The equation of a vertical asymptote to the graph of y = sec(6x - π) is x = π/6. Hence, option a is correct.
The function y = sec(6x - π) has vertical asymptotes at the values of x where the denominator of sec(6x - π) becomes zero. The reciprocal of sec(θ) is cos(θ). Because the cosine function has the values π/2, 3π/2, 5π/2, we will insert such an input that we get 0 in denominator.
6x - π = π/2
Solving for x,
6x = π/2 + π
6x = 3π/2
x = (3π/2) / 6
x = π/6
Therefore, the equation of a vertical asymptote to the graph of y = sec(6x - π) is x = π/6.
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Can someone please help me with this??
A heptagon has angles x, 105 degrees, 105 degrees, 160 degrees, 124 degrees, 97 degrees, 137 degrees. Find the missing angle measure in the heptagon. The sum of the interior angles of a heptagon is °. The measure of the missing angle is °.
Answer:
900 and 172 for edg 2020-2021
Step-by-step explanation:
HELP!!!!!! will give brainlist
Answer:
1. 112 cm
2 135 ft
3 53.67
Step-by-step explanation:
Answer:i
Step-by-step explanation:
Travis has $1,500 in a savings account. He deposits $75. How much interest will he earn after 2 years at a simple annual interest rate of 1.3%?
(The links don’t work so please just give the answer)
Answer:
40.95
Step-by-step explanation:
P = 1500 + 75 = 1575
I = Prt
I = 1575(1.3%)(2)
I = 40.95
Solve the given initial-value problem for yo > 0. dy = Vy, y(x) = Yo dx y(x) = (1 xo 2. х 2 + Yo ) Find the largest interval I on which the solution is defined.
The given differential equation is given by `dy/dx = V*y` and the initial condition is `y(x) = Yo`.
The solution of the differential equation is given by `y(x) = Yo*e^(V*x)`.
Using this formula and the initial condition `y(x) = Yo`,
we get `Yo = Yo*e^(V*x)`.
This implies that `e^(V*x) = 1` or `V*x = 0`.
Thus `x = 0` is the only value of x on which `y(x) = Yo` for any value of `V`.
Now, we are given `y(x) = (1 + x^2)/(x^2 + Yo)` which is valid only if `Yo > 0` (as given). We need to find the largest interval on which the solution is defined. This means that we need to find the largest interval of x-values for which the given expression for `y(x)` makes sense. Since the denominator of the expression `y(x) = (1 + x^2)/(x^2 + Yo)` is `x^2 + Yo`, the expression is defined only if `x^2 + Yo > 0`. As `Yo > 0`, this inequality holds for all values of `x`. Thus, the solution is defined for all `x` in the real line. Therefore, the largest interval on which the solution is defined is `(-∞, ∞)`.
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What is the greatest common factor of
12x3 + 6xy + 18x?
Answer:
6x
Step-by-step explanation:
12x^3, 6xy, and 18x can all be evenly divided by 6x
Cereal box Design Project Connexus
30 points
The most cost-efficient container is the Rectangular Prism.
1. Rectangular Prism:
Volume: V = lwh = 10 x 5 x 15 = 750 cubic units
Cost: C = $0.01 x 750 = $7.50
Cost per unit volume: C/V = $7.50 / 750 = $0.01 per cubic unit
2. Rectangular Pyramid:
Volume: V = (1/3) x lwh = (1/3) x 10 x 5 x 15 = 250 cubic units
Cost: C = $0.02 x 250 = $5.00
Cost per unit volume: C/V = $5.00 / 250 = $0.02 per cubic unit
3. Cylinder:
Volume: V = πr²h = π x 5² x 15 ≈ 1178.1 cubic units
Cost: C = $0.015 x 1178.1 = $17.67
Cost per unit volume: C/V = $17.67 / 1178.1 ≈ $0.015 per cubic unit
Now, comparing the cost per unit volume for each container:
a. Rectangular Prism: $0.01 per cubic unit
b. Rectangular Pyramid: $0.02 per cubic unit
c. Cylinder: $0.015 per cubic unit
The container with the lowest cost per unit volume is the Rectangular Prism, with a cost of $0.01 per cubic unit.
