In medieval warfare, one of the greatest technological advancement was the trebuchet. The trebuchet was used to sling rocks into castles. You are asked to study the motion of such a projectile for a group of local enthusiast planning a medieval war reenactment. Unfortunately an actual trebuchet had not been built yet, so you decide to first look at the motion of a thrown ball as a model of rocks thrown by a trebuchet. Specifically, you are interested in how the horizontal and the vertical components of the velocity for a thrown object change with time. 1. Make a large rough sketch of the trajectory of the ball after it has been thrown. Draw the ball in at least five different positions; two when the ball is going up, two when it is going down, and one at its maximum height. Label the horizontal and vertical axes of your coordinate system.
2. On the sketch, draw and label the expected acceleration vectors of the ball (relative sizes and directions) for the five different positions. Decompose each acceleration vector into its vertical and horizontal components.
3. On the sketch, draw and label the velocity vectors of the object at the same positions you chose to draw your acceleration vectors. Decomposes each velocity vector into its vertical and horizontal components. Check to see that the changes in the velocity vector are consistent with the acceleration vectors.
4. Looking at the sketch, how does someone expect the ball's horizontal acceleration to change with time? Could you give a possible equation giving the ball's horizontal acceleration as a function of time? Graph this equation. If there are constants in your equation, what kinematic quantities do they represent? How would someone determine these constants from the graph?
5. Looking at the sketch, how does someone expect the ball's horizontal velocity to change with time? Is it consistent with the statements about the ball's acceleration from the previous question? Could you give a possible equation for the ball's horizontal velocity as a function of time? Graph this equation. If there are constants in the equation, what kinematic quantities do they represent? How would someone determine these constants from the graph?
6. Could you give a possible equation for the ball's horizontal position as a function of time? Graph this equation. If there are constants in the equation, what kinematic quantities do they represent? How would someone determine these constants from the graph? Are any of these constants related to the equations for horizontal velocity or acceleration?
7. Repeat questions 4-6 for the vertical component of the acceleration, velocity, and position. How are the constants for the acceleration, velocity and position equations related?

Answer:

Mass of Exoplanet =  0.58 kg

Explanation:

First, we will calculate the speed of the forest moon:

[tex]speed = v = \frac{Circumference}{time}\\[/tex]

circumference = 2πr = 2π(14441566 m) = 90739035.3 m

time = 6 days 10 hr = (6 days)(24 h/1 day)(3600 s/1 h) + (10 h)(3600 s/1 h)

time = 554400 s

Therefore,

[tex]v = \frac{90739035.3\ m}{554400\ s}\\\\v = 163.67\ m/s[/tex]

We know that the centripetal force on forest moon will be equal to the gravitational force given by Newton's Gravitational Law, as follows:

[tex]Centripetal\ Force = Gravitational\ Force\\\frac{m_{moon}v^2}{r} = \frac{Gm_{moon}m_{exoplanet}}{r^2}\\\\m_{exoplanet} = \frac{v^2r}{G}\\\\m_{exoplanet} = \frac{(163.67\ m/s)^2(14441566)}{6.67\ x\ 10^{-11}\ N.m^2/kg^2}[/tex]

Mass of Exoplanet =  0.58 kg

Answer:

According to the law of magnetism, "Like poles repel, unlike poles attract" If the bar magnet on the left is broken, both halves will consequently have two poles, the north and south poles. If the right sides of both halves are of the south pole, the bar magnet on the right is of the north pole

Answer:

lightning is a sudden electrostatic discharge during an electrical storm. This discharge allows charged regions in the atmosphere to temporarily equalize themselves, when they strike an object on the ground.

Answer:

You can see lightning before u hear it.

light travels faster than soun

Answer:

0.39 m/s²

Explanation:

From the question,

a = v²/r.................... Equation 1

Where v = velocity, r = radius.

Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.

Substitute thses values into equation 1

a = 9.83²/249.94

a = 96.63/249.94

a = 0.39 m/s²

Hence the  acceleration is 0.39 m/s²

The value of the centripetal acceleration is equal to 4g.

