Explanation:
Advantages
It is a good conductor of heat and hence, can measure even high temperatures.
It gives results quickly – has a fast response time.
It expands linearly and less than alcohol and any other liquid.
It is more durable than alcohol thermometer because mercury does not evaporate easily.
Is the ability to discriminate between two close objects.
Answer:
resolution
Explanation:
That is the definition of resolution
What is tan for the given triangle?
Answer:
tan is 15 for that triangle
Answer:
c. 1.33
Explanation:
edmentum
Why is digital forensics important?
Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.
what is difference between heat engine and carnot engine
Answer: A heat engine uses temperature differences which cause pressure changes to exert force on a moving part. A Carnot Process is a theoretical explanation of a process involving pressure and temperature changes during ,amongst other things, phase changes.
Explanation:
Answer: The difference is a heat engine uses temperature differences which cause pressure changes to exert force on a moving part, A Carnot engine is only a theoretical explanation of a process involving pressure and temperature changes during or amongst other things.
Explanation:
What is the meaning of the safety symbol shown below?
Answer:
D. Poison
Explanation:
when solving for t you used sin theta instead of cos theta?
Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse . No matter the size of the triangle, the values of sin(θ) and cos(θ) are the same for a given θ, as illustrated below.
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#1
The kinetic energy decreases
#2
This is because of law of conservation of linear momentum .
The momentum is conserved
So the velocity of ball decreases than before .
So kinetic energy also decreases
#3 and #4
Kinetic energy of the can increases as after the collision the velocity of the can increases so the kinetic energy also increases
Swamps and other wetlands do not offer much value to humans. True or false?
The subject for this question is science (I'm not sure if science is called physics or chemistry)
The statement 'Swamps and other wetlands do not offer much value to humans' is FALSE.
What are Swamps?Swamps and other wetlands are specific ecosystems that are abundant in biodiversity and therefore offer many advantages.
Biodiversity is fundamental to discovering new biotechnological applications and therefore swamps are fundamental for humans.
In conclusion, The statement 'Swamps and other wetlands do not offer much value to humans' is FALSE.
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An object has an initial velocity of 15 m/s and a constant acceleration of 4 m/s2. How long will it take before its final velocity is equal to three times its initial velocity?
Based on the calculations, it would take 7.5 seconds before the final velocity of this object would be equal to three times its initial velocity.
Given the following data:
Initial velocity = 15 m/s.Constant acceleration = 4 m/s².Final velocity = 3 × 15 = 45 m/s.How to calculate the acceleration of an object?Mathematically, acceleration can be calculated by using the first equation of motion:
v = u + at
Where:
v is the final velocity.u is the initial velocity.t is the time measured in seconds.Making t the subject of formula, we have:
t = (v - u)/a
Substituting the given parameters into the formula, we have:
t = (45 - 15)/4
t = 30/4
t = 7.5 seconds.
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(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire
From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is 6.4 * 10^7 .
What is Hookes law?According to Hooke's law, the force is directly proportional to the extension of the wire.
Given that;
F = Ke
F = 240N
e = 0.8 mm or 0.0008m
K = F/e
K = 240N/0.0008m
K = 3.0 * 10^5 N/m
Now;
Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3
= 6.4 * 10^7
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how much force is required to accelerate an 8.6kg wagon by 15 m/s ?
The amount of force required to accelerate the given mass of the wagon is 129 Newtons.
What is force?A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.
From Newton's Second Law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration.
Given the data in the question;
Mass of the rock m = 8.6kgAcceleration a = 15m/s²Force F = ?F = 8.6kg × 15m/s²
F = 129kgm/s²
F = 129N
Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.
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Friction can only occur between solids and ________
Friction can only occur between solids, liquids and gas.
What is friction?Friction can be defined as the force that a moving object encounters when sliding over a surface.
The various phases of matter include solid, liquid and gases and friction occurs in all the three phases of matter.
Therefore, Friction can only occur between solids, liquids and gas.
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You drive a car east on the highway at 26 m/s. Another car passes you moving east traveling at 32 m/s. How fast do you view the car passing you?
The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
Relative velocity of the carThe speed of the car passing you is determined by applying relative velocity principle as shown below;
Vr = Va - Vb
Vr = 26 m/s - 32 m/s
Vr = -6 m/s
Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
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Discuss the role of oxygen in air supply.
T he role of oxygen in air supply is to keep all the ling beings live and healthy.
What is Oxygen?Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.
Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.
Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.
