in order to raise enough money to buy a travelling bag, Ebuta deposits the sum of $200 in a savings account for 2 years at 5% per month interest on the initial principal. How much will be accruing to him at the end of the period​

Answer:

Step-by-step explanation:

A' = (2 + 3, 1 + 2) = (5, 3)

B' = (-1 + 3, -3 + 2) = (2, -1)

C' = (3 + 3, -3 + 2) = (6, -1)

Answer:

x=10

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

6x-7 = 26+2x+7

Combine like terms

6x-7 = 2x+33

Subtract 2x

6x-7-2x =2x+33-2x

4x-7 = 33

Add 7 to each isde

4x-7 +7 = 33+7

4x=40

Divide by 4

4x/4 = 40/4

x=10

Answer: 125

Step-by-step explanation: ∠4 and 55 are supplementary angles. This means that ∠4 and 55 add up to 180. We can use this to solve for ∠4.

180 - 55 = ∠4

125 = ∠4

So, ∠4 is equal to 125 degrees.

Would appreciate brainly <3

The relationships between the two medians and an altitude marked on

ΔABC can be used to determine the true statements.

The true statements are;

Reasons:

A median line is a line that extends from the vertex to the midpoint of the

opposite side, bisecting the opposite side.

In the figure, we have;

The median of ΔABC are; JC, and BI

The point of intersection is the point K

The altitude is a perpendicular line from a vertex to the opposite side

known as the base of the triangle.

The given altitude of ΔABC is; AH

Therefore, the statements that are true are;

A. AH is an altitude

C. JC is a median

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[tex]W = \displaystyle \int^{5}_{2} F(x) ~ dx\\\\\\= \displaystyle \int^{5}_{2} \left(12x^2 +7\right) ~dx\\\\\\= 12\displaystyle \int^{5}_{2} x^2 ~dx + \displaystyle \int^{5}_{2} 7~ dx\\\\\\=12 \left[\dfrac{x^3}3 \right]^{5}_{2} + 7\left[x\right]^{5}_{2}\\\\\\=4(5^3-2^3) + 7(5-2) = 468 + 21 = 489~ J[/tex]

we know that the colony is doubling, namely the rate of growth is 100% of whatever is existent, thus

[tex]\textit{Amount of Population Growth} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &5000\\ r=rate\to 100\%\to \frac{100}{100}\dotfill &1\\ t=\textit{elapsed time}\dotfill &t\\ \end{cases} \\\\\\ A = 5000e^{1\cdot t}\implies \boxed{A = 5000e^t}[/tex]

Answer:

B. -2x + 10 is the correct answer

Answer:

(C) -2x + 10

Step-by-step explanation:

This is going to be multiplication from the first number outside the "Bubble"

                              -2 multiplied by x = -2x ,

why ? because a negative times a positive makes a negative    

                      Next is -2 multiplied by -5 = 10

why ? because a negative times a negative = equals a positive !

now .. you add up all of the sums together to make an equation ..

                            Answer would be -2x+10

Answer:

[tex]y < 3x - 4[/tex]

Step-by-step explanation:

We can tell right away, that the line has a positive slope, since it goes upwards and to the right. To find the slope exactly, we will use rise/run. We will count the units from the first given point until we reach the next point.

So we can tell that the slope is 3/1 or just 3.

Also, since the line crosses the y-axis at -4, this will be the y-intercept.

Next, since the line is dotted, we know that the inequality sign will either be the "greater than" sign, or the "lesser than" sign. In this case, since the shaded area is below the line, we will use the "lesser than" sign.

So all together, we have y < 3x - 4.

Hope this helps you :)

Probabilities are used to determine the chances of an event.

Let P represents the event that a student passes the course, and C represents the event that a student completes the assignment

(a) The probability a student passed the course given that they completed their homework?