Data Given;

Using formula of centripetal acceleration,

[tex]a_c = \frac{v^2}{r}\\ [/tex]

v = (222 * 1.467) ft/s

v = 325.6 ft/s

substitute the values into the formula

[tex]a_c = v^2/r\\ a_c = \frac{325.6^2}{820}\\ a_c = 129.28 ft/s^2\\ [/tex]

But the value of g = 32.174 ft/s62

This makes a = 4g.

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Answer:

The velocity would decrease

Explanation:

Let

[tex]m_1[/tex] = Mass of car

[tex]m_2[/tex] = Mass of trash can

[tex]u_1[/tex] = Initial velocity of car = 10 m/s

[tex]u_2[/tex] = Initial velocity of trash can = 0

v = Velocity of combined mass

From the question the momentum balance of the system will be

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{10m_1}{m_1+m_2}[/tex]

The velocity would decrease as now the mass of the car and trash will both be moving as one. The mass would increase resulting in a lower velocity of the combined mass.

Answer:

3m/s up

Explanation:

Answer:

the power of the two light bulbs is 23.4 W

Explanation:

Given;

the resistance of the two identical light bulbs in series, R₁ and R₂ = 6.77 ohms and 6.77 ohms respectively

battery voltage , V = 17.8 V

The equivalent resistance of the two light bulbs, R = R₁ + R₂

R = 6.77 + 6.77

R = 13.54 ohms

The power of the two light bulbs is calculated as follows;

[tex]P = IV = (\frac{V}{R} )V = \frac{V^2}{R} = \frac{17.8^2}{13.54} = 23.4 \ W[/tex]

Therefore, the power of the two light bulbs is 23.4 W

Answer:

first braliest me

Explanation:

Answer:

The discrimination which is based on affirmative action, inherent requirement of a particular job, productivity and compulsory discrimination by law are termed as fair discrimination.

hope it helps :)

Explanation:

Answer:

grid or metal sheets or metal foams

Explanation:

Electric and magnetic fields are generated in electrical circuits that often cause interference in the measurements made.

To avoid these interferences, shields are generally used for the electric fields, Farday boxes are used, which are metal grids connected to earth.

For the magnetic field there is also a grid or metal sheets or metal foams,

It should be noted that the gaps in the screening must be smaller than the wavelength of the radiation to be screened.

Answer:

From the graph, it looks like 40 g

Explanation:

See where the NaCl line crosses the red vertical line = 40 gm

Answer:

Fs = -kx is the formula

Explanation:

Fs = spring force

k = spring constant

x = spring compression

Answer:

Equation of Hooks law

F=kx

Where,

F=Force applied

k= spring constant

x=extension of spring

Answer:

yes

Explanation:

gl m8

Answer:A

Explanation:I TOOK THE Test

When scientists calculate the trajectory a satellite takes on its way to

study a planet, they use C. Speed, Velocity, and acceleration.

A trajectory, often known as a flight path, is the route taken by an object moving under the influence of gravity. Typically, the phrase is applied when referring to projectiles or satellites.  A parabola curve is usually a decent approximation of the trajectory form when an object is propelled for in a short distance.

When scientists calculate the trajectory a satellite takes on its way to

study a planet they take the speed, velocity, and acceleration into consideration.

The formula for calculating the trajectory can be expressed as:

[tex]\mathbf{y = h + xtan (\alpha) - \dfrac{gx^2 }{2V_o^2cos^2 (\alpha)}}[/tex]

where;

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Answer:

With a zero signal applied to the Base of the transistor it turns “OFF” acting like an open switch and zero collector current flows. With a positive signal applied to the Base of the transistor it turns “ON” acting like a closed switch and maximum circuit current flows through the device.

Explanation:

please give me brainlist and follow

A transistor is a semiconductor device that can function as an electronic switch, controlling the flow of current between its two main terminals.