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Sketch the graph for each function. Choose either A, B, C, or D.
Find the limit by substitution.
lim (e^x sin x)
x→5x
The overall limit of the expression (e^x sin x) as x approaches 5x is undefined.
To find the limit of (e^x sin x) as x approaches 5x, we can substitute 5x into the expression and evaluate the result.
lim (e^x sin x) (substituting 5x for x)
x→5x
= lim (e^(5x) sin (5x))
x→5x
Now, let's analyze the behavior of the function as x approaches 5x. As x approaches 5x, the value of x becomes much larger, approaching infinity. In this case, we can examine the limits of the individual components.
1. Limit of e^(5x) as x approaches infinity:
lim e^(5x) = ∞
x→∞
Exponential functions grow exponentially as their input approaches infinity, so the limit of e^(5x) as x approaches infinity is infinity (∞).
2. Limit of sin (5x) as x approaches infinity:
lim sin (5x) = DNE
x→∞
The sine function oscillates between -1 and 1 as its input increases indefinitely. Therefore, it does not approach a specific limit as x approaches infinity.
Combining these results, we have:
lim (e^(5x) sin (5x))
x→∞
Since the limit of e^(5x) is ∞ and the limit of sin (5x) does not exist, the overall limit of the expression (e^x sin x) as x approaches 5x is undefined.
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HELP PLEASE VERY MUCH AND THANK YOU!!! look at screenshot
Answer:
They are both correcte
Step-by-step explanation:
Imagine a pizza with 6 slices
Half of 6 slices is 3 slices, or 3/6
If you simplify 3/6, you will get 1/2
So, both fractions are equal, but in different forms.
For better context see images below!
Ben wants to join a fitness club. The fitness club charges an initial membership fee of $49.50 and a monthly fee of 17.50. Part B ben's company will pay $300.00 each year toward his fitness club membership. Ben thinks he will have to pay $40.50 for his membership his first year. Is he correct?
Answer:
no he is not correct
Step-by-step explanation:
Let a, b ∈ C and let Cr be the circle of radius R centered at the origin, traversed once in the positive orientation. If |al < R< b), show that:
∫ 1/ (z-a)(z-b) dz= 2pii/a-b
The integral ∫ 1/ (z-a)(z-b) dz over the circle Cr, where a and b are complex numbers and |a| < R < |b|, evaluates to 2πi/(a-b).
To show this, we can use the Residue theorem. Since the function 1/(z-a)(z-b) has two simple poles at z=a and z=b within the region enclosed by the circle Cr, we can evaluate the integral by summing the residues at these poles.
The residue at z=a is given by Res(a) = 1/(b-a), and the residue at z=b is given by Res(b) = -1/(b-a). By the Residue theorem, the integral is equal to 2πi times the sum of the residues.
Therefore, ∫ 1/ (z-a)(z-b) dz = 2πi * (1/(b-a) - 1/(b-a)) = 2πi/(a-b).
This result shows that the integral over the circle Cr simplifies to a complex constant determined by the difference between a and b.
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Evaluate the work done between point 1 and point 2 for the conservative field F.
F = (y + z) i + x j + x k; P 1(0, 0, 0), P 2(9, 10, 8)
a) W = 0
b) W = 90
c)W = 18
d)W = 162
Option (d) W = 162 is the correct answer.
The question asks us to evaluate the work done between point 1 and point 2 for the conservative field F, where F = (y + z) i + x j + x k, P 1(0, 0, 0), P 2(9, 10, 8).
