The screen is approximately 2.27 meters away from the slit. The width of the first bright fringe to the side of the central maximum is approximately 8.06 mm.
a)
The width of the central maximum on a screen is given by the formula:
W = (λ * L) / d
Where:
W is the width of the central maximum
λ is the wavelength of light
L is the distance between the slit and the screen
d is the width of the slit
We can rearrange the formula to solve for L:
L = (W * d) / λ
Substituting the given values:
W = 8.00 mm = 8.00 × 10⁻³m (converting millimeters to meters)
λ = 600 nm = 600 × 10⁻⁹ m (converting nanometers to meters)
d = 0.170 mm = 0.170 × 10⁻³m (converting millimeters to meters)
L = (8.00 × 10⁻³) * 0.170 × 10⁻³) / (600 × 10⁻⁹)
L ≈ 2.27 m
Therefore, the screen is approximately 2.27 meters away from the slit.
b) The width of the first bright fringe to the side of the central maximum can be calculated using the formula:
w = (λ * L) / d
Where:
w is the width of the fringe
Substituting the given values:
λ = 600 nm = 600 × 10⁻⁹) m (converting nanometers to meters)
L = 2.27 m (from part a)
d = 0.170 mm = 0.170 × 10⁻³m (converting millimeters to meters)
w = (600 × 10⁻⁹) * 2.27) / (0.170 × 10⁻³)
w ≈ 8.06 mm
Therefore, the width of the first bright fringe to the side of the central maximum is approximately 8.06 mm.
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the luminous efficacy of a tungsten lamp is about 12 lumens/watt. what is the efficacy of a fluorescent tube (in lumens/watt)? group of answer choices 20 50 80 100
The efficacy of a fluorescent tube, in lumens/watt, is typically in the range of 50 to 100 lumens/watt.
Fluorescent tubes are more efficient than tungsten lamps in converting electrical energy into visible light. They generally have higher luminous efficacy due to their different technology and design. While the specific efficacy can vary depending on the tube's characteristics and design, a range of 50 to 100 lumens/watt is a common estimate for the efficacy of fluorescent tubes. Therefore, among the given options, the closest answer is 50 lumens/watt.
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how long would it take a leopard, running at an average speed of 20 m/s to travel 500 m?
Answer:
25 seconds
Explanation:
500/20
The purple arrow on the graph shows speed and direction.
What is this arrow called?
A. an acceleration arrow
B. a vector
C. a force arrow
D. a speed arrow
The purple arrow on the graph that shows speed and direction, this arrow called B. a vector.
Vectors have magnitude (size) and direction. They are represented graphically as arrows, in which the direction of the arrow denotes the direction of the vector, while the length of the arrow represents the vector's magnitude (size). Furthermore, the term "vector" is used in physics to refer to a quantity that has both magnitude and direction, such as velocity, force, and acceleration.
They are essential in physics since they enable scientists to precisely describe how objects move and interact. Moreover, vector quantities, such as velocity and force, are often depicted with arrows in physics diagrams, with the direction of the arrow representing the vector's direction and the arrow's length representing its magnitude. The use of vectors in physics and other fields has made a significant contribution to the advancement of science and technology. So therefore the correct answer is B. a vector, the purple arrow on the graph that shows speed and direction.
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are positively charged ions form when atoms lose electrons
Answer: Atoms that lose electrons acquire a positive charge as a result because they are left with fewer negatively charged electrons to balance the positive charges of the protons in the nucleus. Positively charged ions are called cations. Most metals become cations when they make ionic compounds.
Explanation: hope this helps
How many people does it take to change a lightbulb?
How fast would a 20 kg dog have to run, to reach a momentum of 120 kg x m/s? Include unit in your answer. Worth 40 points!
Answer:
6 m/s
Explanation:
momentum= mass times velocity
120 = 20v
v = 120/20
Answer:
7
Explanation:
7
Two long parallel wires are separated by 9.03 cm and carry currents 1.71 A and 4.67 A. Find the magnitude of the magnetic force that acts on a 3.17-m length of either wire.
The magnitude οf the magnetic fοrce that acts οn a 3.17 m length οf either wire is 0.0405 Newtοns.
What is magnetic fοrce?Magnetic fοrce refers tο the fοrce exerted οn a charged particle οr a current-carrying cοnductοr due tο the presence οf a magnetic field.