It has three terminals: the emitter, the base, and the collector. In the context of a common bipolar junction transistor (BJT), here's how it behaves as a switch:

BJT Basics:

A BJT comes in two types: NPN (Negative-Positive-Negative) and PNP (Positive-Negative-Positive). For simplicity, let's consider the NPN type. In an NPN transistor, the emitter is made up of an N-type semiconductor, the base is a P-type semiconductor, and the collector is an N-type semiconductor.

Operating Regions:

A transistor has three operating regions: cutoff, active, and saturation.

Cutoff Region: When no current flows from the collector to the emitter. The transistor is effectively "off" in this state.

Active Region: When the transistor is operating as an amplifier, allowing a controlled current flow between the collector and emitter based on the current flowing into the base terminal.

Saturation Region: When the transistor is fully turned on, and maximum current flows from the collector to the emitter. The transistor is effectively "on" in this state.

Switching Operation:

To use a transistor as a switch, we configure it to work in either the cutoff or saturation region. The active region is avoided because it allows variable current flow, which is not desired for a switch.

a. NPN Transistor as a Switch:

To turn the NPN transistor "ON" (saturation), a small current is passed from the base to the emitter (IB). This current allows a larger current to flow from the collector to the emitter (IC).

To turn the NPN transistor "OFF" (cutoff), no current is allowed to flow into the base terminal (IB = 0). Consequently, no significant current flows from the collector to the emitter, and the transistor behaves as an open switch.

b. PNP Transistor as a Switch:

The PNP transistor works similarly but in the opposite direction. To turn it "ON" (saturation), a small current flows from the emitter to the base (IB). This enables a larger current to flow from the emitter to the collector (IC).

To turn the PNP transistor "OFF" (cutoff), the current flowing into the emitter is restricted (IB = 0), causing the transistor to behave as an open switch.

Applications:

Transistors used as switches find applications in digital logic circuits, microcontrollers, and other electronic devices. They play a crucial role in controlling the flow of current through various components, enabling or disabling functionalities as needed.

It's essential to note that when using transistors as switches, care should be taken to ensure that the base current (IB) and collector current (IC) remain within safe operating limits to prevent damage to the transistor and the circuit. Proper resistors or other current-limiting mechanisms are often employed to control these currents.

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La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.

Answer:

6.77 minutes

Explanation:

172 degree - 78 degree = (185 degree - 78 degree)e−2 k

=> 94 = 107

e−2 k => 94 ÷ 107

k => ln (94÷107) / 2

147 - 78 = (185 - 78)e ^[ln (94÷107) / 2]

=> 69 = 107 e^ [ln (94÷107) / 2]

e^[ln (94÷107) / 2] =69 ÷ 107

=> t = [ln (69 ÷ 107)] ÷ [ln (94÷107) / 2]

t=> -0.4387 ÷ -0.0648

t => 6.77 minutes.

Therefore, the final answer to the question is 6.77 minutes.

Answer:

F = 3750 N

Explanation:

Given that,

Pressure, P = 150 Pa

Area, a = 25m²

We need to find the force applied. We know that, pressure is equal to the force acting per unit area. It can be given by :

[tex]P=\dfrac{F}{A}\\\\F=P\times A\\\\F=150\ Pa\times 25\ m^2\\\\F=3750\ N[/tex]

So, the required force is 3750 N.

Answer:

the canoe moved 1.2234 m in the water

Explanation:

Given that;

A man whose mass = 69 kg

A woman whose mass = 52 kg

at opposite ends of a canoe 5 m long, whose mass is 20 kg

now let;

x1 = position of the man

x2 = position of canoe

x3 = position of the woman

Now,

Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3

= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20

= (0 + 260 + 50 ) / ( 141 )

= 310 / 141

= 2.19858 m

Centre of mass is 2.19858 m

Now, New center of mass will be;

52 × 2.5 / ( 69 + 52 + 20 )

= 130 / 141

= 0.9219858 m  { away from the man }

To get how far, the canoe moved;

⇒ 2.5 + 0.9219858 - 2.19858

= 1.2234 m

Therefore, the canoe moved 1.2234 m in the water

The canoe move in the water will be 1.2234 m. The canoe move depending on the center of mass of the bodies.

