LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )

Answer:

2a(7b+5)

Step-by-step explanation:

yeah-ya....... right?

Answer:

A-4.51

Step-by-step explanation:

I was going to ask to what place but then I saw all the others wouldn't make sense.

Answer:

144

Step-by-step explanation:

divide 50 by 3 and then multiply by 9

Refer to attatchment.

Answer:

4x2+4x-5

Step-by-step explanation:

Hopes this helps

Plz markas brainliest

A

Step-by-step explanation:

the origin, (0, 0)

For center of dilation Q, the image of a point A after dilation by a factor of k is ...   A' = kA + (k-1)Q Then for points A, A', and dilation factor k, the center of dilation can be found to be ...   (A' -kA)/(k-1) = Q

Here, that is ...   Q = ((-2, -2) -(1/2)(-4, -4))/(1/2 -1) = (0, 0)/(-1/2)  

Q = (0, 0) 

well, a WHOLE is 1, which we can split in many fractions, say 5/5, 10/10 or 999/999 and so on.

we know 1/5 of the jar is chocolate chip, and there's the rest, well, the Whole jar in 5ths have to be 5/5, if we take away 1/5 from 5/5, the "rest" is 5/5 - 1/5 = 4/5.

now, we also know that 1/2 of the "rest" is peanut butter, or namely that 1/2 of 4/5 is peanut butter, how much will that be?  let's divide 4/5 by 2

[tex]\cfrac{4}{5}\div 2\implies \cfrac{4}{5}\div \cfrac{2}{1}\implies \cfrac{4}{5}\cdot \cfrac{1}{2}\implies \cfrac{4}{10}\implies \cfrac{2}{5}[/tex]

Answer:

3b

Step-by-step explanation:

The percentage of motorists falling in each category, in the long term, are as follows:

High-risk category = 70%

Low-risk category = 30%

Data and Calculations:

Risk Profile Categories of Motorists

                                                       High Risk      Low Risk

Probability of remaining

 in the same category                      50%              10%

Probability of moving to another

 category                                          50%              90%

Probability a motorist falling in the high-risk category = (50% x 50%) + (50% x 90%)

= 25% + 45%

= 70%

Probability a motorist falling in the low-risk category = (50% x 50%) + (50% x 10%)

= 25% + 5%

= 30%

Thus, the probability of a motorist falling in the high-risk category is 70%, while the probability of a motorist falling in the low-risk category is 30%.

Learn more about probability here: https://brainly.com/question/24756209

The value of f(15), to the nearest hundredth is 253.88

The standard exponential equation is given as:

If f(4.5) = 16, then;

16 = ab^4.5 ..............1

Similarly, if f(9.5) = 60, then:

60 = ab^9.5 ........................... 2

Dividing both equations will give:

60/16 = ab^9.5/ab^4.5

60/16 = b^9.5-4.5

60/16 = b^5

3.75 = b^5

b = 1.3

Get the value of a. Recall that;

60 = ab^9.5

60 = a(1.3)^9.5

60 = 12.09a

a = 60/12.09

a = 4.96

Get the value of f(15)

f()15 = 4.96(1.3)^15

f(15) = 4.96(51.18)

f(15) = 253.88

Hence the value of f(15), to the nearest hundredth is 253.88

Learn more on exponential functions here: https://brainly.com/question/12940982

Answer:

No

Step-by-step explanation:

These are the artists of each subject, not the general function of each genre.

Brainliest for

for the answer I think it is 2 cm

the answer : 10 cm :>

Answer:

Step-by-step explanation:

We can use the compound interest formula to find how much money he will have after 4 years:

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex] ;

where

A= final amount

P= initial amount

r= interest rate

n= number of times interest applied per time period

t= number of time periods elapsed,

so from the given information, we know that 1500 is our initial amount, so P= 1500.

Annual interest means once a year, so n= 1, and the interest rate is 4%, so r= 4% or 0.04

and we are asked to find the amount in his account after 4 years, so t= 4

Now, all we need to do is plug in these values for each of the variables and solve.

[tex]A= 1500(1+\frac{0.04}{1} )^{(1)(4)}[/tex]

and we get

A= $1,754.79

[tex]\begin{cases} f(x) = x^4+14x\\ g(x) = 6-x \end{cases}\qquad \qquad h(x) = f(x) + g(x) \\\\\\ h(x) = (x^4+14x)+(6-x)\implies h(x) = x^4+14x-x+6 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = x^4+13x+6~\hfill[/tex]

now, if we graph h(x), Check the picture below, we can see that horizontally the line keeps on moving towards the left, going going and going towards -infinity, and it also keeps on moving towards the right, going going and going towards +infinity, and since the horizontal area used by the function is the domain of it, the domain for h(x) will be (-∞ , +∞).