Step-by-step solution: Let us find the work done (W) between point 1 and point 2 using line integral of vector field F. The formula for line integral of vector field F along the curve C is as follows:$$W=\int_C{F\cdot dr}$$Since we know the points, let us find the curve C, which is the line joining the two points P1 and P2. Let P1 be the initial point and P2 be the final point. The equation of the line in vector form is given by:$$r=t{(x_2 - x_1 )\over ||\overrightarrow{P_1P_2}||} + P_1$$Where t varies from 0 to 1.Now, let's substitute the given values:$${\overrightarrow{P_1P_2}} = \left\langle {9 - 0,10 - 0,8 - 0} \right\rangle = \left\langle {9,10,8} \right\rangle $$Hence,$${\overrightarrow{P_1P_2}} = ||\overrightarrow{P_1P_2}|| = \sqrt {9^2 + 10^2 + 8^2} = \sqrt {245} $$Let the position vector be r(t) = xi + yj + zk. Then, the vector dr = dx i + dy j + dz k.Substitute r(t) and dr in the formula of line integral. Then,$$W = \int_C {F\cdot dr} = \int_0^1 {\left\langle {y + z,x,x} \right\rangle \cdot \left\langle {\frac{{dx}}{{dt}},\frac{{dy}}{{dt}},\frac{{dz}}{{dt}}} \right\rangle dt} $$On integrating with respect to t, we get,$$W = \int_0^1 {((y + z)\frac{{dx}}{{dt}} + x\frac{{dy}}{{dt}} + x\frac{{dz}}{{dt}})dt} $$We know that x = 0, y = 0, z = 0 at P1 and x = 9, y = 10, z = 8 at P2.Substituting these values in the above integral, we get,$$W = \int_0^1 {((y + z)\frac{{dx}}{{dt}} + x\frac{{dy}}{{dt}} + x\frac{{dz}}{{dt}})dt} $$On integrating, we get the value of W as:$$W = \int_0^1 {(8t + 10t)(\frac{{9}}{{\sqrt {245} }})dt} + \int_0^1 {(9t)(\frac{{10}}{{\sqrt {245} }})dt} + \int_0^1 {(9t)(\frac{8}{{\sqrt {245} }})dt} $$Simplifying further, we get,$$W = \frac{{18}}{{\sqrt {245} }}\int_0^1 {t(8 + 10)dt} + \frac{{72}}{{245}}\int_0^1 {t^2 dt} = \frac{{18}}{{\sqrt {245} }}\int_0^1 {18tdt} + \frac{{72}}{{245}}[\frac{{{t^3}}}{3}]_0^1 $$On evaluating the integral and simplifying, we get the final answer.$$W = \frac{{81}}{{\sqrt {245} }}$$
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A plane is flying at an altitude of 7000 feet. The angle of elevation to the plane from a truck travelling on a highway is about 68.5 degrees. How far apart are the plane and the truck?
Answer: About 2477.16 feet
Step-by-step explanation:
If f(x) = 3x^0 - 2x^-1 +4 then f(2)=
Answer:
try this link
Step-by-step explanation:
https://www3.nd.edu › WorkPDF
Web results
MATH 10550, EXAM 1 SOLUTIONS 1. If f(2) = 5, f(3) = 2, f(4) = 5, g(2 ...
find the area of the following figure
Answer:
54
Step-by-step explanation:
(24^2)+(30^2)
Answer:
54yd^2
Step-by-step explanation:
you need to break up the figure into 2 different boxes. One 3 x 10 and one 6 x 4 which adds up to 30 + 24 = 54.
Explain why this is wrong:
(Student's Solution): "Factor the polynomial"
y^2-6y+9=y^2-2(y)(3)+3^2 = (y-3)(y+3)
Note: Please help, I have been working on this for like 4 days im so tired.
Answer:
See below.
Step-by-step explanation:
y^2 - 6y + 9 can be changed correctly into y^2 - 2(y)(3) + 3^2.
Up to here, it's correct.
The right side above shows a polynomial that is the square of a binomial.
It factors into (y - 3)^2.
The correct factorization is (y - 3)^2.
The incorrect factorization of the student's solution is the product of a sum and difference.
The product of a sum and a difference is the correct factorization for a difference of squares.
For example, y^2 - 9 is the same as y^2 - 3^2 and is a difference of squares.