From the table, we have:

[tex]\mathbf{n(P\ n\ C) = 25}[/tex]

[tex]\mathbf{n(C) = 30}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P\ n\ C)}{n(C)}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{25}{30}}[/tex]

[tex]\mathbf{Pr = 0.8333}[/tex]

Express as percentage

[tex]\mathbf{Pr = 83.33\%}[/tex]

Hence, the probability a student passed the course given that they completed their homework is 83.33%

(b) The probability a student passed the course given that they didn't complete their homework

From the table, we have:

[tex]\mathbf{n(P\ n\ C'= 7}[/tex]

[tex]\mathbf{n(C') = 25}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P\ n\ C')}{n(C')}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{7}{25}}[/tex]

[tex]\mathbf{Pr = 0.28}[/tex]

Express as percentage

[tex]\mathbf{Pr = 28\%}[/tex]

Hence, the probability a student passed the course given that they didn't complete their homework is 28%

(c) The probability a student completed their homework given that passed the course?

From the table, we have:

[tex]\mathbf{n(P\ n\ C) = 25}[/tex]

[tex]\mathbf{n(P) = 32}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P\ n\ C)}{n(P)}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{25}{32}}[/tex]

[tex]\mathbf{Pr = 0.78125}[/tex]

Express as percentage

[tex]\mathbf{Pr = 78.125\%}[/tex]

Approximate

[tex]\mathbf{Pr = 78.13\%}[/tex]

Hence, the probability a student completed their homework given that they passed the course is 78.13%

(d) The probability a student didn't complete their homework given that they didn't pass the course

From the table, we have:

[tex]\mathbf{n(P'\ n\ C'= 18}[/tex]

[tex]\mathbf{n(P) = 23}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P'\ n\ C')}{n(P')}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{18}{23}}[/tex]

[tex]\mathbf{Pr = 0.7826}[/tex]

Express as percentage

[tex]\mathbf{Pr = 78.26\%}[/tex]

Hence, the probability a student didn't complete their homework given that they didn't pass the course is 78.26%

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Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

[tex]D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}[/tex]

The odd multiples of 9, [tex]m[/tex], in the range [tex]2\le m \le 82[/tex] form the set

[tex]\{9,27,45,63,81\}[/tex]

Each member of the set is a term of the arithmetic progression

[tex]U_n=18n+9[/tex]

where the values of [tex]n[/tex] range from 0 to 4, or [tex]0\le n\le 4[/tex]

Putting these facts together, we get the result

[tex]D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}[/tex]

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Answer:

Average County Tax Rate

0.520%

(Mercer County)

Property Taxes

$121

(Annual)

Step-by-step explanation: I'm assuming this is the answer, if you can please can you mark me Brainliest.

Answer: 6.087 tablespoons. or rounded to nearest whole, 6

Step-by-step explanation:

I just know

The second option has a lower amount of interest paid.

In order to determine the loan option that minimizes loan payment, the future value of both loan options has to be determined.

FV = P (1 + r)^nm

FV = Future value  

P = Present value  

R = interest rate  

m = number of compounding

N = number of years  

First loan option

65000( 1 + 0.063/12)^300 = 312,707.21

Second loan option

65000( 1 + 0.048/12)^240 = 169,435.51

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Answer:

24

Step-by-step explanation:

Step-by-step explanation:

24 is 3×8

so, when

3c = 5c-2

then

8×3c = 24c = 8×(5c-2) = 40c - 16

Answer:

The answer is 7 she Can Buy 7 packages of cookies.

Step-by-step explanation:

1. 15-5.50=9.50

2.9.50-7.75=1.75

3. 1.75-0.25*7=0

She wouldn't have any money left over to buy it

Answer:

μX = the mean of X

σX = the standard deviation of X

If you draw random samples of size n, then as n increases, the random samples  

¯¯¯¯¯

X

which consists of sample means, tend to be normally distributed.

¯¯¯¯¯

X

~ N (

μ

x

,

σ

x

√

n

)

The central limit theorem for sample means says that if you keep drawing larger and larger samples (such as rolling one, two, five, and finally, ten dice) and calculating their means, the sample means form their own normal distribution (the sampling distribution). The normal distribution has the same mean as the original distribution and a variance that equals the original variance divided by, the sample size. The variable n is the number of values that are averaged together, not the number of times the experiment is done.

