name the reactants in the equation P+O​

Answer:

In other words, you conducted the four fundamental activities that make up the interaction design process – establishing requirements, designing alternatives, prototyping designs, and evaluating prototypes.

Explanation:

Answer:

true.......................

New cars use embedded computers to make driving safer. The given statement is true.

The word RAM stands for random-access memory and it is known as memory of short term where data is stored and as required by the processor. This is not there to deal with long term data and it is working after the computer turned off.

Generally, there are three types of RAM and these are SRAM, ECC, and DRAM. The SRAM stands for static random memory, and DRAM stands for dynamic access memory.

CPU stands for central processing unit and commonly it is known as brain of the computer, the main function of CPU is to control the function of the computer or system and it gives command to the parts of computer.

Therefore, New cars use embedded computers to make driving safer. The given statement is true.

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Answer:

C.

Devices can be remotely locked or wiped if connected

Explanation:

Answer:

The correct answer is B. Cipher.

Explanation:

Cipher is a system of reversible transformations that depends on some secret parameter, called key, and is designed to ensure the secrecy of transmitted information.

The cipher can be a combination of conventional characters or an algorithm for converting ordinary numbers and letters. The process of making a message secret with a cipher is called encryption. An important parameter of any cipher is the key - a parameter of the cryptographic algorithm, which ensures the selection of one transformation from the set of transformations possible for this algorithm. In modern cryptography, it is assumed that all the secrecy of a cryptographic algorithm is concentrated in the key.

Answer:

try this

Explanation:

#include<stdio.h>

#include<malloc.h>

typedef struct poly{ double coff;

int pow;

struct poly *link; }SL;

void create(SL **head)

{

*head=NULL;

}

//Insertion  

void ins_beg(SL ** head, double c, int pw)

{

SL *ptr;

ptr=(SL *)malloc(sizeof(SL));

ptr->coff=c;

ptr->pow=pw;

ptr->link=*head;

*head=ptr;

}

void trav(SL **head)

{

SL *ptr;

ptr=*head;

printf("\n\t Cofficient Exponent\n");

while(ptr!=NULL)

{ printf("\t\t%3.2f \t%d\n",ptr->coff, ptr->pow);

ptr=ptr->link;

}

}

//addition of polynomial............

void mult(SL *pl1, SL *pl2, SL **res)

{

SL trav1, trav2, ptr, new1,*loc;

int x,y;

trav1=*pl1;

while(trav1!=NULL)

{

trav2=*pl2;

while(trav2!=NULL)

{

x=(trav1->coff)*(trav2->coff);

y=(trav1->pow)+(trav2->pow);

//printf("\t%d\t%d\n",x,y);

if(*res==NULL)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=x;

new1->pow=y;

new1->link=NULL;

*res=new1;

}

else

{

ptr=*res;

while((y<ptr->pow)&&(ptr->link!=NULL))

{

loc=ptr;

ptr=ptr->link;

}

if(y==ptr->pow)

ptr->coff=ptr->coff+x;

else

{

if(ptr->link!=NULL)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=x;

new1->pow=y;

loc->link=new1;

new1->link=ptr;

}

else

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=x;

new1->pow=y;

ptr->link=new1;

new1->link=NULL;

}

}

}

trav2=trav2->link;

}

trav1=trav1->link;

}

}

//...addition..............

void add(SL *pl1, SL *pl2)

{

SL trav1, ptr, *new1,*loc; trav1=*pl1;

while(trav1!=NULL)

{

loc=ptr=*pl2;

while((trav1->pow<ptr->pow)&&(ptr->link!=NULL))

{

loc=ptr; ptr=ptr->link;

}

if(loc==ptr)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=trav1->coff;

new1->pow=trav1->pow;

new1->link=*pl2;

*pl2=new1;

}

else

if(trav1->pow==ptr->pow)

{

ptr->coff=ptr->coff+trav1->coff;

//ptr->pow=ptr->pow+trav1->pow;

}

else

if(ptr->link!=NULL)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=trav1->coff;

new1->pow=trav1->pow;

new1->link=ptr;

loc->link=new1;

}

else

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=trav1->coff;

new1->pow=trav1->pow;

new1->link=NULL;

ptr->link=new1;

}

trav1=trav1->link;

}

}

int main()

{

SL first, sec, *res;

create(&first);

ins_beg(&first,10.25,0);

ins_beg(&first,4,1);

ins_beg(&first,5,2);

ins_beg(&first,4,4);

printf("\nFirst Polinomial:\n");

trav(&first);

create(&sec);

ins_beg(&sec,11,0);

ins_beg(&sec,6,1);

ins_beg(&sec,4,2);

ins_beg(&sec,3,3);

printf("\nSecond Polinomial:\n");

trav(&sec);

create(&res);

printf("\nMultiplication of two Polinomial:\n");

mult(&first,&sec,&res);

trav(&res);

printf("\nAddition of two Polinomial:\n");

add(&first,&sec);

trav(&sec);

//trav(&first);

return 0;

}

Answer:

Write an algorithm to input a natural number, n, and calculate the odd numbers equal or less than n. ... Design an algorithm and flowchart to input fifty numbers and calculate their sum. Algorithm: Step1: Start Step2: Initialize the count variable to zero Step3: Initialize the sum variable to zero Step4: Read a number say x Step 5: Add 1 to the number in the count variable Step6: Add the ..

