Answer:
824 g
Explanation:
First we convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles, using Avogadro's number:
7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl
Finally we convert 23.24 moles of chlorine into grams, using chlorine's molar mass:
23.24 mol * 35.45 g/mol = 824 g
C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work
Answer:
[tex]\Delta H_{comb}=2043.85kJ/mol[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:
[tex]\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}[/tex]
Thus, given the values of the enthalpies of formation on the attached file, we obtain:[tex]-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol[/tex]
Best regards!
12. How many moles of atoms are present in 154 g of Na2O?
A) 2.48 mol
B) 7.45 mol
C) 51.3 mol
D) 0.827 mol
Answer:
[tex]\boxed {\boxed {\sf A. \ 2.48 \ mol \ Na_2O}}[/tex]
Explanation:
We are asked to convert an amount in grams to moles. To do this, we use the molar mass. This is the number of grams in one mole of a substance. It is the same value numerically as the atomic mass on the Periodic Table, however the units are grams per mole, not atomic mass units.
Look up the molar masses for the individual elements.
Sodium (Na): 22.9897693 g/mol Oxygen (O): 15.999 g/molLook back at the formula: Na₂O. Notice there is a subscript of 2 after sodium. This means there are 2 atoms of sodium in every molecule, so we have to multiply sodium's molar mass by 2 before adding oxygen's.
Na₂O: 2(22.9897693 g/mol)+ 15.999 g/mol = 61.9785386 g/molSet up a ratio using the molar mass.
[tex]\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}[/tex]
Multiply by the given number of grams.
[tex]154 \ g \ Na_2O*\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}[/tex]
Flip the ratio so the grams of sodium oxide can cancel each other out.
[tex]154 \ g \ Na_2O*\frac {1 \ mol \ Na_2O}{61.9785386 \ g \ Na_2O}[/tex]
[tex]154 *\frac {1 \ mol \ Na_2O}{61.9785386 }[/tex]
[tex]\frac {154}{61.9785386 } \ mol \ Na_2O[/tex]
[tex]2.48473106141 \ mol \ Na_2O[/tex]
The original measurement of grams given has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.
2.48473106141The 4 in the thousandth place tells us to leave the 8.
[tex]2.48 \ mol \ Na_2O[/tex]
There are 2.48 moles of sodium oxide in 154 grams, so choice A is correct.
The weight for this compound is 74. what is the molecular formula
Explanation:
ur question is incomplete what elements make the compound and we talk of mass not weight and what are the units kjmol ,grams ,kgs
A chemical breaks down in a flow-balanced, steady-state CFMR according to first-order reaction kinetics. At steady state, the upstream and downstream concentration of the chemical are 15 mg/L and 5 g/m3. Water is being treated at a rate of 0.42 m3/sec. The volume of the tank is 500,000 liters. Assuming a first-order reaction, what is the rate constant
Answer:
[tex]k =0.101 \ min^{-1}[/tex]
Explanation:
From the given information:
The initial concentration of a chemical [tex]C_{AO} = 15 \ mg/L[/tex]
The final concentration is [tex]C_A = 5 \ g/m^3[/tex] = 5 mg/L
Volume flow rate [tex]V_o = 0.42 \ m^3/sec[/tex]
Volume of the tank V = 500 000 L = 500 m³
The time t is determined by using the formula:
[tex]t= \dfrac{V}{V_o}[/tex]
[tex]t= \dfrac{500 \ m^3}{0.42 \ m^3/sec}[/tex]
t = 1190.47 sec
t ≅ 19.8 min
∴
The rate of the decay constant is:
[tex]kt= \dfrac{C_{AO}-C_{A}}{C_A} \\ \\ k = \dfrac{1}{19.8}( \dfrac{15-5}{5})[/tex]
[tex]k =0.101 \ min^{-1}[/tex]
How many molecules of O2 will be required to produce 28.8 g of water?
