It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:
2.9 x 10^20 N3.5 x 10^22 N3.5 x 10^22 NWhat is gravitational force?Generally, The gravitational force between two objects is given by the equation:
force = G * (mass1 * mass2) / distance^2
Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.
The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.
The gravitational force between the Earth and the Moon is:
force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force
= 2.9 x 10^20 N
The gravitational force between the Earth and the Sun is:
force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force
= 3.5 x 10^22 N
To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.
Net force = 2.9 x 10^20 N + 3.5 x 10^22 N
= 3.5 x 10^22 N
When it is a Full Moon the distance is the same 384,400 km
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The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration.
The magnitude of the constant acceleration of the ball is 9.7 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the constant acceleration of the ball, we use the formula below.
Formula:
a = (v-u)/t................. Equation 1From the question,
Given:
a = Acceleration,v = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 33 m/su = 0 m/s t = 3.4 secondsSubstitute these values into equation 1
a = (33-0)/3.4a = 9.7 m/s²Hence, the acceleration is 9.7 m/s².
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Corn plants and milkweed plants grow in the same area. Over several years, the milkweed plants have taken over the field and the corn plants no longer have space to grow.
This best demonstrates which type of an interaction between the plants?
cooperation
parasitism
commensalism
competition
The interaction between the Corn plants and milkweed plants demonstrates as competition.
What is competition in Plants community?Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.
In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.
As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and milkweed plants demonstrates competition.
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On what basis is it considered that the universe is expanding?
There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.
The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.
Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.
Hope This Helps You!
Which ideas did you include in your answer? Check all that apply.
Scientists use relative and absolute dating to determine age of rocks.
Scientists can organize the rocks layers based on their age on the geologic time scale.
The type of rocks and the fossils in the rock layers tell scientists about Earth’s history.
By contrasting a fossil with related rocks and fossils of known ages, relative dating can estimate the fossil's age.
By utilising radiometric dating to track the isotope decay inside the fossil or, more frequently, the rocks it is linked with, absolute dating may pinpoint an object's exact age.
What are the benefits of using relative and absolute dating of rocks?It is possible to identify whether one artefact, fossil, or stratigraphic layer is older than another using relative dating, which does not provide particular dates.
Absolute dating techniques offer more precise dates and times of origin, such as a range in age in years.
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A horse trots past you and then a fencepost that is 36m away from you. It takes the horse 11.0 sec to make this trot. What is the average velocity of the horse?
As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
A horse trots past you and then a fencepost that is 36m away from you.
Time taken to make this trot = 11.0 second.
Hence, the average velocity of the horse is = total distance travelled/time interval
= 36/11.0 m/s
= 3.27 m/s.
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The monster wants to make himself known to the family in the cottage in chapters 9-12 of Frankenstein. He decides he can't do that until he masters something. What skill
must he master?
A. How to dress properly
B. Language
C. The rules of etiquette
D. Music
Answer:
c
Explanation:
A horse pulls a wagon with a force of 1450 Newtons. How many meters sis the wagon travel if the horse exerted 798 watts of power over 3.5 minutes? (convert min. to seconds).
The distance traveled by the horse pulling the wagon with a force of 1450N is 115.57 metres.
How to calculate power?Power is defined as the amount of energy used or transferred in a certain amount of time. This means that power can be calculated by dividing the work done by the time taken.
P = W/t
When a force is applied to move an object, work is done on the object. Work done = force × distance
Power = (Force × distance)/time
According to this question, a horse pulls a wagon with a force of 1450 Newtons.
798 = 1450 × d/210
167,580 = 1450d
Distance = 167,580 ÷ 1450
Distance = 115.57 metres
Therefore, 115.57 metres is the distance traveled by the wagon.
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n experimental vehicle starts from rest (0 = 0) at = 0 and accelerates at a rate given by
= (7m/s
3
). What is (a) its velocity and (2) its displacement 2 later?
The velocity of the experimental vehicle after 2 seconds is 14 m/s.
The displacement of the experimental vehicle after 2 seconds is 14 m.
What is the velocity and displacement of the experimental vehicle?The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.