Explanation:

Answer:

e. volts through it

Explanation:

volts through it

The contents (top to bottom) left on the stack is volts through it. Thus, option E is correct.

When a computer program begins execution, standard streams are interconnected input and output channels of communication between the program and its surroundings. The three I/O connections are known as standard input (stdin), standard output (stdout), and standard error (stderr).

A negative sign in the input indicates that the stack should be popped, and the return value should be sent to standard output, whereas any other string means that the string should be pushed into the stack. Assume that the following input is processed: this parrot would not voom if I pushed — four thousand —- volts - through it.

The contents of the stack (from top to bottom) are volts via it. As a result, option E is correct.

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Answer:

digital

Explanation:

Today, video production has become digital, and all playback devices work on the open standard known as digital technology.​

Answer:

The vendor management process includes a number of different activities, such as: Selecting vendors. The vendor selection process includes researching and sourcing suitable vendors and seeking quotes via requests for quotation (RFQs) and requests for proposal (RFPs), as well as shortlisting and selecting vendors. hope it helps

Answer:

the two programs to play multimedia products are;windows media player and VLC media player and the two programs to create multimedia products are;photoshop and PowerPoint

Answer:

Explanation:

The following code is written in Java. It contains the interface Shape, the class Box, and a tester class called Brainly with the main method. Box implements the Shape interface and contains, the instance variables, the constructor which takes in the inputs for length and width, getter methods for length and width, and the defines the area() method from the interface. Then the object is created within the Brainly tester class' main method and the area() method is called on that object. Output can be seen in the image attached below. Due to technical difficulties, I have added the code as a txt file below.

Answer:

ok where do i put anwaer?

Explanation:

Answer:

HURRY

Dr. Khan works for the marketing department of a company that manufactures mechanical toy dogs. Dr. Khan has been asked to assess the effectiveness of a new advertising campaign that is designed to be most persuasive to people with a certain personality profile. She brought four groups of participants to the lab to watch the video advertisements and to measure the likelihood that they would purchase the toy, both before and after watching the ad. The results of Dr. Khan’s study are presented below.

Part A

Explain how each of the following concepts applies to Dr. Khan’s research.

Survey

Dependent variable

Big Five theory of personality

Part B

Explain the limitations of Dr. Khan’s study based on the research method used.

Explain what Dr. Khan’s research hypothesis most likely was.

Part C

Use the graph to answer the following questions.

How did the trait of agreeableness affect how people responded to the new ad campaign?

How did the trait of conscientiousness affect how people responded to the new ad campaign?

Answer: MrBeast is a y0utuber who has lots of money

Explanation:

Answer:

He is a You tuber who likes to donate do stunts and best of all spend money.

It's like he never runs out of money.

Explanation:

Answer: A. Who will use the database?

Explanation:

When determining the statement of purpose for a database design,the most important question to ask is  Who will use the database?

Statement of purpose in a data base is very essential to know more about the database, this is why it is important to ask the question Who will use the database?

This question help the programmer to know the kind of data that will be running at the database so as make sure the database serve the required purpose.

Therefore option A is correct.

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Answer:

work book, work sheet, cell, columns and rows

Answer:

try this

Explanation:

#Python program for calculating avg

#Given data

m1 = [99.5, 78.25, 76, 58.5, 100, 87.5, 91, 68, 100]

f1 = [55, 62, 100, 98.75, 80, 85.25]

#combine scores

all_scores = m1 + f1

#number of m1 and f1

num_midterm = len(m1)

num_final = len(f1)

#find avg of scores

avg_midterm = sum(m1) / num_midterm

avg_final = sum(f1) / num_final

#print the avg

print("Average of the m1 score:",round(avg_midterm,2))

print("Average of the f1 score:",round(avg_final,2))

Answer:

The function in Python is as follows:

import math

import numpy as np    

def exp(x):

   mylist = []

   for n in range(10):

       num = (x**n)/(math.factorial(n))

       mylist.append([num])

   exp_approx = np.asarray(mylist)

   sum = 0

   for num in exp_approx:

       sum+=num

   return sum

Explanation:

The imports the python math module

import math

The imports the python numpy module

import numpy as np    

The function begins here

def exp(x):

This creates an empty list

   mylist = []

This iterates from 0 to 9

   for n in range(10):

This calculates each term of the series

       num = (x**n)/(math.factorial(n))

This appends the term to list, mylist

       mylist.append([num])

This appends all elements of mylist to numpy array, exp_approx

   exp_approx = np.asarray(mylist)

This initializes the sum of the series to 0

   sum = 0

This iterates through exp_approx

   for num in exp_approx:

This adds all terms of the series

       sum+=num

This returns the calculated sum

   return sum

Answer:

In a Scrum project, the work or the tasks are not allotted specifically. The Scrum Master is not allowed to assign tasks to the team members under any circumstance. Once the client provides the details regarding their requirements in detail, the tasks are distributed based on the expertise and skills of the employee.

