Answer:
nice calculations!
Explanation:
During the Egg Drop lab sim you manipulated several variables like height, egg mass and impact surface. If you dropped a large egg from 10 meters which one condition would allow the best chance for the egg to survive unbroken?
Answer:
An egg with a thick shell.
Explanation:
Hope this helps.
Which action would decrease the entropy of a deck of playing cards?
A. Shuffling the deck
B. Dropping the deck on the floor
O C. Stacking the cards in order of face value
D. Throwing the deck up into the air
SUBMIT
Answer:
A. Stacking the cards in order of face value
Explanation:
A deck of playing cards' entropy would be reduced by being stacked in order of face value. Option C is correct.
What is entropy?The degree of randomness of the system is known as entropy.
If the system is organized its entropy is less. Stacking the cards in order of face value is an organized action.
Stacking the cards in order of face value is the action would decrease the entropy of a deck of playing cards.
Hence, option C is correct.
To learn more about entropy refer to;
https://brainly.com/question/13146879
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What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4
Answer:
[tex]x = 2\sqrt 2[/tex]
Explanation:
Given
[tex]Hypotenuse = 4[/tex]
Required
Find x
Since the triangle is a 45-45-90 triangle, the following relationship exists
[tex]x^2 + x^2 = 4^2[/tex] --- i.e. the other legs are equal
So, we have:
[tex]2x^2 = 16[/tex]
Divide both sides by 2
[tex]x^2=8[/tex]
Take square roots of both sides
[tex]x = \sqrt 8[/tex]
Simplify
[tex]x = 2\sqrt 2[/tex]
Answer:
7√2
Explanation:
for the light bulb to produce the aame illuminace with the candle to the screen, the luminous intensity of the bulb is _______ that of the candle?
Answer:
9 times
Explanation:
luminosity decreases to the square of the distance
Which of the following best describes how a transformer works?
O A. Converts electric energy into mechanical energy
B. Converts the voltage of a current source
C. Converts mechanical energy into electrical energy
D. Converts the direction of current flow in a circuit
Answer:
B.Converts the voltage of a current source
A transformer is an electrical apparatus designed to convert alternating current from one voltage to another. It can be designed to "step up" or "step down" voltages and works on the magnetic induction principle. ... When voltage is introduced to one coil, called the primary, it magnetizes the iron core.
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an object of volume 1m3 and density of 500kg/m3 float in water what volume of water is displaced
Answer:
[tex]0.5\; \rm m^{3}[/tex].
Explanation:
Calculate the mass of this object:
[tex]\begin{aligned}& m(\text{object}) \\ &= \rho(\text{object}) \cdot V(\text{object}) \\ &= 500\; \rm kg \cdot m^{-3} \times 1\; \rm m^{3} = 500\; \rm kg\end{aligned}[/tex].
Multiple the mass of this object by the gravitational field strength, [tex]g[/tex], to find the weight of this object: [tex]W(\text{object}) = m(\text{object}) \cdot g[/tex].
Since this object is floating in water, the buoyancy force on it should be equal to its weight:
[tex]F(\text{buoyancy}) = W(\text{object}) = m(\text{object}) \cdot g[/tex].
By Archimedes' Principle, the weight of the water that this object displaces would be equal to [tex]F(\text{buoyancy})[/tex], the size of buoyancy force on this object,
Hence, the weight of water displaced would be [tex]W(\text{object}) = m(\text{object}) \cdot g[/tex].
Divide this weight by [tex]g[/tex] to find the mass of water displaced:
[tex]\begin{aligned} & m(\text{water displaced}) \\ &= \frac{W(\text{water displaced})}{g} \\ &= \frac{m(\text{object}) \cdot g}{g} = m(\text{object}) = 500\; \rm kg\end{aligned}[/tex].