The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:
v = u + at
where;
u is the initial velocity = 0 m/s
a is the acceleration = 7 m/s²
t is time = 2 seconds
v = 0 + 7 * 2
v = 14 m/s
The displacement, s, of the vehicle is calculated below as follows:
v² = u² + 2as
14² = 0² + 2 * 7 * s
s = 196 / 14
s = 14 m
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A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible
The horizontal distance travelled by the box is 143 m.
What is the horizontal distance travelled by the box?
The horizontal distance travelled by the box is calculated by determining the time of motion of the box and the horizontal velocity of the airplane.
The time of motion of the box from the vertical height in which it was dropped is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the box = 0t is the time of motion of the boxg is acceleration due to gravityh is the height of fall of the boxh = 0 + ¹/₂gt²
t = √ ( 2h / g )
t = √ ( 2 x 40 / 9.8 )
t = 2.86 seconds
The horizontal distance travelled by the box is calculated as follows;
d = Vₓ t
where
Vₓ is the horizontal velocity of the airplanet is the time of motiond = ( 50 m/s ) x ( 2.86 s )
d = 143 m
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The complete question is below;
A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible. Find the horizontal distance travelled by the box.
A graph of v(t) is shown for a world-class track sprinter in a 100 -m race. (See figure below. For each answer, enter a number.)
(a) What is his average velocity (in m / s ) for the first 4 s} ?
______ m/ s
(b) What is his instantaneous velocity (in m / s ) at t=6 s ?
______ m / s
(c) What is his average acceleration (in m / s²) between 0 and 4s?
________m / s²
(d) What is his time (in s) for the race?
______ s
a) The average velocity at 4s is 12 m/s
b) The instantaneous velocity at t= 6s is 12 m/s
c) The average acceleration is; 12 - 0/ 4 - 0 n= 3 m/s^2
d) The time for the race is 10 s
What is the velocity time graph?We know that the velocity time graph is the kind of set up that has two axis and we can be able to use it to be read off the velocity of the acceleration of the object. I would want us to recall that the acceleration is the rate of change of the velocity of the object with time.
Now we have that;
The graph for the velocity of the object can be obtained by looking at the image that has been shown and then we read off the points that are on the graph. The vertical axis shows the velocity of the graph while the horizontal axis shows the time that is covered in the graph.
The acceleration would be the ratio of the change in the velocity to the change in the time of the object.
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Which of the following is the only group in mission control that gets to communicate with the astronauts in space?
Flight Director
CAPCOM
Senior Flight Controller
Lead Ground Astronaut
Capsule communicator or Capcom is the only group in mission control that gets to communicate with the astronauts in space. Hence, option (B) is correct.
What is capsule communicator or Capcom?The capsule communicator, or Capcom, was the only voice that spoke to the astronauts during their trip to avoid any mistake. To ensure that the men in the capsule always had a familiar individual who understood their situation and could provide the information they required, Capcom was always manned by astronauts.
Both the technical control team on the ground and the astronauts in space are represented by Capcom.
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Someone please help me with this question
How are mass and weight different?
Answer:
The mass is the amount of matter in something. Weight is mass times gravitational field strength and so also includes gravity. Mass is measured in grams (g) and weight is measured in Newtons (N)
Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. What is MOST likely TRUE about this goal?
Since Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. The option that MOST likely TRUE about this goal is option A:It is a short-term goal.
What is the fitness goal about?A short-term goal is a goal that can be achieved within a relatively short period of time, usually less than a year. In this case, the goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January.
In this case, Taylor's goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. This goal is specific, as it clearly states what Taylor wants to accomplish, and it is measurable.
This goal can be achieved within the month of January and it's a specific, measurable and time-bound goal, which are characteristics of short-term goals.
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See full question below
Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. What is MOST likely TRUE about this goal?
It is a short-term goal.
It is a long-term goal.
It is an unrealistic goal.
It is a mental health goal.