F = (μ₀ * I₁ * I₂ * L) / (2π * d)
Given:
I₁ = 1.71 A
I₂ = 4.67 A
L = 3.17 m
d = 9.03 cm = 0.0903 m
After applying the formula to the supplied values, we get:
F = (4π × 10⁻⁷ T·m/A) * (1.71 A) * (4.67 A) * (3.17 m) / (2π * 0.0903 m)
Simplifying the expressiοn:
F ≈ 4π × 10⁻⁷ * 1.71 * 4.67 * 3.17 / 2 * 0.0903
F ≈ 0.0405 N
Therefοre, the magnitude οf the magnetic fοrce that acts οn a 3.17 m length οf either wire is 0.0405 Newtοns.
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As an airplane takes off, the air flows across the wings of the airplane. Which of the following would be the best description? I. The air flow across the top of the wing is greater than the air flows across the bottom of the wing. II. The air flow across the top and bottom of the wing is the same. III. The lift force is present because the pressure across the top is less than the pressure across the bottom of the wing.
Answer:
III. The lift force is present because the pressure across the top is less than the pressure across the bottom of the wing.
Explanation:
What happened to the kelp forest when the otter was hunted to near extinction?
Answer: Sea otter is the pioneer species in the kelp forest as it regulates and controls the population of other species in the kelp forest.
Explanation:
If sea otters are hunted and their population is brought to extinction then this will cause major harm the ecosystem of the kelp forest and it will disturb the ecological balance in the kelp forest. The herbivorous animals consumed by the sea otters will increase in population and they will consume a lot of vegetation in the forest. The kelp forest which forms the coastline will not remain effective in providing protection against the storms to the neighboring areas.
what must you do to maintain steerage on a personal water craft? you must apply the throttle apply the brakes and turn hard drag a foot in the water
To maintain steerage on a personal watercraft, you must apply the throttle, apply the brakes and turn hard, and drag a foot in the water,as you move forward, the watercraft will start moving in the direction you want it to go
Steering a personal watercraft is not as simple as it looks. It can be dangerous and can lead to accidents if the rider does not know how to handle the watercraft. To maintain steerage on a personal watercraft, you must first apply the throttle. As you move forward, the watercraft will start moving in the direction you want it to go. Applying the brakes and turning hard will help you steer the watercraft in the desired direction.
This is achieved by slowing down the watercraft and allowing it to turn naturally in the water. The final step is to drag a foot in the water. This is important when you want to make a sharp turn. Dragging a foot in the water helps to create a pivot point that helps you turn the watercraft in the desired direction, this technique is also used to help you maintain balance on the watercraft. So therefore to maintain steerage on a personal watercraft, you must apply the throttle, apply the brakes and turn hard, and drag a foot in the water,as you move forward, the watercraft will start moving in the direction you want it to go.
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Question
If you are tracking the energy in a system, but the total energy seems to be going down, where has the energy gone ?
What I ferromagnetism??
Answer:
Ferromagnetism is a kind of magnetism that is associated with iron, cobalt, nickel, and some alloys or compounds containing one or more of these elements. It also occurs in gadolinium and a few other rare-earth elements.
Explanation:
Hope this helped Mark BRAINLIEST!!!
use molecular orbital theory to complete the ground state electron configuration for each of the molecules.
The ground state electron configurations for the molecules are:
Oxygen (O2): σ2s^2 σ*2s^2 σ2p^4 π2p^2
Nitrogen (N2): σ2s^2 σ*2s^2 σ2p^3 π2p^2
To determine the ground state electron configurations of the molecules using molecular orbital theory, we need to consider the molecular orbital diagram and the electron filling order.
Oxygen (O2):
The atomic configuration of oxygen is 1s^2 2s^2 2p^4. In molecular oxygen (O2), we combine the atomic orbitals to form molecular orbitals. The molecular orbital diagram for O2 is as follows:
The filling order for molecular orbitals is as follows: σ2s < σ2s < σ2p < π2p < π2p < σ*2p. According to Hund's rule, each orbital should be singly filled before pairing occurs.
The electron configuration for O2 can be obtained by filling the molecular orbitals with the valence electrons from each oxygen atom:
σ2s^2 σ*2s^2 σ2p^4 π2p^2
Nitrogen (N2):
The atomic configuration of nitrogen is 1s^2 2s^2 2p^3. In molecular nitrogen (N2), we combine the atomic orbitals to form molecular orbitals. The molecular orbital diagram for N2 is as follows:
The filling order for molecular orbitals is the same as in the case of oxygen: σ2s < σ2s < σ2p < π2p < π2p < σ*2p.