Assume that the density of water is [tex]\rho(\text{water}) = 1000\; \rm kg \cdot m^{-3}[/tex]. The volume of water displaced would be:
[tex]\begin{aligned}& V(\text{water displaced}) \\ &= \frac{m(\text{water displaced})}{\rho(\text{water})} \\ &= \frac{500\; \rm kg}{1000\; \rm kg \cdot m^{-3}} = 0.5\; \rm m^{3}\end{aligned}[/tex].
A 1.50 kg ball moving at 4.50 m/s is caught by a 60.0 kg man while the man is standing on ice. How fast will the man / ball combination be moving after the ball is caught by the man?
Answer:
Explanation:
The Law of Momentum Conservation applies, and the formula for us here specific to this problem is:
[tex][(m_bv_b)+(m_mv_m)]_b=[(m_b+m_m)v_{both}]_a[/tex] and filling in:
[(1.50*4.50)+60.0*0)] = [(1.50 + 60.0)v] and
6.75 + 0 = 61.5v so
v = .110 m/s in the same direction as the ball
The absorption of a photon causes a hydrogen atom
to change from the n = 2 to the n = 3 energy state.
What is the energy of the absorbed photon?
A) 4.9 eV
C) 1.9 eV
B) 3.4 eV
D) 10.2 eV
4.9 eV is the correct answer
Hope it helps you ^ _ ^
convert 3 hours 30 minutes into second
Answer:
9000 SECONDS
Explanation:3 hours=180 mins
180+30=210mins
150x60=12600secs
A 5L container has a
Answer:a gas at pressure of 0.8 m column of H g
Explanation:I thinkCalculate the force that is applied on this 0.25 kg ball, as it goes down to hit the ground.
(given gravity= 9.8 m/s2).
Answer:
F = 2.45 N
Explanation:
m = 0.25 kg
a = 9.8 m/s^2
F = ma
F = (0.25)(9.8)
F = 2.45 N
A householder has a 10.8 kW electric shower installed in the bathroom. Calculate the current drawn from the mains electricity supply by the shower.
Answer:
90 A
Explanation:
Applying,
P = VI.............. Equation 1
Where P = Power, V = Supply voltage, I = current.
Make I the subject of the equation
I = P/V.............. Equation 2
From the question,
Assuming the Voltage of the main electric supply is 120 V
Given: P = 10.8 kW = 10800 W, V = 120 V (household voltage)
Substitute these values into equation 2
I = 10800/120
I = 90 A
what is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?
Answer:
[tex]momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} [/tex]
Mass is 7.5 kg
Velocity is 1.6 m/s
we know that,
momentum = mass × velocity
or; momentum =7. 5 kg × 1. 6 m/s
or; momentum = 12 kgms^1
Which wave shows the loudest sound below?
Answer:
I think C
Explanation:
If im right give brainliest :)
how can professional education improve life of people?
Answer:
Professional education as a science has been defined as a field of educational science that studies the growth of a person into a profession and the related problems. It refers to organized education aimed at the knowledge and skills needed in the profession and working life, as well as growing into active citizenship and membership of society. Professional education as a discipline studies vocational training, skills and learning related to the profession and working life.
It enables young people and adults to pursue goal-oriented learning with the aim of acquiring and developing the necessary skills in the profession and creating the conditions for independent professional activity and continuous development in the profession.
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Answer:
Gravitational energy and kinetic energy
2. CaCl2 (s) + 2H20 ---> Ca(OH)2 (aq) + 2HCl (g) + heat
Is it an endothermic reaction?
Answer:
no
Explanation:
Calcium chloride is a chemical compound made up of calcium ions and chlorine ions. ... Mixing calcium chloride with water is an exothermic reaction, which means that the combination of the two substances releases heat. Thus, when you add calcium chloride to water, the solution heats.
A man who weighs 75kg on the surface of the earth whose mass is 6*10^24kg. If the radius of earth is 6480km ,calculate the force of attraction between them.
