Kiedy błyska blisko slyszymy krótki grzmot, kiedy daleko długi. Dlaczego ?

Answer:

a)   i₈ = 0.5 i₄,  b)   i₁₀ = 0.3 i₃,    i₁₀ = 0.8 i₈

Explanation:

For this exercise we use ohm's law

       V = i R

        i = V / R

we assume that the applied voltage is the same in all cases

let's find the current for each resistance

R = 4 Ω

         i₄ = V / 4

R = 8 Ω

         i₈ = V / 8

we look for the relationship between these two currents

         i₈ /i₄ = 4/8 = ½

         i₈ = 0.5 i₄

R = 3 Ω

        i₃ = V3

R = 10 Ω

        i₁₀ = V / 10

we look for relationships

       i₁₀ / 1₃ = 3/10

       i₁₀ = 0.3 i₃

       i₁₀ / 1₈ = 8/10

       i₁₀ = 0.8 i₈

Answer:

[tex]U_x = \frac{1}{2} kx^2[/tex]

Explanation:

Find the image uploaded for the chart.

The energy stored in a stretched elastic material is known as elastic potential energy. Mathematically this energy is expressed as follows;

[tex]U_x = \frac{1}{2} fx\\\\where ;\\\\f = kx\\\\U_x = \frac{1}{2}kx^2[/tex]

The terms are defined as follows;

f is the load applied to the elastic material (N)

k is the spring constant (N/m)

x is the extension of the material (m)

Ux is the elastic potential energy (J)

Explanation:

average speed =(first velocity + second velocity)/2

=(10 +20)/2=15m/s

distance=average speed × time

= 15 × t ( but time not given)

Answer:

the kinetic energy lost due to friction is 22.5 J

Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

[tex]\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 - \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J[/tex]

Therefore, the kinetic energy lost due to friction is 22.5 J

Answer:

22.5 J

Explanation:

It loses the difference in kinetic energy between the starting and ending speeds and that is (1/2)(M)(V1)^2 - (1/2)(M)(V2)^2 = (1/2)(M)((V1)^2 -(V2)^2) = (1/2)(0.2 kg)((25)^2 - (20)^2) = 22.5 Joules.

Answer:

Increasing or recovering population number for eagle will reduce the number of salmons

Explanation:

Eagle feed upon the salmon  or is a predator for salmon.

If the population of eagle is recovering then it is clear that they will feed upon large number of salmon thereby reducing their numbers.

Hence the increasing or recovering population number for eagle will reduce the number of salmons

The slow recovery of the bald eagle population likely affected the recovery of the salmon population by Increasing  population number for eagle will reduce the number of salmons.

The large group of same or different kinds of species living in the same habitat are collectively called as population.

Eagle feed upon the salmon or said to be a predator for salmon.

If the population of eagle is increasing then it is clear that they will feed upon large number of salmon which will reduce their numbers.

Hence, the increasing population number for eagle will reduce the number of salmons denotes slow recovery.

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Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

Answer:

50km/h

Explanation:

Average Speed = Distance/Time

100km/2h = 50km/h

Answer:

A simple machine is a device that multiply an applied force by the use of the mechanical advantage built into the machine. Therefore, a simple machine changes the direction in which the applied force acts or the magnitude of the applied force, or both in order to do work

A retractable measuring tape is a device used for length measurement such that the direction of the applied force is reversed during retraction, while the magnitude of the output force is constant and dependent on the coil in the measuring

Therefore, the measuring tape does not have a constant mechanical advantage or act as a force multiplier, and therefore;

It is not a simple machine

Explanation:

Answer:

The net magnetic field ta the center of square is[tex]1.36\times10^{-4} T[/tex].

Explanation:

Current, I = 12 A , side ,a = 10 cm =  0.1 m

Let the magnetic field due to the one side is B.