Answer:it’s a short-term goal
Explanation:
because it’s only for the month of January she will be doing this goal.
with what speed will a clock have to be moving in order to run at a rest that is one half the rate of clock at rest
The speed at which a clock would have to be moving in order to run at half the rate of a clock at rest depends on the theory of relativity that you are using.
What is the clock speed about?In special relativity, time dilation is the phenomenon where time appears to pass differently for objects in motion relative to an observer at rest.
According to the theory, time appears to slow down for an object as it approaches the speed of light. The rate at which time appears to pass for an object is given by the equation:
T' = T / [tex]\sqrt{(1 - (v^2 / c^2))}[/tex]
Where T is the time as measured by an observer at rest, T' is the time as measured by an observer moving relative to the object, v is the velocity of the object, and c is the speed of light.
In addition, this is a theoretical scenario, practically in order to measure time dilation in a laboratory, it is required a very high precision of measurements, that are currently not possible.
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After Victor returns to the house in chapters 21-continuation of Frankenstein, he looks out the window and sees the monster standing outside grinning. How does Victor react
to seeing him?
A. He invites him in to have a talk.
B. He runs outside to embrace him.
C. He draws his pistol and shoots at him.
Victor reacts when he sees him and threatens to call the police if he doesn't leave. Therefore, choice C is correct.
How does Frankenstein play out?When the court learns of Victor's residence on the Orkney Islands, Kirwin presents a compelling defense of Victor at the trial and is successful in securing Victor's release. Victor's absence from his lab in the Orkneys at the time of the murder is evidence that he did not commit the crime. Victor is taken home by Alphonse.
At the conclusion of Frankenstein, what happens to Victor?Victor Frankenstein wishes he could kill the monster he created when he dies in Frankenstein. Frankenstein is visited by the Monster. He informs Walton that he intends to kill himself and expresses regret for the murders he has committed.
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Full Question = After Victor returns to the house in chapters 21-continuation of Frankenstein, he looks out the window and sees the monster standing outside grinning. How does Victor react
to seeing him?
A. He invites him in to have a talk.
B. He draws his pistol and shoots at him.
C. He threatens to call the police if he doesn't go away.
D. He runs outside to embrace him.
A student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water. In the experiment, she uses 150 milliliters of water in each trial and stirs for five minutes each time.
The independent variable that we have in the experiment is the temperature. Option B
What is an experiment?We know that if we are talking about an experiment, what we have to look at is that we must consider the interplay of the variables that is taking place in the process. As we change one of the variables in the experiment, there would be a change in another variable in the experiment also.
Now, the variable that we usually beging to alter is the one that we call the independent variable. As we change the value of this particular variable, there would be a change in the independent variable.
We have been told that; a student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water.
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Exercise 24.28
For the capacitor network shown in (Figure 1), the potential difference across ab is 48 V.
Part A
Find the total charge stored in this network.
Express your answer with the appropriate units.
Q = ___ ____
Part B
Find the charge on the 150nF capacitor.
Express your answer with the appropriate units.
Q₁ = 7.2uC
Part C
Find the charge on the120nF capacitor.
Express your answer with the appropriate units.
Q₂ = 5.76 uC
Part D
Find the total energy stored in the network.
Express your answer with the appropriate units.
U = ____ ____
Part E
Find the energy stored in the 150nF capacitor.
Express your answer with the appropriate units.
U₁ = ______
Part F
Find the energy stored in the 120nF capacitor.
Express your answer with the appropriate units.
U₂= _____
Part G
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₁= ____
Part H
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₂ = ____
The evaluation of the capacitor (in series) network is as follows;
Part A
Q = 3.2 μC
Part B
Q₁ = 3.2 μC
Part C
Q₂ = 3.2 μC
Part D
U = 76.8 μJ
Part E
U₁ = 34 2/15 μJ
Part F
U₂ = 53 1/3 μJ
Part G
V₁ = 21 1/3 V
Part H
V₂ = 26 2/3 V
What is a capacitor?A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.
