If y varies inversely as x and y=3 when x=4, then y=12 when x=15
Please select the best answer from the choices provided
T
F

The nature of roots of quadratic equation x² = -2x + 1 is real and distinct.

The standard form of a quadratic equation is:

ax² + bx + c = 0

The discriminant is defined as:

D = b² - 4ac

Using  the value of discriminant, we can determine the nature of roots of a quadratic equation.

If:

D > 0, the quadratic equation has two distinct real roots or the roots are real and distinct.

D = 0, the quadratic equation has 1 real equal roots or the roots are unique

D < 0, the quadratic equation has complex conjugate roots or the roots are imaginary.

In this case, the quadratic equation is:

x² = -2x + 1

transform it into the standard form:

x² + 2x - 1 = 0

Calculate the discriminant:

D = 2²  - 4 (-1) = 8

Since D > 0, the roots are two distinct real roots.

Your question is incomplete, but most probably your question was:

What is the nature of roots of quadratic equation x² = -2x + 1?

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If his growth spurt continued at the same rate Andrew will grow 26/7 inches per month during that growth spurt.

To calculate someone's age, you would subtract their birth year from the current year. For example, if someone was born in 1995 and it is now 2020, their age would be calculated as 2020 - 1995 = 25 years old.

If you have a birthdate, you can use a date calculator to find the exact age in years, months and days.

It's also important to note that, if the person's birthday hasn't occurred yet in the current year, you would subtract the birth year from the current year minus one.

We can start by converting the mixed number 4 1/3 to an improper fraction by multiplying the whole number by the denominator and adding the numerator: 4 x 3 + 1 / 3 = 13/3

To find out how much Andrew grew per month, we need to divide the total growth by the number of months.

13/3 inches / 3 1/2 months = (13/3) / (7/2) = (13/3) x (2/7) = 26/7 inches/month.

So, Andrew grew 26/7 inches per month during that growth spurt.

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To solve complex fractions there are two methods -

1 - Divide the numerator by the denominator by multiplying the numerator by the reciprocal of the denominator and then simplify further if necessary.

2 - Multiply the numerator and denominator of the overall complex fractions and then simplify further if necessary.

What is a complex fraction?

A rational expression with a fraction in the numerator, denominator, or both is referred to as a complex fraction.

There are two ways to solve a complex fraction -

Method 1 : Take an example - (1/3-1/4)/(1/8+1/2)

Step 1 - If necessary, combine the denominator and numerator into a single fraction.

Add the numerator -

=1/3-1/4

=(4-3)/12

=1/12

Add the denominator -

=1/8+1/2

=(1+4)/8

=5/8

Combine back to form a complex fraction -

=(1/12)/(5/8)

Step 2: Multiply the numerator by the denominator's reciprocal, then divide the result by the denominator.

Step 3: Simplify the rational expression if necessary.

=(1/12)×(8/5)

=8/60

=2/15

Method 2: Take an example - [(2x+1)/(x^2-25)]/[(4x^2-1)/(x-5)]

Step 1 - Divide the LCD of the smaller fractions by the numerator and denominator of the total complex fractions.

(x^2-25)=(x+5)(x-5)

The denominator of the denominator’s fraction  has the following factor -

(x-5)

Using the highest exponent and combining all the other factors, we arrive at the LCD shown below for all the little fractions -

(x+5)(x-5)

By multiplying the LCD by the numerator and denominator -

=[{(2x+1)/(x+5)(x-5)}×(x+5)(x-5)]/[{(2x+1)(2x-1)/(x-5)}×(x+5)(x-5)]

=(2x+1)/(2x+1)(2x-1)(x+5)

Step 2 - Simplify the rational expression if necessary.

=(2x+1)/(2x+1)(2x-1)(x+5)

=1/(2x-1)(x+5)

Therefore, there are two methods to solve complex fractions.

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The equivalent form   [tex][latex] {{8}^{\frac{1}{3}}}[/latex][/tex]can be determined where the origin of the numerator of 1.

When rewriting a radical with a fractional exponent, the numerator is the power to which the radicand is increased, and the denominator is the root or index.

The link between [tex][latex] \sqrt[n]{{{a}^{m}}}[/latex]and [latex] {{a}^{\frac{m}{n}}}[/latex][/tex]also applies to rational exponents with a numerator of 1. For instance, the radical [tex][latex] \sqrt[3]{8}[/latex][/tex]

can also be expressed as [tex][latex] \sqrt[3]{{{8}^{1}}}[/latex][/tex].