The magnetic field is given by

[tex]B = \frac{\mu o}{4\pi}\times \frac{I}{r}\times \left (Sin A +Sin B \right )\\\\B = 10^{-7}\times \frac{12}{0.05}\times \left ( sin 45 + sin 45 \right )\\\\B = 3.4\times 10^{-5} T[/tex]

Net magnetic field at the center of the square is

B' = 4 B

[tex]B'= 4\times 3.4\times 10^{-5}\\\\B' = 1.36\times10^{-4} T[/tex]

Answer:

Explanation: A lightbulb is connected to an outlet that has a source of electricity. The electrical energy is converted into light energy to allow the bulb to glow.

Explanation:

Answer:

The first law states that an object at rest will stay at rest, and an object in motion will stay in motion unless acted on by a net external force. Mathematically, this is equivalent to saying that if The second law states that the rate of change of momentum of a body over time is directly proportional to the force applied, and occurs in the same direction as the applied force. the net force on an object is zero, then the velocity of the object is constant. The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction

Explanation:

Answer:

105571.2 m/s

Explanation:

Using the formula connecting linear and angular velocity;

V = rω

r = radius of the circular path

ω = angular velocity

Since

1 rpm = 2π60 rad/s

800 rpm = 800 * 2π60 rad/s = 301632 rad/s

Substituting values;

V = 35/100 *  301632 rad/s

V= 105571.2 m/s

Answer:While walking, one foot is in contact with the ground at a time. The surface area of one foot is less than two feet. Therefore, the pressure is more than the pressure exerted while standing, as the surface area of both feet is more.

Answer:

Pressure (P) is the amount of force applied perpendicular to the surface of an object per unit area. The SI unit of pressure is the pascal (Pa), which is equivalent to N/[tex]m^{2}[/tex] (newtons per meter squared).

Answer:

True

Explanation:

I took the quiz and got it right.

TRUST

The "max out" method, also known as the "1RM" (One Repetition Maximum) method, is commonly used in strength training to determine the maximum amount of weight an individual can lift for a particular exercise.

The purpose of this method is to assess muscular strength accurately. While it is essential to perform warm-up sets to prepare the body for intense lifting, the process of determining the 1RM involves a specific protocol:

Warm-up Sets: Before attempting the 1RM, it is crucial to warm up the muscles and joints properly. Warm-up sets are typically performed with lighter weights and higher repetitions to gradually prepare the body for the heavier load.

Complete Sets: After the warm-up sets, the individual performs one or more "complete sets" with progressively heavier weights, but not at maximal effort. These sets help acclimate the body to heavier loads and prepare the nervous system for the upcoming maximal lift.

1RM Attempt: Once adequately warmed up and prepared, the individual makes an attempt to lift the heaviest weight possible for one repetition. It is essential to have a spotter or a qualified trainer to ensure safety during this maximal effort lift.

Rest: After the 1RM attempt, it is essential to allow sufficient rest and recovery, as attempting maximal lifts can be physically and mentally demanding.

It's important to note that determining 1RM carries a higher risk of injury compared to typical strength training. It's best to perform 1RM assessments under the guidance of a qualified trainer or coach who can provide proper instruction and ensure safety throughout the process. Additionally, the 1RM should be assessed periodically, as it can change over time with training and adaptation.

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Answer:

2 is the numerical answer.

Explanation:

Hello there!

In this case, according to the given information and formula, it is possible for us to remember that equation for the calculation of the average kinetic energy of a gas is:

[tex]KE=\frac{3}{2} \frac{R}{N_A} T[/tex]

Whereas R is the universal gas constant, NA the Avogadro's number and T the temperature.

Which means that for the given ratio, we can obtain the value as follows:

[tex]=\frac{\frac{3}{2} \frac{R}{N_A} T_1}{\frac{3}{2} \frac{R}{N_A} T_2} \\\\=\frac{T_1}{T_2} \\\\=\frac{500K}{250K} \\\\=2[/tex]

Regards!

Answer:

A causes free electrons to flow

Explanation:

The amount of force that causes electrons to flow in a conductor is called electromotive force.

Answer:

Time = 80.91 seconds

Explanation:

Given the following data;

Velocity = 5.50 m/s.

