the solution. The correct option is a)

From the question, we are to determine the solution of the given system of equations

The given system of equations are

2 x + 3 y = 6 -------  (1)

x + 3 y = 12   ------- (2)

From equation (2)

x + 3y = 12

Then, we can write that

x = 12 - 3y ---------   (3)

Substitute this into equation (1)

2x + 3y = 6

2(12 -3y) + 3y = 6

24 - 6y + 3y = 6

24 -3y = 6

24 - 6 = 3y

18 = 3y

∴ y = 18/3

y = 6

Substitute the value of y into equation (3) to get the value of x

x = 12 - 3y

x = 12 -3(6)

x = 12 - 18

x = -6

∴ x= -6 and y = 6 ; Thus, (-6, 6) is a solution

Hence, the values of x = -6 and y = 6 satisfy both the equations; therefore, (-6, 6) is the solution. The correct option is a)

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The difference between 0.58 million and 36,475 is 543,525 the answer is 543,525.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have:

= 0.58 million - 36,475

As we know,

1 million = 1,000,000

0.58 million = 580,000

= 580,000 - 36,475

= 543,525

Thus, the difference between 0.58 million and 36,475 is 543,525 the answer is 543,525.

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Answer:

18

Step-by-step explanation:

mack has 18cats because she has 2×9 cats as Wayne 2×9 is 18

Answer:

18

Step-by-step explanation:

[tex]\sf Twice = *2\\9 * 2 = 18[/tex]

[tex]A = B \log_x C\\\\\text{Given that,}~~ A = 11, ~B = 4~ C = 190\\\\~~~~~~~~11 = 4 \log_x (190)\\\\\implies \log_x (190) = \dfrac{11}4\\\\\implies x^{\tfrac{11}4} = 190\\\\\implies x = 190^{\tfrac 4{11}}\\\\ \implies x \approx 6.7397[/tex]

(-3 - y) / (x - 4)

(-3 - (-3)) / ((-5) - 4)

(0)/(-9)

0

hope it helps...!!!

Answer:

0

Step-by-step explanation:

[tex] \frac{ (- 3 - y)}{(x - 4)} \\ when \: x = - 5 \: \: y = - 3 \\ \frac{( - 3 - - 3)}{ (- 5 - 4)} = \frac{ - 3 + 3}{ - 9} \\ = \frac{0}{ - 9} \\ 0[/tex]

Answer:

3(x + 4) = 3(x) + 3(4)
3(x + 4) = 3x + 12
3x + 12 = 3x + 12

Subtract 12 from both sides
3x + 12 - 12 = 3x + 12 - 12

3x = 3x
3x - 3x = 3x - 3x
= 0

Answer:

-137

Step-by-step explanation:

The difference between two numbers can be found through subtraction.

-45 - 95 = -137.

Answer: 3240-755

Step-by-step explanation:

We know that:

[tex](1+2+\cdots+80)-(71+72+\cdots+80)=1+2+\cdots+70[/tex]

Thus, [tex]1+2+\cdots+70=\boxed{3240-755}[/tex]

The point at which the graph of the function has a tangent line with the given slope is (-5,15)

A tangent is a straight line that touches any point on a curve.

Analysis:

slope of the curve [tex]x^{2}[/tex] + 2x is equal to dy/dx = d/dx( [tex]x^{2}[/tex] + 2x) = 2x+2

Which is equal to -8

2x+2 = -8

2x = -8-2

2x = -10

x = -5

substitute x into the equation

y = [tex](-5)^{2}[/tex] + 2(-5) = 25 - 10 = 15

In conclusion, the point at which the graph of the function has a tangent at -8 is (-5,15)

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The probability of drawing a black ball on the second draw will be 3/5.

From the information given, the total number of balls will be:

= 2 + 3 = 5 balls.

When the first ball is black and the second is red. This will be:

= 2/5 × 3/4

= 3/10

When the first is red and the second is black, this will be:

= 3/5 × 2/4

= 3/10

Therefore, the probability of drawing a black ball on the second draw will be:

= 3/10 + 3/10

= 3/5.

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Answer:

Zoe's number is 6

Step-by-step explanation:

Let the number be 'n'

a) Multiply 'n' by 3 ⇒ n*3 = 3n

  Add 4 to '3n' ⇒ 3n + 4

Add 5 to 'n' ⇒  n +5

Multiply (n+ 5) by 2 ⇒ (n +5)*2 = 2n + 5*2 = 2n + 10

    3n + 4 = 2n + 10

b) 3n + 4 = 2n + 10

Subtract 4 form both sides

       3n = 2n + 10 - 4

       3n = 2n + 6

Subtract 2n from both sides

    3n - 2n = 6

          [tex]\sf \boxed{\bf n = 6}[/tex]

Answer:

21 is probably the best answer