Since any number retains its value when raised to the first power, [/latex]. Now that you have the equivalent form of [tex][latex] {{8}^{\frac{1}{3}}}[/latex][/tex], you can determine where the origin of the numerator 1.

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The number √2 is called an irrational number because the value of √2 = 1.41421356... and the the value is non terminating and non repeating .

What are Irrational Numbers ?

The Numbers whose vales are Non Repeating and Non Terminating are called as Irrational Numbers ,

also the numbers that cannot be expressed on the form of [tex]\frac{p}{q}[/tex] are called as Irrational Numbers .

the number is given as √2 ;

we know that the values of √2 is = 1.41421356... ,

we see that the the value is non terminating and the numbers after decimal point are non repeating ,

Therefore  , the number √2 is an irrational number .

The given question is incomplete , the complete question is

Why the number √2 is called a Irrational Number ?

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â' in mathematics refers to the hexadecimal representation of the number 10.

In machine code and assembly programming languages, hexadecimal is widely utilised. It is frequently used to refer to memory addresses. It can be used to represent numbers kept in a CPU's registers or in main memory, as well as during the debugging phase of designing a computer programme.

Although there are six more digits to consider, counting in hex is very similar to counting in decimal. When a digit position exceeds "F," you roll that place over to "0" and increase the digit to the left by 1. And once you've reached 1F16, move on to 2016 and keep churning the right-most

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You can ride in many places, so be sure to look for hazards that could cause injury or other risks while bicycling.

The number of miles you can cycle in a single day is unlimited. It depends on your level of fitness, your exercise regimen, and the distance you cycle. Starting out, 10 kilometres per day is OK.

If you're an experienced cyclist who can pedal 25–30 miles every day, 45 miles is a realistic limit.  You can ride a certain bike trail. By riding a bike to work, you can get in shape. If you've never rode a bike before, start out slowly. If you ride your bike for at least three miles every day, you might be able to travel further.

You may be able to make the most of your speed sensor’s accuracy, depending on how accurate it is. You need to know exactly how much effort you put in during your rides.

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Option C is correct. The coordinates of ADE'F' after dilation by a scale factor of 4 are A'(8,0), D'(8,0), E'(12,12), and F'(16,4).

Using one or more numbers, or coordinates, a coordinate system in geometry establishes a unique way to locate points or other geometrical objects on a manifold, such Euclidean space. The order of the coordinates is important, and they can sometimes be distinguished by their place in an ordered tuple or by a letter, such as "the x-coordinate." In simple mathematics, the coordinates are assumed to be real numbers, while they could also be complex numbers or components of a more abstract structure, such a commutative ring. Analytic geometry is based on the usage of coordinate systems, which make it possible to convert geometry-related problems into numerical problems and vice versa.

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The equation of line passes through the point (2, 3) will be;

⇒ y = 1/2x + 2

And, Graph of this equation of line is shown in figure.

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

The point on the line are (2, 3).

And, The perpendicular line is,

⇒ y - 4 = - 2 (x + 3)

⇒ y -  4 = - 2x - 6

⇒ y = - 2x - 2

Now,

Since, The equation of line passes through the point (2, 3).

So, We need to find the slope of the line.

Since, The product of slope of the perpendicular line is - 1.

Hence, Slope of the given perpendicular line is,

⇒ y = - 2x - 2

m = dy/dx = - 2

m = - 2

So, The slope of line is,

⇒ m₂ = - 1/m

         = 1/2

Thus, The equation of line with slope 1/2 is,

⇒ y - 3 = 1/2 (x - 2)

⇒ y - 3 = 1/2 (x - 2)

⇒ y - 3 = 1/2x - 1

⇒ y = 1/2x - 1 + 3

⇒ y = 1/2x + 2

Therefore, The equation of line passes through the point (2, 3) will be;

⇒ y = 1/2x + 2

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Equation that will determine the amount of last year’s budget

Two or more expressions with an Equal sign is called as Equation.

Given that a school plans to spend twice the amount it did last year on its winter dance , less the cost of the disco ball which was $150 since they have it from last year

A total of $1,500 is being spent this year.

We need to find the equation which determine the amount of last year’s budget

2a-150=1500

When a is the amount of last year’s budget

Hence, 2a-150=1500 is the equation that will determine the amount of last year’s budget

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On solving the provided question, we can say that stabilizing selection type of selection does this demonstrate is shown by frequency distribution.