The specified parameters are;
The voltage across ab = 48 V
The capacitance of the first capacitor, C₁ = 150 nF
Capacitance of the second capacitor, C₂ = 120 nF
Part A
The total charge in a capacitor network can be found as follows;
[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]
[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]
[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]
Therefore;
[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC
The total charge in the circuit is 3.2 μCPart B
The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;
Q = C₁V₁ = C₂V₂
The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC
The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC
Q₁ = 3.2 nCPart C
The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.
Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC
Q₂ = 3.2 μF
Part D
The total energy stored in the network can be obtained using the formula;
U = (1/2)·C·V²
Where;
U = The energy in the capacitor
C = The equivalent capacitance of the network = 66 2/3 nF
V = The voltage
Therefore;
[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]
[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]
The total energy in the circuit, U = 76.8 μJPart E
The energy stored in the 150 nF capacitor is found as follows;
[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁
V₁ = [tex]Q_{eq}[/tex] ÷ C₁
Therefore;
V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V
U₁ = 0.5×C₁×V₁²
U₁ = 0.5 × 150×10⁻⁹ × [tex]\left(21\frac{1}{3} \right)^2[/tex] = 34[tex]\frac{2}{15}[/tex] μJPart F
The energy stored in the 120 nF capacitor, U₂, can be found as follows;
V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V
U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]
The energy in the 120 nF capacitor is; U₂ = 53 1/3 μJPart G;
The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V
V₁ = 21 1/3 VPart H
The potential difference across the 120 nF, obtained in part F, is 26 2/3 V
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Read the following poem by Lola Ridge. Then, respond to the prompt that follows.
Wild Ducks
By Lola Ridge
That was a great night we spied upon
See-sawing home,
Singing a hot sweet song to the super-stars
Shuffling off behind the smoke-haze …
Fog-horns sentimentalizing on the river …
Lights dwindling to shining slits
In the wet asphalt …
Purring lights …red and green and golden-whiskered …
Digging daintily pointed claws in the soft mud …
…But you did not know …
As the trains made golden augers
Boring in the darkness …
How my heart kept racing out along the rails,
As a spider runs along a thread
And hauls him in again
To some drawing point …
You did not know
How wild ducks' wings
Itch at dawn …
How at dawn the necks of wild ducks
Arch to the sun
And new-mown air
Trickles sweet in their gullets.
In a well-written paragraph of 5–7 sentences, analyze the ambiguous nature of "Wild Ducks." Your response should include:
an explanation of your interpretation of the poem's meaning
evidence from the poem (PReP) that supports your interpretation
an explanation of how another reader could interpret the poem differently
evidence from the poem to support an alternative interpretation
Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.
What does the poem discuss?Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:
You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.
You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.
You could argue that a different reading would imply that the speaker is the one being dumped by her lover.
You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.
But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.
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8. If the m<5 is 63°, find the
measure of <3.
The statement indicates that angle 3 seems to have a 117 degree measurement.
Short answer: What is measure?Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.
Briefing:An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.
The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.
Angle 3 is therefore = 180 - 63 = 117 degrees.
Consequently, angle 3 has a measure of 117 degrees.
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POSSIBLE POINTS: 1
This is another example of a lever.
Identify each part, A, B and C, and then classify the lever as 1st, 2nd, or 3rd class.
Responses
A. fulcrum, B. load, C. effort. 2nd class
A. fulcrum, B. load, C. effort. 2nd class
A. load, B. fulcrum, C. effort. 1st class
A. load, B. fulcrum, C. effort. 1st class
A. load, B. fulcrum, C. effort. 3rd class
A. load, B. fulcrum, C. effort. 3rd class
A. effort, B. fulcrum, C. load. 1st class
In the given image A. load, B. fulcrum, C. effort. 1st class. The correct option is B.
What is fulcrum?The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.
The fulcrum of first-class levers is in the centre. Levers of the second class have the load in the centre.
This indicates that a heavy load can be moved with only moderate effort. - Levers of the third class exert middle-of-the-road force.
The illustration shows a class 1 lever with a fulcrum in the middle and load and effort located at the other two ends.
Thus, the correct option is B.
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The same resultant force acts on objects 1 and 2. Object 1 accelerates at 2m/s² and Object 2 accelerates at 5m/s². Which object has the greater mass?