The center of mass of an item or set of objects is a place specified relative to it. It's the average location of all the system's components, weighted by their mass.

The centroid is the location of the center of mass for simple rigid objects with homogeneous density. The center of mass of a uniform disc shape, for example, would be at its center.

The given data in the problem is;

m₁ is the mass of man = 69 kg

m₂ is the mass of woman whose= 52 kg

m₃ is the mass  of  canoe =  20 kg

L is the length of canoe = 5 m

x₁ is the position of the man

x₂ is the position of the canoe

x₃ is the position of the woman

The center of mass will be;

[tex]\rm COM= \frac{[m_1x_1 + m_2x_2 + m_3x_3]}{ m1 + m2 + m3} \\\\ \rm COM= \frac{[69 \times 0 +52 \times 5 + 20 \times 2.5]}{ 69+ 52 + 20} \\\\ \rm COM= (0 + 260 + 50 ) / ( 141 )\\\\ \rm COM = 310 / 141 \\\\ \rm COM = 2.19858 m[/tex]

The new center of mass is;

[tex]\rm COM= \frac{52 \times 2.5 }{69+52+20} \\\\ \rm COM=\frac{130}{141} \\\\ \rm COM= 0.9219 m[/tex]

The distance to find how the canoe moved will be found by;

[tex]\rm x= 2.5+0.9219-2.1985 = 1.2234[/tex]

Hence the canoe move in the water will be 1.2234 m.

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Answer:

Astronomers can detect them by watching for their effects on nearby stars and gas. ... The star clusters then sink to the center of the galaxy, where the intermediate-mass black holes merge to form a supermassive black hole.

Answer:

.66354 T

Explanation:

Use F=ILB

B =  [tex]\frac{F}{IL}[/tex]

B = Magnetic field

F= force due to magnetic

I= current

L= length in meters

F = mg

Final formula:

B=[tex]\frac{mg}{IL}[/tex]

B=[tex]\frac{(.13)(9.8)}{(6)(.32)}[/tex]

B= .66354

ayo btw ion know how to find direction, my b G

The minimum magnetic field required to move the wire is 66354 T.

The direction of magnetic field is normal to the page outwards.

The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

Given parameter:

Current passing through the wire, I = 6.0 A.

Length of the wire ,L = 32 cm = 0.32 m.

Mass of the wire, m = 0.13 Kg.

Acceleration due to the gravity, g = 9.8 m/s².

We know that, force acting on a current caring wire due to magnetic field is,  F=ILB

Where,

B = Required magnetic field.

To find the minimum magnetic field that is required to move the

wire, force acting on a current caring wire due to magnetic field is equal to weight the wire, that is, mg.

Hence, we can write,

mg = ILB

⇒ B = mg/IL

= (0.13 * 9.8)/(6.0 * 0.32)

=0.66354 Tesla

Hence, the minimum magnetic field is 0.66354 Tesla.

b) By using Maxwell's right hand thumb Rule along current flow, the direction of magnetic field is  determined as normal to the page pointing outwards.

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Answer:

Gravity

Explanation:

Pretty self-explanatory

We are kept on earth because of gravity and it keeps planets orbiting around the sun.

Answer:

Hi how are you doing today Jasmine

Answer:

16kg*m/s

Explanation:

a)p=m*v=2*4=8kg-m/s

b)p=m*v=1*8=8kg-m/s

add them

=16kg-m/s

Answer:

Forced vibrations, such as those between a tuning fork and a large cabinet surface, resulting in a much lower sound than was produced by the original vibrating body.

Explanation:

Just took the test, this is correct. :)

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2[/tex]

Let d be the breaking distance. It can be calculated using third equation of motion as :

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m[/tex]

So, the required distance covered by the car is 44.64 m.