In order to make the information easier to understand, frequencies are organized into frequency distributions, which are visual displays. The frequencies displayed in a frequency distribution can be absolute or relative, like ratios or percentages. Both a graph and a table of frequencies can be used to represent a frequency distribution. Both the exact number of observations and the proportion of observations falling within each range can be displayed in a frequency distribution. A relative frequency distribution is the name given to the distribution in the latter scenario. The frequency of an observation is the frequency with which it appears in the data. The frequency of the number 9 in the following list of numbers, for instance, is 5. (because it occurs 5 times). 1, 2, 3, 4, 6, 9, 9, 8, 5, 1, 1, 9,

stabilizing selection type of selection does this demonstrate is shown by frequency distribution.

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Complete question: The frequency distribution of birthweights in human infants is bell shaped with most birthweights in the middle of the range of birthweights. What type of selection does this exemplify?

Answer:

2(3n^2-4) and 6n^2-8

Step-by-step explanation:

There are two different answers but try at least both of them.

The score of Larry is 32 points.

Two algebraic expressions having same value and symbol '=' in between are called as an equation.

Given:

Ervin scores half as many points in a game as Larry.

If Larry scored x points,

then the points of Ervin are x/2 points.

Here, x = 16,

So,

Ervin's points = Larry's points

The equation is,

16 = x/2

x = 16(2)

x = 32 points

Therefore, 32 points are the score of Larry.

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To find the unknown part of a right triangle, you can use the Pythagorean theorem or the trigonometric ratios.

A right triangle is a triangle that has one angle measuring exactly 90 degrees, this angle is called the right angle.

To find the unknown part of a right triangle, you can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two shorter sides (legs) is equal to the square of the length of the longest side (the hypotenuse). The formula is:

a² + b² = c²

Where c is the length of the hypotenuse and a and b are the lengths of the legs.

You can use this theorem to find the length of a missing side, if you know the length of the other two sides. For example, if you know the lengths of the two legs (a and b) and you need to find the length of the hypotenuse (c), you can use the formula:

c = √(a² + b²)

Alternatively, if you know the length of the hypotenuse (c) and one leg (a), you can use the formula to find the length of the other leg (b):

b = √(c² - a²)

Another way to find the unknown part of a right triangle is the use of trigonometric ratios. As you know, in a right triangle, there are three main ratios: sine, cosine, and tangent. These ratios are defined as follows:

Sin(A) = a/c

Cos(A) = b/c

Tan(A) = a/b

Where A is one of the acute angles of the triangle, and a,b,c are the sides of the triangle. By using the known side and the known angle you could find the unknown side.

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The domain and range of the functions are Domain: (-∞,∞),{x|x∈R} and Range: [4,∞),{y|y≥4}.

The vertex form of a quadratic function is f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola. The coefficient a determines whether the graph of a quadratic function will open upwards or downwards.

From the graph, vertex is (h, k)=(0, 4) and (x, y)=(2, 0)

Here, y= a(x - h)² + k

0=a(2-0)+4

-4=2a

a=2

Substitute, a=2 and (h, k)=(0, 4) in y= a(x - h)² + k, we get

y=2(x-0)²+4

y=2x²+4

So, f(x)=2x²+4

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain: (-∞,∞),{x|x∈R}

Range: [4,∞),{y|y≥4}

Now,

(a) f(-3)= 2(-3)²+4=18

(b) f(2)= 2(2)²+4=12

(c) f(0)= 2(0)²+4=4

(d) f(3)= 2(3)²+4=18

Therefore, the domain and range of the functions are Domain: (-∞,∞),{x|x∈R} and Range: [4,∞),{y|y≥4}.

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Yes, it is a perfect square trinomial.

Perfect squares are numbers that are the product of a number multiplied by itself. Examples of perfect squares include 4 (2 x 2), 9 (3 x 3), 16 (4 x 4), 25 (5 x 5), 36 (6 x 6), 49 (7 x 7), and 64 (8 x 8). Perfect squares are also referred to as "square numbers" or "whole-number squares."

The equation X² + 10X + 25 can be factored into (X + 5)²,

which is a perfect square trinomial. In general, a perfect square trinomial is any polynomial of the form A² + 2AB + B² where A and B are constants or variables.

