If the position of a particle on the x-axis at time t is −5t2, then the average velocity of the particle for 0 ≤ t ≤ 3 is

Answers

Answer 1

Answer:

v = 15 m / s

Explanation:

In this exercise we are given the position function

          x = 5 t²

and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval

          [tex]v= \frac{v_{f} - v_{o} }{t_{f} - t_{o} }[/tex]

let's look for the displacements

        t = 0     x₀ = 0 m

        t = 3     [tex]x_{f}[/tex] = 5 3 2

                     x_{f} = 45 m

 

we substitute

           [tex]v = \frac{45 -0}{3 - 0}[/tex]

           v = 15 m / s


Related Questions

3
Question 2 (1 point)
If a runner is racing at a velocity of 1.7 m/s North for 3.0 seconds, how far did they
run?
5.1 m [N]
0.57 m IN)
57 m
51 m[N]
O 1.8 m [N]

Answers

Answer:

A, 5.1 m [N]

Explanation:

1.7 times three equals 5.1, and since the runner was running north, the direction was north.

Which one hits the ground first, a
bullet dropped from a height, or a
bullet fired simultaneously from
the same height?

Answers

Answer:

A bullet fired simultaneously from the same height

Explanation:

It will reach the ground first because a greater force is being acted upon it. The first option is only acted on by gravity

what is the velocity for an object at rest?

Answers

Answer:

e

Explanation:

An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

Answer:

If an object is at rest, it has no velocity - its velocity is zero. More precisely, since velocity is a vector, in this case the velocity would be the null vector.

Explanation: Hope this helps

Jerry is pushing a 50-kg box across a moth floor with an acceleration of 0.6 m/s2. What force is he applying to the box? *

83.3 N
0.012 N
0
30 N

Answers

Answer:

30 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 50 × 0.6

We have the final answer as

30 N

Hope this helps you

1. The geologic time scale divides time into years and centuries, true or false

Answers

Answer:

The answer is "False"

Explanation:

The geologic time scale is the "schedule" for occasions in Earth history. It partitions time into named units of unique time called in descending order of duration "eons, eras, periods, epochs, and ages". The specification of those geologic time units depends on stratigraphy, which is the relationship and order of rock layers. The fossil structures that happen in the stones, nonetheless, give the central methods for setting up a geologic time scale, with the circumstance of the development and vanishing of far and wide species from the fossil record being used to outline the beginnings and endings of ages,, periods, and different stretches.

Geologic time is the broad time period involved by the geologic history of Earth. Formal geologic time starts toward the beginning of the Archean Eon (4.0 billion to 2.5 billion years back) and proceeds to the current day.

Question 1 (0.5 points)
Electric circuits provide a path for ___ to flow.
protons
matter
electrons
energy

Answers

Electric circuits provide a path for electrons.

The passage of electrons is facilitated by electric circuits.

An electric circuit resembles a roadway consisting of wires over which electrons are transferred.

The force that causes the electrons to travel comes from a battery or another power source. To allow electrons to travel from the source of power to the gadget and back, wires must be run from the source of electricity to the gadget and back.

So, Option "C" is the correct answer to the following question.

Learn more:

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Where would you find convergent and divergent plate boundaries relative to
convection currents in the mantle?

Answers

Answer:

When two tectonic plates meet, we get a “plate boundary.” There are three major types of plate boundaries, each associated with the formation of a variety of geologic features.

Explanation:

When the plates meet at the boundaries the convergent boundaries lie at the collision of two plates and the divergent lies near mid-oceanic ridges.

What are plate boundaries?

The earth plate tectonics are divided into the three types of plates as convergent which is the destruction of crust and are found where the heavy and light plate comes and colloid with each other submerging the heavier plate into the mantel.

The divergent ones found near the mid-oceanic ridges are the formation of a new plate as the plates diverge away from the ridges.

Find out more information about the plate boundaries.

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A car is traveling with 90km/hr and another car with 20m/s in opposite direction. Calculate the relative velocity.

Answers

Answer:

Vba = -20 m/s - 25 m/s = -45 m/s

Vab = 25 m/s + 20 m/s = 45 m/s

Explanation:

Relative Velocity

The relative velocity of object B with respect to object A (Vba) measures the velocity of B in the rest frame of object A.

It's calculated as:

Vba = Vb - Va

The velocity of car B is Vb=-20 m/s and the velocity of car A is Va=90 Km/h.

Converting Va to m/s:

Va = 90 Km/h * 1000/3600 = 25 m/s

Thus, the relative velocity of B with respect to A is:

Vba = -20 m/s - 25 m/s = -45 m/s

And the relative velocity of A with respect to B is:

Vab = 25 m/s + 20 m/s = 45 m/s

True or False? Will mark Brainlest

Answers

Answer:

False

Explanation:

They had no free oxygen though they has oceans forming and it was very hot and today is much different hope that helps!