The most common experimental technique to perform elemental analysis is combustion analysis, where a sample is burned in a large excess of oxygen and the combustion products are trapped in a variety of ways. A 99.99% pure, 0.4808 g sample containing only carbon, hydrogen, and nitrogen is subjected to combustion analysis, resulting in the formation of 0.6859 g CO2, 0.6973 g H2O, and 0.4646 g NO. What is the empirical formula of the sample
Answer:
C₂H₅N₂
Explanation:
In the combustion analysis, all NO comes from the nitrogen of the sample, that means:
Moles NO = Moles N in the sample
In the same way:
Moles CO2 = Moles C in the sample
Moles H2O = 1/2 moles H in the sample
To solve this problem we must convert the mass of each gas to moles in order to find the moles of each atom. The empirical formula is the simplest whole number ratio of atoms presents in the molecule:
Moles NO = N -Molar mass: 30g/mol
0.4646g * (1mol / 30g) = 0.01549 moles N
Moles CO2 = C -Molar mass: 44.01g/mol-
0.6859g * (1mol / 44.01g) = 0.01559 moles C
Moles H2O = 1/2moles H -Molar mass: 18.02g/mol-
0.6973g * (1mol / 18.02g) = 0.03870 moles H
The ratio of atoms is -Dividing in the low number of moles = moles N-:
C = 0.01559 / 0.01549 = 1
N = 0.01549 / 0.01549 = 1
H = 0.03870 / 0.01549 = 2.5
Twice this ratio of atoms -Because empirical formula must be given only with whole numbers:
C = 2
N = 2
H = 5
The empirical formula is:
C₂H₅N₂A bottle containing air is initially at a temperature of 33 degrees C and a pressure of 0.81 atm. After being placed in the freezer, the final temperature is 1 degrees C. What is the final pressure ?
Answer:
The final pressure is 0.725 atm.
Explanation:
Gay Lussac's Law establishes the relationship between pressure and temperature of a gas when the volume is constant. This law says that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, pressure and temperature are directly proportional quantities.
Mathematically, Gay-Lussac's law states that, when a gas undergoes a constant volume transformation, the quotient of the pressure exerted by the gas temperature remains constant:
[tex]\frac{P}{T} =k[/tex]
When analyzing an initial state 1 and a final state 2, the following is satisfied:
[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]
In this case:
P1= 0.81 atmT1= 33 C= 306 KP2= ?T2= 1 C= 274 KReplacing:
[tex]\frac{0.81 atm}{306 K} =\frac{P2}{274 K}[/tex]
Solving:
[tex]P2=274 K*\frac{0.81 atm}{306 K}[/tex]
P2= 0.725 atm
The final pressure is 0.725 atm.
What is the volume of 45 g of Hydrogen gas (H2) at STP?
Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16]
What is the percentage oxygen in N2O5? (Give your answer in 4 significant figures)
Answer:
74.08%
Explanation:
We'll begin by calculating the mass of
Oxygen in 4 g of N₂O₅. This can be obtained as follow:
Molar mass of N₂O₅ = (14×2) + (16×5)
= 28 + 80
= 108 g/mol
Mass of oxygen in N₂O₅ = 5 × 16 = 80 g
Mass of oxygen in 4 g of N₂O₅
= 80 / 108 × 4
= 2.963 g
Finally, we shall determine the percentage of oxygen in 4 g of N₂O₅. This can be obtained as follow:
Mass of oxygen = 2.963 g
Mass of N₂O₅ = 4 g
Percentage of oxygen =?
Percentage of oxygen = mass of oxygen / mass of N₂O₅ × 100
Percentage of oxygen = 2.963 / 4 × 100
Percentage of oxygen = 74.08%
calculate the percentage of CL in AL(CLO3)3
Answer:
46.41%
Explanation:
Find the total r.m.m of AL(CLO3)3 put it equals to 100%.....The take 106.5,the total r.m.m of Cl and find the missing which is the percentage by cross multiplication
According to the data, which part is described by the letter K?
a
constellation
b
galaxy
c
meteoroid
d
planet
Answer:
C meteoroid
Explanation:
Meteoroids are the only ones of the four that are under a kilometer in size.
observation made when lead oxide passes through hydrogen gas
Answer:
a gray substance and colourless liquid
Explanation:
lead oxide is reduced to lead while hydrogen is oxidized to water
Consider the following ionization reaction.
HNO3 (aq) + H20 () = NO,- (aq) + H2O* (aq)
a)
Define acid and base according to Bronsted-Lowry, and give an example of each.
(3 marks)
b) Identify all acids and its conjugate base pairs from the above equation.
(2 marks)
Answer:
See explanation
Explanation:
According to Bronsted-Lowry, an acid is a proton donor while a base is a proton acceptor.