The electron configuration for N2 can be obtained by filling the molecular orbitals with the valence electrons from each nitrogen atom:
σ2s^2 σ*2s^2 σ2p^3 π2p^2
Using molecular orbital theory, we determined the ground state electron configurations for the molecules as follows:
Oxygen (O2): σ2s^2 σ*2s^2 σ2p^4 π2p^2
Nitrogen (N2): σ2s^2 σ*2s^2 σ2p^3 π2p^2
Please note that the electron configurations obtained through molecular orbital theory represent the ground state electronic distribution based on the available orbitals and their energy levels.
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On the dot below, which represents the book, draw and label the forces (not components) that act on the book at the lowest point of its circular path. Each force must be represented by a distinct arrow starting on, and pointing away from, the dot. ii. At the lowest point of the circular path, the book is moving only in the horizontal direction. In what direction, if any, is the net vertical force on the book? Up _No Down direction, since the net vertical force is equal to zero Without deriving any equations, briefly explain your reasoning in terms of the book's motion.
At the lowest point of its circular path, the book experiences three distinct forces: the gravitational force (downward), the normal force (upward), and the centripetal force (toward the center of the circular path).
At the lowest point of the circular path, the book is moving only in the horizontal direction. This means that the book has no vertical acceleration since its velocity in the vertical direction remains constant. According to Newton's second law, when there is no vertical acceleration, the net vertical force must be zero.
The gravitational force acts downward, pulling the book toward the center of the Earth. The normal force, exerted by the surface supporting the book, acts upward and balances the gravitational force. These two forces have equal magnitudes and opposite directions, resulting in a net vertical force of zero.
Therefore, at the lowest point of its circular path, the book experiences no net vertical force. The cancellation of the gravitational force and the normal force allows the book to move in a centripetal force circular path with only horizontal motion.
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wave is modeled with the function y(x,t)=0.25\cos(0.30x-0.90t+\frac{\pi}{3})y(x,t)=0.25cos(0.30x−0.90t+3 π ) where all lengths are in meters and all times in seconds.
- Find the wavelength of the wave.
- Find the period of the wave
- Find the wave speed (a positive number).
-What is the instantaneous velocity of one of the particles that make up the medium at position 0 at time 22 sec? Make sure to use the correct sign (plus or minus) for your answer.
The wavelength of the wave is 20π/0.30 meters, which simplifies to approximately 209.44 meters.
The period of the wave is 2π/0.90 seconds, which simplifies to approximately 6.98 seconds.
The wave speed is given by the ratio of the wavelength to the period, which is approximately 29.97 meters per second.
To find the instantaneous velocity of a particle at position 0 at time 22 seconds, we differentiate the displacement equation with respect to time and evaluate it at the given time and position.
The derivative of y(x,t) with respect to t is 0.25(0.90)sin(0.30x - 0.90t + π/3). Plugging in x = 0 and t = 22, we find the instantaneous velocity to be approximately 0.177 m/s in the positive direction.
Determine how to find the wavelength of the wave?The given wave equation is y(x,t) = 0.25cos(0.30x - 0.90t + π/3), where x represents the position and t represents the time. The coefficient of x, 0.30, corresponds to the angular wave number (k) of the wave.
The coefficient of t, -0.90, corresponds to the angular frequency (ω) of the wave. By comparing the equation with the general form y(x,t) = Acos(kx - ωt + φ), we can identify the values for k and ω.
Determine how to find the period of the wave?The wavelength (λ) of a wave is given by λ = 2π/k. In this case, k = 0.30, so the wavelength is 2π/0.30, which simplifies to approximately 209.44 meters.
Determine how to find the wave speed?The period (T) of a wave is given by T = 2π/ω. In this case, ω = -0.90, so the period is 2π/(-0.90), which simplifies to approximately 6.98 seconds.
Determine find the instantaneous velocity particles?The wave speed (v) is the ratio of the wavelength to the period, v = λ/T. Substituting the values, we get v = (2π/0.30) / (2π/(-0.90)), which simplifies to approximately 29.97 meters per second.
To find the instantaneous velocity of a particle at position 0 at time 22 seconds, we differentiate the displacement equation with respect to time.
The derivative of cos(0.30x - 0.90t + π/3) with respect to t is -0.90sin(0.30x - 0.90t + π/3).
