If i have a lawn mower for 3 $ and its 50 percent of what is the orginial price ?

Zeros be a and b

Function

[tex]\\ \sf\longmapsto y=x^2-(a+b)x+ab[/tex]

[tex]\\ \sf\longmapsto y=x^2-(7+13)x+(7)(13)[/tex]

[tex]\\ \sf\longmapsto y=x^2-20x+91[/tex]

Option B

The mean score for all 23 students is 77.17.

Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number.

The first step is to determine the total scores of the 22 students.

Total scores = mean score x number of students

22 x 76.5 = 1683

The second step is to add the score of the student that took the exam late tot he total scores.

New total score = 1683 + 92 = 1775

The third step is to determine the new mean score.

new mean score = new total score / total number of students

1775 / 23 = 77.17

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Answer:

x=10

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

6x-7 = 26+2x+7

Combine like terms

6x-7 = 2x+33

Subtract 2x

6x-7-2x =2x+33-2x

4x-7 = 33

Add 7 to each isde

4x-7 +7 = 33+7

4x=40

Divide by 4

4x/4 = 40/4

x=10

Answer: 6.087 tablespoons. or rounded to nearest whole, 6

Step-by-step explanation:

I just know

Answer:

-3

Step-by-step explanation:

a. Simply put (x+h) wherever you have x.

[tex]f(x+h) = -3(x+h)+7 = -3x +7 -3h[/tex]

b. We have the first part, just subtract

[tex]f(x+h) = -3(x+h)+7 = -3x +7 -3h - (-3x+7) = -3x+7-3h +3x -7 = -3h[/tex]

c. Finally, we divide by h[tex]\frac{-3h}h = -3[/tex]

[tex]W = \displaystyle \int^{5}_{2} F(x) ~ dx\\\\\\= \displaystyle \int^{5}_{2} \left(12x^2 +7\right) ~dx\\\\\\= 12\displaystyle \int^{5}_{2} x^2 ~dx + \displaystyle \int^{5}_{2} 7~ dx\\\\\\=12 \left[\dfrac{x^3}3 \right]^{5}_{2} + 7\left[x\right]^{5}_{2}\\\\\\=4(5^3-2^3) + 7(5-2) = 468 + 21 = 489~ J[/tex]

Answer:

3

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Step-by-step explanation:

24 is 3×8

so, when

3c = 5c-2

then

8×3c = 24c = 8×(5c-2) = 40c - 16

Probabilities are used to determine the chances of an event.

Let P represents the event that a student passes the course, and C represents the event that a student completes the assignment

(a) The probability a student passed the course given that they completed their homework?

From the table, we have:

[tex]\mathbf{n(P\ n\ C) = 25}[/tex]

[tex]\mathbf{n(C) = 30}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P\ n\ C)}{n(C)}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{25}{30}}[/tex]

[tex]\mathbf{Pr = 0.8333}[/tex]

Express as percentage

[tex]\mathbf{Pr = 83.33\%}[/tex]

Hence, the probability a student passed the course given that they completed their homework is 83.33%

(b) The probability a student passed the course given that they didn't complete their homework

From the table, we have:

[tex]\mathbf{n(P\ n\ C'= 7}[/tex]

[tex]\mathbf{n(C') = 25}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P\ n\ C')}{n(C')}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{7}{25}}[/tex]

[tex]\mathbf{Pr = 0.28}[/tex]

Express as percentage

[tex]\mathbf{Pr = 28\%}[/tex]

Hence, the probability a student passed the course given that they didn't complete their homework is 28%

(c) The probability a student completed their homework given that passed the course?