Hence, if we consider the reaction above, we will notice that for each base there is a conjugate acid and for each acid there is a conjugate base.
For the acid HNO3, its conjugate base is NO3^- while for the acid H3O^+, its conjugate base is H2O.
1 interpret geochemistry in your words. 2. how can you explain that the solar system (sun, all planets and satellites) has all been formed from a special nebula ?
Explanation:
(I only know this thing vaguely lol)
1.) It's the study of the chemistry that is happening here on earth that is not bounded by a laboratory.
2.) The early gas clouds compressed and formed a star we now call the sun and the massive gravitational pull of this star grabbed nearby debris and the debris formed and compressed into the planets and moons that we know today.
Which of the following patients should be admitted as an inpatient at a
hospital?
A. Katie's having her tonsils removed and will be able to go home
shortly after she wakes up from surgery.
B. Phil's having his blood sugar tested and having his annual
physical
c. Salvatore's having a hip transplant and will need to be closely
monitored for a week.
D. Chen's having chest X-rays taken to determine if he has a broken
rib.
SUBMIT
A wavelength is traveling at 6,420m/s and has a frequency of 600Hz. What is the wavelength
According to the theory of plate tectonics,
which of the following statements is true?
A Earthquakes and volcanoes con change Earth's surface, but the
overall locations of land and ocean do not change over time.
B. Continents have grown, shrunk, and
moved over the course of Earth's history.
C. The ratio of ocean to land on Eorth has been
pretty much the same throughout Earth's history,
What happens to the rate if the concentration of 1-iodopropane remains the same and the concentration of sodium hydroxide is doubled
Answer:
The rate of reaction is doubled
Explanation:
The reaction between 1-iodopropane and sodium hydroxide is an SN2 reaction. This reaction takes place by a concerted mechanism and the hydroxide ion is the nucleophile.
In an SN reaction, the reaction is second order because the rate of reaction depends both on the concentration of the alkylhalide and that of the nucleophile. Hence, when the concentration of 1-iodopropane (the alkyl halide) is held constant and the concentration of hydroxide ion (the nucleophile) is doubled, the rate of reaction is doubled since;
Rate =k [1-iodopropane] [OH^-]
Identify the reaction type of the chemical reaction below. Check all that apply.
Mg (s)+2 HCl (aq) MgCl 2 (aq)+H 2 (g)
Answer:
The type of reaction is a single-replacement reaction.
Explanation:
Mg switches places with H, leaving H by itself.
Complete the sentence using the correct word: conduction,
convection or thermal energy.
The method of heat transfer that occurs when particles move
through a fluid is called
Answer:
Convection
Explanation:
Convection definition:
the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.
The method of heat transfer that occurs when particles move through a fluid is called convection.
Convection relies on the principle of fluid flow, where hotter particles become less dense and rise while cooler particles sink due to their increased density.
This movement creates a continuous circulation of the fluid, enabling the transfer of thermal energy. As the hot particles rise, they carry their thermal energy with them, and as the cooler particles sink, they absorb heat from their surroundings.
Convection is also observed in natural phenomena such as ocean currents, air currents, and even the movement of magma in the Earth's mantle.
To learn more about the convection, follow the link:
https://brainly.com/question/4138428
#SPJ6
Question 2
1 pts
r
A compound is 31.1 % S, the rest is chlorine. The compound has a molecular mass of 205.94 amu.
What is its molecular formula?
Explanation:
its hard to explain unless we know what the question fully asks..
What is the proper formula for vanadium (iv) percholrate?
Answer:VO(ClO4)3 i'm sure this is it
Explanation:
Which lava contains a lot of water
Answer:
i think its magma ajani i looked it up... and chelsey said u had corona so if its true hope u get better bro
Explanation:
1. Given the following unbalanced equation:
Al(SO3)3 + NaOH
---> Na2SO3 + Al(OH)3
If you start with 389.4 grams of Al(SO3)3 and 200 grams of NaOH ?
Identify the limiting reactant:
Identify the reactant in excess and by how much:
How many grams of Na2SO, will be produced:
If you perform the same reaction but get 212.4 grams of Na2SO3, what is
your percent yield?
Answer:
Limting reactant: NaOH
Excess reactant: Al₂(SO₃)₃ by 104.9 grams.