To put it more formally, if you draw random samples of size n, the distribution of the random variable

¯¯¯¯¯

X

, which consists of sample means, is called the sampling distribution of the mean. The sampling distribution of the mean approaches a normal distribution as the sample size n increases.

The random variable

¯¯¯¯¯

X

has a different z-score associated with it from that of the random variable X. The mean

¯¯¯

x

is the value of

¯¯¯¯¯

X

in one sample.

z =

¯¯¯

x

−

μ

x

σ

x

√

n

μ

x

=

μ

¯¯¯

x

 (mean of X = mean of

¯¯¯¯¯

X

. )

σ

¯¯¯

x

=

σ

x

√

n

= standard deviation of

¯¯¯¯¯

X

and is called the standard error of the mean.

Step-by-step explanation:

sorry if its hard/ confusing

Answer:

5+5=10

but if you mean

5+-5 then that = 0

Step-by-step explanation:

The mean score for all 23 students is 77.17.

Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number.

The first step is to determine the total scores of the 22 students.

Total scores = mean score x number of students

22 x 76.5 = 1683

The second step is to add the score of the student that took the exam late tot he total scores.

New total score = 1683 + 92 = 1775

The third step is to determine the new mean score.

new mean score = new total score / total number of students

1775 / 23 = 77.17

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Answer:

3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Evan has 43 and Brayden has 42. Reid has 76 and Bryce has 23. Which pair of boys has more? How much more do they have?

Reid and Rryce have more. If you add 43 and 42 you get 85 and when you add 76 and 23 you get 99. So now subtract 99 and 23 which is 76.

The rate is a fraction that compares the values of two quantities. The expected answers to the questions are given below:

1. Given that 3 cakes takes 6 hours to bake, then:

1 cake = [tex]\frac{6}{3}[/tex]

           = 2 hours

So that;

the number of cake to be baked in 12 hours = [tex]\frac{12 hours}{2 hours}[/tex]

                                    = 6

The number of cake to be baked in 12 hours is 6.

2. Ava's rate of pay = [tex]\frac{15}{2}[/tex]

                                 = $7.5 pr hour

Thus Ava's rate of pay is $7.5 per hour.

3. It took 5 hours to mow 6 yards. Thus;

To mow 1 yard = [tex]\frac{5}{6}[/tex] hours

The number of yards to be mowed in 20 hours = 20 ÷ [tex]\frac{5}{6}[/tex]

                                                = 20 x [tex]\frac{6}{5}[/tex]

                                                = 24

The number of yards to be mowed in 20 hours is 24.

4. Given that 10 bags of rice cost $12, then;

1 bag = [tex]\frac{12}{10}[/tex]

         = 1.2

1 bag = $1.2

The cost of a bag of rice is $1.2.

5. Rate = 30 miles per gallon

The number of gallons required = [tex]\frac{360}{30}[/tex]

                                        = 12

Thus 12 gallons would be required by the car to travel 360 miles.

6. Rate = [tex]\frac{75}{3}[/tex]

            = 25

Rate = 25 words per minute

The typing speed is 25 words per minute.

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Answer:

976

SA=2(S1)+2(S2)+S3

S1=14*24/2

S1=168

S2=25*10

S2=250

S3=14*10

S3=140

SA=2(168)+2(250)+140

SA=976 cm

Answer: 18

Step-by-step explanation: 93 - (46 + 29) = 18

Answer:

The population was 3040 people in 8 years.

Step-by-step explanation:

find unit rate;

3800/10 = 380

380 x 8 = 3040

Answer:

$1,875.01

Step-by-step explanation:

Cash in Bank :

DEBIT(+) :

+ $1,200.00

+ $387.89

+ $250.00

+ $437.12

CREDIT (-) :

- $400.00

Capital:

DEBIT (-) :

- $400.00

CREDIT (+) :

+ $1,200.00

+ $387.89

+ $250

Accounts Payable :

DEBIT (-):

0

CREDIT (+):

+ $437.12