Answer:
718.02N is the answer to the question
A jetliner can fly 8.0 hours on a full load of fuel. Without any wind it flies at a speed of 2.42 x 102 m/s. The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 40.7-m/s wind from the jet stream, which blows from west to east. What is the maximum distance (in kilometers) that the plane can travel due west and just be able to return home
Answer:
3386.23 Km
Explanation:
Without any wind interference the speed of the plane, it flies at 2.42 x 102 m/s or 242 m/s
The magnitude of the velocity of the air = 40.7-m/s
The time taken, for the plane to fly due west, tw = distance, x ÷ (speed of the plane without wind interference, up - the magnitude of the velocity of the air, ua).......... (equation 1)
The time taken, for the plane to fly due east, te = distance, x ÷ (speed of the plane without wind interference, up + the magnitude of the velocity of the air, ua).......... (equation 2)
To calculate the total time, t, the plane can fly to cover east and west distances, we add equation 1 and 2 together
t = (x ÷ (up - ua)) + (x ÷ (up + ua))
Making distance x, the subject of the formula we have:
x = t ( up²- ua²) ÷ 2up
note t = 8.0 hours which is (8 x 60 x 60) seconds = 28,800
So, x = 28,800 ((242 m/s)² - (40.7-m/s)²)÷ 2(242 m/s)
x= 1,638,936,288 ÷ 484
= 3386.23 Km
A motorcycle daredevil plans to ride up a 2.0-m-high, 20∘ ramp, sail across a 10-m-wide pool filled with hungry crocodiles, and land at ground level on the other side. He has done this stunt many times and approaches it with confidence. Unfortunately, the motorcycle engine dies just as he starts up the ramp. He is going 10.4 m/s at that instant, and the rolling friction of his rubber tires (coefficient 0.02) is not negligible. Part A: Justify your answer by calculating the distance he travels through the air after leaving the end of the ramp.
Answer:
The motorcycle daredevil does not sail across the 10-m wide pool filled with hungry crocodiles
Explanation:
The given parameters are;
The height of the ramp = 2.0 m-high
The angle of elevation of the ramp, θ = 20°
The width of the pool = 10 m
The speed with which he is going when the engine fails = 10.4 m/s
The rolling friction between the rubber tires, μ = 0.02
μ·g·cos(θ) = (1/2)·(a)
a = (μ·g·cos(θ))/(1/2)
Where;
a = The acceleration down the plane
∴ a = 0.02 × 9.81 × cos(20°)/(1/2) ≈ 0.369
The length of the ramp, l = 2.0 m/(sin(20°)) ≈ 5.8476088 m
The velocity at the end of the ramp, v² = u² - 2·a·l
∴ v² = 10.4² - 2×(0.369 + 9.81 × sin(20°))×5.8476088 ≈ 64.60446471
v ≈ √(64.60446471) ≈ 8.04
∴ The velocity at the top of the ramp, v ≈ 8.04 m/s
The time it takes the motorcycle to reach ground level from the top of the ramp, t, is given as follows;
h = h₀ + u·t + (1/2)·a·t²
h₀ = 2, u = 8.04×sin(20°), a = -9.81
When h = 0 (ground level), we have;
∴ h = 2+ 8.04×sin(20°)·t - (1/2)×9.81×t²
0 ≈ 2.75·t - 4.905·t² + 2
2.75·t - 4.905·t² + 2 = 0
By using a graphing calculator, we have, t = 0.978 or t = -0.42
At ground level, the time of flight, t ≈ 0.978 s
The horizontal distance the motorcycle travels, before landing, x = u × cos(θ) × t
∴ x = 8.04×cos(20 Degrees) × 0.978 = 7.3889
The horizontal distance the motorcycle travels, before landing, x ≈ 7.3889 m
Therefore, given that the horizontal distance the motorcycle travels in the air 7.3889 m < 10 m, therefore the motorcycle daredevil does not sail across the 10-m wide pool filled with hungry crocodiles
What is speed in a specific direction called
Answer:
my brainly answer got deleted for no reason but its velocity thats the name of speed in 1 direction
Explanation:
How are galaxies named?