From the table, we have:

[tex]\mathbf{n(P\ n\ C) = 25}[/tex]

[tex]\mathbf{n(P) = 32}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P\ n\ C)}{n(P)}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{25}{32}}[/tex]

[tex]\mathbf{Pr = 0.78125}[/tex]

Express as percentage

[tex]\mathbf{Pr = 78.125\%}[/tex]

Approximate

[tex]\mathbf{Pr = 78.13\%}[/tex]

Hence, the probability a student completed their homework given that they passed the course is 78.13%

(d) The probability a student didn't complete their homework given that they didn't pass the course

From the table, we have:

[tex]\mathbf{n(P'\ n\ C'= 18}[/tex]

[tex]\mathbf{n(P) = 23}[/tex]

So, the required probability is:

[tex]\mathbf{Pr = \frac{n(P'\ n\ C')}{n(P')}}[/tex]

This gives

[tex]\mathbf{Pr = \frac{18}{23}}[/tex]

[tex]\mathbf{Pr = 0.7826}[/tex]

Express as percentage

[tex]\mathbf{Pr = 78.26\%}[/tex]

Hence, the probability a student didn't complete their homework given that they didn't pass the course is 78.26%

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Answer:

B. -2x + 10 is the correct answer

Answer:

(C) -2x + 10

Step-by-step explanation:

This is going to be multiplication from the first number outside the "Bubble"

                              -2 multiplied by x = -2x ,

why ? because a negative times a positive makes a negative    

                      Next is -2 multiplied by -5 = 10

why ? because a negative times a negative = equals a positive !

now .. you add up all of the sums together to make an equation ..

                            Answer would be -2x+10

Answer:

Average County Tax Rate

0.520%

(Mercer County)

Property Taxes

$121

(Annual)

Step-by-step explanation: I'm assuming this is the answer, if you can please can you mark me Brainliest.

Answer:

The answer is 7 she Can Buy 7 packages of cookies.

Step-by-step explanation:

1. 15-5.50=9.50

2.9.50-7.75=1.75

3. 1.75-0.25*7=0

She wouldn't have any money left over to buy it

Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

[tex]D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}[/tex]

The odd multiples of 9, [tex]m[/tex], in the range [tex]2\le m \le 82[/tex] form the set

[tex]\{9,27,45,63,81\}[/tex]

Each member of the set is a term of the arithmetic progression

[tex]U_n=18n+9[/tex]

where the values of [tex]n[/tex] range from 0 to 4, or [tex]0\le n\le 4[/tex]

Putting these facts together, we get the result

[tex]D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}[/tex]

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let's firstly change the 1.2 to a fraction

[tex]1.\underline{2}\implies \cfrac{12}{1\underline{0}}\implies \cfrac{6}{5} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{\frac{6}{5}}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{\frac{6}{5}}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{10}}}\implies \cfrac{~~ \frac{6-30}{5}~~}{-6}\implies \cfrac{~~ \frac{-24}{5}~~}{-6}\implies \cfrac{~~ -\frac{24}{5}~~}{-\frac{6}{1}}[/tex]

[tex]-\cfrac{\stackrel{4}{~~\begin{matrix} 24 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{5}\cdot -\cfrac{1}{\underset{1}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \boxed{\cfrac{4}{5}}[/tex]

Answer:

Step-by-step explanation:

A' = (2 + 3, 1 + 2) = (5, 3)

B' = (-1 + 3, -3 + 2) = (2, -1)

C' = (3 + 3, -3 + 2) = (6, -1)

Step-by-step explanation:

What do you mean "no real roots" ?

if I understand correctly we have

2x² + 5kx + k = 0

the solutions for such a quadratic equating are

x = (-b ± sqrt(b² - 4ac))/(2a)

a = 2

b = 5k

c = k

so, we get

x = (-5k ± sqrt(25k² - 8k))/4

why would that have no real solutions ?

e.g. k = 2

x = (-10 ± sqrt(100 - 16))/4 = (-10 ± sqrt(84))/4

since the sqrt is a little bit bigger than 9 we get 2 negative solutions for x. but still real.

I don't understand what your need here.