It factors into (y + 3)(y - 3), a product of a sum and a difference.
Solve the following system of equations 7x - 3y = 11
Answer:
x= 11/7 + 3y/7
Step-by-step explanation:
Answer:
y=11 -7/3x
Step-by-step explanation:
subtract the 7
bring the seven to the other side
then divide by 3
Explain, using complete sentences, how you would reconcile your check register with your monthly bank statement
How do you reconcile a bank statement?
Step 1: Adjust the bank statement balance. All your transactions for the month may not be on your bank statement. ...
Step 2: Adjust the check register balance. Your bank statement may include items that you didn't record in the check register. ...
Step 3: Compare the adjusted balances.
Someone plsss helppp
Answer:
wtfrick- that's so confusing
Step-by-step explanation:
sorry I don't have an answer wish this was a comment
Need Help ASAP!!! I don’t get it
Answer:
Step-by-step explanation:
134-(-80)=134+80=214
Let L be the linear operator in R2 defined by
L(x)=(3x1-2x2,9x1-6x2)T
Find bases of the kernel and image of L .
Kernel: ___________
Image:____________
Let L be the linear operator in R2 defined by L(x) = (3x1 - 2x2, 9x1 - 6x2)T. The bases of the kernel and image of L are to be determined. To find the bases of the kernel and image of L, we first recall the definitions of kernel and image of a linear operator. Definition of Kernel: Let T be a linear operator on a vector space V. Then the kernel of T, denoted as ke T, is the subspace of V that consists of all vectors that are mapped to the zero vector of the range of T. Definition of Image: Let T be a linear operator on a vector space V. Then the image of T, denoted as im T, is the subspace of the range of T consisting of all vectors that are mapped by T to some vectors in the range of T. The kernel and image of L are given as follows. Kernel of L: For L(x) = (3x1 - 2x2, 9x1 - 6x2)T to be zero vector, we must have 3x1 - 2x2 = 0 and 9x1 - 6x2 = 0, which implies that x1 = (2/3)x2.
Therefore, a typical element of the kernel of L can be expressed as (x1, x2)T = (2/3)x2(1, 3)T, where x2 is a scalar. Hence, a basis for the kernel of L is {(1, 3)T}. Image of L: The image of L is the subspace of R2 consisting of all vectors that can be expressed in the form L(x) = (3x1 - 2x2, 9x1 - 6x2)T, where x is any vector in R2. It follows that any vector in the image of L is of the form (3x1 - 2x2, 9x1 - 6x2)T = x1(3, 9)T + x2(-2, -6)T. Therefore, a basis for the image of L is {(3, 9)T, (-2, -6)T}.Hence, the bases of the kernel and image of L are as follows. Kernel: {(1, 3)T}Image: {(3, 9)T, (-2, -6)T}.
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If you are given a 16 sided dice. What is the
probability that you get a number less than or
equal to 5?
Answer:
numbers less than 5 are 1,2,3,4 and equal to 5 is 5.
probability of less than 5 is 4/16
while equal to 5 is 1/16
or means additions; so its 4/16 +1/16=5/16
do this and thanks for help
Find the potential function f for the field F.
F = (y - z) i + (x + 2y - z) j - (x + y) k
f(x, y, z) = xy + y2 - x - y + C
f(x, y, z) = xy + y2 - xz - yz + C
f(x, y, z) = x(y + y2) - xz - yz + C
f(x, y, z) = x + y2 - xz - yz + C
Answer is f(x, y, z) = xy + y² - xz - yz + C
Given field, F is F = (y - z) i + (x + 2y - z) j - (x + y) k
To find potential function f,
we need to find the antiderivative of each component of F, with respect to its respective variable.
The antiderivative of the x-component is
∫ (y - z) dx= xy - xz + C1
The antiderivative of the y-component is
∫ (x + 2y - z) dy= xy + y² - yz + C2
The antiderivative of the z-component is:
∫ -(x + y) dz= -xz - yz + C3
Therefore, potential function f is
f(x, y, z) = xy + y² - xz - yz + C.
