Answer:
longer
Explanation:
The relationship between the solar day and sidereal is as follows:
The length of the sidereal day is
= (Solar day) (solar year ÷ solar year + 1 day)
As it can be seen that the day i.e. solar its length would be greater as compared with the sidereal day.
In the case when the earn orbited the sun in 9 months rather than 12 so here the sidereal day would be the similar but the solar day would be longer as compared with the original one
1 point
A leak in a swimming pool allows 2.50 liters to flow out every minute. How
many gallons leak out in week? (There are 0.946 liters per quart and 4
quarts per gallon.) *
O 910. gallons
O 12 700 gallons
0 7 140 gallons
6 660 gallons
Answer:
66.6 G
Explanation:
I WILL GIVE U 100 POINTS IF U ANSWER THIS AND GET IT RIGHT!!!!!!!!!!!!!!
Answer:
Free points That's awesome Thanks Brainly User!
Explanation:
A 10kg box is sliding at 50m/s. Find the momentum
Answer:
The momentum of the ball is 500 kg·m/s
Explanation:
The momentum is given by Mass × Velocity
The given parameters are;
The mass of the box = 10 kg
The velocity by which the box is sliding = 50 m/s
Therefore, the momentum of the ball is given as follows;
The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s
The momentum of the ball = 500 kg·m/s
Your family is going to drive to your grandma's house for Christmas dinner. You set the car's odometer to 0 before you leave. When you arrive, the odometer reads 42.6 miles. Looking at a map, you see the direct, straight-line distance is 30 miles due east. When you return home, what will be your distance and displacement for the round trip, in that order?
Answer:
Distance = 85.3 miles
displacement = 0
Explanation:
The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;
Total distance for the round trip = 42.6 + 42.6 = 85.2 miles
Since the trip was a round trip, the displacement is zero because the family returned to their initial location.
How many significant figures are in the number 08.40001
07
3
O 6
O 5
Answer:
5
Explanation:
every number after the decimal
TRUE or FALSE: During a collision between objects of different mass, there is a greater force applied to the less massive object.
I WILL GIVE U 100 POINTS IF U COMPLETE THIS AND GET RIGHT!!!!!!!!!!!!
Answer:
A.
1. when the butter was placed on the spoon it slowly started to boil then began to melt.
2.the order was to heat the bowl, let it boil, then place the butter in.
3.The heat got from the water to the butter by placing it on the spoon then physically moving it into the hot bowl.
4.objects that do not conduct heat are called insulators.
B.
1. When the ice cube got placed into the water it immediately melted.
2.the water from the ice cube to the warm water as soon as it got laced it immediately melted.
3. the heat flowed straight up which made the ice melt really fast.
TABLE A: when I placed the butter in it melted a little bit slower than the ice cube but it still melted very fast.
TABLE B: when I put the colored one in the color slowly dissolved and pushed the color to the middle and the cube melted.
TABLE C: room temp water:75 degrees
cold water:50
hot water:315 degrees
TABLE D: when I blew out the candle the flame went but the smoke started to rise up.
TABLE E: the small beaker heated up quicker and I observed that the less amount of mass the faster it will heat up.
TABLE F: the black piece of paper heated up quicker and I believe its because the darker color the more mount of heat is attracted.
Explanation: I HOPE THIS HELPED! BRAINLESS?
2. What is the power rating of an engine capable of lifting a 100 kg object 5 m vertically
in 4 seconds?
Given values are:
Force,
f = 100Time,
t = 4 secondsNow,
→ [tex]Work \ done= f\times d[/tex]
[tex]= 100\times 50[/tex]
[tex]= 500[/tex]
hence,
The power will be:
= [tex]\frac{Work}{time}[/tex]
= [tex]\frac{500}{4}[/tex]
= [tex]125 \ watt[/tex]
Thus the response above is right.
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How did Galileo increase public support for Copernicus’s model?
by publishing his work in Italian
by using data collected by Tycho Brahe
by explaining why planets appear to move backward
by arguing that Earth’s rotation makes objects appear to move in the sky
Galileo increases public support for Copernicus's model by publishing his work in Italian. Thus option a is correct.
Copernicus's model has been the heliocentric model of the universe given by Nicolaus Copernicus. According to the model, the sun has been the center of the universe, and the planets are revolving around the Sun in a circular path, and at a constant speed.
This idea of Copernicus has been against religious belief and thus has not been accepted. However, the development of Keplar's law helps in the better understanding of Copernicus's model.
Galileo increases public support for Copernicus's model by publishing his work in Italian. Thereby finally the model has been published in 1543. Thus option a is correct.
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Answer: The answer is: by publishing his work in Italian
Explanation: credit to the guy above me!
Have a great day!
-Sunny
A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?
Answer:
[tex]2.33\ m/s^2[/tex]
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = m.a
Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.
The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.
The net force is Fn = 5000 N - 1500 N = 3500 N
To find the acceleration, we solve the equation for a:
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
[tex]\displaystyle a=\frac{3500}{1500}[/tex]
[tex]\boxed{a = 2.33\ m/s^2}[/tex]
The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]
Why must the rockets use great force to get into outer space?
hello, why do all electromagnetic waves travel at the same speed in vacuum?