315 g of Na₂SO₃ are produced in the reaction
67.4 % is the percent yield.
Explanation:
Balaced equation is:
Al₂(SO₃)₃ + 6NaOH → 3Na₂SO₃ + 2Al(OH)₃
We convert the mass of each reactant to moles, to identify the limiting reactant:
389.4 g . 1mol/ 342.15g = 1.14 moles of sulfite
200 g . 1mol / 40g = 5 moles
1 mol of aluminum sulfite react to 6 moles of NaOH, according to stoichiometry.
If we have 1.14 moles of sulfite, we need (1.14 . 6)/1 = 6.82 moles
We only have 5 mol of NaOH, so this is the limiting reactant.
Then the aluminum sulfite is the excess.
6 moles of NaOH react to 1 mol of sulfite
Then, 5 moles of NaOH may react to (5 . 1)/6 = 0.83 moles.
1.14 mol - 0.83 mol = 0.31 moles remains after the reaction goes complete.
We convert to mass: 0.31 mol . 342.15g/mol = 104.9 g
Then, we work with the limiting reactant. Stoichiometry is 6:3 (2)
6 moles of NaOH can produce 3 moles of sodium sulfite
Then 5 moles will produce (5 . 3)/6 = 2.5 moles
We convert moles to mass: 2.5 mol . 126 g/mol = 315 g.
Percent yield = (Yield produced/Thoeretical yield) . 100
Percent yield = (212.4g /315g) . 100 = 67.4 %
How did Robert Millikan's oil drop experiment change scientists' view of the
atom?
A. It identified the location of the nucleus.
B. It showed that atoms could not be divided into smaller particles.
C. It identified the charge on a single electron.
D. It showed that atoms were found in different energy levels.
SUBMIT
Answer:
Hello There!!
Explanation:
I think the answer is possibly C. It identified the charge on a single electron.
hope this helps,have a great day!!
~Pinky~
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
C. It identified the charge on a single electron.
ThanksHope it helps3.
Calculate the mass in grams needed to have 2.65 x 1022 atoms of calcium.
८८
2.65 x 10²
Answer:
[tex]=1.76gCa[/tex]
Explanation:
Hello there!
In this case, according to the given atoms of calcium, it is possible to calculate the mass of this element by considering that the definition of mole is in terms of atoms and also the atomic mass of calcium:
[tex]1molCa=6.022x10^{23}atoms Ca=40.08gCa[/tex]
In such a way, by considering the following setup, we can obtain:
[tex]=2.65x10^{22}atomsCa*\frac{1molCa}{6.022x10^{23}atoms} *\frac{40.08gCa}{1molCa}\\\\=1.76gCa[/tex]
Best regards!
What is NaC2H3O2 coefficient
Answer:yes coefficient u mean??
Explanation:
For the following exothermic reaction system at equilibrium:
H2O(g) CO(g) CO2(g) H2(g)
Choose the changes that will increase the value of K.
a. Decrease the volume (constant T)
b. Add H2O(g) (constant T)
c. Remove H2(g) (constant T)
d. Add a catalyst (constant T)
e. Add CO2(g) (constant T)
f. Increase the temperature
g. Decrease the temperature
Answer:
See explanation.
Explanation:
Hello there!
In this case, for the chemical reaction:
[tex]H_2O(g) CO(g)\rightleftharpoons CO_2(g) H_2(g)[/tex]
It is widely known that the the only factor altering the equilibrium constant is the temperature because of its thermodynamic definition:
[tex]K=exp(-\frac{\Delta G(T)}{RT} )[/tex]
Which is temperature dependent on the denominator and on the Gibbs free energy of reaction. In such a way, the answers can be just f and g, as the other factors modify Q (reaction quotient) rather than K. Thus, we can discuss about f and g:
f. This would increase K if the Gibbs free energy of reaction is positive (nonspontaneous).
g. This would increase K if the Gibbs free energy of reaction is negative (spontaneous).
It is important to discuss those two because the Gibbs free energy is not given.
Regards!
25m
45m
Help pls.........
Answer:
45m
Explanation:
What is the Kc for the following reaction at equilibrium at 500∘C if [N2]= 0.41 M , [H2]= 0.41 M , and [NH3]= 2.2 M ? N2(g)+3H2(g)⇌2NH3(g)
Answer:
answer po Yan hope it help