Maria tenia 6.500kg de patatas. Las envaso en sacos de 25kg y los puso a la venta a 30$ cada uno. Vendio la mitad de los sacos a ese precio y el resto los vendio todos a 2$ menos cada saco. ¿ Cuanto dinero obtuvo?

Answers

Answer 1

Responder:

$ 7540

Explicación paso a paso:

Dado que:

Kilogramos totales de papa = 6500

Número de kilogramos por paquete = 25

Precio por paquete = $ 30

La mitad se vendió a $ 30

El resto se vende a ($ 30 - $ 2)

Número total de paquetes de 25 kg:

6500 kg / 25 kg = 260 paquetes

Por lo tanto, paquete total = 260 paquetes

La mitad se vende a $ 30:

(260/2) * 30

130 * $ 30 = $ 3900

Resto vendido a $ 28:

(260 - 130) * $ 28

130 * $ 28 = $ 3640

Cantidad total realizada:

$ (3640 + 3900) = $ 7540


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Answers

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Answer:

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Answers

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Answers

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The value of the linear equation will be;

⇒ f (x) = -1/3x + 23/3

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

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Let the linear function is,

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Substitute f (-1) = 8 and f (5) = 6 in above equation as;

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a = - 1/3 and b = 23 / 3

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please help i need this done by the next hour and i’m failing and struggling
3. The sector of a circle is shown below. It has a radius of 10 centimeters and a central
angle of 51 degrees. Find to the nearest tenth in both cases:
(a) the length of AB in centimeters(b) the area of the sector in square centimeters

1. An arc has a central angle of 1.8 radians and a radius of 20 inches. a. Determine the length of AB in inches
b. to the nearest degree what is the measure of

Answers

Answer:

Question 3)

[tex]\stackrel{\frown}{AC}=36\text{ inches}[/tex]

[tex]\angle BCA\approx103^\circ[/tex]

Question 1)

[tex]\stackrel{\frown}{AB}\approx 8.9\text{ cm}\\[/tex]

[tex]A\approx44.5\text{ cm}^2[/tex]

Step-by-step explanation:

Question 3)

We are given that the central angle is 1.8 radians and has a radius of 20 inches.  

Part A)

The formula for arc length in terms of radians is given by:

[tex]s=r\theta[/tex]

Where s is the arc length, r is the radius, and θ is the angle in radians.

In this case, r is 20 and θ is 1.8. Hence, the arc length is:

[tex]\stackrel{\frown}{AC}=(20)(1.8)=36\text{ inches}[/tex]

Part B)

BCA is the central angle that measures 1.8 radians.

We can convert radians to degrees using the following formula:

[tex]\displaystyle d=\theta\cdot\frac{180^\circ}{\pi}[/tex]

Where d is the measure in degrees, and θ is the measure in radians.

Therefore:

[tex]\displaystyle d=1.8\cdot\frac{180^\circ}{\pi}\approx103.1324\approx103^\circ[/tex]

Question 1)*

Part A)

We will use the arc length formula in degrees given by:

[tex]\displaystyle s=2\pi r\cdot \frac{\theta^\circ}{360}[/tex]

Where r is the radius and θ is the angle measured in degrees.

We have a radius of 10 centimeters and a central angle of 51°. Therefore, our arc length is:

[tex]\displaystyle \stackrel{\frown}{AB}=2\pi(10)\cdot\frac{51}{360}=20\pi\cdot\frac{51}{360}\approx8.9\text{ cm}[/tex]

Part B)

We will use the formula for the area of a sector in degrees given by:

[tex]\displaystyle A=\pi r^2\cdot\frac{\theta^\circ}{360}[/tex]

So, we will substitute 10 for r and 51 for θ. Hence, the area of the sector is:

[tex]\displaystyle A=\pi (10)^2\cdot \frac{51}{360}=100\pi\cdot\frac{51}{360}\approx44.5\text{ cm}^2[/tex]

*Notes:

For this question, it is possible and completely fine for us to convert 51° to radians and then use the formulas in terms of radians.

Answer:

(1). 36 inch. , 103° ; (2). 8.9 cm , 44.5 cm² ;

Step-by-step explanation:

1).

(b). m∠BCA = 1.8 rad. × [tex]\frac{180}{\pi }[/tex] ≈ 103° ( π ≈ [tex]\frac{22}{7}[/tex] )

(a). C = 2 π r , the length of arc AB = ( 2 × [tex]\frac{22}{7}[/tex] × 20 ) ÷ 360° × 103.132° ≈ 36 inches

3).

(a).  The length of arc AB = ( 2 × [tex]\frac{22}{7}[/tex] × 10 ) ÷ 360° × 51° ≈ 8.9 cm

(b). A = π r² , the area of the sector = ( [tex]\frac{22}{7}[/tex] × 10² ) ÷ 360° × 51° ≈ 44.5 cm²

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