Answer:

D) (6, -4)

Step-by-step explanation:

pt C has coordinates of (6,4)

if you reflect that point across the x-axis the x-value remains the same and the y-value continues to be 4 units from the x-axis, but below it instead of above it

we know that the colony is doubling, namely the rate of growth is 100% of whatever is existent, thus

[tex]\textit{Amount of Population Growth} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &5000\\ r=rate\to 100\%\to \frac{100}{100}\dotfill &1\\ t=\textit{elapsed time}\dotfill &t\\ \end{cases} \\\\\\ A = 5000e^{1\cdot t}\implies \boxed{A = 5000e^t}[/tex]

Answer:

1.4

Step-by-step explanation:

in the graph, the points are 14 points apart, when the step of the graph is set to .1, if you count, they're .14 point apart, or 1.4

Answer:

Step-by-step explanation:

Evan has 43 and Brayden has 42. Reid has 76 and Bryce has 23. Which pair of boys has more? How much more do they have?

Reid and Rryce have more. If you add 43 and 42 you get 85 and when you add 76 and 23 you get 99. So now subtract 99 and 23 which is 76.

Answer:

5+5=10

but if you mean

5+-5 then that = 0

Step-by-step explanation:

The rate is a fraction that compares the values of two quantities. The expected answers to the questions are given below:

1. Given that 3 cakes takes 6 hours to bake, then:

1 cake = [tex]\frac{6}{3}[/tex]

           = 2 hours

So that;

the number of cake to be baked in 12 hours = [tex]\frac{12 hours}{2 hours}[/tex]

                                    = 6

The number of cake to be baked in 12 hours is 6.

2. Ava's rate of pay = [tex]\frac{15}{2}[/tex]

                                 = $7.5 pr hour

Thus Ava's rate of pay is $7.5 per hour.

3. It took 5 hours to mow 6 yards. Thus;

To mow 1 yard = [tex]\frac{5}{6}[/tex] hours

The number of yards to be mowed in 20 hours = 20 ÷ [tex]\frac{5}{6}[/tex]

                                                = 20 x [tex]\frac{6}{5}[/tex]

                                                = 24

The number of yards to be mowed in 20 hours is 24.

4. Given that 10 bags of rice cost $12, then;

1 bag = [tex]\frac{12}{10}[/tex]

         = 1.2

1 bag = $1.2

The cost of a bag of rice is $1.2.

5. Rate = 30 miles per gallon

The number of gallons required = [tex]\frac{360}{30}[/tex]

                                        = 12

Thus 12 gallons would be required by the car to travel 360 miles.

6. Rate = [tex]\frac{75}{3}[/tex]

            = 25

Rate = 25 words per minute

The typing speed is 25 words per minute.

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The second option has a lower amount of interest paid.

In order to determine the loan option that minimizes loan payment, the future value of both loan options has to be determined.

FV = P (1 + r)^nm

FV = Future value  

P = Present value  

R = interest rate  

m = number of compounding

N = number of years  

First loan option

65000( 1 + 0.063/12)^300 = 312,707.21

Second loan option

65000( 1 + 0.048/12)^240 = 169,435.51

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Answer:

How to factor out a polynomial with a 3rd degree-• well here is a For example, let G(x) = 7x³ – 125. Then factoring this third degree polynomial relieve on a differences of cubes as follows: (2x – 5) (4x² + 20x + 25), where ²x is the cube-root of 8x³ and 5 is the cube-root of 1256

Answer:

long division is probably the simplest method of finding out the factors

Step-by-step explanation:

For example,  let G(x) = 8x³ – 125. Then factoring this third degree polynomial relies on a difference of cubes as follows: (2x – 5) (4x² + 10x + 25), where 2x is the cube-root of 8x³ and 5 is the cube-root of 125. Because 4x² + 10x + 25 is prime, you are done factoring.

Answer:

The linear equation that gives the rule of the table is f(x) = x + 25

The linear equation can be represented in a slope intercept form as follows:

y = mx + b

where

m = slope

b = y-intercept

Therefore,

Using the table let get 2 points

(2, 27)(3, 28)

let find the slope

m = 28 - 27 / 3 -2 = 1

let's find b using (2, 27)

27 = 2 + b

b = 25

Therefore,

y = x + 25

f(x) = x + 25

Step-by-step explanation:

Answer:

976

SA=2(S1)+2(S2)+S3

S1=14*24/2

S1=168

S2=25*10

S2=250

S3=14*10

S3=140

SA=2(168)+2(250)+140

SA=976 cm