Answer:

7,7,20 I think

Step-by-step explanation:

7+7 is less then 20

Step-by-step explanation:

Q3

25 - (x-8)²/4 = [100 - (x-8)²]/4

[100 - (x²- 16x + 64)]/4

(100 - x² + 16x - 64)/4 = (-x² + 16x + 36)/4

(36 + 16x - x²)/4 = (36 - 2x + 18x - x²)/4

[2(18 - x) + x(18 - x)]/4 = [(2 + x)(18 - x)]/4

....proved

Q4

3(ax + 7) - 2(x + b) = 4x + 29

expanding,

3ax + 21 - 2x - 2b = 4x + 29

3ax - 2x + 21 - 2b = 4x + 29

Comparing terms; x terms,

3ax - 2x = 4x

3a - 2 = 4

3a = 6

a = 6/3

a = 2

constant terms,

21 - 2b = 29

21 - 29 = 2b

2b = -8

b = -8/2

b = -4

.... proved

Answer:

3/5*5/7*14/3-2/5

8/5...

Answer:

$3.02

Step-by-step explanation:

Convert the Percentage to decimals:

3% / 100% = 0.03

15% / 100% = 0.15

3% / 0.03 part:

19.55 * 0.03 = 0.5865

19.55 + 0.5865 = 20.1365

OR, since it was "adde on" you can just use 1.03:

19.55 * 1.03 = 20.1365

15% / 0.15 part:

20.1365 * 0.15 = 3.020475

Round to nearest cent: $3.02

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Answer:

2/5

Step-by-step explanation:

0.4 x 10/10

= 4/10 divide by 2

=2/5

Answer:

C. Multiply the first equation by -4

Step-by-step explanation:

Hi there!

In order to eliminate the y values, we would have to find a number in which the sum of the top y value and the bottom y value would equal 0. In this case, the bottom y value is equal to +4 (the +4y), so we would have to find the number that would add to make that 0, which is -4. Since the y value for the top equation is 1, all we have to do is multiply the equation by -4 so that our y value is equal to -4y and the y can be eliminated.

I hope this helps!!

Answer:

300

Step-by-step explanation:

[(-4 2/7) x (-18)] x (-3 8/9) x (-1)

= [-30/7 x -18] x -35/9 x -1

= 540/7 x -35/9 x -1

= -300 x -1

= 300

Answer:

check if the question I used is right or not

Answer: 4oz

Step-by-step explanation:

Answer:

1st one:5≥x>-infinity

2nd one :5<x<+infinity

3rd one :5>x>- infinity

Answer:

Step-by-step explanation:

Is this the entire question? Some of it makes no sense without a diagram or something.

To get rid of A you actually have to solve the equation.

7h – 5(3h – 8) = –72        Remove the brackets

7h - 15h + 40 = - 72          Combine the like terms

- 8h + 40 = - 72                Subtract 40 from both sides

- 8h = -112                        Divide by -8

    h = 14

Well the depth is a whole number so A is true.

We don't know anything about time. But the answer is positive.

C is false because B is true.

We don't know exactly what the depth of the well is.

I would pick A, but you need the entire question.

Answer:

-15

Step-by-step explanation:

-16 -|-6| +7

-16 - 6 + 7

= - 15

Absolute value is just taking the positive value of a number.

Step-by-step explanation:

-16-(-2-4)+7=

-16-(-6)+7=

-16+6+7=

-16+13=

-3

Answer:

i think its a and d

Step-by-step explanation:

Answers:

=========================================================

Explanation:

For equation A, I'll transform the right hand side into a similar form as the left side. Throughout the steps below, the left hand side stays the same.

[tex]\sqrt{448x^c} = 8x^3\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{(8x^3)^2}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{3*2}}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{6}}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{6}*7x}\\\\\sqrt{448x^c} = \sqrt{64*7x^{6+1}}\\\\\sqrt{448x^c} = \sqrt{448x^{7}}\\\\[/tex]

Therefore, c = 7

Notice that 7/2 = 3 remainder 1. The quotient 3 is the exponent for the term outside the root for [tex]8x^3\sqrt{7x}[/tex] while the remainder 1 is the exponent for the x term inside the root.

---------------------------------------

We do the same idea for equation B.

[tex]\sqrt[3]{576x^{d}} = 4x\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{(4x)^3}\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64x^3}\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64x^3*9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64*9x^{3+2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{576x^{5}}\\\\[/tex]

This must mean d = 5

Note: 5/3 = 1 remainder 2, which means [tex]\sqrt[3]{x^5} = x^1\sqrt[3]{x^2} = x\sqrt[3]{x^2}[/tex]