How much would a pair of 0.5 kg shoes weigh on Earth? (Include units in
your answer) *

Answers

Answer:

1.1 lbs

Explanation:

To convert kg to lbs you multiply kilograms by 2.2. So 0.5kg × 2.2 equals to 1.1 lbs

what are the effects of moon rotation and revolution​

Answers

Answer:

The effects of the Moon's rotation includes;

1) The Moon rotation and revolution gives the appearance of a perfectly still Moon to observers of the Moon from the Earth

2) The Moon has two sides, the near side that continuously faces the Earth and the "back" or far side, which is also known as the dark side of the Moon

The effect of the Moon's revolution

1) The tides in the ocean and water bodies, due to the gravitational forces from the Moon

2) The changes in the observed shape of the Moon due to the amount of Sunlight that is able to be reflected from the Moon as a result of the relative position of the Moon, the Earth and the Sun, at a given point in time

3) Lunar and Solar eclipse, when the Earth and the Moon blocks the light coming from the Sun respectively, due to their combined revolution

Explanation:

The duration of the Moon's orbit round the Earth = 27.322 days

The time it takes the Moon to rotate round its axis = 27 days

The Moon is the closest cosmic body to the Earth.

A car is traveling with 90km/hr and another car with 20m/s in opposite direction. Calculate the relative velocity.

Answers

90 km/h is 25 m/s
the relative velocity when cars are traveling in opposite directions is the sum of the two
25+20= 45 m/s

If the same total travel at the speed of 0.05 m/s for 40 seconds, how far would it have gone?

Answers

Answer:

Would've traveled 2 miles.

Explanation:

A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power did the cart do? MUST SHOW ALL WORK!!!!!!!!!

Answers

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

[tex]F = 14*6\\F = 84 [N][/tex]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

[tex]W = F*d[/tex]

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

[tex]W = 84*40\\W = 3360 [J][/tex]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

[tex]P=W/t\\[/tex]

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

[tex]P=3360/100\\P=33.6[W][/tex]

The power is given in watts

The photograph shows matter going through a physical change. Which characteristic of the matter changes?

A. shape.

B. shininess.

C. state.

D. type of atoms

Answers

Answer:

Possibly shape.

Explanation:

Because it is ripped in half. As you guys and the questioner can see that there is a wiggly strip down the middle. That also cause of a shape change.

I really hope my answer is right ^_^  

The characteristic of matter which is undergoing change in the picture is it's shape as it is being teared apart.

What is matter?

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.Matter possesses both particle and wave characteristics.Phase is a form of matter having uniform composition as well as physical properties.

Learn more about matter,here:

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Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?

Answers

Answer:

30 Watts

Explanation:

 Power = Work/Time

Work = Force*Distance

Power = Force * Distance / Time

Power = 15 N * 20 meters / 10 sec

Power = 30 Watts

what is gravity???☺️

Answers

Answer:

Gravity

Explanation:

its an invisible force that pulls objects

toward each other.

hope it helps

A force that pulls objects downwards

what phenomenon reduces the adverse effects and pressure imposed by solar wind on earth?​

Answers

Answer:

The earths magnetic field

Explanation:

A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the
ground. How long will it take, in seconds, for the ball to hit the ground?

Answers

Answer:

0.73 s

Explanation:

The time taken can be found by using the formula

[tex] t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{3.5}{4.8} \\ = 0.72916...[/tex]

We have the final answer as

0.73 s

Hope this helps you

The mass of Saturn is 5.69 · 10^26 kg. Calculate the gravitational field that it exerts on its Mimas satellite, knowing that the mean radius of its orbit is 186,000 km. Data: G = 6.67 · 10^-11 N · m2 · kg ^-2.

Answers

Answer:

The gravitational field that Saturn exerts on the satellite, Mimas is approximately 1.097 m/s²

Explanation:

The given mass of Saturn = 5.69 × 10²⁶ kg

The radius of the orbit of the Mimas satellite = 186,000 km

The gravitational constant, G = 6.67 × 10⁻¹¹ N·m²·kg⁻²

From Newton's law of gravitation, we have;

[tex]The \ gravitational \ field =G\times \dfrac{M}{R^{2}} = 6.67 \times 10^{-11} \times \dfrac{5.59 \times 10^{26}}{(186,000,000)^2} \approx 1.097[/tex]

6.67 × 10⁻¹¹ *(5.69 × 10²⁶)/(186,000,000)²

The gravitational field that Saturn exerts on the satellite, Mimas ≈ 1.097 m/s².

marcus is on a merry-go-round holding a string. you are standing next to him and holding the other end of the string so that the string forms a tangent line to the edge of the merry-go-round. if marcus is 2 meters from the center of the ride, what torque are you applying on him if you pull 30 N? _Nm

Answers

Answer: 60 nm

Multiply 30 and 2

Which are compounds ?