Thus, the air supply needs oxygen on the majority.
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An object of volume 2.0×10^4cm³ is under water .calculate the buoyant force of water on the object (Density of water=1000kg/m³)
An object of volume 2.0×10^4cm³ is underwater, the buoyant force of the water on the object
Fb= 1.962 *10^7N
What is the buoyant force?Generally, the equation for buoyant force is mathematically given as
Fb = g * p * V
Therefore
Fb=9.81* 2.0*10^4 *1000
Fb= 1.962 *10^7N
In conclusion, the buoyant force
Fb= 1.962 *10^7N
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Why is it important to to find information about if if crabs can or can't see the plankton, they eat near the ocean floor
Answer:
One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.
Cells are made up of molecules. Why then do we say that a structural unit of a living organism is a cell and not a molecule?
Answer:
Because molecules cannot function independently whereas when they combine they give rise to functional unit called cell.
you can only apply a 200n force but u need to make a 20 kg wagon of mulch travel at a speed of 10 m/s. How long do you have to push the wagon before its speed reaches 10m/s if it starts at rest
Time for which the wagon is pushed before it speed reaches 10m/s from rest.
What is momentum?The momentum is the product of mass of an object and its velocity.
Let the impact force is applied for time t. The impulse is equal to the change in momentum.
F.t = m(Vf -Vi)
where Vf =10 m/s, Vi =0 m/s, m =20kg and F =200N, then time for the force applied will be
200 x t = 20 x (10)
t =1s
Thus, the time for which the wagon is pushed before it speed reaches 10m/s from rest is 1s.
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Of the following, which is the best reason for why a woman's risk for cardiovascular disease increases after menopause?
Answer:
The best reason for the increased risk of cardiovascular diseases in women after menopause is the significant decrease in the levels of Estrogen in the body.
Detailed answer:
Due to the approach of menopause the estrogen levels in the blood decrease drastically. Estrogen helps in relaxing the vessels and keeping them in their natural diameter. But due to a drastic decrease in its level due to menopause, there is a high chance of cholesterol building up on the walls of the artery in the heart, which can cause many cardiovascular diseases.The graph below shows the conservation of energy for a skydiver jumping out
of a plane and landing safely on the ground. Which energy is represented by
line C?
Answer:
Kinetic energy
Explanation:
A rocket is fired with an initial velocity of 100m/s at an angle of 550 above the horizontal. It explodes on the mountain side 12s after its firing. What is the x-and y- coordinates of the rocket relative to its firing point?
The rocket's x- and y-coordinates relative to its launching point will be -0.975 and -0.219 m/sec, respectively.
What is velocity?The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.
Velocity at any angle is resolved to get its component of x and y-direction.
Given data;
V = 100m/s
θ=550°
t= 142 sec
The given velocity is resolved into the component as:
[tex]\rm V_X=Vcos \theta \\\\ V_y = Vsin\theta[/tex]
The x coordinate of the rocket:
[tex]\rm V_x = 100 cos \ 550^0 \\\\ V_x = -0.975616[/tex]
The y coordinate of the rocket:
[tex]\rm V_y =100 sin \ 550^0 \\\\ V_y = -0.219484[/tex]
Hence, the x-and y- coordinates of the rocket relative to its firing point will be -0.975 and -0.219 m/sec.
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Fluid Dynamics links the concept of viscosity to the fluid flow. Mention how the contact angle, surface tension, capillarity governs the flow?
Fluid Dynamics is an area of research that started a long time ago, along with Calculus. It combines techniques of Mathematical Analysis and of Dynamical Systems, such as Bifurcation Theory, among others.
What is surface tension?
Surface Tension is a phenomenon that occurs in all liquids, it is characterized by the formation of a kind of elastic membrane at its ends.
How to calculate the contact angle?Contact angles in powders can be measured using the sessile drop measurement in the compressed powder or using the force tensiometer with the Washburn method.
In fluid dynamics, the variables of surface tension, viscosity and contact angle are treated. When dealing with viscosity we have fluid can be viscous or a real fluid. In general, fluids are viscous.
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The radius of a nucleus is about 1/10000 that of an atom.
Calculate the radius of a magnesium nucleus.
Give your answer in standard form.
The radius of a magnesium atom is 0.160nm. The radius of a nucleus is about 1/10000 that of an atom.
What is nucleus?The nucleus is an organelle that contains the DNA i.e. genetic material and other materials which is required for cellular processes. It is only found in eukaryotic cells that is responsible for controlling the processes of the cell.