Plugging in x = 0 and t = 22, we find the instantaneous velocity to be approximately 0.177 m/s in the positive direction.
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Which is a property of every
mixture?
What happens to the volume of sound as the amplitude gets larger?
benedict's test shows the presence of choose... . a positive benedict's test appears as choose... . a negative benedict's test appears as
Benedict’s test is a chemical test used to detect the presence of reducing sugars. This test is particularly used to check the presence of glucose in the urine to determine the presence of diabetes. Benedict's test is carried out by adding Benedict's reagent to the test solution and heating the mixture.
Benedict’s reagent is a blue solution made up of sodium citrate, sodium carbonate, and copper sulfate. The reaction results in the reduction of copper ions to copper oxide which is red or yellow in color. The presence of reducing sugars in the sample causes the colour of the solution to change from blue to green, yellow, orange, or red depending on the amount of reducing sugar present. A positive Benedict's test appears as green, yellow, orange, or red, whereas a negative Benedict's test appears as blue. The intensity of the colour varies based on the amount of reducing sugar present. The higher the amount of reduced sugar, the more intense the colour change.
Therefore, a positive Benedict's test shows the presence of reducing sugar while a negative Benedict's test shows the absence of reducing sugar. Benedict's test can be used to distinguish between reducing and non-reducing sugars, which are carbohydrates that are capable of reducing copper ions and those that are not.
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Think about it: Suppose a meteorite collided head-on with Mars and becomes buried under Mars's surface. What would be the elasticity of this collision? Explain your answer.
a. Elastic collision
b. Inelastic collision
c. Perfectly elastic collision
d. Perfectly inelastic collision
If a meteorite collides head-on with Mars and becomes buried under Mars's surface, the elasticity of this collision would be a d)perfectly inelastic collision.
The elasticity of the collision is a measure of how much energy is lost during the collision. In a perfectly inelastic collision, all of the kinetic energy of the meteorite would be converted to other forms of energy such as heat, sound, and deformation of the planet's surface. This would result in a large crater on the surface of Mars and the meteorite would be buried under the planet's surface.
A perfectly inelastic collision is a collision where two objects stick together after the collision and move as one. During a perfectly inelastic collision, the kinetic energy of the colliding objects is lost due to the deformation of the objects and the generation of heat. The velocity of the objects after the collision is less than the velocity of the objects before the collision.
In conclusion, if a meteorite collides head-on with Mars and becomes buried under Mars's surface, it would be a perfectly inelastic collision because all of the kinetic energy of the meteorite would be lost during the collision. This would result in a large crater on the surface of Mars and the meteorite would be buried under the planet's surface. The correct option is (d).
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A block of ice at 0∘C is dropped from a height that causes it to completely melt upon impact. Assume that there is no air resistance and that all the energy goes into melting the ice.
What is the height necessary for this to occur. [ Hint: Equate the joules of gravitational potential energy to the product of the mass of ice and its heat of fusion (Lf = 335,000 J/kg).].
A height of about 34,184.49 meters is required for the block of ice to totally melt upon impact.
To determine the height necessary for the block of ice to completely melt upon impact, we need to equate the gravitational potential energy to the energy required to melt the ice.
The gravitational potential energy is given by the formula:
PE = m * g * h
Where PE is the gravitational potential energy, m is the mass of the ice, g is the acceleration due to gravity, and h is the height.
The energy required to melt the ice is the product of the mass of the ice and its heat of fusion (Lf = 335,000 J/kg). Therefore, the energy required to melt the ice is:
E = m * Lf
By equating the gravitational potential energy to the energy required to melt the ice, we have:
m * g * h = m * Lf
The mass of the ice cancels out on both sides, leaving:
g * h = Lf
Now we can solve for the height h:
[tex]\begin{equation}h = \frac{Lf}{g}[/tex]
Substituting the values:
Lf = 335,000 J/kg
g = 9.8 m/s²
h = 335,000 J/kg / 9.8 m/s²
Calculating the height h:
h ≈ 34,184.49 meters
Therefore, the height necessary for the block of ice to completely melt upon impact is approximately 34,184.49 meters.
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Find the change in time (
t) it takes the magnetic field to drop to zero. (A loop of wire of radius 30 mm has electrical resistance 0.038 ohms. The loop is initially inside a uniform magnetic field of magnitude 1.8 T parallel to the loops axis. The magnetic field is then reduced slowly at a constant rate which induces a current 0.20 A in the loop.)