Explanation:

Answer:

$ = dollar sign

Explanation:

In a spreadsheet, the $ symbol is the symbol of the dollar. The dollar is the currency of the United States.

Currency is a form of payment for goods and services. In a nutshell, it is money in the form of paper and coins that is usually issued by a government and is generally accepted as a form of payment at face value.

Currency exchange rates differ between businesses because each one distorts the interbank rate to maximize profits. We encounter numerous competitors who post interbank rates internet as bait to attract new customers, but once the customers are onboard, they drastically change the rate, typically not in the customers' favor.

Therefore, the $ symbol represents the dollar in a spreadsheet. The US dollar is the country's currency.

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Answer:

The program in Python is as follows:

n = int(input("Number of weights: "))

weights= []

for i in range(n):

   inp = float(input("Weight: "))

   weights.append(inp)

capacity = float(input("Capacity: "))

possible_weights = []

for i in range(n):

   for j in range(i,n):

       if capacity >= weights[i] + weights[j]:

           possible_weights.append(weights[i] + weights[j])

print("Maximum capacity is: ",max(possible_weights))

Explanation:

This gets the number of weights from the user

n = int(input("Number of weights: "))

This initializes the weights (as a list)

weights= []

This iteration gets all weights from the user

for i in range(n):

   inp = float(input("Weight: "))

   weights.append(inp)

This gets the weight capacity

capacity = float(input("Capacity: "))

This initializes the possible weights capacity (as a list)

possible_weights = []

This iterates through the weights list

for i in range(n):

   for j in range(i,n):

This gets all possible weights that can be carried by the bag

       if capacity >= weights[i] + weights[j]:

           possible_weights.append(weights[i] + weights[j])

This prints the maximum of all possible weights

print("Maximum capacity is: ",max(possible_weights))

Answer:

Something wrong?

Explanation:

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

 public static void main (String[]args){

   Scanner input = new Scanner(System.in);

   double user[] = new double[2];    double dr1[] = new double[2];

   double dr2[] = new double[2];    double dr3[] = new double[2];    

   System.out.print("Enter user coordinates: ");

   for(int i =0;i<2;i++){        user[i] = input.nextDouble();    }

   System.out.print("Enter driver 1 coordinates: ");

   for(int i =0;i<2;i++){        dr1[i] = input.nextDouble();    }

   System.out.print("Enter driver 2 coordinates: ");

   for(int i =0;i<2;i++){        dr2[i] = input.nextDouble();    }

   System.out.print("Enter driver 3 coordinates: ");

   for(int i =0;i<2;i++){        dr3[i] = input.nextDouble();    }

   double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

   double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

   double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

   System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");

   System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");

   System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");

 }

}

Explanation:

The following array declarations are for the customer and the three drivers

   double user[] = new double[2];    double dr1[] = new double[2];

   double dr2[] = new double[2];    double dr3[] = new double[2];    

This prompts the user for the customer's coordinates

   System.out.print("Enter user coordinates: ");

This gets the customer's coordinate

   for(int i =0;i<2;i++){        user[i] = input.nextDouble();    }

This prompts the user for the driver 1 coordinates

   System.out.print("Enter driver 1 coordinates: ");

This gets the driver 1's coordinate

   for(int i =0;i<2;i++){        dr1[i] = input.nextDouble();    }

This prompts the user for the driver 2 coordinates

   System.out.print("Enter driver 2 coordinates: ");

This gets the driver 2's coordinate

   for(int i =0;i<2;i++){        dr2[i] = input.nextDouble();    }

This prompts the user for the driver 3 coordinates

   System.out.print("Enter driver 3 coordinates: ");

This gets the driver 3's coordinate

   for(int i =0;i<2;i++){        dr3[i] = input.nextDouble();    }

This calculates the distance between driver 1 and the customer

   double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

This calculates the distance between driver 2 and the customer

   double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

This calculates the distance between driver 3 and the customer

   double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

The following print statements print the estimated pickup time of each driver

  System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");

   System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");

   System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");

Answer: 1,2,3,4,7

Just took it (:

Answer:

You're WAN

Explanation:

Wide Area Network