Answer:
Object 1
Explanation:
Newton's 2nd Law: F = ma, therefore m = F/a
This shows that mass is inversely proportional to acceleration. Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass. Therefore, the object that accelerates at 2 m/s² has the greater mass. In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.
In a particular crash test, an automobile of mass 1759 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 12 m/s and 2.2 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Calculate the magnitude of the average force exerted on the automobile during the collision. Answer in units of N.
Based on the data provided about the collision;
the magnitude of the impulse due to the collision is 21105.8 kg.m/sthe magnitude of the average force exerted on the automobile during the collision is 191870.91 NWhat is the magnitude of the impulse due to the collision of the vehicle with the wall?The magnitude of the impulse due to the collision of the vehicle with the wall is calculated using the formula of the impulse on an object given below as follows:
Impulse = change in momentum
Change in momentum = m(v - u)
where;
m is mass
v is the final velocity
u is the initial velocity
Impulse = 1759 (12 - 22)
Impulse = 21105.8 kg.m/s
The average force on the automobile will be:
Force = impulse/time
Force = 21105.8 / 0.11
Force = 191870.91 N
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A man lifts various loads with the same lever. The distance of the applied force from the fulcrum is 2.00 m and the distance from the fulcrum to the load is 0.500 m. A graph of resistance force vs. effort force is shown. What is the mechanical advantage of the lever? What is the ideal mechanical advantage of the lever? What is the efficiency of the lever? Show your work.
The mechanical advantage of the lever is 3.5.
The ideal mechanical advantage of the lever is 4
The efficiency of the lever is 87.5 %.
What is the mechanical advantage of the lever?The mechanical advantage of the lever is the ratio of the load overcame by the lever to the effort applied by the lever.
M.A = Load / Effort
From the graph we will find the change in load to change in effort is calculated as;
M.A = ( 160 N - 20 N ) / ( 50 N - 10 N )
M.A = 3.5
The ideal mechanical advantage of the lever is calculated as follows;
I.M.A = distance travelled by effort / distance travelled by load
I.M.A = ( 2 m ) / ( 0. 5 m )
I.M.A = 4
The efficiency of the lever is calculated as follows;
E = M.A / I.M.A x 100%
E = ( 3.5 / 4 ) x 100%
E = 87.5 %
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Determine the parallel and perpendicular components of the force of gravity for a 369 N object on a 28.4 degree incline
The parallel component of the force of gravity is the net force. The perpendicular component of the force of gravity is directed opposite the normal force and as such balances the normal force.
What is the perpendicular component of the force of gravity?In order to balance the normal force, the perpendicular component of gravity is pointed in the opposite direction. No other force can counteract the parallel component of the gravitational force.
What is the parallel component of the force of gravity?The presence of an imbalanced force will then cause the object to accelerate downward along the inclined plane. This acceleration is brought on by the parallel part of the gravitational force. The net force is a parallel part of the gravitational force.
Steps for Calculating the Force of Gravity on an Object Falling from an Inclined Plane: Determine the inclined plane's angle in the first step.Determine the object's mass on the inclined plane in step two.Determine and compute the gravitational force acting on the item.Determine and compute the parallel and perpendicular forces acting on the object.Formulas to Calculate the Force of Gravity on an Object Falling Down an Inclined Plane using Vocabularyincline plane: a wedged angle.Force of Gravitation the downward-moving gravitational force.Force that is parallel to the inclined plane's face is referred to as the perpendicular force.The force that is parallel to the inclined plane's face is known as the parallel force.Equation for Gravitational Force: The gravitational force is equal to the product of an object's mass and its gravitational acceleration.FGravity=m×g
where m is the object's mass and g is gravity's acceleration, which is 9.8 m/s2. In this case, the negative indicates that the force is downward-directed.