Answer:
due to the magnetic field
Explanation:
magnetic field is the same in the vacuum
Cuatro niños jalan de manera separada un mismo carrito de baleros con un mismo desplazamiento, pero uno con un ángulo de 45°, otro con un ángulo de 35°, otro de 20° y el ultimo con un ángulo de 0°, medidos con respecto al eje horizontal. ¿Cuál de los cuatro realiza un mayor trabajo, si la fuerza que se aplica cada uno de ellos es la misma? Selecciona el ángulo:
Answer:
El niño que aplica una fuerza a un ángulo de 0º realiza el mayor trabajo.
Explanation:
Si consideramos que las fuerzas aplicadas en el carrito de baleros es constante tanto en magnitud como en dirección, el trabajo realizado por cada niño ([tex]W[/tex]), medido en joules, puede definirse mediante la siguiente expresión:
[tex]W =F\cdot x\cdot \cos \alpha[/tex] (1)
Donde:
[tex]F[/tex] - Magnitud de la fuerza aplicada por el niño, medida en newtons.
[tex]x[/tex] - Distancia desplazada por el carrito de baleros, medida en metros.
[tex]\alpha[/tex] - Dirección de la fuerza aplicada, medida en grados sexagesimales.
De (1) tenemos que la fuerza efectiva que empuja el carro es:
[tex]F_{e} = F\cdot \cos \alpha[/tex]
La fuerza aplicada por cada niño es despejada:
[tex]F = \frac{F_{e}}{\cos \alpha}[/tex]
A mayor ángulo, tenemos un menor valor del coseno y, por ende, mayor valor de la fuerza aplicada. Ahora, el mayor trabajo realizado se realiza con el menor ángulo posible y bajo esta consideración, el niño que aplica una fuerza a un ángulo de 0º realiza el mayor trabajo.
1. A book is at rest on a tabletop. Diagram the forces acting on the book.
The free-body diagram of the forces acting on a book resting on a table is shown in the figure.
When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.
So, the forces acting on a book resting on a tabletop are:
1. Weight of the book, W(downward)
2. Normal force (N) perpendicular to the surface in contact.
Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.
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an astronaut with mass ma is within a satellite that orbits earth at a height h above its surface
Answer:
i really dont know why its such a big deal
Explanation:
An astronaut with mass ma is within a satellite that orbits earth at a height h above its surface. The correct expression for the gravitational force exerted on the astronaut by Earth on the basis described can be,
Fg=G MeMa/r²e
What is gravitational force?
Gravity is a basic interaction in physics that produces mutual attraction between all entities that have mass or energy.
Gravity maintains the planets around the sun and the moon orbiting the Earth. The moon's gravitational pull attracts water, causing ocean tides. Gravity creates stars and planets by attracting the elements that go into their formation.
Gravity waves are 'ripples' in space-time caused by some of the most destructive and powerful occurrences in the Universe. In the year 1916, Albert Einstein used to predicted the existence of gravitational waves which can be popularly known as general theory of relativity.
The gravitational force has the lowest non-contact strength in nature. It adheres to the inverse square law. It is always positive. It is directly proportional to the product of the two bodies' masses.
Thus, the equation can be written as,
Fg=G MeMa/r²e
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Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f
Answer: true
Explanation:
A block of concrete weights 1200 N. It’s base is a square with sides 4m long. what pressure does the concrete block exert on the ground ?
Explanation:
pressure=force/area
area =4×4=16 m^2
therefore p= 1200÷16
= 75 Nm^-2/Pa
1) If a projectile launched at a speed of 20m/s above the horizontal axis of an angle 53 ;(usin g=10mls sin 53=0.8 cos 53=0.6)
find
a the displacement at 2sec
b) the velocity of 2sec
c) total time
d) maximum time
e) Range
f) maximum height
Answer:
(a) 26.83 m
(b) 12.65 m/s
(c) 3.2 seconds
(d) 3.2 seconds
(e) 38.4 m
(f) 12.8 m
Explanation:
Given that a projectile launched at a speed of 20m/s above the horizontal axis at an angle of 53 degrees.
The vertical component of the velocity in the upward direction,
u= 20 sin 53= 20 x 0.8 = 16 m/s.
The horizontal component of the initial velocity,
s=20 cos53 = 20x0.6=12 m/s.
As the gravitational force acts in the vertical direction, so it will only change the vertical component of the initial velocity while the horizontal component of the initial velocity remains unchanged.
(a) The displacement at 2 seconds:
The horizontal distance covered in 2 seconds = 12x2= 24 m
By using the equation of motion, s= ut +1/2 at²
Here, a= -10 m/s² (as g=10m/s² acts in the downward direction)
the vertical displacement s= 16x2- 1/2 x 10 x 2²=12 m
Hence, the displacement after 2 seconds = [tex]\sqrt{24^2+12^2}[/tex]=26.83 m
(b) The velocity at 2 seconds:
As the horizontal component of the velocity is not changing, so the horizontal component of the velocity = 12 m/s
By using the equation of motion, v=u+at
The vertical component of the velocity, v= 16 - 10x2=-4m/s
The negative sign shows that the vertical component of the velocity is in the downward direction.