Distance = 445 meters

To find the time;

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

[tex]Velocity = \frac{distance}{time}[/tex]

Substituting into the formula, we have;

5.5 = 445/time

Time = 445/5.5

Time = 80.91 seconds

Answer:

tthe body of what it is supplied in its temperature rises

Answer:

18

Explanation:

12 - 5 + 8 = 15

12 - 8 = 4

7 - 4 = 3

15 + 3 = 18

Answer:

B= 4 A=5

Explanation:

Answer:

a. Final velocity, V = 88 m/s

b. Distance, S = 960 meters

Explanation:

Given the following data;

Initial velocity = 8 m/s

Acceleration = 4 m/s²

Time = 20 seconds

a. To find the final velocity, we would use the first equation of motion;

V = u + at

V = 8 + 4*20

V = 8 + 80

Final velocity, V = 88 m/s

b. To find the distance covered, we would use the second equation of motion.

S = ut + ½at²

S = 8*20 + ½*4*20²

S = 160 + 2*400

S = 160 + 800

S = 960 meters

Answer:

The distance between the diver and the shipwreck is approximately 130.76 m

Explanation:

The depth of the shipwreck below the surface of the water = 35 m

The location of the wreck = 55° South of West

The angle of depression of the wreck = 18°

The location of the diver = 27° South of East

The angle of depression of the diver = 30°

The distance of the wreck from the ship = 35 m/(sin(18°)) ≈ 113.26 m

The horizontal distance of the wreck from the ship = 35 m/(sin(18°)) × (cos(18°)) ≈ 107.72 m

The x-coordinate of the shipwreck, x₁ = 107.72 m × cos(55°) ≈ 61.79

The y-coordinate of the shipwreck, y₁ = 107.72 m × sin(55°) ≈ -88.24

The z-coordinate of the shipwreck, z₁ = -35

The distance of the diver from the ship = 35 m/(sin(30°)) = 70 m

The horizontal distance of the diver from the ship = 70 m × cos(30°) ≈ 60.62 n

The x-coordinate of the diver from the ship, x₂ = -60.62 m × cos(27°) ≈ -54.013

The y-coordinate of the diver from the ship, y₂ = 60.62 × sin(27°) ≈ -27.52

The z-coordinate of the diver from the ship, z₂ = -35

The distance between the diver and the shipwreck, 'd', is given by the distance between two points given the x, y, z coordinates as follows;

d = √((x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²)

Therefore, we have;

d = √((61.79 - (-54.013))² + (-88.24 - (-27.52))² + (35 - 35)²) ≈ 130.76

The distance between the diver and the shipwreck, d ≈ 130.76 m.

Answer:

It is connected in series with the circuit

Explanation:

This is because to measure the current in the circuit, the current in the circuit has to flow through the ammeter. As such, the ammeter must be connected in series with the circuit so as to measure the current flowing through the circuit.

So, to measure the current flowing through a circuit with an ammeter, the ammeter must be connected in series with the circuit.

Answer:

Comencemos con la primera:

si tenemos algo como:

7.1*10^n

Simplemente lo que tenemos que hacer es:

si n es positivo, movemos n veces el punto para la derecha, si no tenemos dígitos, completamos con ceros.

si n es negativo, movemos n veces el punto a la izquierda.

a) 7.1*10

aca tenemos n = 1

entonces movemos una vez el punto a la derecha:

7.1*10 = 71. = 71

b) 2.3*10^3

aca n = 3, entonces movemos el punto 3 veces a la derecha:

2.3*10^3 = 23__.

Tenemos dos huecos ahí, los cuales serán completados con ceros, entonces:

2.3*10^3 = 2,300. = 2,300

c) 1.56*10

n = 1, entonces movemos el punto una vez a la derecha:

1.56*10 = 15.6

d) 4.10^4

acá tenemos n = 4

entonces movemos el punto 4 veces a la derecha, recordar que debemos completar con ceros:

4.10^4 = 40,000. = 40,000

Answer:

property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.

Answer:

Law of inertia, also called Newton's first law, postulate in physics that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Hope this answer is right!

Answer:

increasing wavelength near beach

Explanation:

When wavelength increases, frequency of these waves decreases and the waves suddenly stop.

This is also called damped oscillation.

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b)  If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c)  If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m