Equation for Perpendicular Force: The Perpendicular Force is equal to the gravitational force multiplied by the cosine of the angle of the inclined plane.FParallel=FGravity×Cos(Θ)
Equation for the Parallel Force: The Parallel Force is equal to the gravitational force multiplied by the sine of the inclined plane's angle.FParallel=FGravity×Sin(Θ)
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1. As air in Earth's atmosphere is heated by
the Sun, the warmer air expands and
becomes less dense than the cooler air. As a
result, the warmer air rises and the cooler
air sinks. What is the cycle of warm air
rising and cool air sinking called?
tidal current
surface current
deep current
convection current
The correct answer is D) convection current.
Convection currents are the cycle of warm air rising and cool air sinking that occurs in Earth's atmosphere (as well as in other fluids) as a result of temperature differences. When a fluid (such as air) is heated, it expands and becomes less dense, causing it to rise. When the warmer fluid cools, it contracts and becomes denser, causing it to sink. This cycle of rising and sinking creates a circular flow known as a convection current.
Based on the image shown, write the number that corresponds to the term or phrase. Assume that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3.
Anode:
3
Cathode:
Electrolytes:
1
Salt bridge:
5
Electrode where oxidation occurs:
4
The reaction that takes place in this cell is
✔ spontaneous
.
Based on the image shown, the numbers that correspond to the term or phrase assuming that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3 are:
Anode: 3Cathode: 1Salt bridge: 4Electrolytes: 5Electrode where oxidation occurs: anodeThe reaction that takes place in this cell is spontaneousWhat are electrochemical cells?Electrochemical cells are cells that convert chemical energy to electrical energy.
The components of an electrochemical cell are:
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A sign which weighs 38.3 N is supported symmetrically by two cables which make an angle of 1.0 degrees with the horziontal. A single cable will pull upward on the sign with a force of how may Newtons?
The single cable will pull upward on the sign with a force of 38.3 N.
What is single cable?Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.
This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.
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A particle which is moving in a straight line with a velocity of 15m/s accelerates uniformly for 3.0s, increasing its velocity to 45m/s. What distance does it travel while accelerating
The distance travel while accelerating is 90m
The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.
The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .
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A box with a weight of 25N sits on the floor. What is the maximum force that could be applied horizontally on the box before it would start to accelerate if the coefficient of friction is 0.40?
So, we know that The box isn't moving at all. I'm assuming the coefficient they gave you is for static friction. We know that with static friction, the value that we calculate is a maximum value that represents the force we'd have to apply before an object starts moving!
We also know that the box isn't moving vertically. That means that its Y forces must be cancelling out, which means its weight force and its normal force must be equal to each other!
Now we can plug in these values into our static friction equation!
[tex]F_s[/tex] ≤ [tex]F_N[/tex] * μ[tex]_s[/tex]
[tex]F_s[/tex] ≤ (25N) (0.40)
[tex]F_s = 10[/tex]
Therefore your force that you'd need to apply is 10N!
A single movable pulley is used to lift 4000N load to the height of 50 cm. If the efficiency of the pulley is 75%, Calculate effort distance,effort applied,output work and mechanical advantage.
Since the efficiency of the pulley is 75% and the single movable pulley is used to lift 4000N load to the height of 50 cm, the effort distance, effort applied, output work and mechanical advantage are as follows:
Effort Distance = 50 cm
Effort Applied = 5333.33 N
Output work = 2000 J
Mechanical Advantage = 0.75.
When a single movable pulley is used to lift a load, the effort applied is equal to the weight of the load being lifted, and the effort distance is the distance the effort is applied.
Load (output force) = 4000 N
Height lifted = 50 cm = 0.5 m
Efficiency of the pulley = 75%
Given the above information, we can calculate the effort applied, output work, and mechanical advantage as follows:
Effort applied (input force) = Load ÷ Efficiency
= 4000 N ÷ 0.75
= 5333.33 N
Output work = Load x Height lifted
= 4000 N x 0.5 m
= 2000 J
Effort distance = Height lifted
= 50 cm
Mechanical advantage = Load ÷ Effort applied
= 4000 N ÷ 5333.33 N
= 0.75
It is worth noting that pulley efficiency is the ratio of output work to the input work. And since the efficiency of the pulley is 75% so the input work is greater than the output work, which means some of the energy is wasted in overcoming friction and other losses.
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