So, the the velocity at 2 seconds = 12 i - 4 j m/s
The magnitude of the velocity = [tex]\sqrt{12^2+(-40^2}[/tex]=12.65 m/s
(c) Total time of flight:
Total time of flight = 2 x (time to reach the maximum height)
At maximum height, the vertical component of the velocity = 0
So, by using the equation of motion, v=u+at
0= 16-10 t
t= 16/10=1.6 seconds
Hence, the total time of flight= 2 x 1.6 = 3.2 seconds.
(d) Maximum time:
This is the same as the total time of flight, so the maximum time = 3.2 seconds.
(e) Range:
Range = Horizontal component of the velocity x total time of flight
= 12 x 3.2 = 38.4 m
(f) Maximum height:
As the time to reach the highest point = 1.6 seconds
So, by using the equation of motion s = ut + 1/2 at²
The maximum height, s = 16 x 1.6 + 1/2 (-10)1.6² =12.8 m
Hence, the maximum height is 12.8 m.
I need help
What should be done when the National Weather Service issues a severe weather watch?
Evacuate immediately.
Seek shelter immediately.
Take immediate action.
Begin to prepare.
a traveller covers 1.2km distance in 5mins find it's average velocity
Explanation:
Average Velocity = Displacement / Time
= 1.2km / 5 min
= 1200m / 300s
= 4m/s.
The average velocity of a moving body is the distance covered by time. The average velocity of the traveler covers 1.2 km in 5 min is 4 m/s.
What is velocity ?Velocity is a physical quantity which measures the distance travelled per unit time. Velocity is a vector quantity thus having both magnitude and direction.
Velocity is the ratio of distance to the time. Given that the distance travelled by the man = 1.2 km = 1200 m
time = 5 min = (5 × 60 s) = 300 s.
Thus, velocity = distance/ time
= 1200 m / 300 s
= 4 m/s.
Therefore, the velocity of the traveler is 4 m/s.
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---Spring Question---
A 0.84 kg ball is held at rest against a spring (k = 142 N/m) that has been compressed 0.06 m. The ball and spring are on a table and the ball is 2.0 m above the ground. If friction between the ball and the table is negligible, then how far from the edge of the table (in meters) will the ball hit the ground?
Answer:
The distance from the edge of the table at which the ball will hit the ground is approximately 0.49 meters
Explanation:
The mass of the ball = 0.84 kg
The spring constant k = 142 N/m
The compression of the spring = 0.06
Therefore, by conservation of energy, we have;
The potential energy of the spring = The kinetic energy given to the ball
The potential energy of the spring = 1/2 × k × x² = 1/2 × 142 × 0.06² = 0.2556
The potential energy of the spring = 0.2556 J
The kinetic energy given to the ball = 1/2 × m × v²
Where;
v = The final velocity of the ball
Substituting gives;
1/2 × 0.84 × v² = 0.2556
∴ v = √(0.2556/(1/2 × 0.84)) ≈ 0.78
The final velocity of the ball = v ≈ 0.78 m/s
The height of the ball above the ground, h = 2.0 m
Therefore, we have;
The time, t, it takes the ball to touch the ground from the 2.0 m height, h, is given as follows;
h = 1/2·g·t²
t = √(2·h/g)
Where;
g = The acceleration due to gravity = 9.81 m/s²
∴ By substitution, we have;
t = √(2 × 2/9.81) ≈ 0.63855
t ≈ 0.63855 s
The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground
The horizontal distance covered during before the ball hits the ground = The (horizontal) velocity of the ball × The time it takes the ball to touch the ground
∴ The horizontal distance covered during before the ball hits the ground = 0.78 × 0.62855 ≈ 0.490269 ≈ 0.49
The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground ≈ 0.49 m
The diagrams show objects' gravitational pull toward each other. Which statement describes the relationship between diagram X and Y? х Gravity attracts only larger objects toward one another. Gravity attracts larger objects only if they are close to one another. If the masses of the objects increase, then the force between them also increases. If distance between the objects increases, then the amount of force also increases. Y Z
Answer:
you are right Gravity attracts larger objects only if they are close to one another. If the masses of the objects increase, then the force between them also increases. If distance between the objects increases, then the amount of force also increases. Y Z this is the answer .
Explanation:
Answer:
If distance between the objects increases, then the amount of force also increases.
Explanation:
A plane lands and comes to a complete stop. If the plane covers 200 m and decelerates at 7.5 m/s2 , what was the planes initial velocity as it touched the runway?
Answer:
The initial velocity of the plane is 54.77 m/s
Explanation:
Given;
distance covered by the plane, d = 200 m
deceleration of the plane, a = - 7.5 m/s²
The initial velocity of the plane is given by the following kinematic equation;
v² = u² + 2ad
where;
v is the final velocity of the plane when the plane comes to a complete stop = 0
u is the initial velocity of the plane
0 = u² + 2(-7.5 x 200)
0 = u² - 3000
u² = 3000
u = √3000
u = 54.77 m/s
Therefore, the initial velocity of the plane is 54.77 m/s