Answers

Answer:

water, salt, ammonia, sulfuric acid

Explanation:

I looked it up and decided to be helpful

Answer:

Water, Salt, Ammonia, Sulfuric Acid

Explanation:

A projectile is fired into the air. Three characteristics of its subsequent motion are
1) the horizontal component of velocity
II) the vertical component of velocity
III) the acceleration
Neglecting air resistance, which characteristic(s) change(s) whilst the projectile is in the air.
(1 Point)
I only
Il only
II and III only
I and II only

Answers

Answer:

The answer is C) II and III only

Explanation:

A ball of mass 0.12kg is hit by a tennis player. The velocity of the ball changes from 0m/ s to 5.0m/s in 0.60s. What is the average resultant force acting on the ball while it is being hit?
A 1.0N B 2.5N C 3.6N D 8.3N
(Please add explanation)

Answers

Answer:

A. 1.0N

Explanation:

According to Newton's second law

F = ma

m is the mass = 0.12kg

a is the acceleration = v-u/t

a = 5-0/0.6

a = 5/0.6

a = 8.333m/s²

Get the force

F = 0.12 * 8.333

F = 1.0N

Hence the average resultant force acting on the ball while it is being hit is 1.0N

Give one example where friction is useful. Can someone feed me with correct answer pls c:

Answers

Answer:

Friction is what holds your shoe to the ground. The friction present on the ice is very little, this is the reason why it is hard to walk on the slippery surface of the ice.

Explanation:

Keeping traction on a race track

How long will it take a sample of I-131 to decay to 12.5% assuming it's half-life is 8.07 days?

Answers

Answer:

If you take A0 to be the initial sample of iodine-131, you will be left with. 12⋅A0=A02→ ... m24 hours=12.5%mo=12.5⋅10−2⋅mo

Explanation:

is that what u look for

Sample I-131 decays to 12.5% in 24.21 days.

What is half-life?

Half-life, in radioactivity, is the amount of time needed for half of a radioactive sample's atomic nuclei to decay (change spontaneously into other nuclear species by emitting particles and energy), or, alternatively, the amount of time needed for a radioactive material's rate of disintegrations per second to decrease by half.

Give parameters:

Half-life of  the radioactive element I-131:T = 8.07 day

It decays to 12.5% means it decays to 1/8.

According to definition of half-life,

The radioactive element I-131 decays to half in 8.07 days.

So, the radioactive element I-131 decays to 1/8 in 3×8.07 days = 24.21 days.

Hence,  the radioactive element I-131 decays to12.5% in 24.21 days.

Learn more about half-life here:

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Which of the following is most likely to be a conductor?
OA. Aplastic
OB. A molecule containing only nonmetal atoms
OC. A covalently bonded molecule
D. Acompound containing metallic bonds

Answers

Answer:

D.

Explanation:

A compound containing metallic bonds

hope it helps!

A man speeding at 40m/s decides to outrun the cops and starts to accelerate at a rate of 2.5m/s² for 12 seconds. How far did he travel in this time?

Answers

Answer:

The distance traveled by the man during the acceleration is 1186.32 meters

Explanation:

The initial velocity of the man = 40 m/s

The added acceleration rate of the man to outrun = 2.5 m/s²

The time of acceleration = 12 seconds

The relevant kinematic equation of motion is given as follows;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the car the man is driving = 40 m/s

t = The time of travel during acceleration of the car the man is driving = 12 seconds

a = The acceleration by the man to outrun the cops = 2.5 m/s²

s = The distance traveled by the man during the acceleration

Substituting, gives;

s = 40 × 12 + 1/2 × 9.81 × 12² =  1186.32

The distance traveled by the man during the acceleration = s = 1186.32 m.

A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick

Answers

Answer:

The value is  [tex]M = 42.3 \ kg[/tex]

Explanation:

From the question we are told that

    The first  position of the fulcrum  is  x = 49.7 cm

    The mass  attached is [tex]m = 41.5 \ g[/tex]

    The position of the attachment is  [tex]x_1 = 28.5 \ cm[/tex]  

    The second position of the fulcrum is  [tex]x_2 = 39.2 \ cm[/tex]

Generally the sum of clockwise torque =  sum of anti - clockwise torque

So  

       [tex]CWT = m (x_2 - x_1)[/tex]

Here CWT  stands for clockwise torque

       [tex]ACWT = M ( x - x_2)[/tex]

So

      [tex]m (x_2 - x_1) = M ( x - x_2)[/tex]

=>   [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]

=>    [tex]M = 42.3 \ kg[/tex]

I need help on these 3 questions plz 20 points

Answers

Answer: the first one is speed

the second one is acceleration

the last is velocity

Explanation:

i got you

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