This is because such a polynomial can be factored into (A + B)².

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well, what's 230% of $480?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{230\% of 480}}{\left( \cfrac{230}{100} \right)480}\implies \text{\LARGE 1104}[/tex]

According to the Angle-Angle-Angle (AAA) criterion, "if in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio (or proportion), and hence the two triangles are identical."

Proof:

Consider two triangles ABC and DEF, such that ∠A = ∠D, ∠B = ∠E, and ∠C = ∠F

Now, cut DP= AB and DQ= AC and join PQ. Hence, we can say that a triangle ABC is congruent to the triangle DPQ.

(i.e) ∆ ABC ≅ ∆ DPQ, which gives ∠B = ∠P = ∠E, and also, the line PQ is parallel to EF.

Therefore, by using the basic proportionality theorem, we can write

DP/PE = DQ/QF.

(i.e) AB/DE = AC/DF. …(1)

Similarly,

AB/DE = BC/EF …(2)

From (1) and (2), we can write:

AB/DE = BC/EF = AC/DF.

Therefore, the two triangles ABC and DEF are similar.

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The total number of pizzas consumed by the 10 members of the club is 2.5 and 3.5 pizzas remain, as Mr. Cam bought 6 pizzas and each of the 10 members ate 1/4 of a pizza.

Mr. Cam bought 6 pizzas for the club and each of the 10 members ate 1/4 of the pizza. To find out how many pizzas were eaten, we can use the formula:

Number of members x Pizza per member = Total Pizzas Consumed

In this case, we can substitute the given values in the formula:

10 members x 1/4 pizza/member = 10/4 = 2.5 pizzas

This means 2.5 pizzas were consumed by the members. Since Mr. Cam bought 6 pizzas and 2.5 pizzas were eaten, the total number of pizzas remaining is 6 - 2.5 = 3.5 pizzas.

This equation works because it uses the concept of the unitary method, where we find the total number of pizzas consumed by multiplying the number of members by the number of pizzas each member ate. This way we can find the total amount of pizza consumed.

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By using scale factor formula we can evaluate the measure of side EF.

When a triangle is dilated by scale factors.The base and height change by the scale factor s while the area changes by a factor of s^2. While the scale distances between points dilations do not change angles.Dilation is used to make the objects larger or smaller.

The scale factor can be calculated when the new dimensions and the original dimensions are given. The basic formula to find the scale factor of a figure is Scale factor = Dimension of the new shape ÷ Dimension of the original shape.

From the question ΔE'F'G' is the image formed by the dilation of preimage ΔEFG.

Therefore,

2/3  =[tex]E_{1}[/tex][tex]F_{1}[/tex]/EF

EF=3/2[tex]E_{1}[/tex][tex]F_{1}[/tex]

By substituting any value of F'G' given in the equation we can evaluate the measure of side FG.

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When you and your 3 friends decide to split the bill of $36 evenly and you leaving a 12% tip on your part, you pay a total of $13.32.

Therefore the answer is 13.32 dollars.

When you and your 3 friends decide to split the bill evenly, each person is responsible for paying 1/4 of the total bill. The total bill is $36, so each person is responsible for paying

$36 / 4 = $9

You also decided to leave a 12% tip on your part, so you need to calculate 12% of $36. To do this, you can multiply $9 by 0.12

$36 × 0.12 = $4.32  

So, you are responsible for paying $9 + $4.32 = $13.32

So you are responsible for paying $13.32 in total.

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The expression for f(x) using exponent properties is 8x+11.

Let's first simplify the following statement in order to determine f(x):

[tex]\[\left(\frac{1}{49}\right)^x \cdot \left(\frac{1}{7}\right)^{6x + 11}\][/tex]

Rewrite now with [tex]\(\left(\frac{1}{49}\right)^x\)[/tex] and [tex]\(\left(\frac{1}{7}\right)^{6x + 11}\)[/tex] as a single term's powers:

[tex]\[\left(\frac{1}{7^2}\right)^x \cdot \left(\frac{1}{7}\right)^{6x + 11} \][/tex]

Now, using the rule for exponents [tex](a^{(m*n)} = (a^m)^n)[/tex],

Combine the following words using the same base (1/7 in this case):

[tex]\[ \left(\frac{1}{7}\right)^{2x} \cdot \left(\frac{1}{7}\right)^{6x + 11} \][/tex]

Add their exponents to multiply phrases with the same base:

[tex]\[ \left(\frac{1}{7}\right)^{2x + (6x + 11)} \][/tex]

[tex]\[ \left(\frac{1}{7}\right)^{(8x + 11)} \][/tex]

Now, the given expression becomes:

[tex]\[ \left(\frac{1}{7}\right)^{(8x + 11)} \][/tex]

Now, compare  [tex]\(\left(\frac{1}{7}\right)^{f(x)}\)[/tex],and [tex]\(f(x) = 8x + 11\)[/tex] gives f(x) = 8x+ 11.