Approximately 6.375 seconds pass before the magnetic field disappears completely.
To find the change in time (Δt) it takes for the magnetic field to drop to zero, we can use Faraday's law of electromagnetic induction.
Faraday's law states that the induced electromotive force (EMF) in a loop of wire is equal to the rate of change of magnetic flux through the loop. Mathematically, it can be expressed as:
[tex]\begin{equation}EMF = -\frac{d\Phi}{dt}[/tex]
Where:
EMF is the electromotive force (voltage)
[tex]\frac{d\Phi}{dt}[/tex] is the rate of change of magnetic flux
In this case, the induced current in the loop is 0.20 A. We can use Ohm's law to relate the current, resistance, and voltage:
EMF = I * R
Where:
I is the current (0.20 A)
R is the resistance (0.038 ohms)
Since the magnetic field is reducing at a constant rate, we can assume that the rate of change of magnetic flux is constant.
The magnetic flux (Φ) through the loop is given by:
Φ = B * A
Where:
B is the magnetic field (1.8 T)
A is the area of the loop (π * r²)
Substituting the values:
Φ = (1.8 T) * (π * (0.03 m)²)
= 0.051 m² * T
Now, we can equate the two equations for EMF:
[tex]\begin{equation}EMF = -\frac{d\Phi}{dt}[/tex]
[tex]\begin{equation}I \cdot R = -\frac{d\Phi}{dt}[/tex]
Rearranging for dt:
[tex]\begin{equation}dt = -\frac{d\Phi}{I \cdot R}[/tex]
Substituting the values:
[tex]\begin{equation}dt = -\frac{0.051\text{ m}^2 \cdot T}{0.20\text{ A} \cdot 0.038\text{ ohms}}[/tex]
[tex]\begin{equation}= -\frac{0.051}{0.008\text{ s}}[/tex]
= -6.375 s
The negative sign indicates that the time is decreasing. However, we are interested in the magnitude of the time, so we can take the absolute value:
Δt = |dt| = 6.375 s
Therefore, the change in time it takes for the magnetic field to drop to zero is approximately 6.375 seconds.
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Here is a list of ways of producing electricity
A ) Wind farms
B ) Coal fired power stations
C ) hydroelectric power stations
D ) nuclear power stations
E ) gas fired power stations
F ) tidal power stations
G) using geothermal energy
(1) State which of these produces clean electricity
(2) State which of these uses fossils fuel
(3) state which of these uses a renewable energy resources
Please help me
Please do not answer from links
Urgent !!!!!!
Will give the brainliest!
* please answer correctly
Answer:
1) A,B,F,G
2)B,D,E
3) A,C,F,G
Explanation:
It is much more difficult to move a dresser full of clothes than an empty dresser
Answer:
Newton's Law 2
Hope this helps!
in a pig-calling contest, a caller produces a sound with an intensity level of 87 db.
In a pig-calling contest, the caller produces a sound with an intensity level of 87 dB. Understanding the intensity level of the sound helps evaluate its potential impact on the surrounding environment and human hearing.
The intensity level of a sound is a measure of its loudness and is expressed in decibels (dB). The decibel scale is logarithmic, meaning that each increase of 10 dB represents a tenfold increase in sound intensity.
To calculate the intensity level in decibels, we use the formula:
dB = 10 * log10(I/I₀)
where I is the sound intensity and I₀ is the reference intensity (typically the threshold of hearing, which is approximately 10^(-12) W/m^2).
Given that the intensity level is 87 dB, we can rearrange the formula to solve for I:
87 = 10 * log10(I/I₀)
8.7 = log10(I/I₀)
I/I₀ = 10^(8.7)
I = (10^(8.7)) * I₀
In the pig-calling contest, the caller produces a sound with an intensity level of 87 dB. The calculation of the sound intensity requires knowledge of the reference intensity and the logarithmic relationship of the decibel scale.
By using the formula and considering the logarithmic nature of the scale, we can determine the actual sound intensity. Remember that the decibel scale is logarithmic, so even a small increase in decibels represents a significant increase in sound intensity. Understanding the intensity level of the sound helps evaluate its potential impact on the surrounding environment and human hearing.
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a radio-controlled model airplane has a momentum given by [(−0.75kg⋅m/s3)t2 (3.0kg⋅m/s)]i^ (0.25kg⋅m/s2)tj^, where t is in seconds. What is the x -component of the net force on the airplane?