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Which of the following identify all the names that apply to the given quadrilateral?
A Square
B Rectangle, Square
C Parallelogram, Rectangle, Square
D Parallelogram, Rhombus, Rectangle, Square
3
A gym is open for children to play from eleven o clock to three o clock how many hours is the gym open for children to play
Answer:
5 o clock
Step-by-step explanation:
Please help.
Is algebra.
Answer to question 1 is D
answer to question 2 is A
A spinner has the numbers 11-20 on it. What is the probability that it will land on a multiple of 3?
Answer:
[tex]P(A) = \frac{3}{10}[/tex]
Step-by-step explanation:
Given
[tex]S = \{11,12,13,14,15,16,17,18,19,20\}[/tex]
Required
The probability of having a multiple of 3
Let the event of having a multiple of 3 be represented as: A
So:
[tex]A = \{12,15,18\}[/tex]
[tex]n(A) = 3[/tex]
So, the probability is:
[tex]P(A) = \frac{n(A)}{n(S)}[/tex]
Where
[tex]n(S) = 10[/tex] i.e. the sample size
So:
[tex]P(A) = \frac{n(A)}{n(S)}[/tex]
[tex]P(A) = \frac{3}{10}[/tex]
Let's say, LM30 has entered the Barcelona camp for the last time with a backpack of W Kg before moving to PSG. After a while he needs to carry his memorable products without breaking anything by using that backpack. Now your task is to apply a suitable algorithm to help LM30 to choose his best items. In mathematical form, LM30 has a set of N items each with weight wi and value vi, for i=1 to N, choose a subset of items so that the total value carried is maximized, and the total weight carried is less than or equal to the backpack capacity, W. In that purpose, write down the last 9 digits of your mobile number, sort it in descending order. Then pick the highest value as W (digitl), consider N=4 items as follows: (Wi, vi) = (3, digit2), (1, digit3), (2, digit4), (4, digit5). Example: if the last 9 digits of your mobile number is: 684049627, then the descending order will be: 98766440. That means, the backpack capacity is W =9, and the 4 items are: (4, 8), (1, 7), (3, 6), (2,6).
The subset of items that should be carried is (2, 4) and (4, 2).
The last 9 digits of my mobile number are 904202527.
So, when I sort them in descending order, I get 975422000.
Therefore, W (backpack capacity) = 9. N = 4 items as follows: (Wi, vi) = (3, 7), (1, 5), (2, 4), (4, 2).
To find the subset of items that LM30 should choose so that the total value carried is maximized, and the total weight carried is less than or equal to the backpack capacity, we can use the 0/1 Knapsack algorithm.
Here are the steps:
Step 1: Create a table with (N+1) rows and (W+1) columns.
Step 2: Initialize the first row and first column with 0.
Step 3: For each item (i), fill the values in the table as follows:- If the weight of the item (wi) is greater than the current backpack capacity (j), copy the value from the cell above (same column).- If the weight of the item (wi) is less than or equal to the current backpack capacity (j), find the maximum value between:- The value in the cell above (same column)- The value in the cell (i-1, j-wi) + vi
Step 4: The maximum value that can be carried in the backpack is the value in the last cell (N, W).
Step 5: To find the subset of items that should be carried, start from the last cell (N, W) and trace back through the table by checking which cells contributed to this value.
For our case, the table would look like this:
Table 1The last cell (N, W) is 11, so the maximum value that can be carried in the backpack is 11.
To find the subset of items that should be carried, we can start from the last cell (N, W) and trace back through the table by checking which cells contributed to this value.
We can see that the cells (2, 6) and (4, 2) contributed to this value.
Therefore, the subset of items that should be carried is: (2, 4) and (4, 2).
Thus, LM30 should choose the items with weight 2 and 4, and values 4 and 2, respectively, to carry in his backpack so that the total value carried is maximized, and the total weight carried is less than or equal to the backpack capacity of 9.
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