So, the expression for f(x) is: [tex]\[ f(x) = 8x + 11 \][/tex].

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The question attached here is in appropriate form the appropriate form is

Find the expression for f(x) when rewriting the following expression in the form [tex]\(\left(\dfrac{1}{7}\right)^{f(x)}(7^1) ^{\dfrac{1}{49}^x \cdot \dfrac{1}{7}^{6x+11}}\):[/tex]

[tex]\(\left(\frac{1}{49}\right)^x \cdot \left(\frac{1}{7}\right)^{6x + 11}\)[/tex]

The exponential function y = a · 2ⁿ ⁻ ¹, where a is any real number, is generates the geometric series.

Geometric series are sets of elements generated by exponential functions of the form:

y = a · bⁿ ⁻ ¹, where a and b are real numbers and n is a natural number.

Where:

According to the statement, we derive the following expression between the two sums:

9 · a · (1 + b + b²) = a · (1 + b + b² + b³ + b⁴ + b⁵)

Now we proceed to simplify and find the value of b:

8 · a · (1 + b + b²) = a · (b³ + b⁴ + b⁵)

8 · (1 + b + b²) = b³ + b⁴ + b⁵

b⁵ + b⁴ + b³ - 8 · b² - 8 · b - 8 = 0

Then, the value of b by numerical methods is equal to 2.

The geometric series is generated by the exponential function y = a · 2ⁿ ⁻ ¹, where a is any real number.

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Answer:

-18a^3b^5

Step-by-step explanation:

First do -ab^2*-6ab^2=-6a^2b^4

Then multiply that by 3ab=-18a^3b^5

The longest tornado ever recorded spanned 219 miles of land as it swept through many states at a pace of 60 miles per hour.

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Answer:

[tex]x=\dfrac{\log 6}{\log 23}[/tex]

Step-by-step explanation:

Given exponential equation:

[tex]23^x=6[/tex]

[tex]\textsf{Apply the log law}: \quad a^c=b \iff \log_ab=c[/tex]

[tex]\implies\log_{23}6=x[/tex]

[tex]\textsf{Given change of base formula}: \quad \log_by=\dfrac{\log y}{\log b}}[/tex]

Apply the given change of base formula:

[tex]\implies x=\dfrac{\log 6}{\log 23}[/tex]

Answer:

Step-by-step explanation:80085

Answer:

Graph 1: No

Graph 2: No

Graph 3: No

Graph 4: Yes

Graph 5: No

Graph 6: Yes

Step-by-step explanation: To figure out whether a graph is a function, you need to give each graph a Vertical Line Test. All you need to do is see if more than one point is on the same line whenever a vertical line is placed. If there is more than one point on any vertical line that you drew, it's not a function.

Hope this helps! :)

The value of x and y in triangles AEB and BCD is 40° and 50°.

A triangle is a three-sided closed-plane figure formed by joining three noncolinear points. Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.

We know the sum of all the interior angles in a triangle is 180°.

Therefore, In ΔAEB,

(2x + 5)° + 50° + 45° = 180°.

2x + 100° = 180°.

2x = 180° - 100°.

2x = 80°.

x = 40°.

Now, ΔBCD,

x + y + 90° = 180°.

40° + y + 90° = 180°.

y = 180° - 130°.

y = 50°.

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Ken should leave a $3.59 tip.

We will discuss algebra, a branch of mathematics that deals with symbols and the rules for manipulating them, in the context of algebra word problem worksheets.

They represent variables or quantities without set values. Our abilities to construct and solve equations must be combined in order to solve algebraic word problems.

It is crucial to start by converting verbal descriptions into algebraic formulas before tackling word issues.

To find the amount of tip he should give, we note that 15% is equal to 0.15 as a decimal.

23.95 * 0.15= 3.5925≈3.59 (approximately)

Therefore, Ken should leave a $3.59 tip.

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