Answer:
Some galaxies are given descriptive names (e.g. "Andromeda", "Whirlpool") if they are particularly distinctive in location or appearance. But most galaxies are known from their designation in a catalogue. One of the earliest catalogues of objects in the sky was made by Charles Messier.
if you can't test an explanation through experiment,
A) the phenomena let's not have occurred in the physical world
B) people will disagree on whether the explanation is correct
C) your observation must not have really occurred
D) a group of scientists will vote on their favorite explanation
Answer:
B
Explanation:
You can do only number 1 only
For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C
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the crane takes 2.5s to raise the box 3.0 m. Calculate the power output of the crane
Answer:
Power = 1800 W
Explanation:
Power = work / time
Power = 4500 / 2.5
Power = 1800 W
Scientists today use satellites as well as telescopes to observe the universe. Suggest one way
that developments in equipment have changed the information scientists collect about
planets.
Answer:
Rovers, unmanned space probes, modern instruments,
Explanation:
Write the formula of gravitational force between two bodies of masses x and y kept at a distance r
Answer:
F=Gxy/r^2
Explanation:
F=Gm1m2/d^2
F=Gxy/r^2
Which of the following describes a mixture?( 2 A combination of two or more substances O A combination of two sources of energy An object made of the same substance A substance that is made up of matter
Answer:
A combination of two or more substances.
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
1. At what angle of release did the sepak takraw ball travel farthest? ______ 2. How will you compare the range (horizontal distance) travelled by the ball at angles of 25º and 65º? How about at angles of 40º and 50º? ________________________________________________________________________ 3. At what angle of release did the ball reach the maximum height?_________ 4. How will you compare the height reached by the ball at 25º, 45º and 65º? _______________________________________________________________________ 5. How will you explain the relationship between the angle of release to the height of the projectile? How about angle of release and range before it reaches the farthest distance?
Answer:
1) θ = 45, b) R₄₀ = R₅₀ = (v₀² / g) 0.985, R₂₅ = R₆₅ = (v₀² / g) 0.766
3) θ = 90º, d) y₂₅ = (v₀ / 2g) 0.179, y₄₅ = (v₀ / 2g) 0.5, y₆₅ = (v₀ / 2g) 0.821
Explanation:
This is a projectile throwing exercise, let's use the relations
R = [tex]\frac{v_o^2 \ sin \ 2\theta }{g}[/tex]
1) the angle for a maximum reach (R) is θ = 45
R = v₀²/g
2) let's compare the scopes
θ = 25º
R₂₅ = (v₀² /g) sin 2 25
R₂₅ = (v₀² /g) 0.766
θ = 65º
R₆₅ = (v₀² / g) sin 2 65
R₆₅ = (v₀² / g) 0.766
θ = 40º
R₄₀ = (v₀²/g) sin 2 40
R₄₀ = (v₀²/ g) 0.985
θ = 50
R₅₀ = (v₀²/g) sin 2 50
R₅₀ = (v₀² / g) 0.985
we can see that it has the same scope
R₄₀ = R₅₀ = (v₀² / g) 0.985
R₂₅ = R₆₅ = (v₀² / g) 0.766
3) the maximum height is reached when the vertical speed is zero
[tex]v_y^2 = v_{oy}^2 - 2 g y[/tex]
v_y = 0
y = [tex]\frac{v_{oy}^2}{2g}[/tex]
y = (v₀² /2g) ( sin θ)²
therefore the height is maximum for θ = 90º
4) θ = 25º
y₂₅ = (v₀ / 2g) (sin 25)²
y₂₅ = (v₀ / 2g) 0.179
θ = 45º
y₄₅ = (v₀ / 2g) (sin 45)²
y₄₅ = (v₀ / 2g) 0.5
θ = 65º
y₆₀ = (v₀ / 2g) (sin 65)²
y₆₅ = (v₀ / 2g) 0.821
5) It is appreciated that as the launch angle increases the height increases, the maximum is when the movement is vertical
For the launch angle, the reach has a maximum for the angle of 45º, this is due to the symmetry of the sine function around this value.