So we can conclude that the radius of a magnesium atom is 0.160nm which is equals to about 1/10000 radius of that atom.
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A sewing machine uses 1.6kWh of electricity in one day. If electricity costs 9p per unit, what is the total cost in pence of using the sewing machine that day? Give your answer to 3 significant figures.
Answer:
[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]
Explanation:
Since,
1 kWh = 1 unitSo,
1.6 kWh = 1.6 units
If,
1 unit = 9p1.6 units = 9p × 1.6
1.6 units = 14.4p
[tex]\rule[225]{225}{2}[/tex]
the frequency of a pendulum has a period of 1.13 seconds is?
A) 0.88
B) 1.13
C) 1.27
D) 11.3
Answer:
A 0.88
Explanation:
frequency=1/period
=1/1.13=0.88
3. Two wires increase in length by the same amount when both their temperatures increase by the same amount, as shown in the diagram. Before the temperature increase, the longer wire is 1.2525 m long. The shorter wire’s linear coefficient of thermal expansion is 1.135 times that of the longer wire. How much shorter is the shorter wire before the temperature increase? Answer to three significant figures
Viết cho Ngọc Khánh
Two wires increase in length by the same amount when both their temperatures increase by the same amount, the shortness of the wire before the temperature increase is mathematically given as
dL=0.1485m
How much shorter is the shorter wire before the temperature increase?Generally, the equation for change in length is mathematically given as
[tex]dl=lo \alpha dt[/tex]
Therefore
dl1=dl2
Where
a2=1.35a1
Hence
a1l1dt= a2l2dt
a1(1.2525)= a1*(1.135)(l2)
L2=1.104m
In conclusion, a change in length due to temperature is
dL=1.2525-1.104m
dL=0.1485m
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Define 1 volt. Express it in terms of SI unit of work and charge calculate the amount of energy consumed in carrying a charge of 1 coulomb through a battery of 3 V.
Answer:
Work done =3 joules
Explanation:
1 volt is the same as 1 Coulomb and 1 Joule
V=W/Q
1=W/3
W=3 x 1
W=3 Joules
An infinitely long line of charge has a linear charge density of 8.00*10^−12 C/m. A proton is at distance 19.0 cm from the line and is moving directly toward the line with speed 1200 m/s. How close does the proton get to the line of charge?
Hi there!
To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.
For this, we can use the work-energy theorem to solve.
Recall the following equations:
[tex]W = \Delta KE[/tex]
[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]
We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.
The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]
For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]
**λ = Linear charge density (C/m)
To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]
Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]
[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]
Now, we can begin solving for 'a'.
Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]
Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]
It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.
In the video, the students create two charged tapes, a "pointy" tape and a "square" tape. The pointy tape is first placed on top of the square tape, and the two are pulled apart. After pulling them apart, the students observed the behavior of the tapes when they were brought near each other, but not touching each other.
The two pointy tapes repel. This shows they have the same type of charge.
Attraction of two chargesThe attraction of two charges occurs when the two charges have opposite charges.
Repulsion of two chargesThe repulsion of two charges occurs when the two charges have similar charges.
Thus, since the two pointy tapes will have the same charge, we can conclude that they will repel each other when brought near each other.
The complete question is below:
How did the pointy tapes behave when brought near each other, and what does this demonstrate about their charges?
Two pointy tapes repel. This shows they have opposite types of charge.
Two pointy tapes attract. This shows they have opposite types of charge.
Two pointy tapes repel. This shows they have the same type of charge.
Two pointy tapes attract. This shows they have the same type of charge.
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You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using electric fields. The physical setup is shown in the figure below.
You are working for a manufacturing company, which is mathematically given as
[tex]m=3\sqrt{2}[/tex][tex]m=\frac{15\sqrt{5}}{16}[/tex]x=0.747a[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]What is the value of m that will place the movable bead in equilibrium at x-a a ....?
a)
Generally, the equation for the force of equilibrium is mathematically given as
F=2fcos\theta
Therefore
[tex]K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3[/tex]
[tex]m=3\sqrt{2}[/tex]
b)
By force equilibrium
[tex]K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}[/tex]
Therefore
[tex]n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\[/tex]
[tex]m=\frac{15\sqrt{5}}{16}[/tex]
c)
[tex]K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}[/tex]
x^2+a^2=(14/3)^{2/3}x^2
x=a/1.338
x=0.747a
d)
By force equilibrium
[tex]K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}[/tex]
[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]
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