Express your answer in terms of the given quantities.
The x-component of the net-force acting on the radio-controlled model airplane is given by the expression -1.5 kg·m/s^2 * t.
The x-component of the net force (F_x) on an object can be calculated using Newton's second law, which states that the net force is equal to the rate of change of momentum:
F_x = dp_x/dt
Given that the momentum of the airplane is [(−0.75kg·m/s^3)t^2 (3.0kg·m/s)]i^, we can find the x-component of the momentum (p_x) as the coefficient of the i^ unit vector. Taking the derivative of p_x with respect to time (t), we obtain the x-component of the net force:
F_x = d/dt [(−0.75kg·m/s^3)t^2] = (-0.75kg·m/s^3) * 2t
Simplifying the expression, we find:
F_x = -1.5 kg·m/s^2 * t
Therefore, the x-component of the net force on the airplane is -1.5 kg·m/s^2 * t.
The x-component of the net force acting on the radio-controlled model airplane is given by the expression -1.5 kg·m/s^2 * t, where t is the time in seconds. This equation represents the rate of change of the x-component of the momentum with respect to time.
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A positive point charge is placed at 5 cm from a negatively charged plate.
it is then pulled away from the plate, so it is 10 cm from the plate. Describe
what happened to the potential energy of the charge. (Hint what
happened to the force on the charge more force means more potential
energy) *
Answer: I'm not sure about this one, but you can go to this link to understand it better https://youtu.be/wEQxtUwiV1E.Its a Khan Academy Video Hope This Helps
Explanation:
How would you classify an EM wave with a frequency of 10^7 Hz?
Answer:
I think it is television and radio wave
In which of these can convection not occur
A. Gases
B.solids
C.liquids
D.fluids
I believe the answer would be B.solids.
Explanation:
Hope this helped!
In solids these can convection not occur and convection can occur in both liquids and gases, as they are both considered fluids. Thus, option B is correct.
However, convection cannot occur in solids, as the particles in solids are generally fixed in position and do not have the freedom to move and transfer heat through bulk motion as in convection.
A solid is one of the three fundamental states of matter, along with liquids and gases. It is characterized by having a definite shape and volume. Solids are composed of tightly packed particles, such as atoms, molecules, or ions, that are held together by strong intermolecular forces.
These particles vibrate in fixed positions but do not have the ability to move freely throughout the substance. As a result, solids maintain their shape and volume under normal conditions and exhibit relatively low compressibility compared to gases and liquids. Examples of solids include metals, rocks, wood, plastics, and ice.
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A student watches as a trash can lid moves across a yard. Which of these could have caused the trash can lid to move?
Answer:
wind energy
Explanation:
Wind energy can be defined as a form of a solar energy. It is generated by the immense force of the wind that blows in an area. Wind energy is a useful energy and is mostly used to generate electricity. It is clean source of energy.
In the context, trash can lid is being blown away by the wind energy and it is seen moving across the yard. The energy of the wind forces the lid of the trash can to move from one place to another against friction. Thus, wind energy caused the trash can lid to move across the yard as seen by a student.
What must the charge (sign and magnitude) of a particle of mass 1.46 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 630 N/C?
Use 9.81 m/s^2 for the magnitude of the acceleration due to gravity.
The particle remains stationary in a downward-directed electric field, the charge must be negative to balance the gravitational force.
The two forces acting on the particle are the gravitational force and the electric force. The gravitational force is given by F_gravity = m * g, where m is the mass of the particle and g is the acceleration due to gravity (9.81 m/s^2). The electric force is given by F_electric = q * E, where q is the charge of the particle and E is the magnitude of the electric field.
For the particle to remain stationary, the electric force must exactly balance the gravitational force, i.e., F_electric = F_gravity. Therefore, we can equate the two expressions and solve for the charge.m * g = q * E
Given that the mass of the particle is 1.46 g (0.00146 kg) and the magnitude of the electric field is 630 N/C, we can substitute these values into the equation:0.00146 kg * 9.81 m/s^2 = q * 630 N/C
Solving for q, we have:
q = (0.00146 kg * 9.81 m/s^2) / 630 N/C ≈ 2.262 x 10^-5 C.
Therefore, the charge of the particle must be approximately 2.262 x 10^-5 C. Since the particle remains stationary in a downward-directed electric field, the charge must be negative to balance the gravitational force.
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