Jade has a refractive index of 1.61. If light approaches the gem at an angle of 80.0°, what is the angle of refraction?

Calculate the index of refraction of a material if the angle of incidence is 60° and the angle of refraction is 50°

Answer using calculations & full work and thoughts shown.

Answers

Answer 1

From Snell's law,  the angle of refraction is 38 degree approximately and the index of refraction is 1.13

The given refractive index is 1.61

If light approaches the gem at an angle of 80.0°, that means the angle of incidence is 80.0°

To calculate the angle of refraction, we will use Snell's law which state that:

n = sin i / sin r

where n = refractive index

Substitute all the parameters into the formula

1.61 = sin 80 / sin r

make sin r the subject of formula

sin r = sin 80 / 1.61

sin r = 0.611

r = [tex]Sin^{-1}[/tex](0.611)

r = 37.7

r = 38 degree (Approximately)

We will use the same formula to calculate the index of refraction of a material if the angle of incidence is 60° and the angle of refraction is 50°. That is,

n = sin i / sin R

Where n = index of refraction

i = Incidence

R = refraction

Substitute all the parameters to the formula

n = sin 60 / sin 50

n = 0.866 / 0.766

n = 1.13

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a car is moving due south for 4hr and covered a distance of 144km what is the velocity of the car?​

Answers

Answer:

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Can anyone help me with this question? I’ll give BRAINLIEST to whoever answers first

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Answer:

a) F = 84.64N

b) The force has to increase.

Explanation:

First of all, let's convert everything to the same unit system:

Vo = 0 m/s    Vf = 98 mi/h * 1609.34 m / 1mi * 1h / 3600s = 43.8m/s

d = 1.7m         m = 0.15kg

We can calculate force as:

F = m*a    where a is the acceleration experiencd by the ball and m is its mass.

In order to calculate acceleration, we can use this formula:

   Solving for a:

Now, the force will be:

F = m * a = 84.6N

As we can see in that previous equation, the force is directly proportional to the mass of the ball, so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same), the force will increase in the same proportion as the mass does.

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Answer:

The uneven heating results in some of the atmosphere to be warmer than other parts and changes in volume and pressure which result in updrafts and can cause thunderstorms and other violent weather.

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Answers

Answer: 4.44302176697 m/s^2

Explanation:

formula for acceleration is (final velocity - initial velocity)/time.   So in your case:

(34.7m/s - 0m/s)/ 7.81s  = 4.44302176697 m/s^2

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An electric generator has an 18-cm-diameter, 120-turn coil that rotates at 60 hz in a uniform magnetic field that is perpendicular to the rotation axis.

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A mass 25kg is attached to a spring which is held stretched a distance 120 cm by a force F=300N (Fig. 7-28), and then released. The spring compresses, pulling the mass. Assuming there is no friction, determine the speed of the mass m when the spring returns: (a) to its normal length (x = 0). (b)find the spring constant k?

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"X"

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Answer:

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Explanation:

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Help me quickly! please!!!

A cable pulls a car up a mountain with a force of 4 × 103 N at a vertical constant velocity of 5 m.s-1. It takes 5 minutes to reach the top.

(a)How much work is done in getting the car to the top?
(b)How much work would have been done if the vertical speed was 2,5 m.s-1?
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Answers

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

The work done in getting  the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be  3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.

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In physics, work done is the dot  product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then

W = F.ds

It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.

ds = velocity ×  time

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    = 1500 m.

Thus the work done = F × ds

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If the velocity is reduced to half 2.5 m/s , then work done will be reduced to half as 3 ×10⁶ J.

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